I would like find the exact URL for an image in mediawiki to send in my pinterest code.
To find the page URL I use urlencode($wgTitle->getFullURL()) but I can't figure out what code to use for image and image description.
Thanks
To get the filepath in a wiki page, you can use [[Special:Filepath]], the {{filepath:...}} parser function or a link to the Media namespace.
To get it programmatically with PHP, you might want to have a look at How does MediaWiki calculate the file path to an image? or the code of the filepath function:
$file = wfFindFile( $filename );
$url = $file->getFullUrl();
(getFullUrl() method in the File class)
For your use case you might also have a look at the Extension:AddThis, they plan to support Pinterest too.
$f = wfFindFile( 'Foo.jpg' );
$imageUrl = $f->getCanonicalUrl(); // http://mywiki.com/images/0/06/Foo.jpg
$descriptionPage = $f->getTitle()->getFullUrl(); // http://mywiki.com/wiki/File.jpg
See the File class and Title class docs for details.
You can link to the page /wiki/Special:Filepath/File_name or /wiki/Special:Redirect/file/File_name, that will redirect the request to the full image location, for example: https://en.wikipedia.org/wiki/Special:Filepath/Turtle.jpg redirects to the full image path https://upload.wikimedia.org/wikipedia/commons/6/60/Turtle.jpg
Related
I have an R markdown document which is created using a shiny app, saved as a HTML. I have inserted a logo in the top right hand corner of the output, which has been done using the following code:
<script>
$(document).ready(function() {
$head = $('#header');
$head.prepend('<img src=\"FILEPATH/logo.png\" style=\"float: right;padding-right:10px;height:125px;width:250px\"/>')
});
</script>
However, when I save the HTML output and share the output, of course the user cannot see the logo since the code is trying to find a file path which will not exist on their computer.
So, my question is - is there a way to include the logo in the output without the use of file paths? Ideally I don't want to upload the image to the web, and change the source to a web address.
You can encode an image file to a data URI with knitr::image_uri. If you want to add it in your document, you can add the html code produced by the following command in your header instead of your script:
htmltools::img(src = knitr::image_uri("FILEPATH/logo.png"),
alt = 'logo',
style = 'float: right;padding-right:10px;height:125px;width:250px')
I am offering a pdf document in the form of a download from my website via a landing page.
I want to hide the URL/link that displays in the address bar and when i hover over the download button on the web page so that the link cant be shared.
What is the best way to do this? Please explain carefully.
Thanks
Ok, you cannot do that with plain HTML. You can use all kind of tricks but they can be a problem to the user experience, you are to use a server side language.
What you can do is create a php page, name it the way you want (let's say download.php), and link to that one. The page should be something like this:
// Path to the file
$path = '/home/folder/yourfile.pdf';
// This is based on file type of $path, but not always needed
$mm_type = "application/octet-stream";
//Set headers
header("Pragma: public");
header("Expires: 0");
header("Cache-Control: must-revalidate, post-check=0, pre-check=0");
header("Cache-Control: public");
header("Content-Description: File Transfer");
header("Content-Type: " . $mm_type);
header("Content-Length: " .(string)(filesize($path)) );
header('Content-Disposition: attachment; filename="'.basename($path).'"');
header("Content-Transfer-Encoding: binary\n");
// Outputs the content of the file
readfile($path);
exit();
This way you just link to your download.php page and it downloads/opens the PDF, like so:
Download
Edited based on BenjaminC suggestions
The other chance you have is to connect this to a database. The database has a table named downloads_table and inside you have 2 fields:
secret: char(32)
downloaded: int(1) dafault 0
Then you create an md5 string
$secret = md5(rand(1000, 9999999));
Place it inside the secret field, create the link:
Download
The user receives/sees a link, when pressed you are to edit the first line of the above code to check in the db if downloaded field = to 0 than procede to download, otherwise the person sees an error page.
This is so that it can be downloaded only once.
(Edit)
If in the future, this gets useful for anyone, the functionality can be seen in this fiddle: https://jsfiddle.net/aznjr87g/
It downloads 2.1.3 jquery.min.js from google.
(Edit end)
This can be achieved using Html5 's Download attribute.
Download PDF
If you hover your mouse over that, it simply shows yoursite.com/#
Place this somewhere in the body of the webpage:
And place this somewhere in the webpage:
<script>
function download() {
document.getElementById("download").src = "/path/to/download";
}
<script>
Then, on the element of the button (In the example of a div) do this in the tag:
<div onclick="download()"> </div>
However if it's a link you will want to do:
An element needs a href to work properly.
I put the user uploaded image files on separate disk partition on my local dev server(OS windows) which is outside of project folder. I need to access those image files in html pages of web app.
I tried out giving paths like: http://localhost:8080/C://tmp/thumbnails/pl_2001.JPEG but no help. Image is not fetched. How to properly access such files in html pages ?
You will have to use rewrites for this so you don't display sensitive folder names.
if you are using php you can use .htaccess rewrites for a slug something like images/someimage.mime and split/get what's after images/ and have a php function that takes the filename and makes sure it exists and if you want you can check if its a valid mime then send a header to say its a image/somemime so the browser can display the image instead of gibberish it will display without it.
$filename = "C://tmp/" . $file;
if(file_exists($filename)){
$img = getimagesize($filename);
if(in_array($img['mime'], array('jpg','jpeg','gif','png','etc'))){
header("Content-type: image/" . $img['mime']);
readfile($filename);
}else{
//default image
}
}else{
//default image
}
I haven't tested this but it should give you a idea on getting you started. If this isn't the language you are looking for try searching for something similar for your language you are using.
Is there a way to have a button/link and when you click on it, it will take the current page location and download an HTML version of it? It will be an iframe too, and the link should just download the iframe's content. Thanks!
The following JavaScript will take the current document and provide it as a download link. Tested in Chrome, not sure about others. Keep in mind that IE has limits for DataURI size. Furthermore, you'll lose your external images/CSS/etc, unless you inject the base tag into the top of the head tag (or find some other way to roll in resources):
// create the link to trigger download
// you could alternatively fetch an existing tag and update it
var a = document.createElement('a');
// send as type application/octet-stream to force download, not in browser
a.href =
"data:application/octet-stream;base64," +
btoa("<html>"+ document.getElementsByTagName('html')[0].outerHTML +
"</html>");
a.innerText = "Download this page";
// put the link wherever you want
document.body.appendChild(a);
EDIT: also doesn't provide a filename, or a .htm at the end of the download link... hmph. Those things can only really be provided by the Content-Disposition header, and that requires sending a request off to the server, so... not a fantastic user experience, but the easiest way to get the exact page state as the user sees it.
All you need is a simple script that takes the file name as a param and generates a zip. Here is an example in PHP.
Images are stored in the folder name upload in my website directory.
can anybody tell me how will i display it in another page name show.php
This question might be very basic level but I am very new to php.
Scan the directory for all image names and then output the image tag with the src set to the path for the image.
<img src="/upload/name-of-image-file-here" />
assuming the upload directory is web-accessible and whatnot. If not, then you'll need to do a script to handle the output of the image, of which there are plenty of sample questions/answers on this site.
You want to use PHP to scan the directory with the images in it and then generate HTML to show them.
You might want to look into the Directory Iterator object. You can use that to loop through the images and then generate the HTML as needed.
For getting files, you might want to use the following code (based on this PHP Documentation sample):
<?php
$iterator = new DirectoryIterator(dirname(__FILE__));
foreach ($iterator as $fileinfo) {
if ($fileinfo->isFile()) {
//Add filetype check here and then echo the HTML
echo $fileinfo->getFilename();
}
}
?>