I am in a problem and i am confused. I have a table for events and in it there is a column that holds the timestamp of the date time when it was created. I want to get all events(rows) that were created in this month, the last month, and 2 more month before the last month. So, basically 4 months. I want to show them separately so, i can think i can query the datebase for all rows in this month in one query and another query for previous month and so on for 4 months. The problem is i don't know how can i do that. There is a month() function in mysql but i am lost, no idea how to use it.
Any help would be very much appreciated. Thanks
Edit: table structure is like this.
Title | Uri | created
Event | Event| 1337782223
name | uri |
.......
EDIT 2
Thanks all for your help..
I tried it myself and with my friend google...:)
I used this
SELECT * FROM `events` WHERE MONTH(FROM_UNIXTIME(created)) = $month;
and this seems to work for me, i will just pass the month whos rows i want from php thats easier for me...lol
Thanks again to all for your answers its appreciated. This place is awesome
Select * From your_table Group By Month(column_with_date);
Of couse you have to have a timestamp column in your table.
If not then it's impossible to restore the informations when the entry was inserted.
$month = '5,4,3,2';
select colum_name from table_name where month(table_field_name) IN ($thismonth) Group By month(table_field_name)
try this one if you are using separate query for each month
$todayDate = date("Y-m-d");
$thismonth = strtotime($todayDate);
$previous_month = mktime(0, 0, 0, date("m")-1, date("d"), date("Y"));
and you can get past months just do minus NUMBER ex -2,-3 .....for current month
select colum_name from table_name where month(table_field_name) = month ($thismonth) AND year(table_field_name) = year ($thismonth) Group By month(table_field_name);
for previous month
select colum_name from table_name where month(table_field_name) = month ($previous_month ) AND year(table_field_name) = year ($thismonth) Group By month(table_field_name)
Related
I am trying to retrieve last 3 months records. I need to sum order total amount by week. I have made following query.
select CONCAT("Week", WEEK(created_at)) as week_number, sum(total_cost)
from certified_diamond_orders
where created_at > 2016-11-22
and status = "delivered"
group by week("created_at")
But I am only getting one record with this. Infact my table has 2 years entries. Also I was trying to figure out how I can pull week start date and end date to diplay on my chart.
Any suggestions where I am making mistake?
week("created_at") looks like you're trying to determine the week of the string "created_at" rather than the column created_at. Which might explain why you're only getting one row in your result.
The date 2016-11-22 also looks suspiciously like a sum instead of a date (2016 - 11 - 22 = 1983 vs "2016-11-22"
Try this:
SELECT
CONCAT('Week', WEEK(created_at)) AS week_number,
SUM(total_cost)
FROM certified_diamond_orders
WHERE
created_at > '2016-11-22' AND
status = 'delivered'
GROUP BY WEEK(created_at)
There is table called payment and timestamp is column which has data like 1462399200.I want to extract records of specific month from this database table. For example I want all records of May month.Here is the code I am using, but it isn't yielding me any result.
$sql="SELECT * FROM payment WHERE monthname(timestamp)=5";
$result=mysqli_query($db,$sql);
$counta=mysqli_num_rows($result);
You could use this
SELECT *
FROM payment
WHERE MONTH(FROM_UNIXTIME(timestamp)) = MONTH(CURDATE())
AND YEAR(FROM_UNIXTIME(timestamp)) = YEAR(CURDATE());
To get all values for this month.
SELECT *
FROM payment
WHERE MONTH(FROM_UNIXTIME(timestamp)) = 1
AND YEAR(FROM_UNIXTIME(timestamp)) = 2016;
And the second option to get all values for january 2016
Please let me know if this is helpfull.
You need to use below code:-
mysql> SELECT MONTH(FROM_UNIXTIME(1462399200));
MYSQL Convert timestamp to Month
I have also mentioned in comment
I have a table with the following format:
offer_id consumer_id date
1 1 1282454200
1 1 1282453200
2 2 1282453240
1 3 1282455200
2 1 1282453210
"date" is in unix format.
I need to count all of the daily entries, so if I have 10 entries from yesterday and 8 entries from today, I should get:
2013-06-23 10
2013-06-24 8
This is part of my work on trying to optimize code, so far I have been doing this via PHP code, but you can imagine what happens with a growing database :). This is my php (codeigniter) attempt that I'm trying (unsuccessfully) to translate into mysql:
foreach ($offers as $item) {
$date = $item->date;
$day_date = date("Y-m-d", $date);
$day_start = strtotime(date("Y-m-d 00:00:00", $date));
$day_end = strtotime(date("Y-m-d 23:59:59", $date));
if (!in_array($day_date, $day_array)) {
$day_array[] = $day_date;
$this->db->where("date >=", $day_start);
$this->db->where("date <=", $day_end);
$this->db->from("offers_consumers_history");
$total_points = $this->db->count_all_results();
$db_date = array($day_date, $total_points);
$data[] = $db_date;
}
}
I basically grabbed all of the entries in a previous query and went through every date, if the date isn't in my final array, I had to it by counting all results from 00:00:00 to 23:59:59.
Looking for help in building equivalent SQL code.
You could use this SQL query:
SELECT DATE(FROM_UNIXTIME(date)), COUNT(*)
FROM offers_consumers_history
GROUP BY DATE(FROM_UNIXTIME(date))
Please see fiddle here.
Try like
SELECT count(*) as cnt , date FROM `my_table` GROUP BY date
Then you can change them as your required format.It is simple and same that to change the dates into FROM_UNIXTIME and then counting
If I have right understood your question, group by is what you need
There is a table Post in my database which contains posts of different users. What I wanna do is to create an sql query that'll return as per respective month the number of posts being made each day. Kindly let me know how can i do that generically in one query i can create multiple queries for all days but that is a worst case scenario. So I need expert's solution to this.
Thanks
Expected output:
(Query counts the number of posts for all the days in a respective month)
Day : Number of posts
1 : 20
2 : 25
3 : 10
4 : 17
.........................
30 : 6
Table Structure:
ID | postid | post | date
select DAYOFMONTH(date) as Day , count(*) as Number_of_posts
from table
group by DAYOFMONTH(date)
You should know that if table contains data from different months number of posts will be wrong.
So the group by should be by date and you should use date in selected instead of day of month.
SELECT DAYOFMONTH(date), count(*) FROM Post
GROUP BY DAYOFMONTH(date)
ORDER BY DAYOFMONTH(date) ASC;
If you want to query for a specific month (say, February) then use this:
SELECT DAYOFMONTH(date), count(*) FROM Post
WHERE MONTH(date) = '2'
GROUP BY DAYOFMONTH(date)
ORDER BY DAYOFMONTH(date) ASC;
Note: Months are returned in number form where the MONTH() function is used.
EDIT: If you're looking to return counts for EVERY day in a given month, then I'd push you here - a great accepted answer to a similar question: How to get values for every day in a month
SELECT date, COUNT(id) as number_of_posts FROM table_name GROUP BY date.
I have a mysql database that looks like this:
id | userid | timestamp | activity
Timestamp is a datetime data type, I need to get the data grouped by month, day and hour. I am using mysql and php for my scripts.
I am able to do it by month and day with the following query:
$query = "SELECT COUNT(id) as totals FROM security_transactions WHERE YEAR(timestamp) = 2012 GROUP BY MONTH(timestamp), DAY(timestamp)";
I need to do it by month day and hours.
Please help.
Thanks.
You can add , HOUR(TIME(timestamp)) to your group by query providing your column is of DATETIME format
http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_hour
Also, from the error messages put in the comments below, it looks like #Aprentice is not using mysql, but I've improved this answer for others looking for mysql.
I have never used mssql, so I can't test this but the following might work to group by nearest hour:
GROUP BY dateadd(hour, datediff(hour, 0, timestamp, 0)
Just take it one step further and use HOUR() as well. You will first need to extract the time portion of the timestamp. But guess what, there is a function for that as well ;)