I have an article table which contains all the articles of my website.
Design looks like this:
id | user_id | name | date
I also have a followers table which contains all followers that follow each article
It's design looks like this:
id | article_id | user_id | date
Currently I have a SQL query which brings me 50 articles that exist ordered by date
SELECT id,user_id,name,date
FROM articles
ORDER BY date
LIMIT 50
I also have one more query which shows me 50 of the followers of an article
SELECT id, article_id, user_id, date
FROM followers
WHERE article_id = 5
LIMIT 50
How can i make this one query so I don't have to call 2 queries since I find it useless and could take more time to load?
Try this solution:
SELECT a.*, b.*
FROM
(
SELECT *
FROM articles
ORDER BY date
LIMIT 50
) a
INNER JOIN
(
SELECT aa.*
FROM followers aa
LEFT JOIN followers bb ON aa.article_id = bb.article_id AND aa.id < bb.id
GROUP BY aa.id
HAVING COUNT(1) < 50
) b ON a.id = b.article_id
This gets the 50 oldest articles joined with the 50 latest followers for each of those articles.
It is also quite flexible:
Change aa.id < bb.id to aa.id > bb.id to get the 50 first followers.
Change ORDER BY date to ORDER BY date DESC to get the 50 latest articles.
Change LIMIT n where n represents the amount of articles you want to retrieve.
Change HAVING COUNT(1) < n where n represents the amount of followers you want to retrieve per article.
And you can mix all four up to facilitate any combination you want.
SELECT a.id, a.user_id, a.name, a.date, f.id, f.article_id, f.user_id, f.date
FROM articles a, followers f
WHERE f.article_id = 5
ORDER BY a.date
LIMIT 50
Related
I want to retrieve variants of the same article which are part of the same group. DBM is MySQL 5.7.
There are 2 tables:
articles
articles_group
Table articles has the fields:
article_id | title
1 first product
2 second prod
3 3rd prod
4 4th example
Table articles_groups:
group_id | article_id
1 1
1 2
1 3
2 4
In this example I would like to retrieve all other articles which are in the same group as article 1. So that would be article 2 and 3.
My best shot, but somehow pretty complex:
SELECT
art.article_id,
model
FROM
articles art
INNER JOIN
articles_group art_g ON art.article_id = art_g.article_id
WHERE art_g.group_id = (
SELECT ag.group_id
FROM articles a
INNER JOIN articles_group ag ON a.article_id = ag.article_id
WHERE a.article_id = 1
)
How can I retrieve all other articles which belong to the same group of given article in an easy way? I can still change the shema if there is a better setup.
Let's say your given article is 1. To get all articles in same group of given article, you can use subquery to get group_id of given article. Then use outer query to get all articles in same group.
SELECT a.article_id, a.title
FROM articles a
JOIN articles_groups g ON a.ref_id = g.ref_id
WHERE g.group_id = (
SELECT g.group_id
FROM articles a
JOIN articles_groups g ON a.ref_id = g.ref_id
WHERE a.article_id = '1'
)
Working example: http://sqlfiddle.com/#!9/80995/20
I have three tables, a user table, a user_group table, and a link table.
The link table contains the dates that users were added to user groups. I need a query that returns the count of users currently in each group. The most recent date determines the group that the user is currently in.
SELECT
user_groups.name,
COUNT(l.name) AS ct,
GROUP_CONCAT(l.`name` separator ", ") AS members
FROM user_groups
LEFT JOIN
(SELECT MAX(added), group_id, name FROM link LEFT JOIN users ON users.id = link.user_id GROUP BY user_id) l
ON l.group_id = user_groups.id
GROUP BY user_groups.id
My question is if the query I have written could be optimized, or written better.
Thanks!
Ben
You actual query is not giving you the answer you want; at least, as far as I understand your question. John actually joined group 2 on 2017-01-05, yet it appears on group 1 (that he joined on 2017-01-01) on your results. Note also you're missing one Group 4.
Using standard SQL, I think the next query is what you're looking for. The comments in the query should clarify what each part is doing:
SELECT
user_groups.name AS group_name,
COUNT(u.name) AS member_count,
group_concat(u.name separator ', ') AS members
FROM
user_groups
LEFT JOIN
(
SELECT * FROM
(-- For each user, find most recent date s/he got into a group
SELECT
user_id AS the_user_id, MAX(added) AS last_added
FROM
link
GROUP BY
the_user_id
) AS u_a
-- Join back to the link table, so that the `group_id` can be retrieved
JOIN link l2 ON l2.user_id = u_a.the_user_id AND l2.added = u_a.last_added
) AS most_recent_group ON most_recent_group.group_id = user_groups.id
-- And get the users...
LEFT JOIN users u ON u.id = most_recent_group.the_user_id
GROUP BY
user_groups.id, user_groups.name
ORDER BY
user_groups.name ;
This can be written in a more compact way in MySQL (abusing the fact that, in older versions of MySQL, it doesn't follow the SQL standard for the GROUP BY restrictions).
That's what you'll get:
group_name | member_count | members
:--------- | -----------: | :-------------
Group 1 | 2 | Mikie, Dominic
Group 2 | 2 | John, Paddy
Group 3 | 0 | null
Group 4 | 1 | Nellie
dbfiddle here
Note that this query can be simplified if you use a database with window functions (such as MariaDB 10.2). Then, you can use:
SELECT
user_groups.name AS group_name,
COUNT(u.name) AS member_count,
group_concat(u.name separator ', ') AS members
FROM
user_groups
LEFT JOIN
(
SELECT
user_id AS the_user_id,
last_value(group_id) OVER (PARTITION BY user_id ORDER BY added) AS group_id
FROM
link
GROUP BY
user_id
) AS most_recent_group ON most_recent_group.group_id = user_groups.id
-- And get the users...
LEFT JOIN users u ON u.id = most_recent_group.the_user_id
GROUP BY
user_groups.id, user_groups.name
ORDER BY
user_groups.name ;
dbfiddle here
having a hard time pulling articles based on user country views
i have the following tables with their fields
user: id, country_id
article: id
article_views: id, user_id, article_id
each time a user views an article I insert it into the article_views table, like this:
article_views.id article_id user_id
2 1 1
3 2 1
4 2 2
5 2 2
I want to pull the highest viewed article for current user.country_id. I imagine it will contain:
order by article_views.article_id DESC
Any suggestions?
This should work fine:
select article_id, count(*) as views
from article_views inner join user on article_views.user_id = user.id
group by user.country_id
order by views desc;
Edit. I forgot about grouping article_id as #Josien pointed, the correct query is:
select country_id, article_id, count(*) as views
from article_views inner join user on article_views.user_id = user.id
where country_id = ':countryID'
group by user.country_id, article_id
order by views desc;
select av.id, count(*) as views
from article_views av inner join user u on av.user_id = u.id
where u.country_id = 'cc'
group by u.country_id
order by views desc;
I have this problem with SQL and I can't figure it out.
Imagine that I have 3 tables as follows
Names
Nameid name
1 Starbucks Coffee
2 Johns Restaurant
3 Davids Restaurant
user_likes
userid Nameid
1 1
2 1
2 3
user_visited
userid Nameid
1 2
I want to find the places with the most number of (likes+visited). I also want to select all places not just those who have been liked or visited
I do:
SELECT n.nameid, n.name , COUNT(f.nameid) AS freq
FROM names AS n
LEFT JOIN user_likes ON n.nameid=user_likes.nameid
LEFT JOIN user_visited ON n.nameid=user_visited.nameid
ORDER BY freq DESC
But it doesn't give me the total frequency. The problem is, if a place is both visited and liked, it is counted only once, while I want it to be counted twice.
Any suggestions?
I've made a quick test and although I prefer Serge's solution, this one seemed to perform faster as the amount of items to join will be less:
SELECT n.nameId, n.name, coalesce(sum(likesCount), 0) totalCount FROM NAMES n
LEFT JOIN (
SELECT nameId, count(*) likesCount FROM user_likes
GROUP BY nameId
UNION ALL
SELECT nameId, count(*) visitsCount FROM user_visited
GROUP BY nameId
) s ON n.nameId = s.nameId
GROUP BY n.nameId
ORDER BY totalCount DESC
I'm assuming the following indexes:
alter table names add index(nameid);
alter table user_likes add index(nameid);
alter table user_visited add index(nameid);
Probably the OP can compare the efficiency of both queries with actual data and provide feedback.
SELECT n.name, t.nameid, COUNT(t.nameid) AS freq
FROM Names n
JOIN (
SELECT nameid FROM user_likes
UNION ALL
SELECT nameid FROM user_visited
) t
ON n.nameid = t.nameid
GROUP BY t.nameid ORDER BY freq DESC
Mosty, your usage of coalesce() gave me an idea and I came up with this:
SELECT n.nameid, n.name ,
SUM((IFNULL(user_likes.userid,0)>0)+(IFNULL(user_visited.userid,0)>0) ) AS freq
FROM names AS n LEFT JOIN user_likes ON n.nameid=user_likes.nameid LEFT JOIN
user_visited ON n.nameid=user_visited.nameid ORDER BY freq DESC
Since my example here was a simplification of my problem (I have to join more than two tables to the main table) I'm reluctant to use SELECT inside SELECT, because I know it's not very efficient. Do you see any fundamental problem with my solution?
I've tried to look other posts to do a Mysql query, I think I'm almost there but for some reason I have a bug.
I have those tables :
POSTS [id_post (int) / activity (int) ]
VOTES [id_vote (int) / id_post (int) / user_id (int)]
ACTIVITIES [id_activity (int) / activity_name (varchar)]
I have in fact more tables and fields than that, but these are the relevant one for my problem. I created a vote system that adds a user vote to the VOTES table, refering to the post that is being voted and the user account of the voting person.
So the votes table may look like this :
id_vote | id_post | user_id
1 5 8
2 6 8
Every post belongs to an activity. I would like to lists the posts which have the most votes for each activity.
That's where I am so far :
SELECT activities.id_activity, activities.activity_name, votes.id_post, votes.totalvotes AS allvotes
FROM ( SELECT votes.id_post, COUNT(*) as totalvotes
FROM `votes`
GROUP BY votes.id_post
) AS votes
JOIN posts ON posts.id_post = votes.id_post
JOIN activities ON posts.activity = activities.id_activity
GROUP BY activities.id_activity
HAVING allvotes = MAX(totalvotes)
This works well, I retrieve what I want except that if 2 posts in the same activity have the same amount of votes, I have no idea which one only appears after grouping those posts, and why it's not the other one.
id_activity | activity_name | id_post | allvotes
5 eating 5 2
3 sleeping 6 1
More importantly, what is really bugging me is that some activities won't show up for some reason. I noticed that, in the above example, if the post 5 belonging to the eating category is the one that has the most votes indeed, then the category appears. BUT if it happens that the post for the eating category which have the mosts votes IS NOT post 5 (which is the one MYSQL decided to show up by default), the the whole row about the eating category just WON'T SHOW UP at all.
It's been 2 days I'm on this...
Any ideas ?
Thanks a bunch.
It is little complex to implement in a single query. it will be easy with some temporary tables. if you want it in a single query then you can try with row_number.
example:
SELECT id_activity,activity_name,id_post,v_count FROM(
SELECT id_activity,activity_name,id_post,v_count
,#rownum := IF(#prev_value=id_activity,#rownum+1,1) AS RowNumber
,#prev_value := id_activity
FROM (
select a.id_activity,a.activity_name,p.id_post,v.v_count
from activities a
left join posts p on p.activity=a.id_activity
left join (
select id_post,count(*) v_count from votes v1
group by id_post
) v on v.id_post=p.id_post
order by a.id_activity, v.v_count desc) as tmp
,(SELECT #rownum := 0) r
,(SELECT #prev_value := '') y
)tmp2
WHERE rownumber=1
FIDDLE
i guess its because you group by the activity, i wonder why this statement is allowed in mysql, in mssql you are not allowed to group only by activities.id_activity in this case, you had to group by activity and/or id_post
try this:
SELECT activities.id_activity, activities.activity_name, votes.id_post, COUNT(*) as totalvotes
FROM votes
INNER JOIN posts ON posts.id_post = votes.id_post
INNER JOIN activities ON posts.activity = activities.id_activity
GROUP BY votes.id_post
HAVING totalvotes = MAX(totalvotes)
and lmk if it works :)
or your statement modified:
SELECT activities.id_activity, activities.activity_name, votes.id_post, votes.totalvotes AS allvotes
FROM ( SELECT votes.id_post, COUNT(*) as totalvotes
FROM `votes`
GROUP BY votes.id_post
) AS votes
JOIN posts ON posts.id_post = votes.id_post
JOIN activities ON posts.activity = activities.id_activity
GROUP BY votes.id_post
HAVING allvotes = MAX(totalvotes)
if i get you right then its because you have 2 posts with the same activity, as soon as you group the activities and not group the posts, one post disappears.