I use wget to download number of papers matching a given query in scholar.google.com
and I obtain a file which shows all the content of the page.
I want to retrieve the last number in the following part of the file
"Results 1 - 10 of about 8,890."
I tried:
cat /dir/file | tr -d "," | grep -o -E -- 'about ([^"]+) \w+'
but it outputs:
about <b>8890</b>. (<b>0.12</b> sec) </font></td></tr></table></form> <div class
whereas I just want the 8890 (with no comma which is taken care by tr -d ","
any suggestion on how to improve it?
Thank you in advance!
Grep pulls out the right line - use sed after that to chop away what you don't want.
cat /dir/file | tr -d "," | grep -o -E -- 'about ([^"]+) \w+' |sed -e 's/.*about <b>//' -e 's/<.b>.*//'
If the html tags (<b> and </b>) are present in your file, you'll have to modify your regex to take care of them too. To get just the fragment you're interested in use a lookbehind assertion. Here's something that should work:
cat /dir/file | tr -d "," | grep -oP -- '(?<=about <b>)[^/<> ]+'
Try something like: sed -n 's#.*about <b>\([0-9]*\)</b>.*#\1#p' instead of grep.
-n means don't print input lines as default, s flag p means print if substituted.
Related
I have a csv file named file1.csv:
something;AD;sss;Andorra;nothing;type_1;sss
something222;AD;sss222;Andorra;nothing222;type_2;aaa
thing;NL;thing3;Netherlands;thing;type_2;bb
etc;US;etc;United States;etc;type_2;nothing
I want to create separate files for each country. I make greps like that:
grep -e "\;AD\;.*\;Andorra\;" file1.csv > fileAD.csv
grep -e "\;NL\;.*\;Netherlands\;" file1.csv > fileNL.csv
grep -e "\;US\;.*\;United\sStates\;" file1.csv > fileUS.csv
This works, but I have all countries in the world. And i don't want to write these lines for every country. Is there any other solution ? Any help is really apreciated.
Edit: I updated my question. I also have a column with type_1 and type_2. And after all the files corresponding each country are created , I need to create new files for every country with just type_1 and new files with just type_2.
For example, for Andorra, I need the files:
fileAD.csv :
something;AD;sss;Andorra;nothing;type_1;sss
something222;AD;sss222;Andorra;nothing222;type_2;aaa
fileADtype_1.csv:
something;AD;sss;Andorra;nothing;type_1;sss
fileADtype_2.csv:
something222;AD;sss222;Andorra;nothing222;type_2;aaa
I think that is ok to look just for the column with the abbreviation, but i wanted the 2 columns, the one with "AD" and the one with the full_name "Andorra" for security reasons.
I go for a one liner with only one instance of awk, without temporary files:
awk -F ';' '{print >> "file" $2 ".csv"}' file1.csv
As one liner with awk:
for code in $(awk -F';' '{print $2}' data.csv | uniq); do awk -F';' -v pat="$code" '$2 ~ pat {print $0}' data.csv > "file${code}.csv"; done
Given the following string:
arn:aws:secretsmanager:us-east-1:3264873466873:secret:foo/bar 1564681234.974 foo/bar {"username":"admin","password":"admin123","secret_key":"KASJDFJHAKHFKAHASDF"} 4e397333-3797-4f0b-ad7e-8c1cc0ed041c VERSIONSTAGES AWSCURRENT
Within a shell script, how do you extract just the JSON portion to end up like this:
{"username":"admin","password":"admin123","secret_key":"KASJDFJHAKHFKAHASDF"}
I was able to do it using two sed commands:
echo $longString | sed 's/^.*{/{/' | sed 's/}.*$/}/'
but was wondering if there is a way to do it using only one command.
To extract continuous part of the input, you can use grep with its -o option (if supported on your system). It tells grep to only output the matching part.
grep -o '{.*}'
For extracting columns, use awk:
echo $longString | awk '{print $4}'
Or cut:
echo $longString | cut -f 4 -d ' '
Beware if you have spaces in your JSON data. You might be better off using jq to process the results of aws secretsmanager list-secrets and similar.
You can use
echo $longString | sed -n 's|.*\({.*}\).*|\1|p'
to match and print the desired pattern
you can just join the sed commands to a single command
sed 's/^.*{/{/;s/}.*$/}/'
This awk should do. I will handle if there are any space in the string.
echo $string | awk -F"[{}]" '{print $2}'
"username":"admin","password":"admin123","secret_key":"KASJDFJHAKHFKAHASDF"
I have a csv file with thousands of lines in it. I'd like to be able to find values that only appear once in this file.
For instance
dog
dog
cat
dog
bird
I'd like to get as my result:
cat
bird
I tried using the following awk command but it returned one of each value in the file:
awk -F"," '{print $1}' test.csv|sort|uniq
Returns:
dog
cat
bird
Thank you for your help!
Just with awk:
awk -F, '{count[$1]++} END {for (key in count) if (count[key] == 1) print key}' test.csv
Close. Try:
awk -F"," '{print $1}' test.csv |sort | uniq -c | awk '{if ($1 == 1) print $2}'
the -c flag on uniq will give you counts. Next awk will look for any items with the count of 1 (first field) and print the value of the second field ($2)
Only caveat is that this will return bird before cat due to it being previously sroted. you could pipe once more to sort -r to reverse the sort direction. This would be identical to the expected answer you asked for, but it is not the original sort order.
Cutting to first field, then sorting and displaying only uniques:
cut -d ',' -f 1 test.csv | sort | uniq -u
That is, if you append -u to your command, it'd work. This is just using cut instead of awk.
If Perl is an option, this code is similar to #glenn jackman's:
perl -F, -lane '$c{$F[0]}++; END{for $k (sort keys %c){print $k if $c{$k} == 1}}' test.csv
These command-line options are used:
-n loop around each line of the input file
-l removes newlines before processing, and adds them back in afterwards
-a autosplit mode – split input lines into the #F array. Defaults to splitting on whitespace.
-e execute the perl code
-F autosplit modifier, in this case splits on ,
#F is the array of words in each line, indexed starting with $F[0]
i have to use awk to print out 4 different columns in a csv file. The problem is the strings are in a $x,xxx.xx format. When I run the regular awk command.
awk -F, {print $1} testfile.csv
my output `ends up looking like
307.00
$132.34
30.23
What am I doing wrong.
"$141,818.88","$52,831,578.53","$52,788,069.53"
this is roughly the input. The file I have to parse is 90,000 rows and about 40 columns
This is how the input is laid out or at least the parts of it that I have to deal with. Sorry if I made you think this wasn't what I was talking about.
If the input is "$307.00","$132.34","$30.23"
I want the output to be in a
$307.00
$132.34
$30.23
Oddly enough I had to tackle this problem some time ago and I kept the code around to do it. You almost had it, but you need to get a bit tricky with your field separator(s).
awk -F'","|^"|"$' '{print $2}' testfile.csv
Input
# cat testfile.csv
"$141,818.88","$52,831,578.53","$52,788,069.53"
"$2,558.20","$482,619.11","$9,687,142.69"
"$786.48","$8,568,159.41","$159,180,818.00"
Output
# awk -F'","|^"|"$' '{print $2}' testfile.csv
$141,818.88
$2,558.20
$786.48
You'll note that the "first" field is actually $2 because of the field separator ^". Small price to pay for a short 1-liner if you ask me.
I think what you're saying is that you want to split the input into CSV fields while not getting tripped up by the commas inside the double quotes. If so...
First, use "," as the field separator, like this:
awk -F'","' '{print $1}'
But then you'll still end up with a stray double-quote at the beginning of $1 (and at the end of the last field). Handle that by stripping quotes out with gsub, like this:
awk -F'","' '{x=$1; gsub("\"","",x); print x}'
Result:
echo '"abc,def","ghi,xyz"' | awk -F'","' '{x=$1; gsub("\"","",x); print x}'
abc,def
In order to let awk handle quoted fields that contain the field separator, you can use a small script I wrote called csvquote. It temporarily replaces the offending commas with nonprinting characters, and then you restore them at the end of your pipeline. Like this:
csvquote testfile.csv | awk -F, {print $1} | csvquote -u
This would also work with any other UNIX text processing program like cut:
csvquote testfile.csv | cut -d, -f1 | csvquote -u
You can get the csvquote code here: https://github.com/dbro/csvquote
The data file:
$ cat data.txt
"$307.00","$132.34","$30.23"
The AWK script:
$ cat csv.awk
BEGIN { RS = "," }
{ gsub("\"", "", $1);
print $1 }
The execution:
$ awk -f csv.awk data.txt
$307.00
$132.34
$30.23
I want to extract the URL from within the anchor tags of an html file.
This needs to be done in BASH using SED/AWK. No perl please.
What is the easiest way to do this?
You could also do something like this (provided you have lynx installed)...
Lynx versions < 2.8.8
lynx -dump -listonly my.html
Lynx versions >= 2.8.8 (courtesy of #condit)
lynx -dump -hiddenlinks=listonly my.html
You asked for it:
$ wget -O - http://stackoverflow.com | \
grep -io '<a href=['"'"'"][^"'"'"']*['"'"'"]' | \
sed -e 's/^<a href=["'"'"']//i' -e 's/["'"'"']$//i'
This is a crude tool, so all the usual warnings about attempting to parse HTML with regular expressions apply.
grep "<a href=" sourcepage.html
|sed "s/<a href/\\n<a href/g"
|sed 's/\"/\"><\/a>\n/2'
|grep href
|sort |uniq
The first grep looks for lines containing urls. You can add more elements
after if you want to look only on local pages, so no http, but
relative path.
The first sed will add a newline in front of each a href url tag with the \n
The second sed will shorten each url after the 2nd " in the line by replacing it with the /a tag with a newline
Both seds will give you each url on a single line, but there is garbage, so
The 2nd grep href cleans the mess up
The sort and uniq will give you one instance of each existing url present in the sourcepage.html
With the Xidel - HTML/XML data extraction tool, this can be done via:
$ xidel --extract "//a/#href" http://example.com/
With conversion to absolute URLs:
$ xidel --extract "//a/resolve-uri(#href, base-uri())" http://example.com/
I made a few changes to Greg Bacon Solution
cat index.html | grep -o '<a .*href=.*>' | sed -e 's/<a /\n<a /g' | sed -e 's/<a .*href=['"'"'"]//' -e 's/["'"'"'].*$//' -e '/^$/ d'
This fixes two problems:
We are matching cases where the anchor doesn't start with href as first attribute
We are covering the possibility of having several anchors in the same line
An example, since you didn't provide any sample
awk 'BEGIN{
RS="</a>"
IGNORECASE=1
}
{
for(o=1;o<=NF;o++){
if ( $o ~ /href/){
gsub(/.*href=\042/,"",$o)
gsub(/\042.*/,"",$o)
print $(o)
}
}
}' index.html
You can do it quite easily with the following regex, which is quite good at finding URLs:
\b(([\w-]+://?|www[.])[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|/)))
I took it from John Gruber's article on how to find URLs in text.
That lets you find all URLs in a file f.html as follows:
cat f.html | grep -o \
-E '\b(([\w-]+://?|www[.])[^\s()<>]+(?:\([\w\d]+\)|([^[:punct:]\s]|/)))'
I am assuming you want to extract a URL from some HTML text, and not parse HTML (as one of the comments suggests). Believe it or not, someone has already done this.
OT: The sed website has a lot of good information and many interesting/crazy sed scripts. You can even play Sokoban in sed!
This is my first post, so I try to do my best explaining why I post this answer...
Since the first 7 most voted answers, 4 include GREP even when the
post explicitly says "using sed or awk only".
Even when the post requires "No perl please", due to the previous
point, and because use PERL regex inside grep.
and because this is the simplest way ( as far I know , and was
required ) to do it in BASH.
So here come the simplest script from GNU grep 2.28:
grep -Po 'href="\K.*?(?=")'
About the \K switch , not info was founded in MAN and INFO pages, so I came here for the answer....
the \K switch get rid the previous chars ( and the key itself ).
Bear in mind following the advice from man pages:
"This is highly experimental and grep -P may warn of unimplemented features."
Of course, you can modify the script to meet your tastes or needs, but I found it pretty straight for what was requested in the post , and also for many of us...
I hope folks you find it very useful.
thanks!!!
In bash, the following should work. Note that it doesn't use sed or awk, but uses tr and grep, both very standard and not perl ;-)
$ cat source_file.html | tr '"' '\n' | tr "'" '\n' | grep -e '^https://' -e '^http://' -e'^//' | sort | uniq
for example:
$ curl "https://www.cnn.com" | tr '"' '\n' | tr "'" '\n' | grep -e '^https://' -e '^http://' -e'^//' | sort | uniq
generates
//s3.amazonaws.com/cnn-sponsored-content
//twitter.com/cnn
https://us.cnn.com
https://www.cnn.com
https://www.cnn.com/2018/10/27/us/new-york-hudson-river-bodies-identified/index.html\
https://www.cnn.com/2018/11/01/tech/google-employee-walkout-andy-rubin/index.html\
https://www.cnn.com/election/2016/results/exit-polls\
https://www.cnn.com/profiles/frederik-pleitgen\
https://www.facebook.com/cnn
etc...
Expanding on kerkael's answer:
grep "<a href=" sourcepage.html
|sed "s/<a href/\\n<a href/g"
|sed 's/\"/\"><\/a>\n/2'
|grep href
|sort |uniq
# now adding some more
|grep -v "<a href=\"#"
|grep -v "<a href=\"../"
|grep -v "<a href=\"http"
The first grep I added removes links to local bookmarks.
The second removes relative links to upper levels.
The third removes links that don't start with http.
Pick and choose which one of these you use as per your specific requirements.
Go over with a first pass replacing the start of the urls (http) with a newline (\nhttp). Then you have guaranteed for yourself that your link starts at the beginning of the line and is the only URL on the line.The rest should be easy, here is an example:
sed "s/http/\nhttp/g" <(curl "http://www.cnn.com") | sed -n "s/\(^http[s]*:[a-Z0-9/.=?_-]*\)\(.*\)/\1/p"
alias lsurls='_(){ sed "s/http/\nhttp/g" "${1}" | sed -n "s/\(^http[s]*:[a-Z0-9/.=?_-]*\)\(.*\)/\1/p"; }; _'
You can try:
curl --silent -u "<username>:<password>" http://<NAGIOS_HOST/nagios/cgi-bin/status.cgi|grep 'extinfo.cgi?type=1&host='|grep "status"|awk -F'</A>' '{print $1}'|awk -F"'>" '{print $3"\t"$1}'|sed 's/<\/a> <\/td>//g'| column -c2 -t|awk '{print $1}'
That's how I tried it for better view, create shell file and give link as parameter, it will create temp2.txt file.
a=$1
lynx -listonly -dump "$a" > temp
awk 'FNR > 2 {print$2}' temp > temp2.txt
rm temp
>sh test.sh http://link.com
Eschewing the awk/sed requirement:
urlextract is made just for such a task (documentation).
urlview is an interactive CLI solution (github repo).
I scrape websites using Bash exclusively to verify the http status of client links and report back to them on errors found. I've found awk and sed to be the fastest and easiest to understand. Props to the OP.
curl -Lk https://example.com/ | sed -r 's~(href="|src=")([^"]+).*~\n\1\2~g' | awk '/^(href|src)/,//'
Because sed works on a single line, this will ensure that all urls are formatted properly on a new line, including any relative urls. The first sed finds all href and src attributes and puts each on a new line while simultaneously removing the rest of the line, inlcuding the closing double qoute (") at the end of the link.
Notice I'm using a tilde (~) in sed as the defining separator for substitution. This is preferred over a forward slash (/). The forward slash can confuse the sed substitution when working with html.
The awk finds any line that begins with href or src and outputs it.
Once the content is properly formatted, awk or sed can be used to collect any subset of these links. For example, you may not want base64 images, instead you want all the other images. Our new code would look like:
curl -Lk https://example.com/ | sed -r 's~(href="|src=")([^"]+).*~\n\1\2~g' | awk '/^(href|src)/,//' | awk '/^src="[^d]/,//'
Once the subset is extracted, just remove the href=" or src="
sed -r 's~(href="|src=")~~g'
This method is extremely fast and I use these in Bash functions to format the results across thousands of scraped pages for clients that want someone to review their entire site in one scrape.