MySQL column grate that counts number of words that match query? - mysql

Question

I'm trying to rate matches based on the number of words from the query that are found in the row. I stared doing this:
SELECT Text, MATCH(`Text`) AGAINST ('$s') AS Grade
But soon I realised this didn't work since Grade is based on a lot of stuff like for example the order the words are, each word's length and so on.
I only want to know the % of words that are present in a row.
EG:
$s = 'i want pizza'
`Text` = 'pizza I want' // In this case Grade should be 100 as all words are found
Other examples:
Text | Grade
pizza I want too | 100 // All words were found, It doesn't matter if there are extra words
pizza I want | 100
i want | 66 // Only 66% of the words are present
want want want | 33 // Only 33% of the words are present

Answer 1

$s = 'i want pizza';
$text = 'pizza I want';
//move to lower-case to ignore case-differences
$s = strtolower($s);
$text = strtolower($text);
//count the number of words in $s
$slen = count(explode(" ", $s));
//create an array of words from the text that we check
$arr = explode(" ", $text);
$count = 0;
//go over the words from $text and count words that appear on $s
foreach ($arr as $word) {
if(strpos($s, $word) !== false){
$count++;
}
}
//display the percentage in format XX.XX
echo number_format((double)(100 * $count/$slen),2);