I have this table for users that stores their usernames and other data, thats done like this (stripped down):
CREATE TABLE `prod_users` (
`p_user_id` INT(11) NOT NULL AUTO_INCREMENT,
`p_user_name` VARCHAR(200) NOT NULL DEFAULT ''
`p_comp_name` VARCHAR(300) NOT NULL DEFAULT '',
PRIMARY KEY (`p_user_id`)
)
COLLATE='utf8_general_ci'
ENGINE=MyISAM
Each time a user signs up, he'll provide a company name as well.
There's another table called prod_profiles, which stores profile details like phone nos. fax nos. etc.
CREATE TABLE `prod_profiles` (
`pf_gen_id` INT(11) NOT NULL AUTO_INCREMENT,
`pf_user_id` INT(11) NOT NULL DEFAULT '0',
`pf_user_name` VARCHAR(200) NOT NULL DEFAULT ''
`pf_comp_name` VARCHAR(300) NOT NULL DEFAULT '',
PRIMARY KEY (`pf_gen_id`)
)
COLLATE='utf8_general_ci'
ENGINE=MyISAM
When a new user signs up and his details are added to prod_users, is it possible to automatically add his new user_id, user_name and comp_name details to prod_profile using MySql itself? Since each user will have a new p_user_id and we wont know it, it'll be difficult using php. Can this be achieved inside MySql itself without any problems?
It isn't difficult using PHP, since you have the LAST_INSERT_ID() available for use, be it via mysql_insert_id() or mysqli::$insert_id, PDO::lastInsertId() or whatever your API provides. As long as you call the two INSERT statements in immediate succession on the same script (it is connection dependent), MySQL will supply the correct p_user_id.
However, you can use an AFTER INSERT trigger to force MySQL to create the new row automatically:
CREATE TRIGGER build_profile AFTER INSERT ON prod_users
FOR EACH ROW
BEGIN
INSERT INTO prod_profiles
(pf_user_id, pf_user_name, pf_comp_name)
VALUES (NEW.p_user_id, NEW.p_user_name, NEW.p_comp_name)
END
Review the MySQL CREATE TRIGGER syntax reference for full details and options.
You can use the next mysql function: LAST_INSERT_ID(); which returns the last auto increased id.
Therefore , add a user and then add a prod_profile , while pf_user_id value will be the returned value of last_insert_id().
INSERT INTO `prod_users`(`p_user_name`,`p_comp_name`) VALUES('Dan' , 'Stackover')
INSERT INTO `prod_profiles`(`pf_user_id`,`pf_user_name`,`pf_comp_name`) VALUES(LAST_INSERT_ID(),'Dan','Stackover')
Please notice: I have to say , that storing the username and company_name twice for the same user in two different tables is a reall waste...
Consider re-thinking about your DB structre and logic.
Related
Im revisiting my database and noticed I had some primary keys that were of type INT.
This wasn't unique enough so I thought I would have a guid.
I come from a microsoft sql background and in the ssms you can
choose type to "uniqeidentifier" and auto increment it.
In mysql however Ive found that you have to make triggers that execute on insert for the tables you want
to generate a guide id for. Example:
Table:
CREATE TABLE `tbl_test` (
`GUID` char(40) NOT NULL,
`Name` varchar(50) NOT NULL,
PRIMARY KEY (`GUID`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
Trigger:
CREATE TRIGGER `t_GUID` BEFORE INSERT ON `tbl_test`
FOR EACH ROW begin
SET new.GUID = uuid();
Alternatively you have to insert the guid yourself in the backend.
Im no DB expert but still remember that triggers cause performance problems.
The above is something I found here and is 9 years old so I was hoping something has changed?
As far as stated in the documentation, you can use uid() as a column default starting version 8.0.13, so something like this should work:
create table tbl_test (
guid binary(16) default (uuid_to_bin(uuid())) not null primary key,
name varchar(50) not null
);
This is pretty much copied from the documentation. I don't have a recent enough version of MySQL at hand to test this.
You can make a
INSERT INTO `tbl_test` VALUES (uuid(),'testname');
This would generate a new uuid, when you call it.
Or you can also use the modern uuid v4 by using one of these functions instead of the standard uuid(), which is more random than the uuid in mysql
How to generate a UUIDv4 in MySQL?
You can use since 8.0.13
CREATE TABLE t1 (
uuid_field VARCHAR(40) DEFAULT (uuid())
);
But you wanted more than unique, but here are only allowed internal functions and not user defined as for uuid v4, for that uyou need the trogger
As per the documentation, BINARY(x) adds some hidden padding bytes to the end of each entry, & VARCHAR(40) also wastes space by not being encoded directly in binary. Using VARBINARY(16) would be more efficient.
Also, more entropy (unguessability / security) per byte is available from RANDOM_BYTES(16) than standardized UUIDs, because they use some sections to encode constant metadata.
Perhaps the below will work for your needs.
-- example
CREATE TABLE `tbl_test` (
`GUID` VARBINARY(16) DEFAULT (RANDOM_BYTES(16)) NOT NULL PRIMARY KEY,
`Name` VARCHAR(50) NOT NULL
);
Im revisiting my database and noticed I had some primary keys that were of type INT.
This wasn't unique enough so I thought I would have a guid.
I come from a microsoft sql background and in the ssms you can
choose type to "uniqeidentifier" and auto increment it.
In mysql however Ive found that you have to make triggers that execute on insert for the tables you want
to generate a guide id for. Example:
Table:
CREATE TABLE `tbl_test` (
`GUID` char(40) NOT NULL,
`Name` varchar(50) NOT NULL,
PRIMARY KEY (`GUID`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1;
Trigger:
CREATE TRIGGER `t_GUID` BEFORE INSERT ON `tbl_test`
FOR EACH ROW begin
SET new.GUID = uuid();
Alternatively you have to insert the guid yourself in the backend.
Im no DB expert but still remember that triggers cause performance problems.
The above is something I found here and is 9 years old so I was hoping something has changed?
As far as stated in the documentation, you can use uid() as a column default starting version 8.0.13, so something like this should work:
create table tbl_test (
guid binary(16) default (uuid_to_bin(uuid())) not null primary key,
name varchar(50) not null
);
This is pretty much copied from the documentation. I don't have a recent enough version of MySQL at hand to test this.
You can make a
INSERT INTO `tbl_test` VALUES (uuid(),'testname');
This would generate a new uuid, when you call it.
Or you can also use the modern uuid v4 by using one of these functions instead of the standard uuid(), which is more random than the uuid in mysql
How to generate a UUIDv4 in MySQL?
You can use since 8.0.13
CREATE TABLE t1 (
uuid_field VARCHAR(40) DEFAULT (uuid())
);
But you wanted more than unique, but here are only allowed internal functions and not user defined as for uuid v4, for that uyou need the trogger
As per the documentation, BINARY(x) adds some hidden padding bytes to the end of each entry, & VARCHAR(40) also wastes space by not being encoded directly in binary. Using VARBINARY(16) would be more efficient.
Also, more entropy (unguessability / security) per byte is available from RANDOM_BYTES(16) than standardized UUIDs, because they use some sections to encode constant metadata.
Perhaps the below will work for your needs.
-- example
CREATE TABLE `tbl_test` (
`GUID` VARBINARY(16) DEFAULT (RANDOM_BYTES(16)) NOT NULL PRIMARY KEY,
`Name` VARCHAR(50) NOT NULL
);
Here's what I'm trying to do:
CREATE TABLE IF NOT EXISTS hashes (
id int NOT NULL AUTO_INCREMENT,
text varchar(50) NOT NULL,
hash varchar(64) NOT NULL AS (SHA2(CONCAT(text), 256) STORED,
PRIMARY KEY (id)
) DEFAULT CHARSET=utf8;
And then I want to run an insert like this:
INSERT INTO `hashes` (`text`) VALUES ('testing');
From the research I've done, the id should be automatically generated since auto_increment is enabled, so I don't need to define it in the insert query.
From my CREATE TABLE query, the hash should be automatically generated based upon the data entered into the text field. However, when I run the CREATE TABLE command I get an error with this line:
hash varchar(64) NOT NULL AS (SHA2(CONCAT(text), 256) STORED
I'm just wanting the hash to be automatically generated similar to how CURRENT_TIMESTAMP will automatically generate the current time by default.
What am I doing wrong?
It seems you have syntax error. You should write NOT NULL after SHA2 hash function. Please try:
CREATE TABLE IF NOT EXISTS hashes (
id int NOT NULL AUTO_INCREMENT,
text varchar(50) NOT NULL,
hash varchar(64) AS (SHA2(CONCAT(text), 256)) STORED NOT NULL ,
PRIMARY KEY (id)
) DEFAULT CHARSET=utf8;
INSERT INTO `hashes` (`text`) VALUES ('testing');
You don't need to declare your hash column as NOT NULL. It's based on another NOT NULL column, text, so the hash will naturally be NOT NULL as well.
You also have forgotten a closing parenthesis.
hash varchar(64) AS (SHA2(CONCAT(text), 256) STORED,
1 2 3 3 2 ^
You need another closing paren where I indicated ^.
If you already have the table filled by some content, you can Alter it with :
ALTER TABLE `page` ADD COLUMN `hash` char(64) AS (SHA2(`content`, 256)) AFTER `content`
This solution will add hash column right after the content one, make hash for existing and new records too. Unique index can be added to prevent insertion of large content duplicates.
I have been testing a database i am doing right now and i am noticing that it is letting me insert null values into fields that are part of a primary key, despite stating in the script that the value of the field should be NOT NULL. I am using MAC's MySQL Workbench, and I have been googling around and can't figure out why this is happening. (Maybe I am too brain-fried right now... I am even starting to doubt myself)
Part of the script of the database creation (these are the tables I have tested..):
DROP DATABASE IF EXISTS solytierra ;
CREATE DATABASE IF NOT EXISTS solytierra DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci ;
USE solytierra ;
DROP TABLE IF EXISTS solytierra.Cliente ;
CREATE TABLE IF NOT EXISTS solytierra.Cliente (
CIF VARCHAR(25) NOT NULL,
Nombre VARCHAR(100) NULL,
EmailGeneral VARCHAR(45) NULL,
Web VARCHAR(45) NULL,
Notas VARCHAR(150) NULL,
insertado Timestamp,
CONSTRAINT pk_Cliente PRIMARY KEY (CIF)
) ENGINE=InnoDB;
DROP TABLE IF EXISTS solytierra.PersonaContacto ;
CREATE TABLE IF NOT EXISTS solytierra.PersonaContacto (
Cliente_CIF VARCHAR(25) NOT NULL,
Nombre VARCHAR(50) NOT NULL,
Apellidos VARCHAR(100) NOT NULL,
Notas VARCHAR(150) NULL,
CONSTRAINT pk_PersonaContacto PRIMARY KEY (Cliente_CIF , Nombre , Apellidos),
CONSTRAINT fk_PersonaContacto_Cliente FOREIGN KEY (Cliente_CIF)
REFERENCES solytierra.Cliente (CIF)
ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB;
...
It will let me create Clients without CIF, "PersonaContacto" without Cliente_CIF or without "Nombre"....
I have also tested other databases that i already had that used to work and it is happening the same in an all them.
Got it!!
I don't know what sql mode i was running on by default, but with this:
SET sql_mode = TRADITIONAL;
It is now running perfectly! I didn't know that there were different sql modes! Thanks a lot to everyone for your time and efforts! It really helped me to see that the problem was in my workbench, not the code and look for the answer accordingly! I hope this thread will be useful for future beginners like me!
If the value being stored in the column CIF is actually a NULL, then the expression LENGTH(CIF) should also return NULL. (If it's a zero length string, then LENGTH(CIF) will return 0.
To verify:
SELECT c.CIF, LENGTH(c.CIF) FROM solytierra.Cliente c ;
SELECT c.CIF FROM solytierra.Cliente c WHERE c.CIF IS NULL;
If you are running an INSERT statement, I can't explain the behavior you are observing, either MySQL allowing a NULL value to be stored or MySQL providing an implicit default value.)
If it's a zero length string being stored, that's the behavior we would expect if the columns were not explicitly declared to be NOT NULL but were later declared to part of the primary key. It's also the behavior we'd expect if the column were defined NOT NULL DEFAULT ''.
When the NOT NULL is omitted from the column declaration and the column is later declared to be part of the PRIMARY KEY, MySQL will use an an implicit default value based on the datatype of the column (zero length string for VARCHAR, zero for an integer, etc.)
But I'm not able to reproduce the problem you report, with the table definitions you've posted.
I recommend you check the table definition by getting the output from:
SHOW CREATE TABLE solytierra.Cliente;
Friends,
two tables one table is
CREATE TABLE `vbw_push_notifications` (
`push_notification_id` int(11) NOT NULL AUTO_INCREMENT COMMENT 'Primary key ,Auto increment field',
`push_notification_customer_ids` text NOT NULL COMMENT 'comma separated customer id list which was used for messaging/related customers/broadcasting',
`push_notification_message` varchar(500) NOT NULL COMMENT 'The notification message.(A new message from Veebow/A new message from <Merchant Name>/A new public deal <Deal Name> from <Merchant Name>/A new game deal <Deal Name> from <Merchant Name>',
`push_notification_time` datetime NOT NULL,
`push_notification_is_processed` tinyint(4) NOT NULL,
PRIMARY KEY (`push_notification_id`)
) ENGINE=InnoDB AUTO_INCREMENT=2 DEFAULT CHARSET=latin1 COMMENT='The comma separated customer ids of the customers who needs ';
-- ----------------------------
-- Records of vbw_push_notifications
-- ----------------------------
INSERT INTO `vbw_push_notifications` VALUES ('1', '165836,65802,65829,65837,65838', 'test test test', '2013-11-07 12:36:42', '0');
And I have another table with the following details.
CREATE TABLE `vbw_mobile_sessions` (
`mobile_session_id` int(10) NOT NULL AUTO_INCREMENT COMMENT 'The unique identifier for a mobile session',
`mobile_session_start_time` datetime DEFAULT NULL COMMENT 'The starting time # server of a mobile session',
`mobile_session_end_time` datetime DEFAULT NULL COMMENT 'The ending time # server of a mobile session',
`mobile_session_token` varchar(255) DEFAULT NULL COMMENT 'The mobile session token generated for this session',
`mobile_session_device_id` varchar(50) DEFAULT NULL COMMENT 'The device id of the device used for making the session',
`mobile_session_customer_id` int(10) DEFAULT NULL COMMENT 'The customer ID of the customer who made this session',
`mobile_session_device_type` tinyint(4) DEFAULT NULL COMMENT 'The type of device that customer uses for this session. 0 - iOS, 1 - Android',
PRIMARY KEY (`mobile_session_id`),
KEY `fk_mobile_session_customer_id` (`mobile_session_customer_id`)
) ENGINE=InnoDB AUTO_INCREMENT=677 DEFAULT CHARSET=latin1 COMMENT='This table holds the merchant account activation links creat';
I want to use a subquery like this.
SELECT DISTINCT(mobile_session_customer_id)
FROM vbw_mobile_sessions
WHERE mobile_session_end_time IS null
AND mobile_session_customer_id IN (SELECT push_notification_customer_ids FROM vbw_push_notifications WHERE push_notification_id=6) .
This query not returns zero rows. But i am getting result when i have used like this.
SELECT DISTINCT(mobile_session_customer_id)
FROM vbw_mobile_sessions
WHERE mobile_session_end_time IS null
AND mobile_session_customer_id IN ( SELECT DISTINCT(mobile_session_customer_id)
FROM vbw_mobile_sessions
WHERE mobile_session_end_time IS null
AND mobile_session_customer_id IN (65836,65802,65829,65837,65838)
I think its in a different format the subquery is returning the result . Can you please point out the mistake i have made. Many Thanks.
Your answer is obvious. String 'a,b,c,d' has nothing to do with set of values (a,b,c,d). This is not how it will work.
The correct solution is not to use delimiter-separated values in one field. You should normalize your DB structure and create linking table. Then place your values into it and build your query with using subquery, selecting from it.
Another, possible solution is to select your data (string data) from your field in application, split it by delimiter and substitute to another query then.
The subquery is returning you a varchar with a value '1,2,3' and you need a set of integers which is 1,2,3...
The engine is treating your result of the subquery as a varchar() not a set of integers.
You can go through this question, asking exactly what you need