Getting the closest time in a PDO statement - mysql

I am working from 2 databases and I need to find records which matches the closest times. Both fields are datetime().
So in essence:
table1.time = 2012-06-07 15:30:00
table2.time = 2012-06-07 15:30:01
table2.time = 2012-06-07 15:30:02
table2.time = 2012-06-07 15:30:03
NOTE: The table I am querying (table2) is a mssql table, and table1.time is a datetime() time. I need to find in table2 the row which closest matches table1.time, but I have no guarnatee that it would be an exact match, so I need the closest. I only need to return 1 result.
I tried the SQL below based on an example from a previous stackoverflow query but it failed to work.
Table1 is a mysql database where table2 is mssql and the query happens on table2 (mssql)
try {
$sql = "
SELECT
PCO_AGENT.NAME,
PCO_INBOUNDLOG.LOGIN AS LOGINID,
PCO_INBOUNDLOG.PHONE AS CALLERID,
PCO_INBOUNDLOG.STATION AS EXTEN,
PCO_INBOUNDLOG.TALKTIME AS CALLLENGTH,
PCO_INBOUNDLOG.CHANNELRECORDID AS RECORDINGID,
PCO_SOFTPHONECALLLOG.RDATE,
PCO_INBOUNDLOG.RDATE AS INBOUNDDATE
FROM
PCO_INBOUNDLOG
INNER JOIN
PCO_LOGINAGENT ON PCO_INBOUNDLOG.LOGIN = PCO_LOGINAGENT.LOGIN
INNER JOIN
PCO_SOFTPHONECALLLOG ON PCO_INBOUNDLOG.ID = PCO_SOFTPHONECALLLOG.CONTACTID
INNER JOIN
PCO_AGENT ON PCO_LOGINAGENT.AGENTID = PCO_AGENT.ID
WHERE
PCO_INBOUNDLOG.STATION = :extension
AND ABS(DATEDIFF(:start,PCO_SOFTPHONECALLLOG.RDATE))
";
$arr = array(":extension" => $array['extension'], ":start" => $array['start']);
$query = $this->mssql->prepare($sql);
$query->execute($arr);
$row = $query->fetchAll(PDO::FETCH_ASSOC);
$this->pre($row);
}
I am getting the following error at the moment:
SQLSTATE[HY000]: General error: 174 General SQL Server error: Check messages from the SQL Server [174] (severity 15) [(null)]SQLSTATE[HY000]: General error: 174 General SQL Server error: Check messages from the SQL Server [174] (severity 15) [(null)]

Found a shorter version:
SELECT * FROM `table` WHERE `date` < '$var' ORDER BY date LIMIT 1;

Related

A Database Error Occurred (SQL_BIG_SELECTS=1 or SET MAX_JOIN_SIZE=# if the SELECT is okay)

This database has worked fine for two years, now it's getting the following error? Can someone explain this issue and suggest a way to resolve this?
Error Number: 1104
The SELECT would examine more than MAX_JOIN_SIZE rows; check your WHERE and use SET SQL_BIG_SELECTS=1 or SET MAX_JOIN_SIZE=# if the SELECT is okay
Code:
select
salary_tb.*, order_tb.order_no,
daily_target_tb.customer as customer_name,
jobs_tb.job as job_name
from
salary_tb
left join
order_tb on salary_tb.order_id = order_tb.id
left join
daily_target_tb on order_tb.id = daily_target_tb.order_id
left join
jobs_tb on salary_tb.job_id = jobs_tb.id
where
salary_tb.id > 0
and salary_tb.isDeleted = 0
and salary_tb.employee_id = '1'
group by
salary_tb.id
Filename: models/SalaryModel.php
Line Number: 22
The issue is your query is either returning huge number of rows which is more than value set for MAX_JOIN_SIZE configuration or your SQL_BIG_SELECTS is set to 0 which will not allow you to run queries which take too long to return a result. You can do one/all of the following 3 things :
1.SET SQL_BIG_SELECTS=1;
2.MAX_JOIN_SIZE= (More than the no of rows returned by the join statement)
Refine your query so that it returns appropriate values within the set parameters and in less time.(Using Indexing, Returning less no. of rows).
Current Query
function get_rows($where)
{
$sql =
"select salary_tb.*, order_tb.order_no, daily_target_tb.customer as customer_name, jobs_tb.job as job_name
from salary_tb
left join order_tb on salary_tb.order_id = order_tb.id
left join daily_target_tb on order_tb.id = daily_target_tb.order_id
left join jobs_tb on salary_tb.job_id = jobs_tb.id
where salary_tb.id > 0";
if($where != ""){
$sql .= $where;
}
$query =# $this->db->query('SET SQL_BIG_SELECTS=1');
$this->db->query($sql);
return $query->result_array();
}

Correct syntax to use in mysql 5.5.25 for not exists

Hi I'm trying to write a cursor in powerbuilder 12 to fetch some records . Here this is my query.
I'm trying to fetch some records from the trninvhdr table which are not in the second table.
SELECT
INV_DATE,
INV_NO,
INV_TYPE,
CUR_CODE,
EXCH_RATE,
usd_rate,
CR_TERM,
DUE_DATE,
bl_date,
TOT_AMT
FROM trninvhdr
WHERE
COMP_CODE ='NFL1' AND
CUST_CODE = 'NLML' AND
INV_TYPE ='F' AND
INV_DATE <= '2016-03-25' AND
NOT EXISTS
(SELECT * FROM trninvoiceavailability WHERE trninvoiceavailability.COMP_CODE = trninvhdr.COMP_CODE
AND trninvoiceavailability.INV_TYPE = trninvhdr.INV_TYPE AND trninvoiceavailability.INV_NO = trninvhdr.INV_NO);
Here how I use it in the program.
DECLARE lc_retrieve CURSOR FOR
SELECT
trninvhdr.INV_DATE,
trninvhdr.INV_NO,
trninvhdr.INV_TYPE,
trninvhdr.CUR_CODE,
trninvhdr.EXCH_RATE,
trninvhdr.usd_rate,
trninvhdr.CR_TERM,
trninvhdr.DUE_DATE,
trninvhdr.bl_date,
trninvhdr.TOT_AMT
FROM trninvhdr
WHERE
COMP_CODE = :as_comp_code AND
CUST_CODE = :as_cust_code AND
INV_TYPE ='F' AND
INV_DATE <= :as_inv_date )AND
NOT EXISTS (SELECT * FROM trninvoiceavailability
WHERE trninvoiceavailability.COMP_CODE = trninvhdr.COMP_CODE
AND trninvoiceavailability.INV_TYPE = trninvhdr.INV_TYPE AND
trninvoiceavailability.INV_NO = trninvhdr.INV_NO);
open lc_retrieve ;
The query works fine in the mysql server but in the progra it gives me the following error .
Database c0038 SQLSTATE = 3700 MySQL ODBC 5.2 a Driver mysql id 5.5.25 You have an error in your syntax. check the manual that corresponds to your mysql version for the right syntax to use near NOT EXISTS (SELECT * FROM trninvoiceavailability.... at line 1.
What is the correct Syntax that I should use to work this query.
I can see a bracket in this code... where did it come from and where is it's friend?
INV_DATE <= :as_inv_date )AND
You need to remove ) from your query as per below-
INV_DATE <= :as_inv_date )AND
sholuld be INV_DATE <= :as_inv_date AND

Mysqli query inner join error

Whats wrong with this query
$yourfriendsbud = mysqli_query($con, "SELECT avatar,firstname,lastname,id
FROM people
INNER JOIN friends
ON
people.id=friends.zatrazio_id
WHERE status=0 AND dobio_id='$user_id' LIMIT 50");
while($row = mysqli_fetch_array($yourfriendsbud))
It reports the error:
Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in /home/u573639388/public_html/menu.php on line 64
line 64 is
while($row = mysqli_fetch_array($yourfriendsbud))
That means you have an id column in both tables. You have to be more specific in the SELECT, using SELECT people.id, avatar, firstname...

SQL error #1064 when nesting a SELECT MAX in a LEFT JOIN

Please let me know why I get an error on the following SQL (I am using a MySQL database) and how to rectify it:
SELECT at_award_description.ad_id,
at_award_description.ad_detail,
at_award_description.ad_archived_date,
a.cad_id,
a.cad_task_completion_date
FROM at_award_description
LEFT JOIN at_cub_award_date AS a ON ((at_award_description.ad_id = a.ad_id)
AND (a.ca_id = 37)
AND a.cad_task_completion_date = (SELECT MAX(b.cad_task_completion_date)
FROM at_cub_award_date AS b
WHERE a.ca_id = b.ca_id AND a.ad_id = b.ad_id
)
)
WHERE at_award_description.aw_id = 5
ORDER BY at_award_description.ad_order;
I broke the SQL down to ensure each part worked.
SELECT MAX(b.cad_task_completion_date)
FROM at_cub_award_date AS b
And
SELECT at_award_description.ad_id,
at_award_description.ad_detail,
at_award_description.ad_archived_date,
a.cad_id,
a.cad_task_completion_date
FROM at_award_description
LEFT JOIN at_cub_award_date AS a ON ((at_award_description.ad_id = a.ad_id)
AND (a.ca_id = 37)
)
WHERE at_award_description.aw_id = 5
ORDER BY at_award_description.ad_order;
Each of these work on their own. When I combine them I get the following error:
Error
SQL query:
LIMIT 0, 25
MySQL said:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'LIMIT 0, 25' at line 1
Regards,
Glyn
EDIT
#Barmar came up with the solution to remove the ";" at the end when testing. However, the result was not what I expected so I ended up changing this to:
SELECT at_award_description.ad_id,
at_award_description.aw_id,
at_award_description.ad_group,
at_award_description.ad_detail,
at_award_description.ad_start_date,
at_award_description.ad_archived_date,
MAX(at_cub_award_date.cad_task_completion_date)
FROM at_award_description
LEFT JOIN at_cub_award_date ON ((at_award_description.ad_id = at_cub_award_date.ad_id)
AND (at_cub_award_date.ca_id = 37))
WHERE at_award_description.aw_id = 5
GROUP BY at_award_description.ad_group
ORDER BY at_award_description.ad_order, at_award_description.ad_group

arel union and latest conversation from messages

I need a list of messages where each one is the most recent in the "conversation" between the current user and each other user.
The same query is described in this question
The code I have so far is:
t1 = Arel::Table.new(:messages, :as => 't1')
t2 = Arel::Table.new(:messages, :as => 't2')
convs1 = t1.
project(
t1[:receiver_user_id].as('other_user_id'),
t1[:receiver_user_id].as('receiver_user_id'),
t1[:sender_user_id].as('sender_user_id'),
t1[:created_at].as('created_at')
).
where(t1[:sender_user_id].eq(user.id))
convs2 = t2.project(
t2[:sender_user_id].as('other_user_id'),
t2[:receiver_user_id].as('receiver_user_id'),
t2[:sender_user_id].as('sender_user_id'),
t2[:created_at].as('created_at')
).
where(t2[:receiver_user_id].eq(user.id))
conv = convs1.union(convs2)
First off, I get an error:
ActiveRecord::StatementInvalid: Mysql2::Error: You have an error in your SQL syntax; check \
the manual that corresponds to your MySQL server version for the right syntax to use near \
'UNION SELECT `t2`...
This works if I manually replace "UNION" with "UNION ALL" in the sql produced below.
conv.to_sql from the above code produces:
SELECT `t1`.`receiver_user_id` AS other_user_id,
`t1`.`receiver_user_id` AS receiver_user_id, `
t1`.`sender_user_id` AS sender_user_id,
`t1`.`created_at` AS created_at
FROM `messages` `t1`
WHERE `t1`.`sender_user_id` = 50
UNION
SELECT `t2`.`sender_user_id` AS other_user_id,
`t2`.`receiver_user_id` AS receiver_user_id,
`t2`.`sender_user_id` AS sender_user_id,
`t2`.`created_at` AS created_at
FROM `messages` `t2`
WHERE `t2`.`receiver_user_id` = 50
Any idea why there's a MySQL UNION error. Is it an arel bug?
Secondly, any help with completing the query would be much appreciated.
Update:
Using Arel::Nodes::Union.new works
I think this is more probably a mysql fault, this is a mySQL error text. Something similar is discussed in here, but not exactly this issue.
Try to migrate to another sql server, and check again, or if union all works then use this:
conv = convs1.union(convs2, :all)
Based on documentation.
The problem is actually the parentheses in the sql. It works if I run:
Message.find_by_sql conv.to_sql.delete('()')
which removes the leading "(" and trailing ")"
Weird.. I don't know how I would chain this to complete the query. (Arel::Nodes::Union doesn't have a group method). This is Rails 3.1.4
I had a similar problem and solved it as follows:
def last_messages
Message.find_by_sql("
SELECT messages.*,
(IF(recipient_id = #{id}, 0,1)) as outlast,
users.avatar_name,
users.name
FROM messages
INNER JOIN users
ON users.id=(IF(recipient_id = #{id}, sender_id,recipient_id))
WHERE messages.id IN
( SELECT max(id)
FROM messages
WHERE recipient_id = #{id} OR sender_id = #{id}
GROUP BY (IF(recipient_id = #{id}, sender_id, recipient_id))
)
ORDER BY messages.id DESC")
end
This is the code I used instead in the end
all_msgs = Message.where("messages.sender_user_id = ? OR messages.receiver_user_id = ?",
user.id, user.id)
msg_ids = all_msgs.select("sender_user_id, receiver_user_id, max(id) as max_id")
.group(:sender_user_id, :receiver_user_id).map { |m| m.max_id }
all_msgs = all_msgs.where(:id => msg_ids)