Clickable image with sprites - html

So I've got a series of clickable images in my page. I've tried to optimise this by generating a single image containing all the images I need and I intend to use sprites to select the one I want. I'm having trouble figuring out the best way to add anchor tags to the sprites though?
So I'm after a clickable HTML element that supports sprites, preferably without using JavaScript. I can do it using JavaScript but I'd prefer to avoid it.
OK, here's my code, what there is:
.touringEscorted {
height:125px;
width: 214px;
background-image: url('/Images/Travel2New/ToursImages/ToursBanners.jpg');
background-position: 0 0;
}
.touringNew {
height:125px;
width: 214px;
background-image: url('/Images/Travel2New/ToursImages/ToursBanners.jpg');
background-position: -10px 0;
}
I've tried
<div class="touringEscorted">
and
and several others. Seems there's no way to use sprites/background images and anchor tags at the same time. Am I right?
Any suggestions?

Ok then :
Should work, but adding display:block; to the CSS :
.touringEscorted {
height:125px;
width: 214px;
background-image: url('/Images/Travel2New/ToursImages/ToursBanners.jpg');
background-position: 0 0;
display:block;
}

Like this?
<a class="sprite sprite1" href="javascript:;">Link Text</a>
sprite {
display: block;
background: url(path/to/image/file.ext);
text-indent: -9999px;
}
sprite1 {
width: WWpx;
height: HHpx;
background-position: -NNpx - MMpx;
}

Doesn't Google consider off screen text as spammy? I came up with a modification. I put the link in another element, in this case a table. I added the background image class in the element and in the link like this:
CSS code:
.sprite{
background: url('images/sprite.png') no-repeat top left;
}
.sprite.termite {
background-position: 0px -499px;
width: 150px; height: 113px;
display: block;
}
HTML code:
<td class="td sprite termite">
</td>
It renders the image in the table perfectly and clicks!

Related

Half my CSS Sprite images not displaying

I have a table of roll over images / links, for which I was hoping to use a sprite for but for some reason when the code goes live only around half of the images display.
My code is here if anyone wants to look at it in the wild:
http://www.geckosourcing.co.uk/ebay/Promotions/Cross_Promotion.html
http://www.geckosourcing.co.uk/ebay/Promotions/Cross_Promotion.css
HTML:
<td height="88" width="88"><a class="1000AQwpanel" href="http://goo.gl/mOu8L">1000 Wetroom Panel</a></td>
CSS:
.1000AQwpanel {
display: block;
width: 88px;
height: 88px;
background: url('http://www.geckosourcing.co.uk/ebay/Promotions/Promotion_Sprite.jpg') -704px 880px;
text-indent: -99999px;
}
.1000AQwpanel:hover {
background-position: -704px 792px;
}
The think that has been getting me as this code looks the same as the sections that work. If anyone can show where I am going wrong it would save me pulling my hair out.
Thanks
I suspect this is due to class names that start with a number:
class="760Corner"
Valid class names must begin with a letter, underscore or hyphen.
class / id names may not start with a number. Html wil valid the code, it's the css that gives the problem.
You can use a different style of css to go around this.
css
a[class="760corner"]{
}
PS.
Why do you have the text inside your image? Try putting text in a span like this
HTML
<a class="corner-760">
<span>Your text</span>
</a>
css
a {
display: block;
position: relative;
background: url('../images/.....jpg');
width: 80px;
height: 80px;
}
a > span {
display: block;
text-align: center;
height: 100%;
}
a:hover > span {
display: none;
}
a.corner-760 {
background-position: ........;
}

CSS Sprites - using just one piece of an image as a background for part of an element

I use the CSS Sprite Technique with a background image that looks something like this:
The CSS code for the icons:
div.icon {
background-color: transparent;
background-image: url("/images/icons.png");
background-position: 0 0;
background-repeat: no-repeat;
display: inline-block;
height: auto;
vertical-align: text-top;
width: auto;
}
div.icon:empty {
width:16px;
height:16px;
}
div.icon:not(:empty) {
padding-left:20px;
}
div.icon.attenuation {
background-position: 0 0;
}
My icons can be used like this:
<div class="icon warning"></div>
I want to put some text inside my icons like:
<div class="icon warning">There is a warning on this page</div>
But the problem is that the background image covers the entire text area:
The question is: how can I use only part of an image as a background image for part of my element?
Notes:
setting width to 16px for div.icon doesn't help.
Remember, where ever possible, you shouldn't change your markup just to achieve a design. It is possible using your markup.
div.icon:before {
content: "";
background-color: transparent;
background-image: url("/images/icons.png");
display: inline-block;
height: 16px;
vertical-align: text-top;
width: 16px;
}
div.icon:not(:empty):before {
margin-right: 4px;
}
div.icon.attenuation {
background-position: 0 0;
}
You have two ways:
1)Your markup must be like this:
<div class="icon warning"></div><div class="txt">There is a warning on this page</div>
.icon {width:10px(for ex.)}
2)You must change the image. Icons in the image must be below the another
Sorry, my previous answer was not well though out.
Edit:
If you have a 16px padding, you should set the width to 0, not 16px. And I've got troubles getting the :not(:empty) bit to work on all browsers; better get rid of it. So the CSS becomes:
.icon {
...
width:0; height:16px; padding-left:16px;
}
.icon:empty {
width:16px; padding-left:0;
}
jsFiddle
set width: 16px; height: 16px; overflow: hidden; text-indent: -9999em; and remove padding

CSS: image link, change on hover

I have an image that is a link. I want to show a different image when the user hovers over the link.
Currently I'm using this code:
<a href="http://twitter.com/me" title="Twitter link">
<div id="twitterbird" class="sidebar-poster"></div></a>
div.sidebar-poster {
margin-bottom: 10px;
background-position: center top;
background-repeat: no-repeat;
width: 160px;
}
#twitterbird {
background-image: url('twitterbird.png');
}
#twitterbird:hover {
background-image: url('twitterbird_hover.png');
}
But I'm having loads of problems: the div isn't picking up the CSS rules (the element just isn't showing the related CSS rules when I view it in Firebug).
Perhaps this is because (as I know) this is invalid HTML: you can't put an <a> around a <div>. However, if I switch to <span> then it seems I get bigger problems, because you can't set a height and width on a span reliably.
Help! How can I do this better?
use a class for the link itself and forget the div
.twitterbird {
margin-bottom: 10px;
width: 160px;
height:160px;
display:block;
background:transparent url('twitterbird.png') center top no-repeat;
}
.twitterbird:hover {
background-image: url('twitterbird_hover.png');
}
If you have just a few places where you wish to create this effect, you can use the following html code that requires no css. Just insert it.
<a href="TARGET URL GOES HERE"><img src="URL OF FIRST IMAGE GOES HERE"
onmouseover="this.src='URL OF IMAGE ON HOVER GOES HERE'"
onmouseout="this.src='URL OF FIRST IMAGE GOES HERE AGAIN'" /></A>
Be sure to write the quote marks exactly as they are here, or it will not work.
The problem with changing it via JavaScript or CSS is that if you have a slower connection, the image will take a second to change to the hovered version. This will cause an undesirable flash as one disappears while the other downloads.
What I've done before is have two images. Then hide and show each depending on the hover state. This will allow for a clean switch between the two images.
<a href="/settings">
<img class="default" src="settings-default.svg"/>
<img class="hover" src="settings-hover.svg"/>
<span>Settings</span>
</a>
a img.hover {
display: none;
}
a img.default {
display: inherit;
}
a:hover img.hover {
display: inherit;
}
a:hover img.default {
display: none;
}
That could be done with <a> only:
#twitterbird {
display: block; /* 'convert' <a> to <div> */
margin-bottom: 10px;
background-position: center top;
background-repeat: no-repeat;
width: 160px;
height: 160px;
background-image: url('twitterbird.png');
}
#twitterbird:hover {
background-image: url('twitterbird_hover.png');
}
It can be better if you set the a element in this way
display:block;
and then by css sprites set your over background
Edit: check this example out http://jsfiddle.net/steweb/dTwtk/
You could do the following, without needing CSS...
<img src="URL_OF_FIRST_IMAGE_SOURCE" onmouseover="this.src='URL_OF_SECOND_IMAGE_SOURCE'" onmouseout="this.src='URL_OF_FIRST_IMAGE_SOURCE_AGAIN'" />
Example: https://jsfiddle.net/jord8on/k1zsfqyk/
This solution was PERFECT for my needs! I found this solution here.
Disclaimer: Having a solution that is possible without CSS is important to me because I design content on the Jive-x cloud community platform which does not give us access to global CSS.
If you give generally give a span the property display:block, it'll then behave like a div, i.e you can set width and height.
You can also skip the div or span and just set the a the to display: block and apply the backgound style to it.
<!---->
<style>
.myImage {display: block; width: 160px; height: 20px; margin:0 0 10px 0; background: url(image.png) center top no-repeat;}
.myImage:hover{background-image(image_hover.png);}
</style>
<!DOCTYPE html>
<html lang="en">
<head>
<title>Change Image on Hover in CSS</title>
<style type="text/css">
.card {
width: 130px;
height: 195px;
background: url("../images/pic.jpg") no-repeat;
margin: 50px;
}
.card:hover {
background: url("../images/anotherpic.jpg") no-repeat;
}
</style>
</head>
<body>
<div class="card"></div>
</body>
</html>

How to make a CSS rollover image? (sprite)

I'm just trying to use this little trick I saw in one of my web design magazines to make a little image rollover but I'm having just a small bit of trouble. My attempt was a terrible fail lol. I just want to see the top half (42px tall) and then the bottom half on rollover (-42px obviously)
width is also 42px. Could someone write something up to make that happen?
image:
http://img826.imageshack.us/img826/6568/homebi.png
It's all about the initial (non-:hover) and final (:hover) values of background-position.
#test {
height: 42px;
width: 42px;
background-image: url(http://img826.imageshack.us/img826/6568/homebi.png);
background-repeat: no-repeat;
background-color: transparent;
background-position: top; /* <-- key step #1 */
}
#test:hover {
background-position: bottom; /* <-- key step #2 */
}
Demo
As per your comment re: wrapping the <div> with an anchor (<a>), here's what to do:
Swap the <div> out for a <span>. This is because valid children of anchors must be inline elements
But inline-displayed elements won't behave accept dimensions! So, fix this new problem with one additional CSS property: display: inline-block on the span.
Demo 2
Try this:
<style type="text/css">
.menu {
}
.menu a {
float: left;
display: inline;
width: 42px;
height: 42px;
text-decoration: none;
}
.menu a span {
display: block;
overflow: hidden;
height: 0;
}
.menu .home {
background: transparent url(http://img826.imageshack.us/img826/6568/homebi.png) 0 0 no-repeat;
}
.menu .link:hover {
background-position: 0 -42px;
}
</style>
<div class="menu">
<span>Home</span>
</div>
Heres the bare bones for an image rollover.
the css
.rollover{display:block; height:42px; width:42px; background:url(http://img826.imageshack.us/img826/6568/homebi.png) top;}
.rollover:hover{background-position:bottom;}
.rollover span{display:none}
The html
<span>Home</span>
The important part is the background position, which on the buttons normal state is set to 'top', when you rollover the background postion is 'bottom'.
Assuming your image which contains both button states is 84px high this will work fine.

a:hover background replacement on a empty a tag not working

Im using hyperlinks as a image, well a background image so that I can do a image swap eaisly with a:hover.
I have the following:
<a class="cross" href='#'></a>
And the following css
a.cross {
background:transparent url(/images/cross-grey.png) no-repeat scroll 0 0;
float: right;
border: none;
width: 19px;
height: 19px;
display: block;
}
a:hover.cross {
background-position: 0 20px;
}
This works fine in Firefox but not in IE6. Is this a issue with IE6 and a simple css fix or is there a better way of implementing what I am doing. Thanks.
Change:
a:hover.cross { }
To:
a.cross:hover { }
I think you should deal the a:hover.cross with javascript.
Regards.