mysql like groupby in oracle how to - mysql

In Mysql i have the fdllowing query along with the results below
drop table tab1;
CREATE TEMPORARY TABLE tab1
(col1 integer,col2 integer(10),col3 varchar(10),col4 integer)engine=memory
insert into tab1
values(100,1,'Hello',9);
insert into tab1
values(200,1,'HelloWrld',8);
insert into tab1
values(300,1,'HelloTher',7);
insert into tab1
values(400,2,'HiThere',6);
insert into tab1
values(500,3,'Howdy',5);
insert into tab1
values(600,3,'Hiya',4);
select col1,col2,col3,col4,min(col4)
from tab1
group by col2
'100', '1', 'Hello', '9', '7'
'400', '2', 'HiThere', '6', '6'
'500', '3', 'Howdy', '5', '4'
In Oracle i want the same result as Mysql
with tab1 as (
select 100 col1, 1 col2, 'Hello' col3,9 col4 from dual
union all
select 200 col1, 1 col2, 'HelloWrld' col3,8 col4 from dual
union all
select 300 col1, 1 col2, 'HelloTher' col3,7 col4 from dual
union all
select 400 col1, 2 col2, 'HiThere' col3,6 col4 from dual
union all
select 500 col1, 3 col2, 'Howdy' col3,5 col4 from dual
union all
select 600 col1, 3 col2, 'Hiya' col3,4 col4 from dual
)
select min(col1),col2,min(col3),col4,min(col4)
from tab1
group by col2,col4
Result I get is this
MIN(COL1) COL2 MIN(COL3) COL4 MIN(COL4)
---------- ---------- --------- ---------- ----------
100 1 Hello 9 9
200 1 HelloWrld 8 8
500 3 Howdy 5 5
600 3 Hiya 4 4
300 1 HelloTher 7 7
400 2 HiThere 6 6
What i would like to have is this
'100', '1', 'Hello', '9', '7'
'400', '2', 'HiThere', '6', '6'
'500', '3', 'Howdy', '5', '4'
How do i achieve Mysql like group by in Oracle
I am unable to get this and this is part of a long query that i am trying to resolve

According to the mysql documentation, the results for columns not specified in the group by can come from any rows.
So, a perfectly reasonable query in Oracle is:
select min(col1),col2,min(col3),min(col4),min(col4)
from tab1
group by col2
If your mysql code was depending on a particular value being chosen, then that code is broken. You will need to figure out exactly what you want, and figure out how to get that in Oracle.

Assuming that your intention is to get a deterministic result (unlike the MySQL result which is not deterministic) and that the col1 - col4 data you want to retain is the data for the row with the smallest col1 value for a given col2 value, you can use analytic functions
SQL> ed
Wrote file afiedt.buf
1 with tab1 as (
2 select 100 col1, 1 col2, 'Hello' col3,9 col4 from dual
3 union all
4 select 200 col1, 1 col2, 'HelloWrld' col3,8 col4 from dual
5 union all
6 select 300 col1, 1 col2, 'HelloTher' col3,7 col4 from dual
7 union all
8 select 400 col1, 2 col2, 'HiThere' col3,6 col4 from dual
9 union all
10 select 500 col1, 3 col2, 'Howdy' col3,5 col4 from dual
11 union all
12 select 600 col1, 3 col2, 'Hiya' col3,4 col4 from dual
13 )
14 select col1,
15 col2,
16 col3,
17 col4,
18 min_col4
19 from (select col1,
20 col2,
21 col3,
22 col4,
23 min(col4) over (partition by col2) min_col4,
24 rank() over (partition by col2 order by col1) rnk
25 from tab1)
26* where rnk = 1
SQL> /
COL1 COL2 COL3 COL4 MIN_COL4
---------- ---------- --------- ---------- ----------
100 1 Hello 9 7
400 2 HiThere 6 6
500 3 Howdy 5 4

Related

SQL - if col1 have value expect 0 and col2 have value except 0 with same value for col3 then values in one row

I have one table with these value
col1 col2 col3
---------------------- ------------------- -------------------------
1 0 ADD SERVICE ACTIVITY 1
0 1 ADD SERVICE ACTIVITY 1
0 8 Docment testing 2 (C07)
I want result like:
col1 col2 col3
---------------------- ------------------- -------------------------
1 1 ADD SERVICE ACTIVITY 1
0 8 Docment testing 2 (C07)
It seems that you want to group your data by column col3. I'm not sure whether results for col1 and col2 are sums or max values.
--for MAX:
SELECT MAX(COL1) as col1, MAX(COL2) as col2, COL3
/*-- for SUM:
SELECT SUM(COL1) as col1, SUM(COL2) as col2, COL3
*/
FROM test
GROUP BY COL3;

How to split one row into two based on 2 different column values

I am trying to accomplish something simple, but cant get to think straight. I have a case where 1 row can have different values in 2 different columns. But if thats the case then instead of displaying just 1 row for these 2 values, I need to display 2 rows for 1 column value each..for example.
ID Col1 col2 col3 col4
46054 2011W3974 164505 1 2
58765 2014W3777 275908 1 NULL
52311 2013W1877 247047 1 NULL
63032 2015W3317 295279 1 NULL
57552 2014W2813 274810 1 NULL
44584 2011W2622 173985 1 2
This needs to be split into 2 rows for row 1 and 6 into 2 rows like below:
46054 2011W3974 164505 1 NULL
46054 2011W3974 164505 NULL 2
58765 2014W3777 275908 1 NULL
52311 2013W1877 247047 1 NULL
63032 2015W3317 295279 1 NULL
57552 2014W2813 274810 1 NULL
44584 2011W2622 173985 1 NULL
44584 2011W2622 173985 NULL 2
What is the best possible way to do this. I looked at SPLIT XML function, but I dont think that will be helpful here. I also played with ranking functions, but since this is 2 columns, I dont think that will work either. Please suggest
Thanks,
RV
I'd properly just union it together:
SELECT Id, Col1, Col2, Col3, NULL AS Col4
FROM <Your Table>
WHERE col4 is NULL
UNION
SELECT Id, Col1, Col2, NULL, Col4
FROM <Your Table>
WHERE Col4 = 2
Just use Union not union All.
SELECT Id, Col1, Col2, Col3, NULL AS Col4
FROM YourTable
WHERE isnull(Col4 , 0) = 0
UNION
SELECT Id, Col1, Col2, NULL as Col3, Col4
FROM YourTable
WHERE isnull(Col3 , 0) = 0

SQL to select distinct values from one column where another column has varying values

I have a huge amount of data. To explain the issue, consider this ultra-minimal set of data:
id col1 col2
-------------------
1 ab 12
2 ab 12
3 ab 12
4 cd 34
5 cd 43
6 ef 34
7 ef 56
8 ef 34
What I need is to select all distinct values in col1 where there is more than one value in col2. So the results from the above would be something like this:
col1
----
cd
ef
Or even better, a row for each unique corresponding value in col2:
col1 col2
------------
ab 12
cd 34
cd 43
ef 34
ef 56
You can do this with a group by and having:
select col2
from t
group by col2
having min(col2) <> max(col2);
If you just want the distinct values, use select distinct:
select distinct col1, col2
from t;
First one, return col1 values having at least two different col2 values:
select col1 from
tablename
group by col1
having count(distinct col2) >= 2
Second, return col1 with col2, when col1 has at least two different col2 values:
select * from tablename
where col1 in (
select col1 from
tablename
group by col1
having count(distinct col2) >= 2)

sql database maths operation on data

I have a database with rows and columns of data, the row,col data is some summed data (ie. 1 3 5 7 from original data = 1 2 2 2).
I want to get the original data by subtraction eg. val=r1c2-r1c1 etc across the rows and columns. Is this possible in sql without having to do lots of individual select statements for each row/column?
I would like to do this for all rows and columns in database, like the following pseudocode
a[ 1,3,5,7;
2,5,6,7 ];
for(i=0;i<size(a,1); i++)
for(j=0;j<size(a,2)-1; j++)
b(i,j)=a(i,j+1)-a(i,j);
Try this.
SELECT col1,
col2 - col1 col2,
col3 - col2 col3,
col4 - col3 col4
FROM (SELECT 1 col1,
3 col2,
5 col3,
7 col4) a
Update: Same query will work for more than one row
SELECT col1,
col2 - col1 col2,
col3 - col2 col3,
col4 - col3 col4
FROM (SELECT 1 col1,3 col2,5 col3,7 col4
UNION ALL
SELECT 1 col1,3 col2,9 col3,11 col4
UNION ALL
SELECT 1 col1,3 col2,5 col3,7 col4) a

Grouping problem

When you use Group By how do you keep the other fields in sync when using aggregates
Here I am trying to find the min value of col4 when col2 = xxx
select col1, col2, col3, min(col4)
from table
where col2 = 'xxx'
group by col3
I can get the minimum value in col4 but col1 is not correct but col2, col3, col4 are.
Can anyone show me how to do this ?
Thanks
You are using non-standard MySQL extension to GROUP BY.
This query in fact reads as "for each distinct value of col3, select the minimal value of col4 along with the values of col1 and col2 from a single row of table having this value of col3 in no particular order"
Like, if we have the following data:
col1 col2 col3 col4
---- --- --- ----
A A 1 1
B B 1 2
C C 2 3
D D 2 4
, this query:
SELECT col1, col2, col3, MIN(col4)
FROM mytable
GROUP BY
col3
will return either of the following:
col1 col2 col3 col4
---- --- --- ----
A A 1 1
C C 2 3
col1 col2 col3 col4
---- --- --- ----
B B 1 1
C C 2 3
col1 col2 col3 col4
---- --- --- ----
A A 1 1
D D 2 3
col1 col2 col3 col4
---- --- --- ----
B B 1 1
D D 2 3
i. e. it can return any value of col1 and col2 found in the rows that contribute to the corresponding group.
This is equivalent of FIRST_VALUE analytic function, but in no particular order.
Update:
To select values of col1 and col2 corresponding to the minimal value of col4 within each group, use this:
SELECT col1, co2, col3, col4
FROM (
SELECT col1, col2, col3, col4,
COALESCE(#col3 = col3, FALSE) AS grp,
#col3 := col3 AS nv
FROM (
SELECT #col3 := NULL
) vars, table
WHERE col2 = 'xxx'
ORDER BY
col3, col4
) q
WHERE NOT grp
select a.col3, a.col2, a.col1, a.col4
from table as a natural join
(select col3, min(col4) as col4 from table
where col2='xxx'
group by col3 ) as b
where a.col2 = 'xxx' -- sometimes this helps the optimizer even though it's redundant
you can get into a bit of trouble here when there may be multiple rows with the same col3, col4, and col2, but different col1s -- pretty straightforward to fix with rownums and such, but that gets db-specific.
I guess you want the col1-3 corresponding to the min(col4) for each
col3?
Something like:
select X.col1, X.col2, X.col3, X.col4 from table X
join (select col3, min(col4) as mcol4 from table where col2='xxx' group by col3) as Y
on X.col3=Y.col3 and X.col4=Y.mcol4
where X.col2='xxx';