I am trying to get all the occurrences of a sub-string in a database field and the location of the next index after each. What I have done so far is to get the first occurrence and the location of the next string after it as following:
SELECT dataset.id,
SUBSTRING(dataset.text, LOCATE('XXXX', dataset.text) + LENGTH('XXXX'))
FROM datatable as dataset
any help please to get all occurrences ??
Perhaps this could help:
delimiter //
CREATE FUNCTION getpos(haystack VARCHAR(255), search VARCHAR(10))
RETURNS VARCHAR(255)
BEGIN
DECLARE ret VARCHAR(255);
DECLARE pos INT;
SET ret = "";
SET pos = LOCATE (search, haystack);
WHILE (pos > 0) DO
SET ret = CONCAT_WS (',', ret, pos);
SET pos = LOCATE (search, haystack, pos+1);
END WHILE;
RETURN ret;
END//
Then do the select:
SELECT dataset.id, getpos (dataset.text, 'XXXX') FROM datatable as dataset
Related
In one of my tables fields I contain age ranges. They would be in a format such as
27-51,18-28,10-17
37-55,60-70
1-5,11-16,30-32,60-90
etc
I'm trying to build a SELECT statement where I can search if my given age falls into any of the ranges... something such as
SELECT * from table where age IN (1-5,11-16,30-32,60-90)
However it would search within the given ranges
I can do it if I only have one range using something like...
WHERE age
BETWEEN
SUBSTRING_INDEX(personsAge,"-",1) + 0 AND
SUBSTRING_INDEX(personsAge,"-",-1) + 0
but how can I accomplish this if I have multiple ranges?
This is an answer extending my comment above.
I'm assuming that you can create a function:
Attention: This is for Sql Anywhere. Please adjust the syntax for MySql (especially the locate-function where the parameters are switched). The code is not production ready and I left out some validity checks. I'm assuming that the values in the column are all well formatted.
Attention 2: This is one of those cases where someone dumps a terrible database design on you and demands that you solve the problem. Please avoid creating the need for solutions like this.
Function:
CREATE FUNCTION "DBA"."is_in_range"(age_range varchar(255), age int)
returns int
begin
declare pos int;
declare pos2 int;
declare strPart varchar(50);
declare strFrom varchar(10);
declare strTo varchar(10);
declare iFrom int;
declare iTo int;
while 1 = 1 loop
set pos = locate(age_range, ',');
if pos = 0 then
-- no comma found in the rest of the column value -> just take the whole string
set strPart = age_range;
else
-- take part of the sting until next comma
set strPart = substr(age_range, 1, pos - 1);
end if;
-- we are parsing the min-max part and do some casting to compare with an int
set pos2 = locate(strPart, '-');
set strFrom = substr(strPart, 1, pos2 - 1);
set strTo = substr(strPart, pos2 + 1);
set iFrom = cast(strFrom as int);
set iTo = cast(strTo as int);
if age between iFrom and iTo then
return 1;
end if;
-- if at end of age_range then quit
if pos = 0 then
return 0;
end if;
-- get the next part of the string after the comma
set age_range = substr(age_range, pos + 1);
set pos = locate(age_range, ',', pos);
end loop;
return 0;
end;
Test data:
create local temporary table #tmpRanges (ident int, age_range varchar(255));
insert into #tmpRanges (ident, age_range) values (1, '27-51,18-28,10-17');
insert into #tmpRanges (ident, age_range) values (2, '37-55,60-70');
insert into #tmpRanges (ident, age_range) values (3, '1-5,11-16,30-32,60-90');
insert into #tmpRanges (ident, age_range) values (4, '1-50');
Call:
select * from #tmpRanges where is_in_range(age_range, 51) = 1;
select * from #tmpRanges where is_in_range(age_range, 10) = 1;
select * from #tmpRanges where is_in_range(age_range, 9) = 1;
etc...
I am trying to run a query that can find all the records from a field contains the letters.
For example suppose a state field contains a record value "New York" and another record conatains NY. Now i am searching for NY or New york will return these 2 records. What will be the query.
Currently i am using
like %New York%" or "%NY%"
Any suggestion
No your query is not correct as it searches for anything containing New York or NY.
So if there is PENNY that will be matched although it shouldn't be....
Your query must be something like this.
SELECT * from TABLE where field in ('NEW YORK','NY')
Now to fetch acronym,you can use
delimiter $$
drop function if exists `initials`$$
CREATE FUNCTION `initials`(str text, expr text) RETURNS text CHARSET utf8
begin
declare result text default '';
declare buffer text default '';
declare i int default 1;
if(str is null) then
return null;
end if;
set buffer = trim(str);
while i <= length(buffer) do
if substr(buffer, i, 1) regexp expr then
set result = concat( result, substr( buffer, i, 1 ));
set i = i + 1;
while i <= length( buffer ) and substr(buffer, i, 1) regexp expr do
set i = i + 1;
end while;
while i <= length( buffer ) and substr(buffer, i, 1) not regexp expr do
set i = i + 1;
end while;
else
set i = i + 1;
end if;
end while;
return result;
end$$
drop function if exists `acronym`$$
CREATE FUNCTION `acronym`(str text) RETURNS text CHARSET utf8
begin
declare result text default '';
set result = initials( str, '[[:alnum:]]' );
return result;
end$$
delimiter ;
So,your final query will be something like this.
SELECT * from TABLE where field in ('NEW YORK',select acronym('Come Again? That Cant Help!'))
Source:- Mysql extract first letter of each word in a specific column
Presumably, the logic that you want is:
col like '%New York%' or col like '%NY%'
or, if you want to use regular expressions:
col regexp 'New York|NY'
Select * from table where col like '%N' or col like '%n'
I have developed a function for split string in tsql but mysql don't have some built in functions. I needed to function in MYSQL as i am new in mysql. Function should accept 2 parameters
1. String to be split
2. separator (',' or whatever)
Kindly reply me.
i had found solution on the internet you can into that.
DELIMITER //
DROP FUNCTION IF EXISTS `splitAndTranslate` //
CREATE FUNCTION splitAndTranslate(str TEXT, delim VARCHAR(124))
RETURNS TEXT
DETERMINISTIC
BEGIN
DECLARE i INT DEFAULT 0; -- total number of delimiters
DECLARE ctr INT DEFAULT 0; -- counter for the loop
DECLARE str_len INT; -- string length,self explanatory
DECLARE out_str text DEFAULT ''; -- return string holder
DECLARE temp_str text DEFAULT ''; -- temporary string holder
DECLARE temp_val VARCHAR(255) DEFAULT ''; -- temporary string holder for query
-- get length
SET str_len=LENGTH(str);
SET i = (LENGTH(str)-LENGTH(REPLACE(str, delim, '')))/LENGTH(delim) + 1;
-- get total number delimeters and add 1
-- add 1 since total separated values are 1 more than the number of delimiters
-- start of while loop
WHILE(ctr<i) DO
-- add 1 to the counter, which will also be used to get the value of the string
SET ctr=ctr+1;
-- get value separated by delimiter using ctr as the index
SET temp_str = REPLACE(SUBSTRING(SUBSTRING_INDEX(str, delim, ctr), LENGTH(SUBSTRING_INDEX(str, delim,ctr - 1)) + 1), delim, '');
-- query real value and insert into temporary value holder, temp_str contains the exploded ID
SELECT <real_value_column> INTO temp_val FROM <my_table> WHERE <table_id>=temp_str;
-- concat real value into output string separated by delimiter
SET out_str=CONCAT(out_str, temp_val, ',');
END WHILE;
-- end of while loop
-- trim delimiter from end of string
SET out_str=TRIM(TRAILING delim FROM out_str);
RETURN(out_str); -- return
END//
reference http://www.slickdev.com/2008/09/15/mysql-query-real-values-from-delimiter-separated-string-ids/
In mysql they they dont support some functionality like sqlserver. so spliting will be difficult in mysql
SELECT e.`studentId`, SPLIT(",", c.`courseNames`)[e.`courseId`]
FROM ..
SELECT TRIM(SUBSTRING_INDEX(yourcolumn,',',1)), TRIM(SUBSTRING_INDEX(yourcolumn,',',-1)) FROM yourtable
CREATE FUNCTION [dbo].[SplitString]
(
#RowData nvarchar(2000),
#SplitOn nvarchar(5)
)
RETURNS #RtnValue table
(
--Id int identity(1,1),
Data nvarchar(100)
)
AS
BEGIN
Declare #Cnt int
Set #Cnt = 1
While (Charindex(#SplitOn,#RowData)>0)
Begin
Insert Into #RtnValue (data)
Select
Data = ltrim(rtrim(Substring(#RowData,1,Charindex(#SplitOn,#RowData)-1)))
Set #RowData = Substring(#RowData,Charindex(#SplitOn,#RowData)+1,len(#RowData))
Set #Cnt = #Cnt + 1
End
Insert Into #RtnValue (data)
Select Data = ltrim(rtrim(#RowData))
Return
END
for example,
I have a dataset as below:
asdf1234asdf
1235asdfasdf
asdfasdfef489
How could I select such that I can get a result as below?
1234
1235
489
If your MySQL version supports it, create a function and use such as regex, to extract the first digits:
DELIMITER $$
CREATE FUNCTION first_digits(str TEXT)
RETURNS TEXT
BEGIN
DECLARE ret TEXT DEFAULT '';
DECLARE chr TEXT DEFAULT '';
DECLARE i INT DEFAULT 1;
WHILE i < (LENGTH(str) + 1) DO
SET chr = SUBSTRING(str, i, 1);
IF chr REGEXP '[0-9]'
THEN SET ret = CONCAT(ret, chr);
ELSEIF ret != ''
THEN RETURN ret;
END IF;
SET i = i + 1;
END WHILE;
RETURN ret;
END;
$$
DELIMITER ;
Then just SELECT desired column with newly created function first_digits();
SELECT first_digits('asdf1234asdf') num;
num
1234
To extract all digits (not only first), drop the ELSEIF part and rename the function such as digits.
To drop the function:
DROP FUNCTION IF EXISTS first_digits;
Hope this helps!
MySQL, unfortunately, doesn't have a good way of replacing regexes, but if you have only one numerical sequence, you could use trim:
SELECT TRIM(BOTH 'abcdefghijklmnopqrstuvwxyz' FROM word)
FROM (SELECT 'asdf1234asdf' AS word
UNION ALL
SELECT '1235asdfasdf'
UNION ALL
SELECT 'asdfasdfef489') t
I have a table with two columns: price (int) and price_display (varchar).
price is the actual numerical price, e.g. "9990"
price_display is the visual representation, e.g. "$9.99" or "9.99Fr"
I've been able to confirm the two columns match via regexp:
price_display not regexp
format(price/1000, 2)
But in the case of a mismatch, I want to extract the value from the price_display column and set it into the price column, all within the context of an update statement. I've not been able to figure out how.
Thanks.
This function does the job of only returning the digits 0-9 from the string, which does the job nicely to solve your issue, regardless of what prefixes or postfixes you have.
http://www.artfulsoftware.com/infotree/queries.php?&bw=1280#815
Copied here for reference:
SET GLOBAL log_bin_trust_function_creators=1;
DROP FUNCTION IF EXISTS digits;
DELIMITER |
CREATE FUNCTION digits( str CHAR(32) ) RETURNS CHAR(32)
BEGIN
DECLARE i, len SMALLINT DEFAULT 1;
DECLARE ret CHAR(32) DEFAULT '';
DECLARE c CHAR(1);
IF str IS NULL
THEN
RETURN "";
END IF;
SET len = CHAR_LENGTH( str );
REPEAT
BEGIN
SET c = MID( str, i, 1 );
IF c BETWEEN '0' AND '9' THEN
SET ret=CONCAT(ret,c);
END IF;
SET i = i + 1;
END;
UNTIL i > len END REPEAT;
RETURN ret;
END |
DELIMITER ;
SELECT digits('$10.00Fr');
#returns 1000
One approach would be to use REPLACE() function:
UPDATE my_table
SET price = replace(replace(replace(price_display,'Fr',''),'$',''),'.','')
WHERE price_display not regexp format(price/1000, 2);
This works for the examples data you gave:
'$9.99'
'9.99Fr'
Both result in 999 in my test. With an update like this, it's important to be sure to back up the database first, and be cognizant of the formats of the items. You can see all the "baddies" by doing this query:
SELECT DISTINCT price_display
FROM my_table
WHERE price_display not regexp format(price/1000, 2)
ORDER BY price_display;
For me CASTING the field did the trick:
CAST( price AS UNSIGNED ) // For positive integer
CAST( price AS SIGNED ) // For negative and positive integer
IF(CAST(price AS UNSIGNED)=0,REVERSE(CAST(REVERSE(price) AS UNSIGNED)),CAST(price AS UNSIGNED)) // Fix when price starts with something else then a digit
For more details see:
https://dev.mysql.com/doc/refman/5.0/en/cast-functions.html
This is a "coding horror", relational database schemas should NOT be written like this!
Your having to write complex and unnecessary code to validate the data.
Try something like this:
SELECT CONCAT('$',(price/1000)) AS Price FROM ...
In addition, you can use a float, double or real instead of a integer.
If you need to store currency data, you might consider adding a currency field or use the systems locale functions to display it in the correct format.
I create a procedure that detect the first number in a string and return this, if not return 0.
DROP FUNCTION IF EXISTS extractNumber;
DELIMITER //
CREATE FUNCTION extractNumber (string1 VARCHAR(255)) RETURNS INT(11)
BEGIN
DECLARE position, result, longitude INT(11) DEFAULT 0;
DECLARE string2 VARCHAR(255);
SET longitude = LENGTH(string1);
SET result = CONVERT(string1, SIGNED);
IF result = 0 THEN
IF string1 REGEXP('[0-9]') THEN
SET position = 2;
checkString:WHILE position <= longitude DO
SET string2 = SUBSTR(string1 FROM position);
IF CONVERT(string2, SIGNED) != 0 THEN
SET result = CONVERT(string2, SIGNED);
LEAVE checkString;
END IF;
SET position = position + 1;
END WHILE;
END IF;
END IF;
RETURN result;
END //
DELIMITER ;
Return last number from the string:
CREATE FUNCTION getLastNumber(str VARCHAR(255)) RETURNS INT(11)
DELIMETER //
BEGIN
DECLARE last_number, str_length, position INT(11) DEFAULT 0;
DECLARE temp_char VARCHAR(1);
DECLARE temp_char_before VARCHAR(1);
IF str IS NULL THEN
RETURN -1;
END IF;
SET str_length = LENGTH(str);
WHILE position <= str_length DO
SET temp_char = MID(str, position, 1);
IF position > 0 THEN
SET temp_char_before = MID(str, position - 1, 1);
END IF;
IF temp_char BETWEEN '0' AND '9' THEN
SET last_number = last_number * 10 + temp_char;
END IF;
IF (temp_char_before NOT BETWEEN '0' AND '9') AND
(temp_char BETWEEN '0' AND '9') THEN
SET last_number = temp_char;
END IF;
SET position = position + 1;
END WHILE;
RETURN last_number;
END//
DELIMETER;
Then call this functions:
select getLastNumber("ssss111www222w");
print 222
select getLastNumber("ssss111www222www3332");
print 3332