I have 2 tables :
tb_doc :
===========================================
| id | document_title | document_summary |
===========================================
| 1 | a data mining | document_summary1 |
| 2 | B | document_summary2 |
===========================================
tb_wrap :
============================================
| id | data_url | data_title | doc_url |
===========================================
| 1 |data_url1 | B | doc_url1 |
| 2 |data_url2 | a data mining | doc_url2 |
============================================
I wanna join data from 2 table where document_title = data_title (match 2 strings), so I will get the result like :
data_title <href data_url>
doc_url
document_summary
here's the query :
SELECT * from tb_wrap as a
JOIN (
SELECT document_title, document_summary from tb_doc) as b`
ON a.data_title LIKE b.document_title
How to get them? thank you :)
The JOIN condition should be an = rather than a LIKE. I see no need to join against a subquery. This is just a rudimentary INNER JOIN.
SELECT
tb_wrap.data_url,
tb_wrap.data_title
tb_wrap.doc_url,
tb_doc.document_summary
FROM
tb_doc
INNER JOIN tb_wrap ON tb_doc.document_title = tb_wrap.data_title
Related
We have 3 tables :
donations
purposes
expenses
Donations :
+--------+------+
| do_id | name |
+--------+------+
| 1 | A |
| 2 | B |
| 3 | A |
| 4 | D |
| 5 | B |
| 6 | B |
| 7 | A |
| 8 | B |
+--------+----- +
purposes:
+-------+-------+--------+
| pu_id | do_id | purpose|
+-------+-------+--------+
| 1 | 2 | abc |
| 2 | 2 | def |
| 3 | 2 | gih |
| 4 | 3 | jkl |
+-------+-------+--------+
expense :
+-------+-------+---------+
| ex_id | do_id | expense |
+-------+-------+---------+
| 1 | 2 | abc |
| 2 | 2 | def |
| 3 | 2 | gih |
| 4 | 3 | jkl |
+-------+-------+---------+
Now i want to make query to get all donations for donor B and join purposes table to get all purposes related to every donation_id then join expenses table to get all expenses related to donation_id and put all of that in every loop independently something like that
Row number 0
donation_id = 1
array(purposes)
array(expenses)
Row number 1
donation_id = 2
array(purposes)
array(expenses)
Row number 2
donation_id = 3
array(purposes)
array(expenses)
Row number 3
donation_id = 4
array(purposes)
array(expenses)
This is my try :
SELECT *, (
SELECT *
FROM `donation_purposes`
WHERE `donation_purposes`.`dopu_donation_id` = 4
) AS `purposes`
FROM `donations`
WHERE `donation_id` = '4'
thanks in advance
You should be able to solive this with an aggregate query using MySQL aggregate function JSON_ARRAYAGG(), like :
SELECT
d.do_id,
JSON_ARRAYAGG(p.purpose) purposes,
JSON_ARRAYAGG(e.expense) expenses
FROM donations d
INNER JOIN purposes p ON p.do_id = d.do_id
INNER JOIN expense e ON e.do_id = d.do_id
GROUP BY d.do_id
I you want to avoid duplicate values in the array, and as JSON_ARRAYAGG() (sadly) does not support the DISTINCT option, you can move aggregation to subqueries, like :
SELECT
d.do_id,
p.agg purpose,
e.agg expenses
FROM donations d
INNER JOIN (
SELECT do_id, JSON_ARRAYAGG(purpose) agg FROM purposes GROUP BY do_id
) p ON p.do_id = d.do_id
INNER JOIN (
SELECT do_id, JSON_ARRAYAGG(expense) agg FROM expense GROUP BY do_id
) e ON e.do_id = d.do_id
This demo on DB Fiddle returns :
| do_id | purpose | expenses |
| ----- | --------------------- | --------------------- |
| 2 | ["abc", "def", "gih"] | ["abc", "def", "gih"] |
| 3 | ["jkl"] | ["jkl"] |
1st Select Query Purposes
SELECT purposes.* FROM purposes
LEFT JOIN donations
ON purposes.do_id = donations.do_id
WHERE donations.do_id = '2' //This depends on the id of the donation
ORDER BY purposes.do_id ASC
2nd Select Query Expenses
SELECT expense.* FROM expense
LEFT JOIN donations
ON expense.do_id = donations.do_id
WHERE donations.do_id = '2' //This depends on the id of the donation
ORDER BY expense.ex_id ASC
All queries generated are from the table structure you've provided, but your question is quite vague!!
I got working code from three queries but I would like to combine them into one or two. Basically I am checking if a provided phone number exists in table contacts or leads as well as if it exists as a secondary number in customfieldsvalues (not all leads have a customfield value though). I am using a CRM system based on CodeIgniter.
What I want to do (non-correct/hypothetical query):
SELECT * FROM contacts OR leads WHERE phonenumber = replace(X, '-', '')
OR leads.id = customvaluefields.relid AND cfields.fieldid = 41 AND cfields.value = X
Tables
table : contacts
+-------+----------------+----------------+
| id | firstname | phonenumber |
+-------+----------------+----------------+
| 1 | John | 214-444-1234 |
| 2 | Mary | 555-111-1234 |
+-------+----------------+----------------+
table : leads
+-------+-----------+---------------------+
| id | name | phonenumber |
+-------+-----------+---------------------+
| 1 | John | 214-444-1234 |
| 2 | Mary | 555-111-1234 |
+-------+-----------+---------------------+
table : customvaluefields
+-------+-----------+-------------+-----------+
| id | relid | fieldid | value |
+-------+-----------+-------------+-----------+
| 1 | 1 | 41 | 222333444 |
| 2 | 1 | 20 | Management|
| 3 | 2 | 41 | 333444555 |
+-------+-----------+-------------+-----------+
If I understand what you are trying to, maybe UNION ALL would work. This is something to get you started:
SELECT C.ID, C.FirstName, C.Phonenumber
FROM Contacts C
JOIN CustomValueField CVF
ON c.ID = CVF.RelID AND
CVF.ID = 41
AND REPLACE(Phonenumber,'-','') = cvf.Value
UNION ALL
SELECT L.ID, L.FirstName, L.Phonenumber
FROM Leads L
JOIN CustomValueField CVF
ON L.ID = CVF.RelID AND
CVF.ID = 41
AND REPLACE(Phonenumber,'-','') = cvf.Value
I'm joining the contacts and leads tables to CustomeValueField in each query and then UNION them together along with the WHERE clause in each. I'm sure it's not 100% correct for what you need, but should get you headed to a solution. Here is more information: https://dev.mysql.com/doc/refman/8.0/en/union.html
I have this query, it joins two tables and give me results of all the data under one a condition CATID is
'videography'
SELECT
pm_categories_images.Image,
pm_categories_images.FileURL,
pm_categories.catname,
pm_categories.`status`,
pm_categories.sortorder,
pm_categories.parentID,
pm_categories_images.CatID
FROM
pm_categories
LEFT JOIN pm_categories_images ON pm_categories_images.CatID = pm_categories.catID
where pm_categories_images.CatID IN (select catid from pm_categories where
parentID = (select catID from pm_categories where catname = 'Videography'))
Now this videography has a results like this
http://prntscr.com/gpkuyl
now i want to get 1 record for every catname
Without a MCVE and actual requirements on which image you want from the images table and a better understanding of why you need a left join when your where clause makes it behave like an inner... and why the where clause is so complex... ...I'm really unsure what the question is after... Here's a shot... and a DEMO:http://rextester.com/CRBN50943
Sample data expected results always a plus: I made my own and several assumptions
I interperted the question as: I would like a list of the categories along with a image having the earliest alphabetic value for each category.
SELECT
CI.Image,
CI.FileURL,
C.catname,
C.`status`,
C.sortorder,
C.parentID,
CI.CatID
FROM pm_categories C
INNER JOIN pm_categories_images CI
ON CI.CatID = C.catID
INNER JOIN (SELECT Min(Image) MI, catID FROM pm_categories_images group by CATID) Z
on CI.Image = Z.MI
and CI.CatID = Z.CatId
##WHERE C.catname = 'Videography'
Order by sortOrder
Giving us
+----+------------+-----------------------------------------------+-------------+--------+-----------+----------+-------+
| | Image | FileURL | catname | status | sortorder | parentID | CatID |
+----+------------+-----------------------------------------------+-------------+--------+-----------+----------+-------+
| 1 | guid1.jpg | https://drive.google.com/BusinessID/Postings/ | Real Estate | 1 | 1 | NULL | 1 |
| 2 | guid4.jpg | https://drive.google.com/BusinessID/Postings/ | commercial | 1 | 2 | NULL | 2 |
| 3 | guid6.jpg | https://drive.google.com/BusinessID/Postings/ | Videography | 1 | 3 | NULL | 3 |
| 4 | guid10.jpg | https://drive.google.com/BusinessID/Postings/ | Other | 1 | 4 | NULL | 4 |
| 5 | guid11.jpg | https://drive.google.com/BusinessID/Postings/ | LackingMCVE | 1 | 5 | NULL | 5 |
+----+------------+-----------------------------------------------+-------------+--------+-----------+----------+-------+
I have case to get filenames from table foto
for the firts table
tb_induk
----------------
id_induk | nomor_induk | id_burung | hen | cock
25 | IND003 | 2 | 91442 | 30441
26 | IND004 | 2 | 10464 | 40020
note : column "hen" and "cock" is "id_data" from birds
second table:
tb_foto
----------------------
id_foto | id_data | filename
566 |91442 |4b584a8cd6cb98d4b4d9614abb223034.JPG
567 |91442 |b526318215b5c12bf79b3284d8bd5db7.JPG
568 |30441 |4db159080e0cefb4fd9a2862502ab0f5.JPG
570 |10464 |4216d01abb3bdce90bd72e40ef1d593b.JPG
571 |40020 |6c5b28bffd79fc661f44733c04d12446.JPG
The query is:
Query
-----------------------
"select
tb_induk.id_induk as id_induk,
tb_induk.nomor_induk as nomor_induk,
case WHEN tb_foto.id_data=tb_induk.Hen THEN tb_foto.filename END as filenamehen,
case WHEN tb_foto.id_data=tb_induk.Cock THEN tb_foto.filename END as filenamecock
from tb_induk INNER JOIN tb_foto ON
tb_induk.Hen=tb_foto.id_data || tb_induk.Cock=tb_foto.id_data
where id_burung=$id_burung GROUP BY tb_induk.id_induk"
Result
Result
------------------------------
id_induk | nomor_induk | id_burung | hen | cock
25 | IND003 | 2 | 4216d01abb3bdce90bd72e40ef1d593b.JPG | NULL
26 | IND004 | 2 | NULL | 207b21895c556bc5fada1ead8ec34d06.JPG
I think you can just join tb_foto twice to pull in the filenames for hens and cocks, for each tb_induk value:
SELECT t1.tb_induk,
t1.nomor_induk,
t1.id_burung,
COALESCE(tf1.filename, 'NA') AS hen,
COALESCE(tf2.filename, 'NA') AS cock
FROM tb_induk t1
LEFT JOIN tb_foto tf1
ON t1.hen = tf1.id_data
LEFT JOIN tb_foto tf2
ON t1.cock = tf2.id_data
I'm having BookTable in database (with foregin hey LibID):
| BookID | BookName | BookPrice | LibID |
-------------------------------------------
| 1 | Book_1 | 200 | 1 |
| 2 | Book_2 | 100 | 1 |
| 3 | Book_3 | 300 | 2 |
| 4 | Book_4 | 150 | 4 |
and also LibraryTable:
| LibID | LibName | LibLocation |
-----------------------------------
| 1 | Lib_1 | Loc_1 |
| 2 | Lib_2 | Loc_2 |
| 3 | Lib_3 | Loc_3 |
| 4 | Lib_4 | Loc_4 |
I need to write SQL query that will return be the info about the library and number of books for that library:
| LibID | LibName | NumberOfBooks|
------------------------------------
| 1 | Lib_1 | 2 |
| 2 | Lib_2 | 1 |
| 3 | Lib_3 | 0 |
| 4 | Lib_4 | 1 |
It should be one SQL query, probably with nested queries or joins.. Not sure how the query should look like:
SELECT L.LibID AS LibID, L.LibName AS LibName, COUNT(B) AS NumberOfBooks
FROM LibraryTable L, BookTable B
WHERE L.LibID = B.LibID
Will that work?
No, this query will not work. COUNT aggregates data, so you must explicitely tell the DBMS for which group of data you want the count. In your case this is the library (you want one result record per library).
COUNT's parameter is a column, not a table, so change this to * (i.e. count records) or a certain column (e.g. LibID).
The join syntax you are using is valid, but deprecated. Use explicit joins instead. In your case an outer join would even show libraries that have no books at all, if such is possible.
select l.libid, l.libname, count(b.libid) as numberofbooks
from librarytable l
left outer join booktable b on b.libid = l.libid
group by l.libid;
You could also do all this without a join at all and get the book count in a subquery instead. Then you wouldn't have to aggregate. That's way simpler and more readable in my opinion.
select
l.libid,
l.libname,
(select count(*) booktable b where b.libid = l.libid) as numberofbooks
from librarytable l;
SELECT lt.LibID AS LibID, lt.LibName AS LibName, count(*) AS NumberOfBooks
FROM BookTable AS bt
LEFT JOIN LibraryTable AS lt ON bt.LibID = lt.LibID
GROUP BY bt.LibID