If I have three different tables like this
table_1
Field 1: victories
Field 2: name
table_2
Field 1: name
Field 2: birthday
Now I would want to get the birthday of the person with the most victories.
So I would do something like this (pseudo code):
select victories from table_1 and sum_it_all
get name and pass name to table_2
select birthday from table_2 where name
Ok, this is pretty ugly pseudo code, but I hope you get the point.
Using Andomar's solution works fine.
Now I tried to nest another table in it, like this though:
select address
from table_3
where birthday =
(
select birthday
from table_2
where name =
(
select name
from table_1
group by
name
order by
sum(victories) desc
limit 1
)
)
I do get a correct answer, but for some reason also get a null back. And how would I output the sum of victories?
select birthday
from table_2 t2
where name =
(
select name
from table_1 t1
order by
victories desc
limit 1
)
If one user can have multiple rows in table_1, you'd have to sum the victories:
select birthday
from table_2 t2
where name =
(
select name
from table_1 t1
group by
name
order by
sum(victories) desc
limit 1
)
I think what you're looking for is something like this:
SELECT t2.name, SUM(t1.victories) as SumOfVictories, t2.birthday
FROM table_1 as t1
JOIN table_2 as t2
ON table_1.name = table_2.name
GROUP BY t2.name, t2.birthday
ORDER BY SUM(t1.victories) DESC
LIMIT 1
You can use following nested SQL:
select name, birthday from table_2 where name in (
select name from table_1 order by victories desc limit 1
)
Would SELECT * FROM table_1 INNER JOIN table_2 ON table_1.name=table_2.name ORDER BY victories DESC give you the desired results?
This might be a solution for your problem:
SELECT table_1.name, table_2.birthday
FROM table_2
JOIN table_1 ON table_1.name=table_2.name
WHERE table_1.victories>=ALL(SELECT table_1.victories
FROM table_1)
try this:
Select name, birthday from table_2 t2
Join table_1 t1 On t1.Name = t2.name
Having Count(*) =
(Select Max(namCount)
From (Select Count(*) namCount
From table_1
Group By name))
Group By t1.name
Related
I have a table, TABLE1, with two columns: SSN and Date.
I have another table, TABLE2, with SSN, name and Surname.
I want to view the Name and the Surname of the person who is associated to the SSN that appears the highest number of times in the first table (the one with SSN and Date)
Which query should I write?
The fastest way is probably to aggregation before joining:
select *
from (select t1.ssn
from table1 t1
group by t1.ssn
order by count(*) desc
limit 1
) t1 left join
table2 t2
using (ssn)
Try this.
SELECT t1.ssn, t2.name, t2.surname, count(*) as vol
FROM table1 t1
LEFT JOIN table2 t1 on t1.ssn = t2.ssn
GROUP BY 1
ORDER BY count(*) DESC
LIMIT 1
Use a subquery in the WHERE clause which returns the SSN that appears the most in table1:
SELECT *
FROM table2
WHERE SSN = (SELECT SSN FROM table1 GROUP BY SSN ORDER BY COUNT(*) DESC LIMIT 1)
With an index on SSN (which I assume exists) this is the fastest way to get the result.
I read few articles about this: Select max date, then max time This one seems most helpful but I do not see way to implement it.
There is five tables. I join them. I need to select only one row with highest date and highest time from first table and same from second table and join the rest on some other value. With the code I wrote I get multiple rows. It seems time selection is not right.
It might be done with subquery in subquery. I've tried something like this:
SELECT * from table1
INNER JOIN table2 ON table1.date = table2.date AND table1.gm = table2.gm
INNER JOIN table3 ON table2.gm = table3.gm ...
WHERE table3.date = :date AND table4.date = :date ...
AND table1.date IN(
SELECT MAX(table1.date) FROM table1 WHERE table1.time IN(
SELECT MAX(table1.time) FROM table1
)
)
AND table2.date IN(
SELECT MAX(table2.date) FROM table1 WHERE table2.time IN(
SELECT MAX(table2.time) FROM table2 )
)
ORDER BY table1.id
Question is:
How to get single row after joining all of this where date is highest and time is highest on that date?
Thanks!
EDIT: I am sorry for this. I forgot to say that I need max time of max date related with specific value from tables(gm columns). So that is one row(in example I gave it is table1.gm and table2.gm ... ) for each one of that .gm values which are same in every table, not just one row all together. Solutions Nick and Salim provided works but I did not solved problem.
EDIT: SOLVED! after implementing solutions by Nick I just neded to add GROUP BY cntrs_reper.gm_company_no, cntrs_reper.date.
And that's it. For every row in one table enties with highest date and time from others!! Thanks to all.
EDIT. If this can help this is full query:
SELECT cntrs_gm.gm_company_no AS company_c_g,
bns_gms.ded_bns AS ded_bns_gms,
bns_gms.no_ded_bns AS no_ded_bns_gms,
bns_gms.wag_ded_bns AS wag_ded_bns_gms,
cntrs_gm.cur_credit AS cur_credit_c_g,
cntrs_gm.cdrop AS cdrop_c_g,
cntrs_gm.total_jp AS total_jp_c_g,
cntrs_gm.games AS games_c_g,
cntrs_gm.wgames AS wgames_c_g,
cntrs_gm.doors AS doors_c_g,
cntrs_gm.power AS power_c_g,
cntrs_gm.total_in AS total_in_c_g,
cntrs_gm.total_out AS total_out_c_g,
cntrs_gm.total_acc AS total_acc_c_g,
cntrs_gm.total_bet AS total_bet_c_g,
cntrs_gm.total_win AS total_win_c_g,
cntrs_gm.total_bonus AS total_bonus_c_g,
cntrs_gm.date AS date_c_g,
cntrs_reper.gm_company_no AS company_reper,
bns_reper.ded_bns AS ded_bns_reper,
bns_reper.no_ded_bns AS no_ded_bns_reper,
bns_reper.wag_ded_bns AS wag_ded_bns_reper,
cntrs_reper.cur_credit AS cur_credit_reper,
cntrs_reper.cdrop AS cdrop_reper,
cntrs_reper.total_jp AS total_jp_reper,
cntrs_reper.games AS games_reper,
cntrs_reper.wgames AS wgames_reper,
cntrs_reper.doors AS doors_reper,
cntrs_reper.power AS power_reper,
cntrs_reper.total_in AS total_in_reper,
cntrs_reper.total_out AS total_out_reper,
cntrs_reper.total_acc AS total_acc_reper,
cntrs_reper.total_bet AS total_bet_reper,
cntrs_reper.total_win AS total_win_reper,
cntrs_reper.total_bonus AS total_bonus_reper,
cntrs_reper.date AS date_reper,
cntrs_reper.time AS time_reper,
bns_reper.time AS time_c_g,
gms_cfg.gm_no AS machine_id,
gms_cfg.denom_cin AS machine_cin
FROM bns_gms
INNER JOIN cntrs_gm
ON bns_gms.gm_company_no = cntrs_gm.gm_company_no AND bns_gms.date = cntrs_gm.date
INNER JOIN bns_reper
ON cntrs_gm.gm_company_no = bns_reper.gm_company_no
INNER JOIN cntrs_reper
ON bns_reper.gm_company_no = cntrs_reper.gm_company_no AND bns_reper.date = cntrs_reper.date
INNER JOIN gms_cfg
ON cntrs_reper.gm_company_no = gms_cfg.gm_no
WHERE bns_reper.date IN(
SELECT MAX(DATE(bns_reper.date)) FROM bns_reper WHERE bns_reper.time IN(
SELECT MAX(TIME(bns_reper.time)) FROM bns_reper
)
)
AND cntrs_reper.date IN(
SELECT MAX(DATE(cntrs_reper.date)) FROM cntrs_reper WHERE cntrs_reper.time IN(
SELECT MAX(TIME(cntrs_reper.time)) FROM cntrs_reper
)
)
ORDER BY cntrs_gm.gm_company_no
DB example
bns_gms
bns_reper
cntrs_gm
cntrs_reper
gms_cfg
The problem with your current query is that it will select all rows where table1.date is the latest date on which the highest time occurs, which may well be more than one e.g. for data such as
id date time
1 2018-03-30 18:40
2 2018-03-31 12:20
3 2018-03-31 19:20
Your WHERE clause:
table1.date IN(
SELECT MAX(table1.date) FROM table1 WHERE table1.time IN(
SELECT MAX(table1.time) FROM table1
)
will select rows with id=2 and id=3 as they both have date = '2018-03-31' which is when the maximum time occurs.
What you want to do is select the row which has the latest time on the latest date, for which you could use
table1.date = (SELECT MAX(date) FROM table1) AND
table1.time = (SELECT MAX(time) FROM table1 WHERE date = (SELECT(MAX(date) FROM table1))
By using aliasing, that can be simplified (since we already know table1.date = MAX(date) FROM table1) to
table1.date = (SELECT MAX(date) FROM table1) AND
table1.time = (SELECT MAX(time) FROM table1 AS t1 WHERE t1.date = table1.date)
I don't have MySQL but here is the general idea you can use. I don't have enough points to write a comment so I am responding as a reply. Essentially make a subquery/inline view for each table to select max of a column, then join those subqueries/inline views together.
Here is Oracle syntax. You can convert it to ANSI syntax.
select table1.column1, table2.column2,table3.column3
from
(select id1, max(column1) as column1 from table1 group by id1) as table1
(select id2, max(column2) as column2 from table2 group by id2) as table2
(select id3, max(column3) as column3 from table3 group by id3) as table3
where
table1.id1 = table2.id2
and table1.id1 = table3.id3
;
The result of this query gives me 0 rows where it should give me the 3 latest rows (grouped by Table1.Name).
Table1 has: "Name", "Timestamp", "Voltage".
Table2 has: "Name", "data".
When I delete "ORDER BY Table1.Timestamp" I do get 3 rows (as expected) but they are the 3 oldest entries in the database where I want the 3 latest.
(I have 3 Name values in Table1 and Table2 that match).
The code:
SELECT * from Table1
INNER JOIN Table2
ON Table1.Name=Table2.Name
GROUP BY Table1.Name
ORDER BY Table1.Timestamp;
You can try to perform a query like this :
SELECT t.*,t2.* from Table1 t
INNER JOIN Table2 t2
ON t.Name=t2.Name
WHERE t.Timestamp = (
SELECT MAX(t3.Timestamp) FROM Table1 t3
WHERE t3.Name = t.Name
)
You could sort and taking the top 3:
SELECT * from Table1
INNER JOIN Table2
ON Table1.Name=Table2.Name
ORDER BY Table1.Timestamp DESC
LIMIT 3
When you are using join two or more tables then don't use * in select query. Use specific column name to avoid column ambiguously in select query , you can also use Table1., Table2. but good way to use specific columns in select query.
SELECT Table1.Name,Table1.Timestamp from Table1
INNER JOIN Table2
ON Table1.Name=Table2.Name
GROUP BY Table1.Name
ORDER BY Table1.Timestamp;
I have table like this one:
I would like to all rows, but if there is user_id 5 if this case, override other rows which have no user_id.
I tried both with MAX(user_id) and GROUP BY country_name, but it still returns, wrong results.
Final result I'm expecting:
Try this;)
select t1.*
from yourtable t1
inner join (
select max(user_id) as user_id, country_name from yourtable group by country_name
) t2 on t1.country_name = t2.country_name and t1.user_id = t2.user_id
This is just a solution based on your sample data. If you have a variety of user_id, it should be more different.
As of SQL Select only rows with Max Value on a Column you can easily get rows with max value on a column by using both MAX(column) and GROUP BY other_column in one statement.
But if you want to select other columns too, you have to this in a subquery like in the following example:
SELECT a.*
FROM YourTable a
INNER JOIN (
SELECT country_name, MAX(user_id) user_id
FROM YourTable
GROUP BY country_name
) b ON a.country_name = b.country_name AND a.user_id = b.user_id
I have a database with many tables.. and each table has stored only IDs. Now what I want to do is:
SELECT id FROM table1, table2, table3
GROUP BY id;
but I also want to sort them by decreasing order of occurrence.
For example the IDs that are in all 3 tables should appear on top and the IDs appearing in only one table should be at the bottom. Any clue on how to do this?
Try this too
select id from
(
SELECT id FROM table1
union all
select id from table2
union all
select id from table3
) as t
GROUP BY id
order by count(id) desc
select sum(t1.id IS NOT NULL,t2.id IS NOT NULL, t3.id IS NOT NULL) as total,t1.id from table1 as t1 join table2 as t2 on t1.id=t2.id join table3 as t3 on t3.id = t1.id order by total desc;
I am not sure about your problem but this can help
select id from
(
SELECT id FROM table1
union all
select id from table2
union all
select id from table3
) as t
GROUP BY id
order by id desc