i want to do paging. but i only want to know the current page number, so i will call the webservice function and send this parameter and recieve the curresponding data. so i only want to know how can i be aware of current page number? i'm writing my project in django and i create the page with xsl. if o know the page number i think i can write this in urls.py:
url(r'^ask/(\d+)/$',
'ask',
name='ask'),
and call the function in views.py like:
ask(request, pageNo)
but i don't know where to put pageNo var in html page. (so fore example with pageN0=2, i can do pageNo+1 or pageNo-1 to make the url like 127.0.0.01/ask/3/ or 127.0.0.01/ask/2/). to make my question more cleare i want to know how can i do this while we don't have any variables in html?
sorry for my crazy question, i'm new in creating website and also in django. :">
i'm creating my html page with xslt. so i send the total html page. (to show.html which contains only {{str}} )
def ask(request:
service = GetConfigLocator().getGetConfigHttpSoap11Endpoint()
myRequest = GetConfigMethodRequest()
myXml = service.GetConfigMethod(myRequest)
myXmlstr = myXml._return
styledoc = libxml2.parseFile("ask.xsl")
style = libxslt.parseStylesheetDoc(styledoc)
doc = libxml2.parseDoc(myXmlstr)
result = style.applyStylesheet(doc, None)
out = style.saveResultToString( result )
ok = mark_safe(out)
style.freeStylesheet()
doc.freeDoc()
result.freeDoc()
return render_to_response("show.html", {
'str': ok,
}, context_instance=RequestContext(request))
i'm not working with db and i just receive xml file to parse it. so i don't have contact_list = Contacts.objects.all(). can i still use this way? should i put the first parameter inpaginator = Paginator(contact_list, 25) blank?
if you user standart django paginator, thay send you to url http://example.com/?page=N, where N - number you page
So,
# urls.py
url('^ask/$', 'ask', name='viewName'),
You can get page number in views:
# views.py
def ask(request):
page = request.GET.get('page', 1)
Related
My website is mostly to display results, so the admin enters the results and they are rendered nicely for the users/clients. Currently, in my main_controller.rb and other controllers I have functions for the main index page...
def index
#next_tournament = helpers.next_tournament()
#last_tournament = helpers.last_tournament()
#last_tournament_date_display = helpers.last_tournament_date_display(#last_tournament)
#next_tournament_date_display = helpers.next_tournament_date_display(#next_tournament)
#current_season = #last_tournament.season_year
#aoys = helpers.display_aoy(#last_tournament.id)
#aoy_diff = helpers.aoy_point_diff(#aoys)
#individual_winners = helpers.individual_winners(#last_tournament.id)
#team_winners = helpers.team_winners(#last_tournament.id)
#big_bass_winners = helpers.big_bass_winners(#last_tournament.id)
#total_club_stats = helpers.total_club_stats()
#annual_club_stats = helpers.annual_club_stats(#current_season )
...
end
Does this mean, that for every person that navigates to my main index page the server will re-run these functions and spit out the result?
I'm trying to understand what happens on the server side. Would this be a problem? Most of these functions would only change when a new result is entered. Is it best practice to do something in the code, so that the function is only re-ran when any of the variables in the equation change, and otherwise static?
I'm having trouble collecting doctors from https://www.uchealth.org/providers/. I've found out it's a POST method but with httr I can't seem to create the form. Here's what I have
url = url = 'https://www.uchealth.org/providers/'
formA = list(title = 'Search', onClick = 'swapForms();', doctor-area-of-care-top = 'Cancer Care')
formB = list(Search = 'swapForms();', doctor-area-of-care = 'Cancer Care')
get = POST(url, body = formB, encode = 'form')
I'm fairly certain formB is the correct one. However, I can't test it since I yield an error when trying to make the list. I believe it is because you can't use "-" characters when naming although I could be wrong on that. Could somebody help please?
I am unable to comment properly but try this to create an list. Code below worked for me.
library(httr)
url = 'https://www.uchealth.org/providers/'
formB = list(Search = 'swapForms();', `doctor-area-of-care` = 'Cancer Care')
get = POST(url, body = formB, encode = 'form')
When you are creating names with spaces or some other special character you have to put it into the operator above.
In Django, I have programmed a form in which you can upload one image. After uploading the image, the image is passed to another method with the type TemporaryUploadedFile, after executing the method it is given to the HTML page.
What I would like to do is display that TemporaryUploadedFile as an image in HTML. It sounds quite simple to me but I could not find the answer on StackOverflow or on Google to the question: How to display a TemporaryUploadedFile in HTML without having to save it first, hence my question.
All help is appreciated.
Edit 1:
To give some more information about the code and the variables while debugging.
input_image = next(iter(request.FILES.values()))
output_b64 = (input_image.content_type, str(base64.b64encode(input_image.read()), 'utf8'))
Well, you can encode the image to base64 and use a data url as the value for src.
A base64 data url looks like this:
<img src="data:image/png;base64,SGLAFdsfsafsf098sflf">
\_______/ \__________________/
| |
File type base64 encoded data
Read the Mozilla docs for more on data urls.
Here's some relevant code:
import base64
def my_view(request):
# assuming `image` is a <TemporaryUploadedFile object>
image_b64 = base64.b64encode(image.read())
image_b64 = image_b64.decode('utf8') # convert bytes to string
image_type = image.content_type # png or jpeg or something else
return render('template', {'image_b64': image_b64, 'image_type': image_type})
Then in your template:
<img src="data:{{ image_type }};base64,{{ image_b64 }}">
I want to thank xyres for pushing me in the right direction. As you can see, I used some parts of his solution in the code below:
# As input I take one image from the form.
temp_uploaded_file = next(iter(request.FILES.values()))
# The TemporaryUploadedFile is converted to a Pillow Image
input_image = pil_image.open(temp_uploaded_file)
# The input image does not have a name so I set it afterwards. (This step, of course, is not mandatory)
input_image.filename = temp_uploaded_file.name
# The image is saved to an InMemoryFile
output = BytesIO()
input_image.save(output, format=img.format)
# Then the InMemoryFile is encoded
img_data = str(base64.b64encode(output.getvalue()), 'utf8')
output_b64 = ('image/' + img.format, img_data)
# Pass it to the template
return render(request, 'visualsearch/similarity_output.html', {
"output_image": output_b64
})
In the template:
<img id="output_image" src="data:{{ image.0 }};base64,{{ image.1 }}">
The current solution works but I don't think it is perfect because I expect that it can be done with less code and faster, so if you know how this can be done better you are welcome to post your answer here.
I'd like to obtain a list of all the titles of all Wikipedia articles. I know there are two possible ways to get content from a Wikimedia powered wiki. One would be the API and the other one would be a database dump.
I'd prefer not to download the wiki dump. First, it's huge, and second, I'm not really experienced with querying databases. The problem with the API on the other hand is that I couldn't figure out a way to only retrieve a list of the article titles and even if it would need > 4 mio requests which would probably get me blocked from any further requests anyway.
So my question is
Is there a way to obtain only the titles of Wikipedia articles via the API?
Is there a way to combine multiple request/queries into one? Or do I actually have to download a Wikipedia dump?
The allpages API module allows you to do just that. Its limit (when you set aplimit=max) is 500, so to query all 4.5M articles, you would need about 9000 requests.
But a dump is a better choice, because there are many different dumps, including all-titles-in-ns0 which, as its name suggests, contains exactly what you want (59 MB of gzipped text).
Right now, as per the current statistics the number of articles is around 5.8M.
To get the list of pages I did use the AllPages API. However, the number of pages I get is around 14.5M which is ~3 times of what I was expecting. I restricted myself to namespace 0 to get the list. Following is the sample code that I am using:
# get the list of all wikipedia pages (articles) -- English
import sys
from simplemediawiki import MediaWiki
listOfPagesFile = open("wikiListOfArticles_nonredirects.txt", "w")
wiki = MediaWiki('https://en.wikipedia.org/w/api.php')
continueParam = ''
requestObj = {}
requestObj['action'] = 'query'
requestObj['list'] = 'allpages'
requestObj['aplimit'] = 'max'
requestObj['apnamespace'] = '0'
pagelist = wiki.call(requestObj)
pagesInQuery = pagelist['query']['allpages']
for eachPage in pagesInQuery:
pageId = eachPage['pageid']
title = eachPage['title'].encode('utf-8')
writestr = str(pageId) + "; " + title + "\n"
listOfPagesFile.write(writestr)
numQueries = 1
while len(pagelist['query']['allpages']) > 0:
requestObj['apcontinue'] = pagelist["continue"]["apcontinue"]
pagelist = wiki.call(requestObj)
pagesInQuery = pagelist['query']['allpages']
for eachPage in pagesInQuery:
pageId = eachPage['pageid']
title = eachPage['title'].encode('utf-8')
writestr = str(pageId) + "; " + title + "\n"
listOfPagesFile.write(writestr)
# print writestr
numQueries += 1
if numQueries % 100 == 0:
print "Done with queries -- ", numQueries
print numQueries
listOfPagesFile.close()
The number of queries fired is around 28900, which results in approx. 14.5M names of the pages.
I also tried the all-titles link mentioned in the above answer. In that case as well I am getting around 14.5M pages.
I thought that this overestimate to the actual number of pages is because of the redirects, and did add the 'nonredirects' option to the request object:
requestObj['apfilterredir'] = 'nonredirects'
After doing that I get only 112340 number of pages. Which is too small as compared to 5.8M.
With the above code I was expecting roughly 5.8M pages, but that doesn't seem to be the case.
Is there any other option that I should be trying to get the actual (~5.8M) set of page names?
Here is an asynchronous program that will generate mediawiki pages titles:
async def wikimedia_titles(http, wiki="https://en.wikipedia.org/"):
log.debug('Started generating asynchronously wiki titles at {}', wiki)
# XXX: https://www.mediawiki.org/wiki/API:Allpages#Python
url = "{}/w/api.php".format(wiki)
params = {
"action": "query",
"format": "json",
"list": "allpages",
"apfilterredir": "nonredirects",
"apfrom": "",
}
while True:
content = await get(http, url, params=params)
if content is None:
continue
content = json.loads(content)
for page in content["query"]["allpages"]:
yield page["title"]
try:
apcontinue = content['continue']['apcontinue']
except KeyError:
return
else:
params["apfrom"] = apcontinue
I have written the following code.
The issue that I am having is that the database is not being updated and a new record is not being made. I am assuming that the way I am retrieving my POST are incorrect but that's why I am asking where do I begin to debug? I have created template variables for quantity,action,building, and test. When I try to call them in the html {{ test }} for example nothing ever shows up even the one that is hardcoded. I used firebug and the form is indeed posting the values that should be posted.
the form consists of two drop down menus one for action and one for building. A numerical input quantity, a text box and a submit button. If anyone can offer me some advice it would be appreciated. I really don't understand why the hardcoded one doesn't show up
If you need any more information please let me know.
def update(request,Type_slug, slug, id):
error = False
Slug = slug
ID = id
Type = Type_slug
test = 'test'
quantity = request.POST['Qty']
action = request.POST['Action']
building = request.POST['Building']
comments = request.POST['Comments']
if Type == 'Chemicals':
item = Chemicals.objects.filter(S_field=Slug, id= ID)
New_Record = ChemicalRecord(Name=item.Name,Barcode=item.Barcode,Cost=item.Cost,Action=action,Building=building)
if building == 'Marcus':
building_two = 'Pettit'
elif building =='Pettit':
building_two ='Marcus'
Record_one = ChemicalRecord.objects.filter(Barcode=New_Record.Barcode).filter(Building=New_Record.Building)
if Record_one:
Record_one = ChemicalRecord.objects.filter(Barcode=New_Record.Barcode).filter(Building=New_Record.Building).latest('id')
New_Record.On_hand = Record_one.On_hand
else:
New_Record.On_hand = 0
if action == 'Receiving':
New_Record.On_hand = New_Record.On_hand+quantity
elif action == 'Removing':
New_Record.On_hand = New_Record.On_hand-quantity
Record_two = ChemicalRecord.objects.filter(Barcode=New_Record.Barcode).filter(Building=building_two)
if Record_two:
Record_two = ChemicalRecord.objects.filter(Barcode=New_Record.Barcode).filter(Building=building_two).latest('id')
Record_two_qty = Record_two.On_hand
else:
Record_two_qty = 0
New_qty = New_Record.On_hand+Record_two_qty
Chemicals.objects.filter(Barcode=obj.Barcode).update(On_hand=New_qty)
New_Record.save()
You can use import pdb;pdb.set_trace() for debugging.