I am developing an application using Springs 2.0.
I have a requirement that when user clicks on a submit button on a form, a poup should be displayed showing a "select" box for selecting a predefined reasons and a "Textarea" to accept comment. (These dropdown options are picked from context so can not use static HTML page.)
These 2 values should also be stored in the database along with the other data fields in the parent form.
My problem is: if I use "window.open" then the parent form data does not get carried to child window as it is not "submitted". Also can not submit the form as it will not display popup window.
I tried searching for solution on sites, but could not find solution suitable for me.
Any help would be really appreicated.
Thanks.
Use a div as a popup instead of a new window. Or use JQuery. Example, messi popup under usage
Edit
If you just want something very basic,
<div id="modal" style="border:3px solid black; background-color:#9999ff; padding:25px; font-size:150%; text-align:center; display:none;">
This is a modal popup!<br><br>
<input type="button" value="OK" onClick="Popup.hide('modal')">
</div>
Show Modal Popup
<br>
Show Modal Popup With A Custom Screen
http://www.javascripttoolbox.com
You can use jQuery modal. Here is a similar example which accepts input in a modal http://jqueryui.com/demos/dialog/modal-form.html.
Resolved it using window.showModalDialog and normal java script. Here are the details.
Firstly I defined 2 hidden fields on parent page. When popup window is opened and submitted, the values entered in the dropdown and text area are assigned to those.
var handle = window.showModalDialog(htmlURL,this,urlProp);
when submitted,
document.getElementById("hiddenRejectionComment").value = handle.rejectionComment;
document.getElementById("hiddenRejectionReason").value = handle.rejectionReason;
Simple, wasn't it?
Related
Am building a Wordpress plugin and am Using Vue Js.
I set up a variable that will be set to true on a button click
Then another div which is a modal that will remaining hidden with v-if as long as the variable is false. The is also a form in the div modal(pop up)
The problem is that once the value changes, on button pressed, the form submits immediately.
This has been happening but I usually ignore it because there was always a required field which will prevent the form from submitting automatically.
Vue.js Data object
{
selected_to_show : false,
}
The modal div
<div v-if="selected_to_show === true" class='mp-modal'>
<form on:submit.prevent="xhrSubmit()">
<form>
</div>
<button v-on:click="selected_to_show = true"></button>
This works but once the modal opens, the form submits immediately.
Note: There is only two button elements in the form where are all set to type="button"
The target is to prevent the form from submitting automatically when shown
If any one still uses this approach to re-render vue apps, my advice is, don't.
The best way to re-render the app is by doing
this.forceUpdate();
This will re-render the vue app instead of modifying data properties of the vue instance which are utilized during rendering.
However, don't overuse it.
Most times when your view is not re-rendering naturally, its probably because you are doing something wrong.
Fairly new to HTML Service in apps script, have written a very basic UI.
The problem is that when the button is clicked (no onclick handler set) it opens up a new blank tab (I'm using Chrome).
Code below reproduces the behaviour, I have jquery / jquery UI references which are used in the broader project so left them in here.
How do I stop this blank tab opening on button click? Not shown here but it also happens when entered hit in a text box.
code.js:
function NewProposal() {
var html = HtmlService.createTemplateFromFile('Index');
var ss = SpreadsheetApp.getActiveSpreadsheet();
ss.show(html.evaluate().setHeight(530).setWidth(1100).setSandboxMode(HtmlService.SandboxMode.IFRAME));
}
Index.html:
<!DOCTYPE html>
<base target="_top">
<link rel="stylesheet" href="//code.jquery.com/ui/1.11.2/themes/cupertino/jquery-ui.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/jquery-ui.min.js"></script>
<script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/jsgrid/1.4.1/jsgrid.min.js"></script>
<form>
<table>
<tr>
<td>
<button id="Create">Create</button>
</td>
</tr>
</table>
</form>
You'll need to either get rid of the button, and use something else, or get rid of the form tags, and use div tags. If you get rid of the form tags, then it's more difficult to collect data from any input tags in the form. But, I don't see any input tags in your form. If you have no input tags in your form, then using form tags is pointless. Maybe you just left them out for purposes of reproducing the error in as little code as possible.
When a button is clicked inside of a form tag, the default behavior is for the current window to issue a POST request. That refreshes the content in the browser, but if there is no callback to display some other content, the page will go blank.
The only way to avoid this built-in feature of a form with a button, is to not use a button, or not use the form tags.
A click event can be added to multiple different types of HTML elements. Like a link <a> tags. Or a <div>. So, you can use something else other than a button, style it to look like a button if you wish, and add a click event to whatever you decide to use.
If you have lots of different types of input tags, it may be better to continue to use the form. But if you can easily get all the data out of the table some other way, you don't really need the form. The form adds nothing to the capability of styling or layout. So, if the benefit of using the form doesn't fit your circumstance, then you can look at other options.
If you want to give feedback to the user about what inputs are required, that's another issue. The form tags, the required attribute, and the button submission are all part of a system to try to make form submission more automatic, and make data validation and data collection easier. But, in order to use that "built-in" functionality, it all needs to work together in a certain way. As with anything that people try to make generic, it's very difficult to make it fit all circumstances. If you don't want the page to go blank when the button is clicked, all of that built-in behavior can become more of a detriment than a help.
When Apps Script gets the form, it strips out most of the content from the form element, and creates an object of input names and their values. So, when the "form" object (No longer a real form object) gets to the server, the only way you can get the values out of the object is by using the name attributes.
Add onsubmit="return(false)" inside your form openning tag:
<form onsubmit="return(false)">
...
</form>
How to make the html input field allow to be blank, when i click the submit button on the form view?
the idea is when I click the submit button, the input is a must to key in something else the behind code is unable to run, I am using the asp.net and the button is the asp button not html button
http://s15.postimg.org/wtl7xtuyx/myinputpic.png
I want to allow the new password can be blank
If clearing fields is what you want, use .reset() method.
document.getElementById("YourFormName").reset();
A working fiddle here:
https://jsfiddle.net/4fpk2z9o/
I may comprehend it wrongly as I do not really understand what do you want.
Update (To disable html 5 form validation) :
Add novalidate='' or <form action="yourform.asp" novalidate> to your form.
In my AngularJS project I have an account details page where you can change your personal account information. This page allows for multiple phone numbers and e-mailaddresses to be supplied. Using mouse input (or tabbing to buttons and pressing them with space bar) works perfectly, however I'd like to add the convenience of the enter key pressing the 'logical' buttons.
My form looks like (accidentally forgot to translate a few items):
A simplified version of the HTML for the form can be found on PasteBin, I've mainly removed the directives for managing the lists.
All buttons are <button> elements except for the cancel button which an <a> to the previous page, and the submit button is <button type="submit">.
When selecting any text box and pressing enter, the first (non-disabled) <button> element is 'clicked'. Meaning if I would change the last name, hit enter, the first phone number would be removed.
When you're in a new entry of phone numbers or e-mailaddresses (the row with the green + button) it should click that button, and if it's disabled do nothing.
When you're in any other text box on the form it should hit the save button, and also if the save button's disabled, do nothing.
Both buttons will be disabled based on form validation.
There'd be no trouble in changing the type of a button from button to submit if that'd help.
I would preferably have an all HTML solution, using just semantics, but I doubt that's really possible. So the logical alternative would be to use an AngularJS directive.
Please do not provide a jQuery or plain JavaScript solution relying on IDs or something like that. I don't want to hack my way around AngularJS, rather embrace it.
In the meantime I've worked on a directive that allows me to declare what I've called 'submit scopes'.
In essence you have actions (inputs) and targets (buttons), they're bound through a service by a key you can assign in the template. To avoid keys from clashing and from simple annoying work you can create a submit-scope which will cause it's children to prepend a unique key to the value they're accessing.
Within a submit-scope you can still override an action to use a global key instead by setting the attribute global-submit="true".
Example code:
<div submit-scope>
<input type="text" submit-action />
<button type="button" submit-target>Pressing enter in the above field will click this button.</button>
</div>
You can view the entire source code and a slightly larger example on Plnkr.
I just tried to replace
<button>Cancel</button>
with
<input type="button" value="Cancel">
and it seems to work correctly...
I have a very long form, so I need to separate it to different pages.
My questions are:
1) How to save the form input when the user navigate to next form, and when the user back to previous form, the data entered previously will still be there.
2) How can I save the data of the incomplete form and provide the user a link so that he can go to that link and continue to fill in the form before actually submit it.
Please advise me on how to achieve these. Thanks in advance.
Simply submit the form to next form page and in next form page you can populate hidden fields with the received data from form1
form2.php
$form1Field = $_POST;
form2.php
<form action="form3.php">
<input id='form1_name' type='hidden' value='<?=form1Field['name']?>' />
<input id='form12_email' type='text' value='' />
</form>
#katti's suggestion is good, easy way is to make divs for each form and hide using css "display:none" all divs except 1st, then on a click button, hide div1 and show div2 so on. that way you wont need many form and will need less code and faster solution.
You can use hidden fields for this purpose. Or save data in cookies.
You can divide the form by dynamically loading the next part of the form using JavaScript.
And it is a better user experience too not loading a new page completely.
In this case you can save the form content in a JSON object which can be posted to the server once the user hits submit.