MS ACCESS- Editing and undoing SQL causes error - ms-access

Question

I have a query (equivalent of View in ORACLE, SQL Server) that I saved in an Access database. Now I need to add another column to my select list. But whenever I change the SQL I get errors. Let's say I remove one comma and then put it back. I get errors like "Syntax error after From","Syntax error in Join operation". So if I change anything and then undo the change I still get errors. How can I avoid this?
Edit:Before editing
SELECT A_B.ALICI, Q.QAINOM, M.TIP, Q.QATARIX, Q.CEMIBORC, R2.ADI AS SAT_NOV, M.TAMADI, M.MARK, SA.MIQDAR, SA.SAQIYM, SA.CEMI, SA.FAIZ, A_B.BORC_SU, A_B.MEBLEG, A_B.FERQ, K_G.CEMI_ODEN, A_B.MOBTEL, SA.NOTE
FROM ([SELECT Round(Sum([DBKASSA].[MEBLEQ]),3) AS CEMI_ODEN, DBKASSA.KODAL_GT
FROM DBKASSA
WHERE (((DBKASSA.TIP)=1) AND ((DBKASSA.KODAL_GT)=[INBUYERID]) AND ((DBKASSA.TARIX)=[INTILLDATE]))
GROUP BY DBKASSA.KODAL_GT]. AS K_G RIGHT JOIN ([SELECT AL.KODALAN,AL.MOBTEL, IIf([Su_CEMIBORC] Is Null,0,[Su_CEMIBORC]) AS BORC_SU, IIf([Su_MEBLEQ] Is Null,0,[Su_MEBLEQ]) AS MEBLEG, (IIf([Su_MEBLEQ] Is Null,0,[Su_MEBLEQ]))-(IIf([Su_CEMIBORC] Is Null,0,[Su_CEMIBORC])) AS FERQ, AL!OBYEKT & (IIf(AL!NUMAY Is Not Null," - " & AL!NUMAY)) AS ALICI
FROM
(
SELECT DBKASSA.KODAL_GT, Sum(DBKASSA.MEBLEQ) AS Su_MEBLEQ
FROM DBKASSA
WHERE (((DBKASSA.TIP)=1) AND ((DBKASSA.KODAL_GT)=[INBUYERID]))
GROUP BY DBKASSA.KODAL_GT
) AS OD_AL
RIGHT JOIN (
(
SELECT DBQAIME.KODALAN, Sum(DBQAIME.CEMIBORC) AS Su_CEMIBORC
FROM DBQAIME
WHERE (((DBQAIME.KODALAN)=[INBUYERID]))
GROUP BY DBQAIME.KODALAN
) AS B_AL
RIGHT JOIN DBALAN AS AL ON B_AL.KODALAN = AL.KODALAN) ON OD_AL.KODAL_GT = AL.KODALAN
WHERE (((AL.KODALAN)=[INBUYERID]))
]. AS A_B INNER JOIN DBQAIME AS Q ON A_B.KODALAN = Q.KODALAN) ON K_G.KODAL_GT = A_B.KODALAN) INNER JOIN (DBMAL AS M INNER JOIN (DBSA AS SA INNER JOIN [SELECT R2.KOD, R2.VID, R2.ADI
FROM DBRAB2 AS R2
WHERE (((R2.VID)=3))]. AS R2 ON SA.KODEMLNO = R2.KOD) ON M.KODMAL = SA.KODMAL) ON Q.QAINOM = SA.QAINOM
WHERE (((Q.QAINOM)=[INSALEINVOICE]))
ORDER BY M.TIP, M.TAMADI;
After editing;
SELECT A_B.ALICI, Q.QAINOM, M.TIP, Q.QATARIX, Q.CEMIBORC, R2.ADI AS SAT_NOV, M.TAMADI, M.MARK, SA.MIQDAR, SA.SAQIYM, SA.CEMI, SA.FAIZ, A_B.BORC_SU, A_B.MEBLEG, A_B.FERQ, K_G.CEMI_ODEN, A_B.MOBTEL, SA.NOTE
FROM ([SELECT Round(Sum([DBKASSA].[MEBLEQ]),3) AS CEMI_ODEN, DBKASSA.KODAL_GT
FROM DBKASSA
WHERE (((DBKASSA.TIP)=1) AND ((DBKASSA.KODAL_GT)=[INBUYERID]) AND ((DBKASSA.TARIX)=[INTILLDATE]))
GROUP BY DBKASSA.KODAL_GT]. AS K_G RIGHT JOIN ([SELECT AL.KODALAN,AL.MOBTEL, IIf([Su_CEMIBORC] Is Null,0,[Su_CEMIBORC]) AS BORC_SU, IIf([Su_MEBLEQ] Is Null,0,[Su_MEBLEQ]) AS MEBLEG, (IIf([Su_MEBLEQ] Is Null,0,[Su_MEBLEQ]))-(IIf([Su_CEMIBORC] Is Null,0,[Su_CEMIBORC])) AS FERQ, AL!OBYEKT & (IIf(AL!NUMAY Is Not Null," - " & AL!NUMAY)) AS ALICI
FROM
(
SELECT DBKASSA.KODAL_GT, Sum(DBKASSA.MEBLEQ) AS Su_MEBLEQ
FROM DBKASSA
WHERE (((DBKASSA.TIP)=1) AND ((DBKASSA.KODAL_GT)=[INBUYERID]))
GROUP BY DBKASSA.KODAL_GT
) AS OD_AL
RIGHT JOIN (
(
SELECT DBQAIME.KODALAN, Sum(DBQAIME.CEMIBORC) AS Su_CEMIBORC
FROM DBQAIME
WHERE (((DBQAIME.KODALAN)=[INBUYERID]))
GROUP BY DBQAIME.KODALAN
) AS B_AL
RIGHT JOIN DBALAN AS AL ON B_AL.KODALAN = AL.KODALAN) ON OD_AL.KODAL_GT = AL.KODALAN
WHERE (((AL.KODALAN)=[INBUYERID]))
]. AS A_B INNER JOIN DBQAIME AS Q ON A_B.KODALAN = Q.KODALAN) ON K_G.KODAL_GT = A_B.KODALAN) INNER JOIN (DBMAL AS M INNER JOIN (DBSA AS SA INNER JOIN [SELECT R2.KOD, R2.VID, R2.ADI
FROM DBRAB2 AS R2
WHERE (((R2.VID)=3))]. AS R2 ON SA.KODEMLNO = R2.KOD) ON M.KODMAL = SA.KODMAL) ON Q.QAINOM = SA.QAINOM
WHERE (((Q.QAINOM)=[INSALEINVOICE]))
ORDER BY M.TIP, M.TAMADI;
By the way, it worked in MS Access 2010. Mine is Access 2003

Answer 1

What has happened is that your subquery or derived table is now bracketed like so
[stuff here].
This causes an error when editing.
The easiest thing to do is use notepad or such like, replace []. with () and paste back.
Try:
SELECT A_B.ALICI,
Q.QAINOM,
M.TIP,
Q.QATARIX,
Q.CEMIBORC,
R2.ADI AS SAT_NOV,
M.TAMADI,
M.MARK,
SA.MIQDAR,
SA.SAQIYM,
SA.CEMI,
SA.FAIZ,
A_B.BORC_SU,
A_B.MEBLEG,
A_B.FERQ,
K_G.CEMI_ODEN,
A_B.MOBTEL,
SA.NOTE
FROM ((SELECT Round(SUM([DBKASSA].[MEBLEQ]), 3) AS CEMI_ODEN,
DBKASSA.KODAL_GT
FROM DBKASSA
WHERE ( ( ( DBKASSA.TIP ) = 1 )
AND ( ( DBKASSA.KODAL_GT ) = [INBUYERID] )
AND ( ( DBKASSA.TARIX ) = [INTILLDATE] ) )
GROUP BY DBKASSA.KODAL_GT) AS K_G
RIGHT JOIN ((SELECT AL.KODALAN,
AL.MOBTEL,
Iif([Su_CEMIBORC] IS NULL, 0, [Su_CEMIBORC])
AS
BORC_SU,
Iif([Su_MEBLEQ] IS NULL, 0, [Su_MEBLEQ])
AS
MEBLEG,
( Iif([Su_MEBLEQ] IS NULL, 0, [Su_MEBLEQ]) ) - (
Iif([Su_CEMIBORC] IS NULL, 0, [Su_CEMIBORC]) )
AS
FERQ,
AL ! OBYEKT & ( Iif(AL ! NUMAY IS NOT NULL,
" - " & AL ! NUMAY) ) AS
ALICI
FROM (SELECT DBKASSA.KODAL_GT,
SUM(DBKASSA.MEBLEQ) AS Su_MEBLEQ
FROM DBKASSA
WHERE
( ( ( DBKASSA.TIP ) = 1 )
AND ( ( DBKASSA.KODAL_GT ) = [INBUYERID] ) )
GROUP BY DBKASSA.KODAL_GT) AS OD_AL
RIGHT JOIN ( (SELECT DBQAIME.KODALAN,
SUM(DBQAIME.CEMIBORC) AS
Su_CEMIBORC
FROM DBQAIME
WHERE ((
( DBQAIME.KODALAN ) = [INBUYERID] ))
GROUP BY DBQAIME.KODALAN) AS B_AL
RIGHT JOIN DBALAN AS AL
ON B_AL.KODALAN = AL.KODALAN)
ON OD_AL.KODAL_GT = AL.KODALAN
WHERE (( ( AL.KODALAN ) = [INBUYERID] ))) AS A_B
INNER JOIN DBQAIME AS Q
ON A_B.KODALAN = Q.KODALAN)
ON K_G.KODAL_GT = A_B.KODALAN)
INNER JOIN (DBMAL AS M
INNER JOIN (DBSA AS SA
INNER JOIN (SELECT R2.KOD,
R2.VID,
R2.ADI
FROM DBRAB2 AS R2
WHERE (( ( R2.VID ) = 3 ))) AS R2
ON SA.KODEMLNO = R2.KOD)
ON M.KODMAL = SA.KODMAL)
ON Q.QAINOM = SA.QAINOM
WHERE (( ( Q.QAINOM ) = [INSALEINVOICE] ))
ORDER BY M.TIP,
M.TAMADI;