Remove Rows From CSV Where A Specific Column Matches An Input File - csv

Question

I have a CSV that contains multiple columns and rows [File1.csv].
I have another CSV file (just one column) that lists a specific words [File2.csv].
I want to able to take remove rows within File1 if any columns match any of the words listed in File2.
I originally used this:
grep -v -F -f File2.csv File1.csv > File3.csv
This worked, to a certain extent. This issue I ran into was with columns that had more than word in it (ex. word1,word2,word3). File2 contained word2 but did not delete that row.
I tired spreading the words apart to look like this: (word1 , word2 , word3), but the original command did not work.
How can I remove a row that contains a word from File2 and may have other words in it?

Answer 1

One way using awk.
Content of script.awk:
BEGIN {
## Split line with a doble quote surrounded with spaces.
FS = "[ ]*\"[ ]*"
}
## File with words, save them in a hash.
FNR == NR {
words[ $2 ] = 1;
next;
}
## File with multiple columns.
FNR < NR {
## Omit line if eigth field has no interesting value or is first line of
## the file (header).
if ( $8 == "N/A" || FNR == 1 ) {
print $0
next
}
## Split interested field with commas. Traverse it searching for a
## word saved from first file. Print line only if not found.
## Change due to an error pointed out in comments.
##--> split( $8, array, /[ ]*,[ ]*/ )
##--> for ( i = 1; i <= length( array ); i++ ) {
len = split( $8, array, /[ ]*,[ ]*/ )
for ( i = 1; i <= len; i++ ) {
## END change.
if ( array[ i ] in words ) {
found = 1
break
}
}
if ( ! found ) {
print $0
}
found = 0
}
Assuming File1.csv and File2.csv have content provided in comments of Thor's answer (I suggest to add that information to the question), run the script like:
awk -f script.awk File2.csv File1.csv
With following output:
"DNSName","IP","OS","CVE","Name","Risk"
"ex.example.com","1.2.3.4","Linux","N/A","HTTP 1.1 Protocol Detected","Information"
"ex.example.com","1.2.3.4","Linux","CVE-2011-3048","LibPNG Memory Corruption Vulnerability (20120329) - RHEL5","High"
"ex.example.com","1.2.3.4","Linux","CVE-2012-2141","Net-SNMP Denial of Service (Zero-Day) - RHEL5","Medium"
"ex.example.com","1.2.3.4","Linux","N/A","Web Application index.php?s=-badrow Detected","High"
"ex.example.com","1.2.3.4","Linux","CVE-1999-0662","Apache HTTPD Server Version Out Of Date","High"
"ex.example.com","1.2.3.4","Linux","CVE-1999-0662","PHP Unsupported Version Detected","High"
"ex.example.com","1.2.3.4","Linux","N/A","HBSS Common Management Agent - UNIX/Linux","High"

Answer 2

You could convert split lines containing multiple patterns in File2.csv.
Below uses tr to convert lines containing word1,word2 into separate lines before using them as patterns. The <() construct temporarily acts as a file/fifo (tested in bash):
grep -v -F -f <(tr ',' '\n' < File2.csv) File1.csv > File3.csv