I have a field urn_sem.studentid that I'd like to replace a few characters in; for example:
ABC/2011/BCOMH_NC/I/12 → ABC/2011/BCOMH/I/12
ABC/2011/BCOMH_NC/I/24 → ABC/2011/BCOMH/I/24
I've tried this query:
SELECT REPLACE(studentid, 'KNC/2011/BCOMH_NC/', ' KNC/2011/BCOMH/')
FROM urn_sem
but it doesn't show the new value.
Do you want this:
update urn_sem
set studentid = REPLACE(studentid, 'KNC/2011/BCOMH_NC/', ' KNC/2011/BCOMH/')
where studentid like '%KNC/2011/BCOMH_NC/%'
The WHERE clause is optional. It ensures that the replace is only on rows that change.
And this sample query does not work?
SELECT REPLACE (studentid, '_', '') FROM urn_sem
Related
I have string data in one cell and column type text.
like example :
Q: {"newColumnName":"xxxx","filterList":[],"columnNames":"pqrs"}
columnNames,filterList,newColumnName are not in fixed position may be change.
i need to replace this above string data to
Need Result:{"columnNames":["pqrs"],"filterList":[],"parameters":{"newColumnName":"xxxx"}}
means i need to search and replace :-
1. "columnNames":"pqrs"------>"columnNames":["pqrs"].
2. "newColumnName":"xxxx" ------>"parameters":{"newColumnName":"xxxx"}.
pqrs and xxxx known to me. It can any string in there.
you can do it with a query like this:
It is ONLY a text replacement
to check
SELECT t.val
, REPLACE(
REPLACE(t.val,'"columnNames":"pqrs"','"columnNames":["pqrs"]')
, '"newColumnName":"xxxx"' , '"parameters":{"newColumnName":"xxxx"}') as result
FROM tt t;
to replace
UPDATE tt
set tt.val =
REPLACE(
REPLACE(tt.val,'"columnNames":"pqrs"','"columnNames":["pqrs"]')
, '"newColumnName":"xxxx"' , '"parameters":{"newColumnName":"xxxx"}');
How i can get value like this in a variable 'TFSEP-2019','TFjul-2018','TFJun-2018' without spaces.
SELECT s.house, s.grade, s.homeroom AS Campus
FROM student s,fees_jrl f
WHERE s.studnum = f.studnum AND
f.name IN (' TFJun-2018 TFJul-2018 ') AND
f.trans_type= 'chg' AND
f.paid_id is NULL AND s.house LIKE '%'
GROUP BY s.house
I am getting like this ('TFJun-2018 TFJUL-2018 TFSEP-2019') but I want like ('TFSEP-2019','TFjul-2018','TFJun-2018') please help
You may refer the following statements with like operators, whenever you need quotes('), use doubled-quotes('') :
create table tab ( Id int, expression varchar(100));
insert into tab values(1 ,'TFJun-2018 TFJUL-2018 TFSEP-2019');
insert into tab values(2,'''TFJun-2018'',''TFJUL-2018'',''TFSEP-2019''');
select * from tab where expression like '''TFJun-2018''%';
Id expression
2 'TFJun-2018','TFJUL-2018','TFSEP-2019'
or
select * from tab where expression like '''TFJun-2018'',''TFJUL-2018''%';
Id expression
2 'TFJun-2018','TFJUL-2018','TFSEP-2019'
or
select * from tab where expression like '''TFJun-2018'',''TFJUL-2018'',''TFSEP-2019''%';
Id expression
2 'TFJun-2018','TFJUL-2018','TFSEP-2019'
Rextester Demo
You can use like for strings
% means any chars, _ means one char
So doing
F.name like %2018%
Will give you all of 2018..
use explicit join and concat
SELECT
concat( concat( concat( concat("'",s.house),"'"),concat( concat("'",s.grade),"'")),
concat( concat("'",s.homeroom),"'"))
FROM student s join fees_jrl f
on s.studnum = f.studnum
where f.name IN (' TFJun-2018 TFJul-2018 ') AND
f.trans_type= 'chg' AND
f.paid_id is NULL AND s.house LIKE '%'
I think you dont need group by as you have no aggregation function
I'm trying to search and replace mobile numbers with the full international code.
So where rows have 07970000007 to replace the beginning with +447970000007
UPDATE tblMemberImportClub
SET msisdn = REPLACE(msisdn, '07', '+447')
WHERE INSTR(msisdn, '07') = 1;
But this also replaces the other matches:
+4479700000+447
I don't think i can use TRIM as some rows will already start with +447 and will therefore nor require any updates.
Thanks in advance for any assistance.
Use LIKE and INSERT():
UPDATE tblMemberImportClub
SET msisdn = INSERT(msisdn, 1, 2, '+447')
WHERE msisdn LIKE '07%';
INSERT() is a string function that replaces exactly the characters you specify (see here).
SELECT
CONCAT(
REPLACE(
LEFT('07970000007',2), '07', '+447'
),
SUBSTRING('07970000007', 3, CHAR_LENGTH('07970000007'))
)as replaced
I'm don't have a lot of knowledge of MySql (or SQL in general) so sorry for the noobness.
I'm trying to update a bunch of String entries this way:
Lets say we have this:
commands.firm.pm.Stuff
Well I want to convert that into:
commands.firm.pm.print.Stuff
Meaning, Add the .print after pm, before "Stuff" (where Stuff can be any Alphanumerical String).
How would I do this with a MySql Query? I'm sure REGEXP has to be used, but I'm not sure how to go about it.
Thanks
Try something like this. It finds the last period and inserts your string there:
select insert(s, length(s) - instr(reverse(s), '.') + 1, 0, '.print')
from (
select 'commands.firm.pm.Stuff' as s
) a
To update:
update MyTable
set MyColumn = insert(MyColumn, length(MyColumn) - instr(reverse(MyColumn), '.') + 1, 0, '.print')
where MyColumn like 'commands.firm.pm.%'
Perhaps use a str_replace to replace commands.firm.pm to commands.firm.pm.print
$original_str = "commands.firm.pm.15hhkl15k0fak1";
str_replace("commands.firm.pm", "commands.firm.pm.print", $original_str);
should output: commands.firm.pm.print.15hhkl15k0fak1
then update your table with the new value...How to do it all in one query (get column value and do the update), I do not know. All I can think of is you getting the column value in one query, doing the replacement above, and then updating the column with the new value in a second query.
To update rows that end in '.Stuff' only:
UPDATE TableX
SET Column = CONCAT( LEFT( CHAR_LENGTH(Column) - CHAR_LENGTH('.Stuff') )
, '.print'
, '.Stuff'
)
WHERE Column LIKE '%.Stuff'
To update all rows - by appending .print just before the last dot .:
UPDATE TableX
SET Column = CONCAT( LEFT( CHAR_LENGTH(Column)
- CHAR_LENGTH(SUBSTRING_INDEX(Column, '.', -1))
)
, 'print.'
, SUBSTRING_INDEX(Column, '.', -1)
)
WHERE Column LIKE '%.%'
I have a MySQL database table 'photos' with a column 'filename'.
I need to replace the spaces in the filename column values with underscores.
Is it possible with a single/multiple query? If so how?
You can use the REPLACE function :
REPLACE(str,from_str,to_str)
Returns the string str with all
occurrences of the string from_str
replaced by the string to_str.
REPLACE() performs a case-sensitive
match when searching for from_str.
So, to replace all occurences of a character by another one in all lines of a table, something like this should do :
update photos set filename = replace(filename, ' ', '_');
ie, you search for ' ' in the column filename and use '_' instead ; and put the result back into filename.
update photos set filename = replace(filename,' ', '_');