MySql - Inserting array values (matching and unmatching) into db matching columns - mysql

Question

So I have a list of optional clothing items as checkboxes, there may be a greater number than the 5 below.
shoes, pants, skirt, socks, jacket //list of possible choices
A comma separated array is created in jquery of the chosen item. Let's say the following are chosen:
shoes, socks, jacket //array posted as $_POST['clothes']
In the db, each customer has these options in the clothes table with 'yes' or 'no' under the clothing items. However, the clothing item are named a bit differently but map out to the same options:
'clothes' table before insert
customer_id dress_shoes elegant_pants long_skirt ankle_socks biker_jacket
1 no yes no no no
With the $_POST['clothes'], I'm trying to loop through the array, updating the corresponding fields to 'yes', and the non corresponding fields to 'no' in the db. I have a hard time doing that.
'clothes' table after insert
customer_id dress_shoes elegant_pants long_skirt ankle_socks biker_jacket
1 yes no no yes yes
I did an array_intersect to get the items to mark as 'yes':
$clothesArray = array("shoes", "socks", "jacket"); // Posted clothes
$clothesArrayAll = array("shoes", "pants", "skirt", "socks", "jacket"); // All clothes
$common = array_intersect($clothesArrayAll,$clothesArray);
print_r($common);
Array ( [0] => shoes [3] => socks [4] => jacket )
I'm trying to somehow loop through the $clothesArrayAll, give a 'yes' to common clothes, and a 'no' to all others in the array. Then, I'm trying to update the 'clothes' table via PDO, setting each corresponding field to a 'yes' or 'no' in the most efficient way. I'm stuck after getting the common clothes array above and not sure how to proceed.
Can someone help me please?
Thank you!

Answer 1

I think you are on the right track. I would just add one additional array that contains the mappings of your fields, e.g.
$mappingArray = array('shoes' => 'dress_shoes', 'socks' => 'ankle_socks', ...);
With this array and the previous you can loop through and set your SQL accordingly based on the value of the $common field with the key in the $mappingArray
Edit with example (probably not the most optimized):
$finalArray = array();
foreach ($mappingArray as $key => $value) {
$finalArray[$value] = in_array($key, $common) ? 'yes' : 'no';
}
$finalArray will now have an yes/no statement for each value that matches your db table.
Edit to include PDO: I would actually update the above loop as follows:
$finalArray = array();
$sql = "INSERT INTO cloths (" . implode(",", array_values($mappingArray)) . ") VALUES (:" . implode(",:", array_values($mappingArray)) . ")";;
foreach ($mappingArray as $key => $value) {
$finalArray[":" . $value] = in_array($key, $common) ? 'yes' : 'no';
}
$q = $conn->prepare($sql);
$q->execute($finalArray);
Going on the fly with this one, so something like that...

Answer 2

Why not change your HTML field names to match your database names, set a default of 'no' in the atabase then...
$cols='INSERT INTO clothes ';
$values=' VALUES ';
$join='(';
foreach ($_POST as $key=>$val) {
$cols.=$join . $key;
$values=$join . ':' . $key;
$join=',';
}
$qry=$cols . ')' . $values . ')';
$stmt = $dbh->prepare($qry);
foreach ($_POST as $key=>$val) {
$stmt->bindParam(':' . $key, $_POST[$key]);
}
But you might want to check the posted names are valid column names - you can get the column names and types from the table using
DESC clothes;