Can I select like this?
SELECT DISTINCT idClient, idAcc,Description
FROM client, account
WHERE (account.idCliente = client.idCliente
OR account.idCliente is NULL )
Im getting trouble because it show to me duplicated results :x How can I do it ?
Thanks
EDIT:
RESULTS
idClient idAcc Description
1 3 good
1 2 bad
1 3 bad
Note that im getting 2 diferent Descriptions for same idAcc
EDIT2:
I realy need that search by NULL or Not NULL.
You are using an implicit join. Try using an explicit JOIN like so:
SELECT DISTINCT Description
FROM client
LEFT JOIN account ON account.idCliente = client.idCliente
I would rewrite your query to use a LEFT JOIN so that you get all situations where there is a client.idCliente, but also those where the account.idCliente doesn't exist.
Like so:
SELECT DISTINCT Description
FROM client
LEFT JOIN account ON client.idCliente = account.idCliente;
Related
Good day,
I have a small issue with MySQL Distinct.
Trying the following query in my system :
SELECT DISTINCT `booking_id`, `booking_ticket`, `booking_price`, `bookingcomment_id`, `bookingcomment_message` FROM `mysystem_booking`
LEFT JOIN `mysystem_bookingcomment` ON `mysystem_booking`.`booking_id` = `mysystem_bookingcomment`.`bookingcomment_link`
WHERE `booking_id` = 29791
The point is that there are bookings like 29791 that have many comments added.
Let's say 10. Then when running the above query I see 10 results instead of one.
And that's not the way DISTINCT supposes to work.
I simply want to know if there are any comments. If the comment ID is not 0 then there is a comment. Of course I can add COUNT(blabla) as comment_number but that's a whole different story. For me now I'd like just to have this syntax right.
You may try aggregating here, to find which bookings have at least a single comment associated with them:
SELECT
b.booking_id,
b.booking_ticket,
b.booking_price
FROM mysystem_booking b
LEFT JOIN mysystem_bookingcomment bc
ON b.booking_id = bc.bookingcomment_link
WHERE
b.booking_id = 29791
GROUP BY
b.booking_id
HAVING
COUNT(bc.bookingcomment_link) > 0;
Note that depending on your MySQL server mode, you might have to also add the booking_ticket and booking_price columns to the GROUP BY clause to get the above query to run.
You can try below - using a case when expression
SELECT DISTINCT `booking_id`, `booking_ticket`, `booking_price`, `bookingcomment_id`,
case when `bookingcomment_message`<>'0' then 'No' else 'Yes' end as comments
FROM `mysystem_booking`
LEFT JOIN `mysystem_bookingcomment` ON `mysystem_booking`.`booking_id` = `mysystem_bookingcomment`.`bookingcomment_link`
WHERE `booking_id` = 29791
I am having some strange issue with the SQL statement below. The result groups by user IDs and some of them turn out right but for one of them (user ID = 1) the "initial_average" is multiplied by 3. I really have no idea why.. Is there something wrong with the structure of the statement? If it is not clear, the aim is to sum the field "initial_avg" in the "tasks" table and have it broken out by user. Some help with this is much appreciated. I am using MySQL.
SELECT sum(initial_avg) AS initial_average
, sum(initial_std) AS initial_standard_dev
, tasks.user
, hourly_rate
FROM tasks
INNER JOIN user_project
ON tasks.user=user_project.user
AND tasks.project=59
AND tasks.user=1
GROUP BY tasks.user
I just solved it by adding another "and" clause (AND user_project.project=59 )
Optimize your query (Try it):
SELECT SUM(initial_avg) AS initial_average, SUM(initial_std) AS initial_standard_dev, tasks.user, hourly_rate FROM tasks INNER JOIN user_project ON tasks.user = user_project.user AND tasks.project = User_project.project WHERE tasks.project = 59 AND tasks.user = 1 GROUP BY tasks.user, hourly_rate
I am working on a query for a datatable and I can't seem to get it to display how I want, I don't know if this is even possible in SQL What I am looking to do is get a query to respond with ideally an extra column of Boolean type.
Currently I can run two queries and they both work perfectly but I can't work out how to join them together bellow is the code from my first query what this does is return beers a user has tried this works fine and as expected and returns as expected.
SELECT *
FROM keg.beer
JOIN keg.userbeer
ON beer.id = userbeer.beer_id
WHERE userbeer.username_id = 1;
The second query is even simpler and is just a select getting the list of beers.
SELECT * FROM keg.beer
What I want to do is run a query and have it return a list of beers with a Boolean value if the user has tried it or not.
You're not going to run into too many scenarios for "Desired Results" that can't be produced with plain 'ol SQL. In this case you'll use a CASE statement to determine if the person has tried a beer. You'll also want a LEFT OUTER JOIN so you don't drop records coming from your beer table when your filtered userid doesn't have a userbeer record for that beer:
SELECT
beer.name,
beer.id,
beer.country,
CASE WHEN userbeer.username_id IS NULL THEN 0 ELSE 1 END AS user_tried_beer_boolean
FROM keg.beer
LEFT OUTER JOIN keg.userbeer
ON beer.id = userbeer.beer_id
AND userbeer.username_id = 1;
As #SeanLange mentioned in the comments here, the restriction of the WHERE statement for the userid would cause records to be dropped that you want in your result set, so we move the restriction of username_id = 1 to the ON portion of the LEFT OUTER JOIN so that the userbeer table results are restricted to just that user before it's joined to the beer table.
Now I need a drink.
SELECT b.id,
b.name,
CASE WHEN u.username_id IS NOT NULL THEN TRUE ELSE FALSE END AS userdrankbeer
FROM keg.beer b
LEFT JOIN ( SELECT * FROM keg.userbeer WHERE username_id = 1 ) u
ON beer.id = userbeer.beer_id
;
This is a very specific question to the kind of code i have written for postgresql and i am migrating to mysql for project requirements.
The code written so far in mysql is as follows :
(select substring(dt,1,9) as dt,concat(vish,visl,visn) as vis,ip
from assignment_walmart.b
where service='ss' and ua not like '%ktxn%'
and ua not like '%khte%'
and ua not like '%keynote%'
group by 1,2,3
) as A1
left join // This is where it shows the error.
(select ip,flag from
assignment_walmart.b1
group by 1,2
) as A2
on A1.ip=A2.ip
where A2.flag is NULL
group by 1,2;
The error is popping up near the naming of the two selected tables as "A1" and "A2", so i'm assuming it's not allowed in mysql.
Can you please help me with an alternate syntax for the above code as I have to use the two tables in this manner only to join in to get required results.
How exactly do i use alias or join 2 tables in such a manner which was clearly working in postgresql?
Any help would be appreciated.
You have a subquery joined to another query. This shouldn't work in either database. You need to wrap these in a select or something like that:
select A2.dt, A2.vis, count(*)
from (select substring(dt,1,9) as dt, concat(vish,visl,visn) as vis,ip
from assignment_walmart.b
where service='ss' and ua not like '%ktxn%'
and ua not like '%khte%'
and ua not like '%keynote%'
group by substring(dt,1,9), concat(vish,visl,visn), ip
) as A1 left join // This is where it shows the error.
(select ip,flag from
assignment_walmart.b1
group by ip, flag
) as A2
on A1.ip=A2.ip
where A2.flag is NULL
group by A2.dt, A2.vis;
I am making a guess on what you want for the outer query and what the aggregation fields are. It is a good idea to be explicit about which fields are being aggregated.
It looks like you are missing the SELECT ... FROM on the outer query.
It looks you mean for your query to be of the form:
SELECT ...
FROM ( inline view query ) A1
LEFT
JOIN ( inline view query ) A2
ON A1.col = A2.col ...
WHERE ...
GROUP BY ...
I got the following sql question that I that won´t work for me. I know that the last CASE row are wrong but I would like to use a CASE statement like that in my where clause.
Short description of my situation:
I got several companies that got there own material linked to them with "companyID". Each material might be linked to a row in pricelist_entries. If I search for one row in the pricelist_entries table that is linked to many material rows all rows will be returned but I just want to return the one that belongs to the current company (the company that performs the search).
Conclusion: If materialID NOT NULL THEN materials.company="current.companyID".
SELECT peID, peName, materialID
FROM pricelist_entries
INNER JOIN pricelist ON pricelist_entries.peParentID=pricelist.pID
LEFT JOIN materials ON pricelist_entries.peID=materials.pricelist_entries_id
WHERE peBrand = 'Kama' AND pricelist.pCurrent = 1
AND (peName LIKE '%gocamp de%' OR peArtnr LIKE '%gocamp de%')
AND pricelist.country=0 AND pricelist_entries.peDeleted=0
CASE materialID WHEN IS NOT NULL THEN materials.companyID=10 END
Please tell me if I need to describe my problem in a better way.
Thanks in advance!
Sounds like just moving the condition into the join would make it simpler;
SELECT peID, peName, materialID
FROM pricelist_entries
INNER JOIN pricelist
ON pricelist_entries.peParentID=pricelist.pID
LEFT JOIN materials
ON pricelist_entries.peID=materials.pricelist_entries_id
AND materials.companyID=10 -- << condition
WHERE peBrand = 'Kama' AND pricelist.pCurrent = 1
AND (peName LIKE '%gocamp de%' OR peArtnr LIKE '%gocamp de%')
AND pricelist.country=0 AND pricelist_entries.peDeleted=0
It will only left join in material rows that are linked to the correct company.
You can't use CASE in the where clause that I'm aware of, you need to use it in the SELECT portion, but it will have the same effect. Something like this should work:
SELECT CASE materialid WHEN IS NOT NULL THEN companyid END as thiscompanyid
This will give you a new column named thiscompanyid and you can query off of that to get what you need.