How create json format with group-concat mysql? - mysql

Question

How create json format with group-concat mysql?
(I use MySQL)
Example1:
table1:
email | name | phone
-------------------------------------
my1#gmail.com | Ben | 6555333
my2#gmail.com | Tom | 2322452
my2#gmail.com | Dan | 8768768
my1#gmail.com | Joi | 3434356
like syntax code that not give me the format:
select email, group-concat(name,phone) as list from table1
group by email
output that I need:
email | list
------------------------------------------------
my1#gmail.com | {name:"Ben",phone:"6555333"},{name:"Joi",phone:"3434356"}
my2#gmail.com | {name:"Tom",phone:"2322452"},{name:"Dan",phone:"8768768"}
Thanks

Answer 1

With the newer versions of MySQL, you can use JSON_OBJECT function to achieve the desired result, like so:
GROUP_CONCAT(
JSON_OBJECT(
'name', name,
'phone', phone
)
) AS list
To get the SQL response ready to be parsed as an array:
CONCAT(
'[',
GROUP_CONCAT(
JSON_OBJECT(
'name', name,
'phone', phone
)
),
']'
) AS list
This will give you a string like: [{name: 'ABC', phone: '111'}, {name: 'DEF', phone: '222'}] which can be JSON parsed.

Answer 2

Try this query -
SELECT
email,
GROUP_CONCAT(CONCAT('{name:"', name, '", phone:"',phone,'"}')) list
FROM
table1
GROUP BY
email;
JSON format result -
+---------------+-------------------------------------------------------------+
| email | list |
+---------------+-------------------------------------------------------------+
| my1#gmail.com | {name:"Ben", phone:"6555333"},{name:"Joi", phone:"3434356"} |
| my2#gmail.com | {name:"Tom", phone:"2322452"},{name:"Dan", phone:"8768768"} |
+---------------+-------------------------------------------------------------+

Answer 3

For Mysql 5.7.22+
SELECT
email,
JSON_ARRAYAGG(
JSON_OBJECT(
'name', name,
'phone', phone
)
) AS list
FROM table1
GROUP BY email;
Result:
+---------------+-------------------------------------------------------------------+
| email | list |
+---------------+-------------------------------------------------------------------+
| my1#gmail.com | [{"name":"Ben", "phone":6555333},{"name":"Joi", "phone":3434356}] |
| my2#gmail.com | [{"name":"Tom", "phone":2322452},{"name":"Dan", "phone":8768768}] |
+---------------+-------------------------------------------------------------------+
The only difference is that column list is now Json-valid, so you can parse directly as Json

Answer 4

I hope this finds the right eyes.
You can use:
For arrays (documentation):
JSON_ARRAYAGG(col_or_expr) as ...
For objects (documentation):
JSON_OBJECTAGG(key, value) as ...

Answer 5

Devart's answer above is great, but K2xL's question is valid. The answer I found was to hexadecimal-encode the name column using HEX(), which ensures that it will create valid JSON. Then in the application, convert the hexadecimal back into the string.
(Sorry for the self-promotion, but) I wrote a little blog post about this with a little more detail:
http://www.alexkorn.com/blog/2015/05/hand-rolling-valid-json-in-mysql-using-group_concat/
[Edit for Oriol] Here's an example:
SELECT email,
CONCAT(
'[',
COALESCE(
GROUP_CONCAT(
CONCAT(
'{',
'\"name\": \"', HEX(name), '\", ',
'\"phone\": \"', HEX(phone), '\"',
'}')
ORDER BY name ASC
SEPARATOR ','),
''),
']') AS bData
FROM table
GROUP BY email
Also note I've added a COALESCE in case there are no items for that email.

Answer 6

Similar to Madacol's answer above, but slightly different. Instead of JSONARRAYAGG, you could also CAST AS JSON:
SELECT
email,
CAST( CONCAT(
'[',
GROUP_CONCAT(
JSON_OBJECT(
'name', name,
'phone', phone
)
),']') AS JSON )
FROM table1
GROUP BY email;
Result:
+---------------+-------------------------------------------------------------------+
| email | list |
+---------------+-------------------------------------------------------------------+
| my1#gmail.com | [{"name":"Ben", "phone":6555333},{"name":"Joi", "phone":3434356}] |
| my2#gmail.com | [{"name":"Tom", "phone":2322452},{"name":"Dan", "phone":8768768}] |
+---------------+-------------------------------------------------------------------+

Answer 7

Going off of #Devart's answer... if the field contains linebreaks or double quotation marks, the result will not be valid JSON.
So, if we know the "phone" field occasionally contains double-quotes and linebreaks, our SQL would look like:
SELECT
email,
CONCAT(
'[',
GROUP_CONCAT(CONCAT(
'{name:"',
name,
'", phone:"',
REPLACE(REPLACE(phone, '"', '\\\\"'),'\n','\\\\n'),
'"}'
)),
']'
) AS list
FROM table1 GROUP BY email;
If Ben phone has a quote in the middle of it, and Joi's has a newline, the SQL would give (valid JSON) results like:
[{name:"Ben", phone:"655\"5333"},{name:"Joi", phone:"343\n4356"}]

Answer 8

Use like this
SELECT email,concat('{name:"',ur_name_column,'",phone:"',ur_phone_column,'"}') as list FROM table1 GROUP BY email;
Cheers