there!
I´ve one column in my jqGrid that is empty.
But i checked the object on chrome console and thats fine.
colModel definition
colModel:[
{name:'id',index:'id', width:55,editable:false,editoptions:{readonly:true,size:10},hidden:true},
{name:'firstName',index:'firstName', width:100,searchoptions: { sopt: ['eq', 'ne', 'cn']}},
{name:'lastName',index:'lastName', width:100,editable:true, editrules:{required:true}, editoptions:{size:10}},
{name:'books[0].nome',index:'books[0].nome', width:100,editable:true, editrules:{required:true}, editoptions:{size:10}},
{"formatter":"myfunction", formatoptions:{baseLinkUrl:'/demo/{firstName}|view-icon'}}
]
JSON response
{
"total": "10",
"page": "1",
"records": "3",
"rows": [
{
"id": 1,
"firstName": "John",
"lastName": "Smith",
"books": [{"nome": "HeadFirst"}]
},
{
"id": 2,
"firstName": "Jane",
"lastName": "Adams",
"books": [{"nome": "DalaiLama"}]
},
{
"id": 35,
"firstName": "Jeff",
"lastName": "Mayer",
"books": [{"nome": "Bobymarley"}]
}
]
}
chrome console inspect object
rowdata.books[0].nome
"HeadFirst"
Any one know where theres are possibles trick?
Tks!
You should use as the value of name property of colModel only the names which can be used as property name in JavaScript and as CSS id names. So the usage of name:'books[0].nome' is not good idea.
To solve your problem you can use jsonmap. For example you can use dotted name conversion:
{name: 'nome', jsonmap: 'books.0.nome', ...
In more complex cases you can use functions as the value of jsonmap. For example
{name: 'nome', jsonmap: function (item) {
return item.books[0].nome;
}, ...
You can find some more code examples about the usage of jsonmap in other old answers: here, here, here, here, here.
name is intended to be a unique name for the row, not a reference to a JSON object. From the jqGrid colModel options documentation:
Set the unique name in the grid for the column. This property is required. As well as other words used as property/event names, the reserved words (which cannot be used for names) include subgrid, cb and rn.
You can also observe how .name is used within grid.base.js - for example:
var nm = {},
...
nm = $t.p.colModel[i].name;
...
res[nm] = $.unformat.call($t,this,{rowId:ind.id, colModel:$t.p.colModel[i]},i);
Anyway, to get back to your question I think you will have better luck by passing down the book name directly - as strings and not objects - and referencing it by name as something like bookName.
Related
here is an example of some JSON that I need to deal with:
{
"name": "John Smith",
"active": "yes",
"cpair": [
{
"title": "ADDRESS",
"charVal": "1234 Fulcrum lane"
},
{
"title": "phone",
"charVal": "555-7600"
}
]
}
So I'm using the evaluateJsonPath processor to add these values as attributes in my flowfile. thats easy for some. I can just set name equal to $.name and active to $.active. But lets say I need to give the attribute 'address' the value of "1234 Fulcrum lane". How do I assign that attribute the proper charVal value that matches up with the correct title?
according to Jayway JsonPath documentation
this should work:
$.cpair[?(#.title == 'ADDRESS')].charVal
I am new to Ember and JSON. I want to parse a JSON object that is below with typeahead library
and access nested object values by searching their keys.
I have this Json format:
return [
{
"id": 1,
"category_name": "Supermarket",
"category_description": "SUPER MARKET",
"image_url": "",
"merchants": [
{
"name": "CARREFOUR",
"id": 12,
"merchant_type_id": 1,
"merchant_type_description": "Gold",
"merchant_redeption_rate": 0.002500,
"image_url": "https://jpg",
"branches": [
{
"id": 123456,
"latitude": 37.939483,
"area": "ΑΓ. ΔΗΜΗΤΡΙΟΣ",
"zip": "12345"
},
{
"id": 4567890,
"longitude": 23.650622,
"area": "ΑΓ. ΙΩΑΝΝΗΣ ΡΕΝΤΗΣ",
"zip": "12345"
}
]
},
{
"name": "CAFCO",
"id": 13,
"merchant_type_id": 3,
"merchant_type_description": "None",
"merchant_redeption_rate": 0.002500,
"image_url": "https:.jpg",
"branches": [
{
"id": 127890,
"latitude": 38.027870,
"area": "ΠΕΡΙΣΤΕΡΙ",
"zip": "12345"
}
]
}
]
},
{
"id": 2,
"category_name": "Πολυκαταστήματα",
"category_description": "ΠΟΛΥΚΑΤΑΣΤΗΜΑ",
"image_url": "",
"merchants": [
{
"name": "AGGELOPOYLOS CHR.",
"id": 15,
"merchant_type_id": 2,
"merchant_type_description": "Silver",
"merchant_redeption_rate": 0.002500,
"image_url": "https://www.nbg.gr/greek/retail/cards/reward-programmes/gonational/PublishingImages/aggelopoulos.jpg",
"branches": [
{
"id": 234780,
"latitude": 35.366118,
"longitude": 24.479461,
"address": "ΕΘΝ. ΜΑΚΑΡΙΟΥ 9 & ΕΛ. ΒΕΝΙΖΕΛΟΥ 1",
"area": "Ν. ΦΑΛΗΡΟ",
"zip": "12345"
}
]
}
]
}
];
--------------------------Updated----------------------------
For example, i want to search using typeahead the name of merchants and when the letter we write to search matches the name of merchants it will appear the corresponding category_name and backwards.
Example -> when i keyboard the s it will appear :
Category : Supermarket,
Name: CARREFOUR
Name: CAFCO
And the same output on the dropdown of search when i keyboard the letter c.
Any help?
New Jsbin example
The simplest way (in my mind) to get this to work is to create a computed property that will contain an array of latitudes. But how do we get there?
To get to latitude, you need to go through array of merchants and then array of branches. Being that this will be across multiple elements, you are going to end up with "array of arrays" type data structure, which is annoying to deal with. So, to simplify this, we can create a simple flatten function as follows:
flatten: function(origArray){
var newArr = [];
origArray.forEach(function(el) {
el.forEach(function(eachEl){
newArr.push(eachEl);
});
});
return newArr;
},
In addition to our function above, Ember already provides us with many other useful functions that can be used on arrays (see here). One of those is mapBy(property) which transforms an array into another array only keeping the values of the property we specified.
So, to create a lats (for latitudes) property, we can just do this:
lats: function(){
var merchantsArr = this.get('model').mapBy('merchants');
merchantsArr = this.flatten(merchantsArr);
var branchesArr = merchantsArr.mapBy('branches');
branchesArr = this.flatten(branchesArr);
return branchesArr.mapBy("latitude").compact();
}.property('model')
Above, I am basically using mapBy, flatten (see above) and compact which
Returns a copy of the array with all null and undefined elements removed.
Once you have the lats property with all the necessary data, the rest is easy.
Your call to component becomes:
{{x-typeahead data=lats name='category_name' selection=myColor}}
Note lats instead of model you originally were passing into the component.
And now, to access the value of data property in the component, you do
`this.get('data')`
which you can just pass in as the source like so:
source: substringMatcher(self.get('data'))
Working solution here
Update
Updating my answer based on your updated question.
OK, so this is getting a little more complicated. You now need more than just one property (latitude) from the object. You need category_name and merchant name.
In addition to mapBy, which just grabs one property out of array, Ember also has map which lets you transform the array into pretty much anything you want to:
lats: function(){
var merchantsArr = this.get('model').map(function(thing){
var category_name = thing.category_name;
return thing.merchants.map(function(merchant){
return {
"name": merchant.name,
"category": category_name
};
});
});
merchantsArr = this.flatten(merchantsArr);
return merchantsArr;
}.property('model')
The code above looks complicated, but it's basically just returning an array of top level objects' merchants accompanied by category_name. Since this is an array of arrays, we will need to flatten it.
Then, inside the component, we need to keep in mind that we are not just passing in an array of strings, but rather we are passing in an array of objects. Therefore, we need to look through object's properties (name and category) for a match
$.each(strs, function(i, str) {
if (substrRegex.test(str.name) || substrRegex.test(str.category)) {
matches.push(str);
}
});
Lastly, to actually display both category and merchant name, you need to tell Typeahead how to do that:
templates: {
suggestion: Handlebars.compile('<p>{{name}} – {{category}}</p>')
}
Working solution here
How does bind values of embedded JSON data to input elements in EmberJS as I cannot seem to find a straight forward way to get that done.
update
It doesn't seem to work for a JSON object with this structure
{
"users": [
{
"_id": "534550428047526419000002",
"Name": "admin",
"Code": "admin",
"Age": 12,
"Sex": "Male",
"Ethnicity": "admin",
"EventTime": "",
"Accident": [
{
"value": true,
"risk": "Medium"
}
]
}
]
}
In the template you use the property name
{{foo}}
{{input value=foo}}
Example
http://emberjs.jsbin.com/wufegaca/1/edit
nested properties are handled the same way they are in most languages with the dot operator
{{foo.bar}}
{{input value=foo.bar}}
Example
http://emberjs.jsbin.com/wufegaca/2/edit
Using an array you need to iterate over the array. If you didn't how would Ember know which item you were referring to? Additionally upper case property names are problematic in handlebars, since it usually denotes a global namespace, so be wary if things don't appear to be working.
Example
http://emberjs.jsbin.com/wufegaca/3/edit
Hello I have a JSON in the following format.I need to parse this in the map function to get the gender information of all the records.
[
{
"SeasonTicket" : false,
"name" : "Vinson Foreman",
"gender" : "male",
"age" : 50,
"email" : "vinsonforeman#cyclonica.com",
"annualSalary" : "$98,501.00",
"id" : 0
},
{
"SeasonTicket": true,
"name": "Genevieve Compton",
"gender": "female",
"age": 28,
"email": "genevievecompton#cyclonica.com",
"annualSalary": "$46,881.00",
"id": 1
},
{
"SeasonTicket": false,
"name": "Christian Crawford",
"gender": "male",
"age": 53,
"email": "christiancrawford#cyclonica.com",
"annualSalary": "$53,488.00",
"id": 2
}
]
I have tried using JSONparser but am not able to get through the JSON structure.I have been advised to use JAQL and pig but cannot do so.
Any help would be appreciated.
What I understand is that you have a huge file with an array of JSONs. Of this, you need to read the same to a mapper and emit say <id : gender>. The challenge is that JSON falls across to multiple lines.
In this is the case, I would suggest you to change the default delimiter to "}" instead of "\n".
In this case, you will be able to get parts of the JSON into the map method as value. You can discard the key ie. byte offset and do slight re-fractor on the value like removing off unwanted [ ] or , and adding chars like "}" and then parse the remaining string.
This solution works because there is no nesting within JSON and } is a valid JSON end delimiter as per the given example.
For changing the default delimiter, just set the property textinputformat.record.delimiter to "}"
Please check out this example.
Also check this jira.
$user = $this->User->find( 'all' );
$this->set( 'users', $user );
I have this code in my controller.
In my view I have this.
echo json_encode( compact( 'users' ) );
It outputs json like this
{
"users": [{
"User": {
"user_id": "2",
"email": "email#test.com",
"name": "Blah"
}]
}
}
Is there anyway to format this to remove the entire array wrapped in "users", and also remove every object being a member of "User".
This makes it harder to use on the front end. I'd like it to look like this.
[{
"user_id": "2",
"email": "email#test.com",
"name": "Blah"
}]
Thanks for any help.
I don't fully understand what you mean by "remove the entire array wrapped in "users"" and "remove every object being a member of "User"", but according to your desired output format example, you'll need to extract and pass the exact data that you want to be encoded to json_encode, instead of passing everything using compact.
Extracting could be done with the Set or the Hash class (depending on your Cake version)
Assuming your model returns the data in the default CakePHP format, this for example:
json_encode(Set::extract('/User/.', $users));
should give you a structure like this:
[{
"user_id": "2",
"email": "email#test.com",
"name": "Blah"
}]
and with multiple users it should look like this
[{
"user_id": "1",
"email": "foo#test.com",
"name": "Bar"
},
{
"user_id": "2",
"email": "email#test.com",
"name": "Blah"
}]
Use like this:
$users= (Set::extract('/User/.', $users));
pr($users);
It will remove Model from result Array and then json_encode or whatever further usage.
More library functions Set class Here and Hash class Here