studentname I II
Vivek Johari 30 20
Chandra Singh 30 20
Avinash Dubey 30 25
Pankaj Kumar 33 29
I have a table named student with details as above. I want to find the average of column I and II and display it on a new column using pivot. Please help me to solve this using pivot..
May I use any sub query to solve this using pivot...
your questions is not specific enough.
Do you want the total average of both columns? just do
select avg (I), avg(II)
from your_table
if you want just one value, you can do:
select (avg (I) + avg(II))/2
from your_table
Related
For example, let us consider this table:
In this image consists of rows of 8 where names like Mike,Glenn,Daryl,Shane and Patricia is included with their respective ages
Id
Name
Age
1
Mike
25
2
Glenn
19
3
Glenn
19
4
Daryl
56
5
Shane
30
6
Shane
30
7
Patricia
16
Now I want to insert the type of query that will show the names without repetitions like This, not like This
EDIT: I entered the data from first picture. The request is to list the names without duplicates, as shown in the second and third picture but I will not convert them to text.
DISTINCT specifies removal of duplicate rows from the result set.
SELECT DISTINCT Name
FROM tablename
see: use DISTINCT in SELECT
You can use GROUP BY to achieve it.
SELECT * FROM your_table
GROUP BY your_table.name
ORDER BY id
With the data you gave, the result from this query will be:
id
name
age
1
Mike
25
2
Glenn
19
4
Deryl
56
5
Shane
30
7
Patricia
16
pnr mnd pris
1 1 600
1 7 900
2 1 600
2 7 600
3 1 40
3 7 40
I have trouble how to sum specific rows on the columns. Looking at the above, the table is called travel and it has 3 columns:
pnr - Personal Number
mnd - Month
Pris - Price
So what I want is to sum total of the price for the a specific month, so in this case, it should be 1240 USD and month 1. For the month 7, it should be 1540 USD.
I have trouble to do the query correct. So far from I have tried is this:
SELECT t.rnr, t.mnd, SUM(t.pris)
FROM travel AS t
WHERE t.mnd = 1
The result I get is 3720 USD which I have no idea how the SQL managed to calculate this for me.
Appreciate if someone could please help me out!
For this you need to drop the pnr column from the output (it is not relevant and will cause your data to split) and add a GROUP BY:
SELECT t.mnd, SUM(t.pris)
FROM travel AS t
WHERE t.mnd = 1
GROUP BY t.mnd
Live demo: https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=b34ec2bb9c077c2d74ffc66748c5c142
(The use of an aggregate function without grouping, as you've got now, is not a standard SQL feature and can often be turned off in MySQL. If turned on, you might not always get the result you expected/intended.)
just group your result with mnd column
SELECT t.mnd, SUM(t.pris)
FROM travel AS t
group by t.mnd
I am new in MySql and help will be much appreciated
I had this assignment which is to get the sum and average of dynamic rows in the table. The table looks like
tbl_grade
id scores
1 10
1 11
1 9
1 10
1 6
2 10
2 9
2 10
I want to show the results like this
id sum average
1 46 9.2
2 29 9.7
Hope anyone can help. Thanks
This is a simple query using GROUP BY clause and the aggregate methods SUM and AVG. For a better understanding about grouping and aggregate methods, please read next: http://www.mysqltutorial.org/mysql-group-by.aspx
SELECT
id,
SUM(scores),
AVG(scores)
FROM
tbl_grade
GROUP BY
id
I have 3 table. final,milestone and milestonewp consider that the three tables is foreigned key like milestonewp<--FK--milestone<--FK--Final .Then I have a column for determining the average of the milestonewp for a certain foreign key. Then getting that average to be average again to be displayed to the final table.Here is my visual representation
milestonewp
condition | mile_id
20 1
20 1
30 1
21 2
21 2
31 2
40 3
30 3
50 3
How can I average the average that the chart above will produce?
I'm trying to work on this
select avg(milewp_condition)
from logs_pms_r_milestone_wp
where mile_id=1;
but i dont have any idea how it can produce for the other mile_id
EDIT
The above code will produce something like this
avg(milewp_condition)
0
0
0
so then, i also want to average that 3 rows.
If I understand well this should be what you look for:
SELECT AVG(milewp_condition)
FROM logs_pms_r_milestone_wp
GROUP BY mile_id;
If you want to average all, just do:
SELECT AVG(milewp_condition)
FROM logs_pms_r_milestone_wp;
Regards
I'm using SQL Workbench.
cust_num date notes
1234 2016-02-01 advice
1234 2016-02-01 something else
1234 2016-02-02 order
1234 2016-02-03 order
4421 2016-02-15 advice
4421 2016-02-17 order
4421 2016-02-18 something else
4421 2016-02-24 order
I know the above is a bit unclear, but basically, there's 3 columns in the above table. One showing customer_num (customer number), one showing date and one showing a notes field.
From the above, I want to perform two queries. I am newish to this so, I hope this is clear. I'm using SQL workbench.
i) I want to count the number of DISTINCT 'customer_num's that placed an order within 4 days of receiving advice.
So the answer based on the table above would be 3. This is because cust_num '1234' made two orders within 4 days and cust_num '4421' made 1 order. So that totals 3
ii)I want to count the number of DISTINCT customer_num's that placed an order within 15 days of receiving advice. Only stipulation is that I don't want to re-count those from (i) that placed an order within 4 days. I want to exclude them.
So the answer to this would be 1. Customer_num '4421' placed 1 order that was bigger than 4 days but smaller than or including 15 days.
Any help really appreciated. Thank you.
One method is to use exists:
select count(distinct cust_num)
from customers t
where exists (select 1
from customers t2
where t2.cust_num = t.cust_num and
t2.date between t.date and date_add(t.date, interval 3 day)
);
The two queries have the same structure. You just need to change the condition in the where clause in the subquery.