I would like to know how can I output a number with 2 decimal places, without rounding the original number.
For example:
2229,999 -> 2229,99
I already tried:
FORMAT(2229.999, 2)
CONVERT(2229.999, DECIMAL(4,2))
When formatting number to 2 decimal places you have two options TRUNCATE and ROUND. You are looking for TRUNCATE function.
Examples:
Without rounding:
TRUNCATE(0.166, 2)
-- will be evaluated to 0.16
TRUNCATE(0.164, 2)
-- will be evaluated to 0.16
docs: https://dev.mysql.com/doc/refman/8.0/en/mathematical-functions.html#function_truncate
With rounding:
ROUND(0.166, 2)
-- will be evaluated to 0.17
ROUND(0.164, 2)
-- will be evaluated to 0.16
docs: https://dev.mysql.com/doc/refman/8.0/en/mathematical-functions.html#function_round
You want to use the TRUNCATE command.
https://dev.mysql.com/doc/refman/8.0/en/mathematical-functions.html#function_truncate
How about
CAST(2229.999 AS DECIMAL(6,2))
to get a decimal with 2 decimal places
Just use
format(number, qtyDecimals)
sample: format(1000, 2)
result 1000.00
This is how I used this is as an example:
CAST(vAvgMaterialUnitCost.`avgUnitCost` AS DECIMAL(11,2)) * woMaterials.`qtyUsed` AS materialCost
Show as decimal
Select ifnull(format(100.00, 1, 'en_US'), 0)
100.0
Show as Percentage
Select concat(ifnull(format(100.00, 0, 'en_US'), 0), '%')
100%
Related
I have the following query:
SELECT
(sign(mr.p1_h2h_win_one_time - mr.p2_h2h_win_one_time)) AS h2h_win_one_time_1,
(abs(mr.p1_h2h_win_one_time - mr.p2_h2h_win_one_time) ^ 2) AS h2h_win_one_time_2
FROM belgarath.match_result AS mr
LIMIT 10
Which returns:
However, when I try to multiply the two fields:
SELECT
(
sign(mr.p1_h2h_win_one_time - mr.p2_h2h_win_one_time)
) *
(
abs(mr.p1_h2h_win_one_time - mr.p2_h2h_win_one_time) ^ 2
) AS h2h_win_one_time_comb
FROM belgarath.match_result AS mr
LIMIT 10
Workbench simply returns OK instead of any rows.
Doing some investigation I can get the first two rows to display if I use LIMIT 2. Looking at the returned values above I guess there must be some issue with multiplying the minus values or zero values from rows 3-10. However, this can be done simply on a calculator so what am I missing?
Maybe you think that the operator ^ is the power operator when in fact it is the Bitwise XOR operator.
MySql has the function pow() for your case:
pow(abs(mr.p1_h2h_win_one_time - mr.p2_h2h_win_one_time), 2)
I need round up the numbers of a complete table of mysql with a funtion leaving the two decimals to zero?
e.g.:
from 75,55 to 86,00
from 75,45 to 75,00
All the prices of a complete table changed a few decimal and I do not know how it happened.
Can anybody help me?
You can simply use Round(X, D) function. From Docs:
Rounds the argument X to D decimal places. The rounding algorithm
depends on the data type of X. D defaults to 0 if not specified. D can
be negative to cause D digits left of the decimal point of the value X
to become zero.
Try:
SELECT ROUND(75.45, 2);
-- Fetches 75.00
SELECT ROUND(75.55, 2);
-- Fetches 76.00
Now, it seems that you want to Update all the values of a particular column, by rounding them to two decimal places. You can do the following:
UPDATE your_table_name
SET your_column_name = ROUND(your_column_name, 2);
-- It will round all the values to 2 decimal places.
"UPDATE your_table_name SET your_column_name = ROUND(your_column_name, 2);" not work for me. I dont know.
¡SOLUTION! = TABLE > ESTRUCTURE > NAME COLUMN > length/values > remove decimal.
All number round up in my row (column). Them I put decimal again. All my fields it's ok.
Hey is there any way to create query with simple formula ?
I have a table data with two columns value_one and value_two both are decimal values. I want to select this rows where difference between value_one and value_two is grater then 5. How can i do this?
Can i do something like this ?
SELECT * FROM data WHERE (MAX(value_one, value_two) - MIN(value_one, value_two)) > 5
Example values
value_one, value_two
1,6
9,3
2,3
3,2
so analogical difs are: 5, 6, 1, 1 so the selected row would be only first and second.
Consider an example where smaller number is subtracted with a bigger number:
2 - 5 = -3
So, the result is a difference of two numbers with a negation sign.
Now, consider the reverse scenario, when bigger number is subtracted with the smaller number:
5 - 2 = 3
Pretty simple right.
Basically, the difference of two number remains same, if you just ignore the sign. This is in other words called absolute value of a number.
Now, the question arises how to find the absolute value in MySQL?
Answer to this is the built-in method of MySQL i.e. abs() function which returns an absolute value of a number.
ABS(X):
Returns the absolute value of X.
mysql> SELECT ABS(2);
-> 2
mysql> SELECT ABS(-32);
-> 32
Therefore, without worrying about finding min and max number, we can directly focus on the difference of two numbers and then, retrieving the absolute value of the result. Finally, check if it is greater than 5.
So, the final query becomes:
SELECT *
FROM data
WHERE abs(value_one - value_two) > 5;
You can also do complex operations once the absolute value is calculated like adding or dividing with the third value. Check the code below:
SELECT *
FROM
data
WHERE
(abs(value_one - value_two) / value_three) + value_four > 5;
You can also add multiple conditions using logical operators like AND, OR, NOT to do so. Click here for logical operators.
SELECT *
FROM
data
WHERE
((abs(value_one - value_two) / value_three) + value_four > 5)
AND (value_five != 0);
Here is the link with various functions available in MySQL:
https://dev.mysql.com/doc/refman/5.0/en/mathematical-functions.html
No, you would just use a simple where clause:
select *
from data
where abs(value_one - value_two) > 5;
How can it convert or round off the decimal digit to nearest 50. for e.g if i get 2.00 to 2.49 then it may change to 2.50 ,
2.50 to 2.99 then it may change to 3.00.
pls solve if anyone knows.
Something like this should produce your required rounding up:
SELECT CEILING(<input> * 2.0) / 2.0
Where <input> is the column or expression that's currently producing the values you want to round.
I don't know if this is an efficient way or not but I tried this :
IF OBJECT_ID('MyTable','U') IS NOT NULL
DROP TABLE MyTable
GO
CREATE TABLE MyTable (num DECIMAL(10,2))
GO
INSERT INTO MyTable
values (1.00),(1.01),(1.49),(1.50),(1.51),(1.99),(2.00),
(11.00),(11.01),(11.49),(11.50),(11.51),(11.99),(12.00)
SELECT [num],
CASE
WHEN ( [num] - [Nbr] ) BETWEEN 0.01 AND 0.49 THEN [Nbr] + 0.5
ELSE [Nbr]
END AS [Result]
FROM (SELECT [num],
ROUND(num, 0) AS [Nbr]
FROM MyTable) t
Note: Case when condition can be modified as per requirement.
I have below table structure and data :
create table sample
(
id INT(10)
);
INSERT INTO sample
values
(23398),
(98743),
(54734);
Now I want to understand CAST function in mysql. Consider following query :
select
cast((id/3) as decimal(2,2)) as cast1,
cast((id/3) as decimal(3,2)) as cast2,
cast((id/3) as decimal(4,2)) as cast3,
cast((id/3) as decimal(5,2)) as cast4,
cast((id/3) as decimal(6,2)) as cast5,
cast((id/3) as decimal(7,2)) as cast6,
id/3 as actualId
from sample;
Please see output of this query at SQL Fiddle.
I am wondering why this query gives 0.99, 9.99 and vice versa.
Can anyone explain it ?
Thanks in advance.
decimal is a type that takes 2 arguments
decimal(size, places) :
size determines how many digits are in the number.
places determines how many of those digits are to the right of the decimal.
decimal(2,2) - .00 - 2 digits both of which are to the right of the decimal
when casting (23398 / 3) = 7799.33333333 to declimal(2, 2) it yields a decimal in the specified amount of space closest to the desired number which is 0.99
decimal(3,2) - 0.00 - 3 digits 2 of which are to the right of the decimal
when casting (23398 / 3) = 7799.33333333 to declimal(3, 2) it yields a decimal in the specified amount of space closest to the desired number which is 9.99
if all of the original numbers were negative you would yield -0.99 and -9.99 because they are the closest numbers to the desired number within the allocated space
As a matter of fact java does something similar if you take the max double and try to convert it to an int you will give the max int which is no where near the max double