I am reading about boost::function and I am a bit confused about its use and its relation to other C++ constructs or terms I have found in the documentation, e.g. here.
In the context of C++ (C++11), what is the difference between an instance of boost::function, a function object, a functor, and a lambda expression? When should one use which construct? For example, when should I wrap a function object in a boost::function instead of using the object directly?
Are all the above C++ constructs different ways to implement what in functional languages is called a closure (a function, possibly containing captured variables, that can be passed around as a value and invoked by other functions)?
A function object and a functor are the same thing; an object that implements the function call operator operator(). A lambda expression produces a function object. Objects with the type of some specialization of boost::function/std::function are also function objects.
Lambda are special in that lambda expressions have an anonymous and unique type, and are a convenient way to create a functor inline.
boost::function/std::function is special in that it turns any callable entity into a functor with a type that depends only on the signature of the callable entity. For example, lambda expressions each have a unique type, so it's difficult to pass them around non-generic code. If you create an std::function from a lambda then you can easily pass around the wrapped lambda.
Both boost::function and the standard version std::function are wrappers provided by the library. They're potentially expensive and pretty heavy, and you should only use them if you actually need a collection of heterogeneous, callable entities. As long as you only need one callable entity at a time, you are much better off using auto or templates.
Here's an example:
std::vector<std::function<int(int, int)>> v;
v.push_back(some_free_function); // free function
v.push_back(&Foo::mem_fun, &x, _1, _2); // member function bound to an object
v.push_back([&](int a, int b) -> int { return a + m[b]; }); // closure
int res = 0;
for (auto & f : v) { res += f(1, 2); }
Here's a counter-example:
template <typename F>
int apply(F && f)
{
return std::forward<F>(f)(1, 2);
}
In this case, it would have been entirely gratuitous to declare apply like this:
int apply(std::function<int(int,int)>) // wasteful
The conversion is unnecessary, and the templated version can match the actual (often unknowable) type, for example of the bind expression or the lambda expression.
Function Objects and Functors are often described in terms of a
concept. That means they describe a set of requirements of a type. A
lot of things in respect to Functors changed in C++11 and the new
concept is called Callable. An object o of callable type is an
object where (essentially) the expression o(ARGS) is true. Examples
for Callable are
int f() {return 23;}
struct FO {
int operator()() const {return 23;}
};
Often some requirements on the return type of the Callable are added
too. You use a Callable like this:
template<typename Callable>
int call(Callable c) {
return c();
}
call(&f);
call(FO());
Constructs like above require you to know the exact type at
compile-time. This is not always possible and this is where
std::function comes in.
std::function is such a Callable, but it allows you to erase the
actual type you are calling (e.g. your function accepting a callable
is not a template anymore). Still calling a function requires you to
know its arguments and return type, thus those have to be specified as
template arguments to std::function.
You would use it like this:
int call(std::function<int()> c) {
return c();
}
call(&f);
call(FO());
You need to remember that using std::function can have an impact on
performance and you should only use it, when you are sure you need
it. In almost all other cases a template solves your problem.
Related
The following trivial Kotlin code snippet
fun main() {}
compiles just fine, but the following
val main : () -> Unit = {}
makes the compiler complain that "No main method found in project.", while I was expecting them to be equivalent (I expect a programming language to be as conceptually uniform as possible).
Why does this happen? Is it related only to main, or does this behaviour concern a larger class of functions? Is there some subtle difference between declaring functions with "fun" and declaring them as lambdas?
Conceptually, they are different things. To see that, let's take a look at roughly what the equivalent Java would be. I'll use JVM for examples in this answer, but the same principles apply to all of the other Kotlin backends.
object Foo {
fun main() { ... }
}
This is roughly
class Foo {
public static void main() { ... }
}
Again, roughly. Technically, you'll get a singleton object and a method on it unless you use #JvmStatic (I assume there's some special handling for main that produces a static function on JVM, but I don't know that for a fact)
On the other hand,
object Foo {
val main: () -> Unit = { ... }
}
Here, we're declaring a property, which in Java is going to get implemented as a getter-setter pair
class Foo {
// Singleton instance
public static Foo instance = new Foo();
public Supplier<Void> main;
Foo() {
main = new Supplier<Void>() {
Void get() {
...
}
}
}
}
That is, there isn't actually a main method. There's a main field which, deep down somewhere, has a function inside of it. In my example above, that function is called get. In Kotlin, it's called invoke.
The way I like to think of it is this. Methods in Kotlin (i.e. the things you define on objects that designate their behavior) are not themselves first-class objects. They're second-class citizens which exist on an object. You can convert them to first-class objects by making them into functions. Functions are ordinary objects, like any other. If you take an ordinary object, which may or may not be a function, and call it with (), then you're actually invoking the method .invoke(...) on it. That is, () is an operator on objects which really ends up calling a method. So in Kotlin, functions are really just objects with a custom invoke and a lot of syntax sugar.
Your val defines a field which is a function. Your fun defines a method. Both of these can be called with (), but only one is a genuine method call; the other is secretly calling .invoke on another object. The fact that they look syntactically the same is irrelevant.
As the old adage goes, functions are a poor man's objects, and objects are a poor man's functions.
There is a subtle (or more than subtle) difference. Declaring it with val means that main is a property containing a reference to an anonymous function (which you defined with the lambda). If you define it with val, then when you call main(), you are actually calling the getter of the main property, and then using the invoke() operator to call invoke() on the return value of the property (the anonymous function).
I noticed that I get the same effect if I define this trivial function:
fun double ( i: Int ) = i*2
and if I define a variable and assign a lambda (with an identical body) to it:
var double = { i : Int -> i*2 }
I get the same result if I call double(a) with either declaration.
This leaves me confused. When is it needed, recommended, advantageous to define a variable as a lambda rather than define a function to it?
When is it needed, recommended, advantageous to define a variable as a lambda rather than define a function to it?
Whenever you have the choice of either, you should use a fun declaration. Even with a fun you can still get a first-class callable object from it by using a function reference.
On the JVM, a fun is significantly more lightweight, both in terms of RAM and invocation overhead. It compiles into a Java method, whereas a val compiles into an instance field + getter + a synthetic class that implements a functional interface + a singleton instance of that class that you must fetch, dereference, and invoke a method on it.
You should consider a function-typed val or var only when something is forcing you to do it. One example is that you can dynamically replace a var and effectively change the definition of the function. You may also receive function objects from the outside, or you may need to comply with an API that needs them.
In any case, if you ever use a function-typed property of a class, you'll know why you're doing it.
First, if I understand you right, your question is "Why are functions first-class citizens in Kotlin -- And when to use them as such?", right?
Kotlin functions are first-class, which means that they can be stored in variables and data structures, passed as arguments to and returned from other higher-order functions. You can operate with functions in any way that is possible for other non-function values. (see here)
As stated in the docs, one use case are higher-order functions. As a first step, I will leave the wikipedia link here: https://en.wikipedia.org/wiki/Higher-order_function
Basically, a higher-order function is a function that takes functions as parameters, or returns a function.
This means that a higher-order function has at least one parameter of a function type or returns a value of a function type.
Following a short example of a higher-order function that receives a parameter of function type (Int) -> Boolean:
fun foo(pred: (Int) -> Boolean) : String = if(pred(x)) "SUCCESS" else "FAIL"
This higher-order function can now be called with any (Int) -> Boolean function.
The docs also state ... [can be used] in any way that is possible for other non-function values.
This means that you can, for example, assign different functions to a variable, depending on your current context.
For example:
// This example is verbose on purpose ;)
var checker: (Int) -> Boolean
if (POSITIVE_CHECK) {
checker = { x -> x > 0 } // Either store this function ...
} else {
checker = { x -> x < 0 } // ... or this one ...
}
if (checker(someNumber)) { // ... and use whatever function is now stored in variable "checker" here
print("Check was fine")
}
(Code untested)
You can define variable and assign it lambda when you want change behaviour for some reason. For example, you have different formula for several cases.
val formula: (Int) -> Int = when(value) {
CONDITION1 -> { it*2 }
CONDITION2 -> { it*3 }
else -> { it }
}
val x: Int = TODO()
val result = formula(x)
If you simply need helper function, you should define it as fun.
If you pass a lambda as a parameter of a function it will be stored in a variable. The calling application might need to save that (e.g. event listener for later use). Therefore you need to be able to store it as a variable as well. As said in the answer however, you should do this only when needed!
For me, I would write the Lambda variable as followed:
var double: (Int) -> Int = { i -> //no need to specify parameter name in () but in {}
i*2
}
So that you can easily know that its type is (i: Int) -> Int, read as takes an integer and returns an integer.
Then you can pass it to somewhere say a function like:
fun doSomething(double: (Int) -> Int) {
double(i)
}
In the following code, I'm trying to create a "function pointer" and an array of functions by regarding function names as usual variables:
proc myfunc1() { return 100; }
proc myfunc2() { return 200; }
// a function variable?
var myfunc = myfunc1;
writeln( myfunc() );
myfunc = myfunc2;
writeln( myfunc() );
// an array of functions?
var myfuncs: [1..2] myfunc1.type;
writeln( myfuncs.type: string );
myfuncs[ 1 ] = myfunc1;
myfuncs[ 2 ] = myfunc2;
for fun in myfuncs do
writeln( fun() );
which seems to be working as expected (with Chapel v1.16)
100
200
[domain(1,int(64),false)] chpl__fcf_type_void_int64_t
100
200
So I'm wondering whether the above usage of function variables is legitimate? For creating an array of functions, is it usual to define a concrete function with desired signature first and then refer to its type (with .type) as in the above example?
Also, is it no problem to treat such variables as "usual" variables, e.g., pass them to other functions as arguments or include them as a field of class/record? (Please ignore these latter questions if they are too broad...) I would appreciate any advice if there are potential pitfalls (if any).
This code is using first class function support, which is prototype/draft in the Chapel language design. You can read more about the prototype support in the First-class Functions in Chapel technote.
While many uses of first-class functions work in 1.16 and later versions, you can expect that the language design in this area will be revisited. In particular there isn't currently a reasonable answer to the question of whether or not variables can be captured (and right now attempting to do so probably results in a confusing error). I don't know in which future release this will change, though.
Regarding the myfunc1.type part, the section in the technote I referred to called "Specifying the type of a first-class function" presents an alternative strategy. However I don't see any problem with using myfunc1.type in this case.
Lastly, note that the lambda support in the current compiler actually operates by creating a class with a this method. So you can do the same - create a "function object" (to borrow a C++ term) - that has the same effect. A "function object" could be a record or a class. If it's a class, you might use inheritance to be able to create an array of objects that can respond to the same method depending on their dynamic type. This strategy might allow you to work around current issues with first class functions. Even if first-class-function support is completed, the "function object" approach allow you to be more explicit about captured variables. In particular, you might store them as fields in the class and set them in the class initializer. Here is an example creating and using an array of different types of function objects:
class BaseHandler {
// consider these as "pure virtual" functions
proc name():string { halt("base name called"); }
proc this(arg:int) { halt("base greet called"); }
}
class HelloHandler : BaseHandler {
proc name():string { return "hello"; }
proc this(arg:int) { writeln("Hello ", arg); }
}
class CiaoHandler : BaseHandler {
proc name():string { return "ciao"; }
proc this(arg:int) { writeln("Ciao ", arg); }
}
proc test() {
// create an array of handlers
var handlers:[1..0] BaseHandler;
handlers.push_back(new HelloHandler());
handlers.push_back(new CiaoHandler());
for h in handlers {
h(1); // calls 'this' method in instance
}
}
test();
Yes, in your example you are using Chapel's initial support for first-class functions. To your second question, you could alternatively use a function type helper for the declaration of the function array:
var myfuncs: [1..2] func(int);
These first-class function objects can be passed as arguments into functions – this is how Futures.async() works – or stored as fields in a record (Try It Online! example). Chapel's first-class function capabilities also include lambda functions.
To be clear, the "initial" aspect of this support comes with the caveat (from the documentation):
This mechanism should be considered a stopgap technology until we have developed and implemented a more robust story, which is why it's being described in this README rather than the language specification.
Now I understand that Defining is to Types as Declaring is to Variables. But which one (Declare or Define) do functions/procedures/methods/subroutines fall under? Or do they have their own terminology?
In C and C++ you can declare a function (a function prototype) like this:
int function(int);
And then you can define it later, say, at the end of the file:
int function(int param) {
printf("This is the param: %d", param);
return 0;
}
So you can say that functions in C and C++ can fit into the terminology of both types and variables. It depends on the language you're using too, but this how I learned it.
What does "Overloaded"/"Overload" mean in regards to programming?
It means that you are providing a function (method or operator) with the same name, but with a different signature.
For example:
void doSomething();
int doSomething(string x);
int doSomething(int a, int b, int c);
Basic Concept
Overloading, or "method overloading" is the name of the concept of having more than one methods with the same name but with different parameters.
For e.g. System.DateTime class in c# have more than one ToString method. The standard ToString uses the default culture of the system to convert the datetime to string:
new DateTime(2008, 11, 14).ToString(); // returns "14/11/2008" in America
while another overload of the same method allows the user to customize the format:
new DateTime(2008, 11, 14).ToString("dd MMM yyyy"); // returns "11 Nov 2008"
Sometimes parameter name may be the same but the parameter types may differ:
Convert.ToInt32(123m);
converts a decimal to int while
Convert.ToInt32("123");
converts a string to int.
Overload Resolution
For finding the best overload to call, compiler performs an operation named "overload resolution". For the first example, compiler can find the best method simply by matching the argument count. For the second example, compiler automatically calls the decimal version of replace method if you pass a decimal parameter and calls string version if you pass a string parameter. From the list of possible outputs, if compiler cannot find a suitable one to call, you will get a compiler error like "The best overload does not match the parameters...".
You can find lots of information on how different compilers perform overload resolution.
A function is overloaded when it has more than one signature. This means that you can call it with different argument types. For instance, you may have a function for printing a variable on screen, and you can define it for different argument types:
void print(int i);
void print(char i);
void print(UserDefinedType t);
In this case, the function print() would have three overloads.
It means having different versions of the same function which take different types of parameters. Such a function is "overloaded". For example, take the following function:
void Print(std::string str) {
std::cout << str << endl;
}
You can use this function to print a string to the screen. However, this function cannot be used when you want to print an integer, you can then make a second version of the function, like this:
void Print(int i) {
std::cout << i << endl;
}
Now the function is overloaded, and which version of the function will be called depends on the parameters you give it.
Others have answered what an overload is. When you are starting out it gets confused with override/overriding.
As opposed to overloading, overriding is defining a method with the same signature in the subclass (or child class), which overrides the parent classes implementation. Some language require explicit directive, such as virtual member function in C++ or override in Delphi and C#.
using System;
public class DrawingObject
{
public virtual void Draw()
{
Console.WriteLine("I'm just a generic drawing object.");
}
}
public class Line : DrawingObject
{
public override void Draw()
{
Console.WriteLine("I'm a Line.");
}
}
An overloaded method is one with several options for the number and type of parameters. For instance:
foo(foo)
foo(foo, bar)
both would do relatively the same thing but one has a second parameter for more options
Also you can have the same method take different types
int Convert(int i)
int Convert(double i)
int Convert(float i)
Just like in common usage, it refers to something (in this case, a method name), doing more than one job.
Overloading is the poor man's version of multimethods from CLOS and other languages. It's the confusing one.
Overriding is the usual OO one. It goes with inheritance, we call it redefinition too (e.g. in https://stackoverflow.com/users/3827/eed3si9n's answer Line provides a specialized definition of Draw().