I'm doing an order on all fields of a table (depending on the user's choice), however one column of that table contains a category (stored as an abbreviation) and those abbreviations are defined in a second table. How can I sort by category name? Example of the table structures below:
Table 1
title | amount | category_abbreviation
Table 2 -> for category
category_name | category_abbreviation
Just join the tables and order on a field from the second table.
SELECT * from table1
INNER JOIN table2
ON table1.category_abbreviation = table2.category_abbreviation
ORDER BY table2.category_name
Create a view and run your query from that:
SELECT
Table1.title, Table1.amount, Table1.category_abbreviation, Table2.category_name
FROM
Table1
INNER JOIN Table2 ON Table1.category_abbreviation = Table2.category_abbreviation
and use that as your datasource. Or just use the SQL as your datasource, however you are doing it.
You don't have to select the Table2.category_name though if you didn't want to
try
SELECT t1.*
FROM Table_1 T1
JOIN Table_2 T2
ON T1.category_abbreviation=T2.category_abbreviation
ORDER BY T2.category_name
Related
I have two tables I'm trying to join to produce a unique set of data for a third table, but having trouble doing this properly.
The left table has an id field, as well as a common join field (a).
The right table has the common join field (a), and another distinct field (b)
I'm trying to extract a result-set of id and b, where neither id nor b are duplicated.
I have an SQL fiddle set up: http://www.sqlfiddle.com/#!9/208de/3/0
The ideal results should be:
id | b
---+---
1 | 1
2 | 2
3 | 3
Each id and b value appears only once (it's only coincidence they match here, that can't be assumed always).
Thanks
What about a CTE along with a DISTINCT, Would that work?
WITH
cte1 (ID, B)
AS
(
SELECT DISTINCT Table1.ID
FROM Table1
WHERE Table1.ID IS NOT NULL
GROUP BY Table1.ID
)
SELECT DISTINCT
Table2.b
FROM Table2 AS sp
INNER JOIN cte1 AS ts
ON sp.b <> ts.ID
ORDER BY ts.ID DESC
I have 2 tables which are linked by column named MID.
I want to fetch name from 1st table but the sequence is mentioned in 2nd table.
My query is as follows:
select name from table1 where MID in(select MID from table2 where CID="100" ORDER BY sequenceNum);
If i only run the query mentioned inside brackets then i get the data ordered by sequence.
But the above query is fetching the data from db as it is and not arranging it in sequence. What can be the problem?
I think this shoukld do the trick...
SELECT name FROM table1
INNER JOIN table2 ON Table2.MID = table1.MID AND CID="100"
ORDER BY
table2.sequenceNum
You want merge two tables and order results by merged table:
SELECT table1.name
FROM table1
LEFT JOIN table2 ON (table2.MID = table1.MID)
WHERE table2.CID = "100"
ORDER BY table2.sequenceNum;
or
SELECT table1.name
FROM table1
LEFT JOIN table2 ON (table2.MID = table1.MID AND table2.CID = "100")
ORDER BY table2.sequenceNum;
If you want get field from concrete table, use table prefix like table1.name
I have three tables that I need to query in order to get my results.
Table 1 has an AppId and a ProjectID
Table2 has an AppID and an AppName.
Table 3 has a ProjectID and a ProjectName
I want to get out of this a list, By AppName, the ProjectNames they are tied to.
So far, a basic query to get what I want works, but I only get the ID's. I need to somehow join these to get the names associated. I need to somehow join this to table2 with the project name information, and table 2 with the appname information.
Select * from Table1 ( this table has only ID's, not names)
Order by AppId
You can join the tables like this:
Select t2.AppName, t3.ProjectName
from table1 t1
inner join table2 t2 on t2.AppID = t1.AppID
inner join table3 t3 on t3.ProjectID = t1.ProjectID
I have 2 tables. I want to find out whether the values present in the first table is there in another table with a different field name.
Here is how it looks,
Table1
BillNo
43529179
43256787
35425676
25467778
24354758
45754748
Table2
BNo
113104808
25426577
268579679
2542135464
252525232
235263663
I have 137 records in table1 that needs to be checked against table2.
Instead of doing it one by one using the following command,
Select * from Table2 where BNo = '43529179';
This gives the result for just the mentioned value. Is there a way to check for all the values in a single query?
Thanks!
You can use a sub-select to compare against:
Select * from Table2 where BNo IN (SELECT BillNo FROM Table1);
That will "evalaute" to something like Select * from Table2 where BNo IN (113104808, 25426577, 268579679, 2542135464, 252525232, ...);
Join the tables, and check how many matching records there are:
select
count(*) as Matches
from
Table1 as t1
inner join Table2 as t2 on t2.BNo = t1.BillNo
You can also use a left join to pick out the records in table 1 that has no matching record in table 2:
select
t1.BillNo
from
Table1 as t1
left join Table2 as t2 on t2.BNo = t1.BillNo
where
t2.BNo is null
i have a db like this:
Table1:
id
id_item
table (enum: 'table2','table3','table4')
table2:
id
value
table3:
id
value
table4:
[...]
And i want to run a query like this:
SELECT t1.id, t2.value FROM table1 AS t1
LEFT JOIN table1.table as t2 ON t1.id_item=t2.id
Is it possible? or i have to select first table1 and after the value?
( sorry for my bad eng :) )
If I understood the last column in Table 1 correctly and it is just a string, you can't.
You cannot write a column into the FORM-clausal and wait for mysql to evaluate it for every row and find the correct table to join it with.
To do this you will need to create a view where you will have the data from all the tables, together with the table name as an additional column. Afterwards you can perform a join like that between Table1 and the new view