I need to make a mySQL query and am not sure what the format should be.
Here is the situation, I have a table with the fields - id, name, type
I would use a query similar to the following to get results from the table:
SELECT * FROM table WHERE type='1'
However, I have a list of ID's from another query. These are items that should be excluded from the results.
I'm sure the answer is simple, but I don't know enough about mySQL queries to find the answer.
A simple NOT IN will be what you want :) It lets you send a list of values and makes sure that its not in them :)
SELECT * FROM table WHERE ID NOT IN (1,2,3)
You could also do it with a subquery with something like:
SELECT id FROM table WHERE ID NOT IN (SELECT id FROM table2 WHERE type = 1)
You can use NOT IN query like this:
SELECT * FROM `table` WHERE `type`=1 WHERE `id` NOT IN (SELECT `blocked_ids` FROM `block`);
So, you would be having blocked IDs in the block table! Hope this helps! :)
Consider this table:
+----+-------------+
| id | name |
+----+-------------+
| 1 | America |
| 2 | Europe |
| 3 | India |
| 4 | Japan |
| 5 | Brazil |
| 6 | Switzerland |
| 7 | Syria |
| 8 | Wales |
| 9 | Taiwan |
| 10 | Zaire |
+----+-------------+
And the blocked table:
+-----+
| IDs |
+-----+
| 1 |
| 4 |
| 6 |
| 8 |
| 9 |
+-----+
Now, when I give a query like:
SELECT * FROM `countries` WHERE `id` NOT IN (SELECT * FROM `blocked`);
I get this result:
+----+--------+
| id | name |
+----+--------+
| 2 | Europe |
| 3 | India |
| 5 | Brazil |
| 7 | Syria |
| 10 | Zaire |
+----+--------+
Hope this helps! :)
Related
My table looks like
+----+------+----+
| Id | from | to |
+----+------+----+
| 1 | 1 | 10 |
| 1 | 10 | 12 |
| 1 | 12 | 23 |
| 1 | 24 | 26 |
| 2 | 2 | 8 |
| 2 | 3 | 4 |
| 2 | 4 | 10 |
+----+------+----+
Now I want to group by Id and select the most spanning range.
So the result table should look like this:
+----+-------------+
| Id | range |
+----+-------------+
| 1 | 1-23, 24-26 |
| 2 | 2-10 |
+----+-------------+
I do not even know how to start.
Thanks in advance for the help!
You can achieve something similar to this by writing a MySQL select query with the CONCAT() function. You can use GROUP BY to categorize the data. But keep in mind that from,to and range are reserved words in MySQL. Therefore, I'll use fooFrom, fooRange and fooTo as column name for this example
Example:
SELECT Id, CONCAT(fooFrom, "-", fooTo) AS "fooRange" FROM fooTable GROUP BY id;
This example code will output:
id | fooRange
1 | 5-6
2 | 12-88
But I'm not sure about how to concat all the content into a one-column value.
I am doing a mini project using MySQL. I came with the following problem:
I created 2 tables, student and book with 6 and 5 columns respectively.
mysql> select * from book;
+--------+------+------------+---------+------+
| bookid | Name | Authorname | edition | cost |
+--------+------+------------+---------+------+
| cc12 | dbms | guna | 5 | 500 |
| cc34 | CA | fasil | 5 | 600 |
| cs113 | OS | rohan | 3 | 300 |
| cs12 | AI | ganesh | 2 | 1000 |
| cs343 | c# | jackesh | 4 | 300 |
+--------+------+------------+---------+------+
5 rows in set (0.00 sec)
mysql> select * from studentbook;
+-----+--------+-----------+
| Sno | bookid | Studid |
+-----+--------+-----------+
| 1 | cc12 | 14vec1088 |
| 2 | cs113 | 14vec1099 |
| 3 | cc34 | 14vec1132 |
| 4 | cs343 | 14vec2011 |
| 5 | cs12 | 14vec100 |
+-----+--------+-----------+
5 rows in set (0.00 sec)
Now, when I enter any of the studid mentioned in the table studentbook (This is performed by PHP in the backend) it should display the details of book associated with the respective studid from the table book.
How can I perform the above using MySQL Query?
This might be work.
SELECT * FROM book
WHERE bookid IN
(SELECT bookid FROM studentbook
WHERE studid = "[Id of which you want book]");
This should get you what you need.
SELECT b.*
FROM book b
INNER JOIN studentbook sb on b.bookid = sb.bookid
WHERE sb.Studid = [your id]
I have a mysql table which has two columns, id and value.
id(auto_increment primary key)
value(varchar 255)
insert into table columns(`id`,`value`)VALUES(,'something1');
insert into table columns(`id`,`value`)VALUES(,'something2');
output
+----+---------------+
| id | value |
+----+---------------+
| 1 | something1 |
| 2 | something2 |
+----+---------------+
Now Inserting one value again
insert into table columns(`id`,`value`)VALUES(8,'something8');
Updated Table
+----+---------------+
| id | value |
+----+---------------+
| 1 | something1 |
| 2 | something2 |
| 8 | something8 |
+----+---------------+
Now I am inserting one value again
insert into table columns(`id`,`value`)VALUES(,'something');
Final Output
+----+---------------+
| id | value |
+----+---------------+
| 1 | something1 |
| 2 | something2 |
| 8 | something8 |
| 9 | something |
+----+---------------+
But I want the final output like this
+----+---------------+
| id | value |
+----+---------------+
| 1 | something1 |
| 2 | something2 |
| 8 | something8 |
| 3 | something |
+----+---------------+
Now id is 3 and further insertion will create id 4,5,6,7,9 and so on.
Is there any way to get achieve this ?
I know it is old post but mybie it will help someone :)
I am afraid it cannot be done automatically, however, I solved it to my client, maybe some of you could find it useful:
DECLARE FirstEmptyId int;
SELECT l.id +1 AS
START
FROM TableName AS l
LEFT OUTER JOIN TableName AS r ON l.id +1 = r.id
WHERE r.id IS NULL
LIMIT 1 INTO FirstEmptyId;
Insert Into TableName (Id..) Values (FirstEmptyId...)
STILL, YOU HAVE TO MIND THAT IT IS NOT ADVISABLE TO INSERT ID VALUE OTHER WAY THAN BY AUTOINCREMENT IT AND THERE IS A REASON FOR THAT :)
Consider creating the second column just for performance purposes.
Good luck fellow coders!
I have the following sample data:
| key_id | name | name_id | data_id |
+--------+-------+---------+---------+
| 1 | jim | 23 | 098 |
| 2 | joe | 24 | 098 |
| 3 | john | 25 | 098 |
| 4 | jack | 26 | 098 |
| 5 | jim | 23 | 091 |
| 6 | jim | 23 | 090 |
I have tried this query:
INSERT INTO temp_table
SELECT
DISTINCT #key_id,
name,
name_id,
#data_id FROM table1,
I am trying to dedupe a table by all fields in a row.
My desired output:
| key_id | name | name_id | data_id |
+--------+-------+---------+---------+
| 1 | jim | 23 | 098 |
| 2 | joe | 24 | 098 |
| 3 | john | 25 | 098 |
| 4 | jack | 26 | 098 |
What I'm actually getting:
| key_id | name | name_id | data_id |
+--------+-------+---------+----------+
| 1 | jim | 23 | NULL |
| 2 | joe | 24 | NULL |
| 3 | john | 25 | NULL |
| 4 | jack | 26 | NULL |
I am able to dedupe the table, but I am setting the 'data_Id' value to NULL by attempting to override the field with '#'
Is there anyway to select distinct on all fields and while keeping the value for 'data_id'? I will take the highest or MAX data_id # if possible.
If you only want one row returned for a specific value (in this case, name), one option you have is to group by that value. This seems like a good approach because you also said you wanted the largest data_id for each name, so I would suggest grouping and using the MAX() aggregate function like this:
SELECT name, name_id, MAX(data_id) AS data_id
FROM myTable
GROUP BY name, name_id;
The only thing you should be aware of is the possibility that a name occurs multiple times under different name_ids. If that is possible in your table, you could group by the name_id too, which is what I did.
Since you stated you're not interested in the key_id but only the name, I just excluded it from the query altogether to get this:
| name | name_id | data_id |
+-------+---------+---------+
| jim | 23 | 098 |
| joe | 24 | 098 |
| john | 25 | 098 |
| jack | 26 | 098 |
Here is the SQL Fiddle example.
RENAME TABLE myTable to Old_mytable,
myTable2 to myTable
INSERT INTO myTable
SELECT *
FROM Old_myTable
GROUP BY name, name_id;
This groups my tables by the values I want to dedupe while still keeping structure and ignoring the 'Data_id' column
I have a table called tags, like this:
+-------+----------+
| tagID | tagName |
+-------+----------+
| 1 | jewelery |
| 2 | gifts |
| 3 | asdf |
| 4 | fashion |
| 5 | diamonds |
+-------+----------+
Then a table called coupon_tags, like this:
+-------+----------+
| tagID | couponID |
+-------+----------+
| 1 | 1 |
| 2 | 1 |
| 3 | 2 |
| 4 | 2 |
| 5 | 3 |
+-------+----------+
And lastly, a table called coupons, here are the pertinent parts (id is the same as couponID elsewhere):
+----+-----------------+
| id | zone |
+----+-----------------+
| 1 | Los Angeles |
| 2 | Orange County |
| 3 | Los Angeles |
| 5 | Orange County |
| 6 | Orange County |
+----+-----------------+
What I need to write a query for: I want to get tagNames via the first table that correspond to the ordered list of the top 10 most used tagIDs in the second table, but it only looks through couponIDs that match another criteria - that the "zone" be a certain zone. In the end, only the top 10 tagNames from a certain zone will show. I've never done a triple-table query before, any help?
I'm trying to keep this purely SQL, as I had a partially working PHP solution but it was messy and very slow.
SELECT tags.tagName FROM
(SELECT tagID, COUNT(*) FROM
coupon_tags
JOIN coupons ON coupons.couponID = coupon_tags.couponID AND zone = 'Los Angeles'
GROUP BY tagID ORDER BY COUNT(*) DESC LIMIT 10) AS most_used
JOIN tags ON most_used.tagID = tags.tagID