-webkit-linear-gradient Not working in Dreamweaver CS6 - html

I've tried multiple times to apply the following piece of code in a CSS document:
display: block;
width: 500px;
margin: 500px auto;
padding: 15px;
text-align: center;
border: 4px solid blue;
background: -webkit-linear-gradient(top,black,white);
outline: 7px solid red;
Everything appears correctly, except the gradient. I have CS6 Live View turned on, and it still refuses to appear. All I get in my box is a white background, as opposed to the black to white gradient. However, when I type the same line of code into the trial of Coda 2 I downloaded, it works perfectly. Is there anything I can do to resolve the issue?


Try this:
background-image: linear-gradient(top, rgb(0,0,0) 0%, rgb(255,255,255) 100%);
background-image: -o-linear-gradient(top, rgb(0,0,0) 0%, rgb(255,255,255) 100%);
background-image: -moz-linear-gradient(top, rgb(0,0,0) 0%, rgb(255,255,255) 100%);
background-image: -webkit-linear-gradient(top, rgb(0,0,0) 0%, rgb(255,255,255) 100%);
background-image: -ms-linear-gradient(top, rgb(0,0,0) 0%, rgb(255,255,255) 100%);
background-image: -webkit-gradient(
linear,
left top,
left bottom,
color-stop(0, rgb(0,0,0)),
color-stop(1, rgb(255,255,255))
);
from : http://gradients.glrzad.com/

Related

CSS gradient on text input

Is it possible to make the text color of an <input> a gradient? I found this solution for static text but it does not work for input:
h1 {
font-size: 72px;
background: -webkit-linear-gradient(to right, rgb(66, 251, 227), rgb(43, 43,
255));
-webkit-background-clip: text;
-webkit-text-fill-color: transparent;
}

Yes it is possible please try this
background-image: linear-gradient(bottom, #f00 5%, #000 100%);
background-image: -o-linear-gradient(bottom, #f00 5%, #000 100%);
background-image: -moz-linear-gradient(bottom, #f00 5%, #000 100%);
background-image: -webkit-linear-gradient(bottom, #f00 5%, #000 100%);
background-image: -ms-linear-gradient(bottom, #f00 5%, #000 100%);
background-image: -webkit-gradient(
linear,
left bottom,
left top,
color-stop(0.05, #f00),
color-stop(1, #000)
);

HTML reduce gradient layer over image?

I have an image section with a gradient layer that was built into the stylesheet of the theme. What in this block of code do I need to change to reduce the gradient?
.image-section {
background: -moz-linear-gradient(top, rgba(0,0,0,0.2) 0%, rgba(0,0,0,0.5) 30%, rgba(0,0,0,0.8) 80%, rgba(0,0,0,0.9) 100%);
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,0,0.2)), color-stop(30%,rgba(0,0,0,0.5)), color-stop(80%,rgba(0,0,0,0.8)), color-stop(100%,rgba(0,0,0,0.9)));
background: -webkit-linear-gradient(top, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.5) 30%,rgba(0,0,0,0.8) 80%,rgba(0,0,0,0.9) 100%);
background: -o-linear-gradient(top, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.5) 30%,rgba(0,0,0,0.8) 80%,rgba(0,0,0,0.9) 100%);
background: -ms-linear-gradient(top, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.5) 30%,rgba(0,0,0,0.8) 80%,rgba(0,0,0,0.9) 100%);
background: linear-gradient(to bottom, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.5) 30%,rgba(0,0,0,0.8) 80%,rgba(0,0,0,0.9) 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#33000000', endColorstr='#e6000000',GradientType=0 );
display: table;
overflow: hidden;
table-layout: fixed;
width: 100%;
}
Any help with handling this block of code is appreciated.

To reduce the gradient you should change the background gradient values for example :
background: -moz-linear-gradient(top, rgba(0,0,0,0.2) 0%, rgba(0,0,0,0.5) 30%, rgba(0,0,0,0.8) 80%, rgba(0,0,0,0.9) 100%);
The previous style it start with opacity 0.2 at 0% of the height and end with opacity 0.9 at 100% of the height, you can change those opacity values as you need.
let say that you want to start with 0.2 and end with 0.5, the style should be like this :
background: -moz-linear-gradient(to bottom, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.3) 30%,rgba(0,0,0,0.4) 80%,rgba(0,0,0,0.5) 100%)
the style :
.image-section {
background: -moz-linear-gradient(top, rgba(0,0,0,0.2) 0%, rgba(0,0,0,0.3) 30%, rgba(0,0,0,0.4) 80%, rgba(0,0,0,0.5) 100%);
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(0,0,0,0.2)), color-stop(30%,rgba(0,0,0,0.3)), color-stop(80%,rgba(0,0,0,0.4)), color-stop(100%,rgba(0,0,0,0.5)));
background: -webkit-linear-gradient(top, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.3) 30%,rgba(0,0,0,0.4) 80%,rgba(0,0,0,0.5) 100%);
background: -o-linear-gradient(top, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.3) 30%,rgba(0,0,0,0.4) 80%,rgba(0,0,0,0.5) 100%);
background: -ms-linear-gradient(top, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.3) 30%,rgba(0,0,0,0.4) 80%,rgba(0,0,0,0.5) 100%);
background: linear-gradient(to bottom, rgba(0,0,0,0.2) 0%,rgba(0,0,0,0.3) 30%,rgba(0,0,0,0.4) 80%,rgba(0,0,0,0.5) 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#33000000', endColorstr='#e6000000',GradientType=0 );
display: table;
overflow: hidden;
table-layout: fixed;
width: 100%;
}
Demo : https://jsfiddle.net/IA7medd/rnjunkod/

Change the flow of colours in a CSS gradient

I use a <div class="menu"></div> and I set a background color with a gradient.
It floats from red in the top to white in the Bottom. Here is my .css code:
.menu {
background-color: #FFF;
background-image: -webkit-gradient(linear, left top, left bottom, from(#791014), to(#FFF));
background-image: -webkit-linear-gradient(top, #791014, #FFF);
background-image: -moz-linear-gradient(top, #791014, #FFF);
background-image: -ms-linear-gradient(top, #791014, #FFF);
background-image: -o-linear-gradient(top, #791014, #FFF);
background-image: linear-gradient(top, #791014, #FFF);
clear: both;
}
I like the starting and end color. My question is, if there is a way that I can change how it flows from red (top) to white (bottom)
For example that it switches very much earlier to white, so that I have the dark red at the beginning of the top but in the middle it is already much more white.
In other words, I want to change how fast it transitions from red to white.

If you want the transition between the colors to happen quicker than normal , just change the point by where the transition should be fully completed. When just two colors are given without any color-stop percentage then the first color starts at 0% and the in between colors are calculated such that second color is reached at 100% mark (100% = container's height by default or background-size in Y-axis if specified). Instead of that give a lower value for the white color. In the below snippet, I have given it as 60% and so the background reaches white color by the time it reaches 60% of the container's height.
Note:
100% = Container's height (default) or background-size in Y-axis (if it is specified) for a vertical gradient.
100% = Container's width (default) or background-size in X-axis (if it is specified) for horizontal gradient.
div {
float: left;
height: 100px;
width: 200px;
line-height: 100px;
text-align: center;
margin-right: 5px;
}
.menu-60 {
background-color: #FFF;
background-image: -webkit-linear-gradient(top, #791014 0%, #FFF 60%);
background-image: -moz-linear-gradient(top, #791014 0%, #FFF 60%);
background-image: -ms-linear-gradient(top, #791014 0%, #FFF 60%);
background-image: -o-linear-gradient(top, #791014 0%, #FFF 60%);
background-image: linear-gradient(top, #791014 0%, #FFF 60%);
}
.menu-40 {
background-color: #FFF;
background-image: -webkit-linear-gradient(top, #791014 0%, #FFF 40%);
background-image: -moz-linear-gradient(top, #791014 0%, #FFF 40%);
background-image: -ms-linear-gradient(top, #791014 0%, #FFF 40%);
background-image: -o-linear-gradient(top, #791014 0%, #FFF 40%);
background-image: linear-gradient(top, #791014 0%, #FFF 40%);
}
.menu-80 {
background-color: #FFF;
background-image: -webkit-linear-gradient(top, #791014 0%, #FFF 80%);
background-image: -moz-linear-gradient(top, #791014 0%, #FFF 80%);
background-image: -ms-linear-gradient(top, #791014 0%, #FFF 80%);
background-image: -o-linear-gradient(top, #791014 0%, #FFF 80%);
background-image: linear-gradient(top, #791014 0%, #FFF 80%);
}
br {
clear: both;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/prefixfree/1.0.7/prefixfree.min.js"></script>
<h3>Red to White at 60%</h3>
<div class='menu-60'>Text</div>
<div class='menu-60'>Text</div>
<div class='menu-60'>Text</div>
<br/>
<h3>Red to White at 40%</h3>
<div class='menu-40'>Text</div>
<div class='menu-40'>Text</div>
<div class='menu-40'>Text</div>
<br/>
<h3>Red to White at 80%</h3>
<div class='menu-80'>Text</div>
<div class='menu-80'>Text</div>
<div class='menu-80'>Text</div>

You can use colour stops to achieve this like
background: -moz-linear-gradient(top, #791014 0%, #ffffff 28%);
background: -webkit-linear-gradient(top, #791014 0%,#ffffff 28%);
background: linear-gradient(to bottom, #791014 0%,#ffffff 28%);
You could use a tool like http://www.colorzilla.com/gradient-editor/ to easily tweak this visually and have the code generated for you.
http://colorzilla.com/gradient-editor/#791014+0,ffffff+28

Prevent scrolling

I have this div, and i need it to be fixed, but i can't use position fixed (the site goes to the left when i push a button, and if the div it's fixed, t will stay in the same spot)... How can i do it?
#baar{
height: 56px;
width: 100%;
background: linear-gradient(top, #e3e3e3 0%, #f9f9f9 100%);
background: -moz-linear-gradient(top, #e3e3e3 0%, #f9f9f9 100%);
background: -webkit-linear-gradient(top, #e3e3e3 0%, #f9f9f9 100%);
background-image: -ms-linear-gradient(top left, #e3e3e3 0%, #f9f9f9 100%);
background-image: -o-linear-gradient(top left, #e3e3e3 0%, #f9f9f9 100%);
background-image: -webkit-gradient(linear, left top, right bottom, color-stop(0, #f9f9f9), color-stop(1, #e3e3e3));
background-image: linear-gradient(to bottom right, #e3e3e3 0%, #f9f9f9 100%);
box-shadow: 0px 0px 9px rgba(0,0,0,0.15);
box-shadow: 0px 0px 9px rgba(0,0,0,0.15);
position: relative;
margin-top: 16px;
left: 0;
text-align: center;
}
I've already tried overflow: hidden...
Thanks

Try this,
position: absolute;
and check if that works, also maybe add a float parameter.
Have a look at this documentation/syntax of style sheets on w3schools, it can be helpful if you forget a couple things now and again.
-http://www.w3schools.com/css/css_syntax.asp

CSS gradient to produce dotted line

I needed to print a textearea content (user input) and I just used css gradient to produce lines below the text. The following css did the trick for me.
.linedText {
color: #000000;
line-height: 24px;
background-color: #ffffff;
background: -webkit-gradient(linear, 2% 2%, 2% 100%, from(#000000), color-stop(1%, #ffffff)) 0 -2px;
background: -webkit-linear-gradient(top, #000000 0%, #ffffff 1%) 0 -1px;
background: -moz-linear-gradient(top, #000000 0%, #ffffff 1%) 0 -1px;
background: -ms-linear-gradient(top, #000000 0%, #ffffff 1%) 0 -1px;
background: -o-linear-gradient(top, #000000 0%, #ffffff 1%) 0 -1px;
background: linear-gradient(top, #000000 0%, #ffffff 1%) 0 -1px;
-webkit-background-size: 100% 24px;
-moz-background-size: 100% 24px;
-ms-background-size: 100% 24px;
-o-background-size: 100% 24px;
background-size: 100% 24px;
}
<p class="linedText">fdfdfdfdfdfdf<br>dfdfd<br>fdf<br>df</p>
And it generates like following:
Now I need to change the style to dotted. Can anyone do it for me please? I tried it for sometimes, but no luck, so thought of SO for a quick response.
Thanks.

This is an example of how you can achieve what you're trying.
It's just a matter of using two linear gradients with rgba colors = transparency and make them overlap to create a pattern to be repeated.
It's not cross browser (webkit only). Just a snippet to get you started.
background-image:
-webkit-linear-gradient(right, rgba(255,255,255,1) 0%, rgba(255,255,255,1) 50%, rgba(255,255,255,0) 51%,rgba(255,255,255,0) 100%),
-webkit-linear-gradient(bottom, rgba(128,128,128,1) 0%, rgba(128,128,128,0) 8%, rgba(128,128,128,0) 100%);
background-size: 12px 24px;