I want to convert a java object to json object with string format*. I am using gson library. Is there any way to do that.
(I am not sure if it is the correct name for this structure) json object with string format:
*
{ [\"name\":\"Ajay\",\"age\":30,\"email\":\"ajay#ajay.com\"]}
I'm pretty sure gson itself can't handle this, but you can. Given string s looking like
{ [\"name\":\"Ajay\",\"age\":30,\"email\":\"ajay#ajay.com\"]}
you only need to call gson on s.replace("\\\"", "\""). Simply clean up you string, so it looks like it should (your quotation marks look differently, maybe you need to fix it, too).
This may be too abstruse, but if you create a JSON string (through GSON or another library like JSON.org) and GSON-serialize that string, you will get the backslashes. This has been an irritation for me, but it would work for your case, with more code than the replace but safer if backslashes are otherwise valid in your JSON.
Related
I found a very strange behavior in spring rest.
Having an endpoint like the following
#GetMapping("/foo")
public String foo() {
return "bar";
}
returns the value bar. Sounds correct, but this is not a valid json, the effective result should be "bar" (note the ""). One might argue that spring expects that if a method returns a string, you have already manually serialized the object, but if all other objects are serialized by spring, then i would expect to have a special way to tell that its already serialized but the default way should be to serialize the value.
Maybe i'm missing something here, that's the reason why i didn't created a ticket in the spring issue tracker jet.
Unregistering the StringHttpMessageConverter as described in this answer should do the trick: https://stackoverflow.com/a/37906098/505621
While not really an answer, there are 2 possible workarounds:
Encode it yourself
Just add the required quotation mark explicitly to the response string \".
This could for example be done by using JSONObject.quote(yourString).
Wrapping
Wrap your string into a simple object or custom class. Then Jackson knows what to do with it.
Collections.singletonMap("value", yourString);
I have a problem while parsing json which includes single quote. I am using JSONDecoder. I added response from API at below and I don't want to do any replacement or some regex operations. Are there any workaround for that?
"{\'value1\': true, \'value2\':\'2021-02-08\'}"
Your string is simply not valid JSON. Since it's not valid JSON there's no way to configure JSONDecoder to decode it.
If you aren't in charge of the service that outputs that string, the only thing you can do to use it with JSONDecoder is to modify the string to become valid JSON by, as you suggested, doing text replacement.
I'm having the below JSON coming in as a String input to my code. Since the string isn't uniformly formatted, overcoming the escape characters and grouping of the quotes to read the string and convert it into Java Object and sub-objects has run into issues
{"payload":{"details":"{\"source\":\"incor\",\"type\":\"build\",\"created\":\"1553855543108\",\"organization\":null,\"project\":null,\"application\":null,\"_content_id\":null,\"attributes\":null,\"requestHeaders\":{}}","content":"{\"project\":{\"name\":\"spinner\",\"lastBuild\":{\"building\":false,\"number\":0}},\"master\":\"IncorHealthCheck\"}","rawContent":null,"eventId":"bb357b79-069b-426d-8d21-8d04b06f5009"},"eventName":"city_spinner_events"}
I've tried using GSON, Jackson so far to try and read the String and convert into object and sub-objects. However, I've been able to objectify only the top level object. I face issues while I need to create sub-objects due to the escape characters and misreading of grouping of quotes by the parser. It throws errors and exceptions.
The expected JSON is as below which can be converted to object :
{"payload":{"details":{"source":"incor","type":"build","created":"1553855543108","organization":null,"project":null,"application":null,"_content_id":null,"attributes":null,"requestHeaders":{}},"content":{"project":{"name":"spinner","lastBuild":{"building":false,"number":0}},"master":"IncorHealthCheck"},"rawContent":null,"eventId":"bb357b79-069b-426d-8d21-8d04b06f5009"},"eventName":"city_spinner_events"}
Try unescapeJava from org.apache.commons.text.StringEscapeUtils,
StringEscapeUtils.unescapeJava(str);
I want to know whether deserialize converts json to string or string to json.I need my string to be returned as Json so i used deserialize, but unsure about its syntax.Can anyone direct me correctly.
My code
JavaScriptSerializer datajson = new JavaScriptSerializer();
var objec = datajson.Deserialize<string>(data);
return Json(objec,JsonRequestBehavior.AllowGet);
Serialisation is the act of taking objects and turning them into something more persistable or communicable, i.e. turning objects into JSON, XML or binary data.
Deserialisation is the act of taking serialised data and turning it back into objects.
So in your case, if you want to turn your objects/variables into JSON, the process is called serialisation.
Your code, assuming it is MVC C# (you may wish to add these tags to your original post), appears to be deserialising a JSON encoded string into a string, then serialising it back to JSON again when it returns the view. I'm not sure why you would want to do this. You should be able to simply do:
return Json(data, JsonRequestBehavior.AllowGet);
I have a request parameter in my ASP.NET app. that is in JSON format, and I was wondering if there is a good (quick and easy) way to convert a JSON string to a Jayrocks JsonObject, so I can easily extract key-value pairs without the need to manually parse the string?
Assuming json is the variable containing JSON text, use Jayrock.Json.Conversion.JsonConvert.Import(json). What you will get back in return is either a JsonObject, JsonArray, JsonNumber, System.String, System.Boolean or a null reference depending on the root JSON value in the source JSON text. If you know it is going to be a JSON object for sure then you can safely cast the return value or use JsonConvert.Import<JsonObject>(json).
I would discourage working against JsonObject directly unless you particularly depend on one of its features. You should just pretend the JSON object you get back is a dictionary; either IDictionary or IDictionary<string, object>. With the latest version for .NET Framework 4, you can also work with a JsonObject as a dynamic object.
I don't know Jayrock, but if you want to accept a JSON object as a parameter of Action in MVC2 than the easiest way to do it is by using JsonValueProviderFactory from Futures assembly.
It's part of System.Web.Mvc in MVC3.