Following on from this question I posed earlier, say I want to add ID to the query:
SELECT client, ID, job_type, SUM(actual_value_fee) FROM jo2details GROUP BY client, job_type WITH ROLLUP
but I don't want MySQL to try to total the ID column as it's an identifier for the records on the table rather than something "summable". How can I exclude ID from the WITH ROLLUP please?
One way is to UNION two queries. The first query will have the id and the second query will generate the subtotals. Using your example, it would look like this:
SELECT a.id, a.client, a.job_type, sum(a.actual_value_fee)
FROM jo2details a
GROUP BY a.client, a.job_type, a.id
UNION
SELECT NULL, b.client, NULL, sum(b.actual_value_fee)
FROM jo2details b
GROUP BY b.client
WITH ROLLUP
From here, you'll have to play around with it to get the subtotals to sort correctly.
Related
I have a table with duplicate skus.
skua
skua
skub
skub
skub
skuc
skuc
skud
SELECT sku, COUNT(1) AS `Count` FROM products GROUP BY sku;
shows me all the skus that have duplicates and the number of duplicates
skua 2
skub 3
skuc 2
skud 1
I am trying to find how many there are with 2 duplicates, 3 duplicates etc.
i.e.
duplicated count
1 1 (skud)
2 2 (skua, and skuc)
3 1 (skub)
and I don't know how to write the sql. I imagine it needs a subselect...
thanks
Just use your current query as an inline view, and use the rows from that just like it was from a table.
e.g.
SELECT t.Count AS `duplicated`
, COUNT(1) AS `count`
FROM ( SELECT sku, COUNT(1) AS `Count` FROM products GROUP BY sku ) t
GROUP BY t.Count
MySQL refers to an inline view as a "derived table", and that name makes sense, when we understand how MySQL actually processes that. MySQL runs that inner query, and creates a temporary MyISAM table; once that is done, MySQL runs the outer query, using the temporary MyISAM table. (You'll see that if you run an EXPLAIN on the query.)
Above, I left your query just as you formatted it; I'd tend to reformat your query, so that entire query looks like this:
SELECT t.Count AS `duplicated'
, COUNT(1) AS `count`
FROM ( SELECT p.sku
, COUNT(1) AS `Count`
FROM products p
GROUP BY p.sku
) t
GROUP BY t.Count
(Just makes it easier for me to see the inner query, and easier to extract it and run it separately. And qualifying all column references (with a table alias or table name) is a best practice.)
select dup_count as duplicated,
count(*) as `count`,
group_concat(sku) as skus
from
(
SELECT sku, COUNT(1) AS dup_count
FROM products
GROUP BY sku
) tmp_tbl
group by dup_count
right now I'm trying to return the biggest COUNT(DISTINCT column)-number from a mysql table.
It's hard to describe, so I'll give you an example:
My table has the following columns: s_id, k_id, p_id.
Now I want to count the different s with the condition that every entry has the same p_id, too. I need this to prepare a HTML-Table (so i know how many Columns this table will have).
Data Example:
This is what I got, so far:
SELECT COUNT(DISTINCT k_id) AS a FROM `table`
the problem with this is, that there may be 4 different k_ids but 3 of them are related to p_id = 1 and the last one is releated to p_id = 2.
a returns 4 instead of 3.
Thanks for support!
I think you want this:
select p_id, count(distinct s_id) as cnt
from table
group by p_id
order by cnt desc
limit 1;
Please consider this:
select max(count(distinct(k_id))) from table
group by p_id
I have collected informations from different sources about certain IDs that should match a single name. Some sources are more trustworthy than others in giving the correct name for a given ID.
I created a table (name, id, source_trustworthiness) and I want to get the most trustworthy name for each ID.
I tried
SELECT name, id, MAX( source_trustworthiness )
FROM table
GROUP BY id
this returns th highest trustworthiness available for each ID but with the first name it finds, regarless of its trustworthiness.
Is there a way I can get that right ?
Mysql has special functionality to help:
SELECT * FROM (
SELECT name, id, source_trustworthiness
FROM table
ORDER BY 3 DESC ) x
GROUP BY id
Although this wouldn't even execute in other databases (not naming all non-aggregate columns in the GROUP BY clause), with mysql it returns the first row encountered for each unique value of the grouped by columns. By ordering the rows greatest first, the first row for each id will be the most trustworthy.
Since this question is tagged mysql, this query is OK. Not only is it really simple, it's also quite fast.
SELECT a.*
FROM TableName a
INNER JOIN
(
SELECT id, MAX(source_trustworthiness) max_val
FROM TableName
GROUP BY ID
) b ON a.ID = b.ID AND
a.source_trustworthiness = b.max_val
I have two tables, both having column a device_id column that I want to count. For the purposes of demonstration, the schema looks like:
Table 1: 'id', 'save_val', 'device_id_major'
Table 2: 'id', 'save_val', 'location', 'device_id_team'
Table 1 could have many of the same 'device_id_major'.
I basically want to get the unique device_id's from both tables, then from that result set, get the count of unique device_id's (the same device_id can appear in both tables).
Is this possible in one query?
select distinct aa.device_id, count(*)
from(select distinct device_id from table1
union all
select distinct device_id from table2) as aa
group by device_id
order by device_id
Or something like... As I don't have the schema to hand, I can't fully validate it.
SELECT count(DISTINCT aa.id)
FROM (SELECT DISTINCT major_id AS id FROM `major`
UNION ALL
SELECT DISTINCT team_id AS id FROM `team`)
AS aa
This seems to do the trick.
You could use a query that takes the UNION of both tables, then SELECT the unique values.
I am trying to select of the duplicate rows in mysql table it's working fine for me but the problem is that it is not letting me select all the fields in that query , just letting me select the field name i used as distinct , lemme write the query for better understading
mysql_query("SELECT DISTINCT ticket_id FROM temp_tickets ORDER BY ticket_id")
mysql_query("SELECT * , DISTINCT ticket_id FROM temp_tickets ORDER BY ticket_id")
1st one is working fine
now when i am trying to select all fields i am ending up with errors
i am trying to select the latest of the duplicates let say ticket_id 127 is 3 times on row id 7,8,9 so i want to select it once with the latest entry that would be 9 in this case and this applies on all the rest of the ticket_id's
Any idea
thanks
DISTINCT is not a function that applies only to some columns. It's a query modifier that applies to all columns in the select-list.
That is, DISTINCT reduces rows only if all columns are identical to the columns of another row.
DISTINCT must follow immediately after SELECT (along with other query modifiers, like SQL_CALC_FOUND_ROWS). Then following the query modifiers, you can list columns.
RIGHT: SELECT DISTINCT foo, ticket_id FROM table...
Output a row for each distinct pairing of values across ticket_id and foo.
WRONG: SELECT foo, DISTINCT ticket_id FROM table...
If there are three distinct values of ticket_id, would this return only three rows? What if there are six distinct values of foo? Which three values of the six possible values of foo should be output?
It's ambiguous as written.
Are you looking for "SELECT * FROM temp_tickets GROUP BY ticket_id ORDER BY ticket_id ?
UPDATE
SELECT t.*
FROM
(SELECT ticket_id, MAX(id) as id FROM temp_tickets GROUP BY ticket_id) a
INNER JOIN temp_tickets t ON (t.id = a.id)
You can use group by instead of distinct. Because when you use distinct, you'll get struggle to select all values from table. Unlike when you use group by, you can get distinct values and also all fields in table.
You can use DISTINCT like that
mysql_query("SELECT DISTINCT(ticket_id), column1, column2, column3
FROM temp_tickets
ORDER BY ticket_id");
use a subselect:
http://forums.asp.net/t/1470093.aspx