I am trying to show three different figures of the same column In a mysql query and joining all three tables, I would like to keep one month static: April, so it would be a case like this I want to show The current month, the previous month and the static month of the year I'm working with, in this case let us stick with 2012
table: persons
ID name
1 Carl
table: vehicle
ID v_name person_veh
100 Dodge Viper 1
Table:payment
pay_id , pay_date, amount person_id
1 2012-02-12 1000 1
2 2012-03-11 780 1
3 2012-04-15 890 1
4 2012-05-12 1200 1
5 2012-06-12 1890 1
6 2012-07-12 1350 1
7 2012-08-12 1450 1
So what I want to do is show the column amount for the month of April as I said I want to keep that row static: 890, the current month lets say the current month is August:1450 and the previous month amount which would be July:1350: so the final result would be something like this:
name v_name april_amount current_month_amount previous_month_amount
Carl Dodge viper 890 1450 1350
You can use the following - which uses an aggregate function with a CASE statement:
select p.name,
v.v_name,
sum(case when Month(py.pay_date) = 4 then amount end) april_amount,
sum(case when Month(py.pay_date) = Month(curdate())
then amount end) current_month_amount,
sum(case when Month(py.pay_date) = Month(curdate())-1
then amount end) previous_month_amount
from persons p
left join vehicle v
on p.id = v.person_veh
left join payment py
on p.id = py.person_id
group by p.name,
v.v_name
see SQL Fiddle with Demo
Try
SELECT a.name, b.pay_date, b.amount, b.person_id, c.v_name
FROM persons a
LEFT JOIN payment b on a.id = b.person_id
LEFT JOIN vehicle c on a.id = c.person_veh
This query assumes id, person_veh and person_id are the like columns which links this user across these three tables
Related
Sorry if the title is not well explained tried my best.
I currently have this transactions table which hold the records, every row has an agent and a currency assigned to it.
id
amount
agent
currency_id
1
400.00
agent1
1
2
170.00
agent5
3
3
110.00
agent4
2
4
430.00
agent5
3
5
155.00
agent1
1
6
370.00
agent2
2
7
10.00
agent2
2
8
150.00
agent1
1
9
130.00
agent3
3
10
445.00
agent4
2
And this other table called currency which holds the unique currency and name.
id
currency
1
USD
2
VES
3
EUR
The query that I want to make is a SUM and group by agent for every currency there is. I am able to do it with a single query like this but only for one currency in the WHERE clause:
SELECT a.agent,
SUM(a.amount)
FROM transactions AS a
INNER JOIN currency AS b ON b.id = a.currency_id
WHERE b.currency = 'VES'
GROUP BY a.agent
I will be getting this result which is only for the VES currency
agent
total
agent2
380.00
agent4
555.00
I am looking for one query that allow me to get the result of all 3 current existing currencies (USD, VES, EUR) this should give a result of 3 different tables
I suspect that you want a report showing all agents, currencies, and their sums. You may try using this cross join approach:
SELECT a.agent, c.currency, COALESCE(SUM(t.amount), 0) AS total
FROM (SELECT DISTINCT agent FROM transactions) a
CROSS JOIN currency c
LEFT JOIN transactions t
ON t.agent = a.agent AND
t.currency_id = c.id
GROUP BY 1, 2
ORDER BY 1, 2;
The first two tables in the join generate all combinations of agents and currencies. We join this to your transactions table and aggregate to get the totals.
The user table looks like this:
user_id
name
surname
1
a
aa
2
b
bb
3
c
cc
The book's table looks like this:
user_id
book_name
1
book1
1
book2
1
book3
2
book1
The expenses table looks like this:
user_id
amount_spent
date
1
10
2020-02-03
1
30
2020-02-02
1
10
2020-02-01
1
15
2020-01-31
1
13
2020-01-15
2
15
2020-02-01
3
20
2020-02-01
The result which I want:
CountUsers
amount_spent
2
65
Explanation: I want to count how many users have book1 and how much total they spend on a date between 2020-02-01 - 2020-02-03.
Now how the query should look like?
I am using MySQL version 8.
I have tried:
SELECT
count(*), sum(amount_spend) as total_amount_spend
FROM
(select sum(amount_spend) as amount_spend
FROM expanses
LEFT JOIN books ON books.user_id = expanses.user_id WHERE books.book_name ='book1 GROUP BY expanses.user_id) src'
And the result is wrong because I am getting a higher amount_spend than in my table result above. I think while joining the table there are some duplicates but I do not know how to fix them.
I want to count how many users have book1 and how much total they spend on a date between 2020-02-01 - 2020-02-03.
I am thinking:
select count(*), sum(e.amount_spent)
from user_books ub join
expenses e
on ub.user_id = e.user_id
where book_name = 'book1';
Note: This assumes that user_books doesn't have duplicate rows.
FIDDLE
You miss the date part in your code.
SELECT
count(*), sum(amount_spent) as total_amount_spend
FROM
(select sum(amount_spent) as amount_spent
FROM expanses
LEFT JOIN books ON books.user_id = expanses.user_id
WHERE books.book_name ='book1'
and expanses.date between '2020-02-01' and '2020-02-03'
GROUP BY expanses.user_id) src;
will do a job.
Please note that you don't need to have left join here (unless you're sure that it may happen that no expenses at all for given user will be), and you don't need to have grouping in subquery. So your query could look like:
select count(distinct expanses.user_id), sum(amount_spent) as amount_spent
from expanses
inner join books on books.user_id = expanses.user_id
where books.book_name ='book1'
and expanses.date between '2020-02-01' and '2020-02-03';
I have to build and SQL query which must do these things:
select all products from table "products" - satisfied
SUM all sales and forecast to the next 3 months - satisfied
check if the product has no one sale, then write "0" -> here is the problem, because I don't know how to do that..
My SQL query is here..
select product.name,
(select sum(amount)
from forecast
where forecast.product_id = product.id),
sum(sale.amount)
from product join
sale
on sale.product_id = product.id
where sale.outlook > -4
group by product.id
Here is the products table:
id name
1 milk
2 roll
3 ham
Table sale (same structure like forecast):
product_id outlook amount
1 -1 9
1 -2 13
1 -3 14
2 -1 88
2 -3 61
3 -1 33
3 -4 16
You can use left join to bring in the rows and coalesce() to get the 0 instead of NULL:
select p.name,
(select sum(f.amount)
from forecast f
where v.product_id = p.id),
coalesce(sum(s.amount), 0)
from product p left join
sale s
on sale.product_id = product.id and
sale.outlook > -4
group by p.id
Understand the requirement to be, show the sales per product and if no sale for a product show "0". Tables are named Products and Sale.
For this, "with" statements are useful and help understanding too:
With SalesSummary as
(
select product_id, sum(amount) as ProductSales
from Sale
Group by product_id
)
select a.ProductID, ISNULL(b.ProductSales,0) as Sales
from products a left join SalesSummary b on a.product_id=b.product_id
I have two tables namely "appointment" and "skills_data".
Structure of appointment table is:
id_ap || ap_meet_date || id_skill || ap_status.
And the value of ap_status are complete, confirm, cancel and missed.
And the skills_data table contains two columns namely:
id_skill || skill
I want to get the count of total number of appointments for each of these conditions
ap_status = ('complete' and 'confirm'),
ap_status = 'cancel' and
ap_status = 'missed'
GROUP BY id_skill and year and
order by year DESC
I tried this query which only gives me count of one condition but I want to get other two based on group by and order by clauses as mentioned.
If there is no record(for example: zero appointments missed in 2018 for a skill) matching for certain conditions, then it should display the output value 0 for zero count.
Could someone please suggest me with a query whether I should implement multiple select query or CASE clause to achieve my expected results. I have lot of records in appointment table and want a efficient way to query my records. Thank you!
SELECT a.id_skill, YEAR(a.ap_meet_date) As year, s.skill,COUNT(*) as count_comp_conf
FROM appointment a,skills_data s WHERE a.id_skill=s.id_skill and a.ap_status IN ('complete', 'confirm')
GROUP BY `id_skill`, `year`
ORDER BY `YEAR` DESC
Output from my query:
id_skill | year | skill | count_comp_conf
-----------------------------------------
1 2018 A 20
2 2018 B 15
1 2019 A 10
2 2019 B 12
3 2019 C 10
My expected output should be like this:
id_skill | year | skill | count_comp_conf | count_cancel | count_missed
------------------------------------------------------------------------
1 2018 A 20 5 1
2 2018 B 15 8 0
1 2019 A 10 4 1
2 2019 B 12 0 5
3 2019 C 10 2 2
You can use conditional aggregation using case when expression
SELECT a.id_skill, YEAR(a.ap_meet_date) As year, s.skill,
COUNT(case when a.ap_status IN ('complete', 'confirm') then 1 end) as count_comp_conf,
COUNT(case when a.ap_status = 'cancel' then 1 end) as count_cancel,
COUNT(case when a.ap_status = 'missed' then 1 end) as count_missed
FROM appointment a inner join skills_data s on a.id_skill=s.id_skill
GROUP BY `id_skill`, `year`
ORDER BY `YEAR` DESC
SELECT a.id_skill,
YEAR(a.ap_meet_date) As year,
s.skill,
SUM(IF(a.ap_status IN ('complete', 'confirm'),1,0)) AS count_comp_conf,
SUM(IF(a.ap_status='cancel',1,0)) AS count_cancel,
SUM(IF(a.ap_status='missed',1,0)) AS count_missed
FROM appointment a,skills_data s WHERE a.id_skill=s.id_skill
GROUP BY `id_skill`, `year`
ORDER BY `YEAR` DESC;
Please try to use if condition along with sum.
With below query you will get output.
select id_skill ,
year ,
skill ,
count_comp_conf ,
count_cancel ,
count_missed ( select id_skill, year, skill, if ap_status ='Completed' then count_comp_conf+1, elseif ap_status ='cancelled' then count_cancel +1 else count_missed+1
from appointment a join skills_data s on (a.id_skill = s.id_skill) group by id_skill, year) group by id_skill,year
order by year desc;
I have 3 tables: product, customer and transaction.
Product:
id_product price
1 1000
2 2000
Customer:
id_customer name
1 Tom
2 Jack
Transaction:
id_transaction id_product id_customer qty date
1 1 1 10 2013-02-21
2 2 1 50 2013-02-21
3 1 2 15 2013-02-21
I want to achieve this result:
id_customer name total_transaction purchase_qty subtotal
1 Tom 2 60 110000
2 Jack 1 15 15000
How I can get that result using a query in MySQL?
SELECT t.id_customer, c.name,
COUNT(t.id_customer) AS total_transaction,
SUM(t.qty) as purchase_qty
FROM transaction t
INNER JOIN customer c
ON t.id_customer = c.id_customer
GROUP BY t.id_customer,c.name
SELECT cs.id_customer, cs.name, COUNT(tr.transaction) AS total_transaction, SUM(tr.qty) as purchase_qty, SUM(tr.qty*pr.prize)
FROM customer AS cs
LEFT JOIN transaction AS tr ON tr.id_customer = cs.id_customer
LEFT JOIN product AS pr ON pr.id_product = tr.id_product
GROUP BY cs.id_customer
I suppose you are a total beginner, so I did this for you. Next time, if you have ANY own ideas, give to us, so we don't have to write the whole query for you. Show some effort.
SELECT c.id_customer, c.name, count(t.id_transaction) AS total_transaction
FORM Customer c INNER JOIN Transaction T
ON C.id_customer = T.id_customer
GROUP BY c.id_customer
You need a group by statement since you want to aggregate results for a given customer :
SELECT id_customer, name, count(id_transaction) AS total_transaction
FORM Customer, Transaction
WHERE Transaction.id_customer = Customer.id_customer
GROUP BY id_customer
This does not solve your whole problem, but you've got the idea.