Drupal Tableselects - mysql

Question

I can (finally!!!) set a query to return results for a checkbox(es) set within a collapsible fieldset in Drupal 7- however when I try to put it into a tableselect, I get no results. Would someone be able to check out this code and see if you can tell me why? I also have a screen shot of both results- but since I am new here it won't allow me to post it.
$form = array();
$secnum = 1;
$result = db_query('SELECT s.secser_id, s.ser_name FROM {secser} s WHERE s.sec_num = :secnum', array(':secnum' => $secnum));
$options = array();
foreach ($result as $record) {
$options[$record->secser_id] = $record->ser_name;
}
$form['secser']['1'] = array(
'#title' => t('Basic Sanitation'),
'#type' => 'fieldset',
'#collapsible' => TRUE,
);
$form['secser']['1']['secser'] = array(
'#title' => t('Choices'),
'#type' => 'checkboxes',
'#multiple' => TRUE,
'#options' => $options,
'#description' => t('choose!'),
);
$form['secser']['2'] = array(
'#title' => t('Community Systems'),
'#type' => 'fieldset',
'#collapsible' => TRUE,
);
$secnum = 2;
$result = db_query('SELECT s.secser_id, s.ser_name FROM {secser} s WHERE s.sec_num = :secnum', array(':secnum' => $secnum));
$opt2 = array();
foreach ($result as $record) {
$opt2[$record->secser_id] = $record->ser_name;
}
$header = array(
'ser_name' => t('Choose Service(s)'),
);
$form['secser']['2']['secser'] = array(
'#type' => 'tableselect',
'#title' => t('Community Systems'),
'#header' => $header,
'#options' => array($opt2),
'#multiple' => TRUE,
);

Answer 1

I haven't tried running your code, but it looks like your options are an array which contains another array.
#options' => array($opt2),
because $opt2 is an array, this should be:
#options' => $opt2,
the same way you have the options set up in your checkboxes