I have the following table (simplified):
user_id date hours
1 2012-03-01 5
2 2012-03-01 8
3 2012-03-01 6
1 2012-03-02 3
3 2012-03-02 7
What I want is to get the the sum of hours worked for a given user id (ex. 1), and the total hours worked regardless of what user (for a given time period) in a single query.
So for user_id = 1, and time period: 2012-03-01 - 2012-03-02 the query should return: own=8, total=29.
I can do it in two separate queries, but not in a single one.
Use CASE:
SELECT SUM(
CASE user_id
WHEN 1 THEN hours
ELSE 0
END) as Own,
SUM(hours) as Total
FROM HoursWorked
WHERE date BETWEEN '2012-03-01' AND '2012-03-02';
I think I have something that works using the following schema:
CREATE TABLE hoursWorked
(
id int,
date date,
hours int
);
INSERT INTO hoursWorked
(id, date, hours)
VALUES
('1','2012-03-01','5'),
('2','2012-03-01','8'),
('3','2012-03-01','6'),
('1','2012-03-02','3'),
('3','2012-03-02','7');
And this query:
select parent.id, parent.date, parent.hours, (select sum(hours)
from hoursWorked child
where child.id = parent.id) as totalHours
from hoursWorked parent
I was able to get these results:
ID DATE HOURS TOTALHOURS
1 March, 01 2012 00:00:00-0800 5 8
2 March, 01 2012 00:00:00-0800 8 8
3 March, 01 2012 00:00:00-0800 6 13
1 March, 02 2012 00:00:00-0800 3 8
3 March, 02 2012 00:00:00-0800 7 13
Diego's answer albeit procedural is a great way to get the answer you are looking for. Of course for your date range you would need to add a WHERE date BETWEEN 'startdate' AND 'enddate'. The dates need to be in a format that mysql recognizes, typically 'yyyy-mm-dd'
Another solution that doesn't get you the results in one row, but in a result set would be to do a UNION
SELECT user_id, SUM(hours) as hours FROM table WHERE date BETWEEN 'startdate' AND 'enddate' WHERE user_id = 3
UNION
SELECT null as user_id, SUM(hours) as hours FROM table WHERE date BETWEEN 'startdate' AND 'enddate'
Related
I have a MySQL requirement to select data from a table based on a start date and end date and group it by weekly also selecting the data in reverse order by date. Assume that, I have chosen the start date as 1st November and the end date as 04 December. Now, I would like to fetch the data as 04 December to 28 November, 27 November to 20 November, 19 November to 12 November and so on and sum the value count for that week.
Given an example table,
id
value
created_at
1
10
2021-10-11
2
13
2021-10-17
3
11
2021-10-25
4
8
2021-11-01
5
1
2021-11-10
6
4
2021-11-18
7
34
2021-11-25
8
17
2021-12-04
Now the result should be like 2021-12-04 to 2021-11-28 as one week, following the same in reverse order and summing the column value data for that week. I have tried in the query to add the interval of 7 days after the end date but it didn't work.
SELECT count(value) AS total, MIN(R.created_at)
FROM data_table AS D
WHERE D.created_at BETWEEN '2021-11-01' AND '2021-12-04' - INTERVAL 7 DAY ORDER BY D.created_at;
And it's also possible to have the last week may have lesser than 7 days.
Expected output:
end_interval
start_interval
total
2021-12-04
2021-11-27
17
2021-11-27
2021-11-20
34
2021-11-20
2021-11-13
4
2021-11-13
2021-11-06
1
2021-11-06
2021-10-30
8
2021-10-30
2021-10-25
11
Note that the last week is only 5 days depending upon the selected from and end dates.
One option to address this problem is to
generate a calendar of all your intervals, beginning from last date till first date, with a split of your choice, using a recursive query
joining back the calendar with the original table
capping start_interval at your start_date value
aggregating values for each interval
You can have three variables to be set, to customize your date intervals and position:
SET #start_date = DATE('2021-10-25');
SET #end_date = DATE('2021-12-04');
SET #interval_days = 7;
Then use the following query, as already described:
WITH RECURSIVE cte AS (
SELECT #end_date AS end_interval,
DATE_SUB(#end_date, INTERVAL #interval_days DAY) AS start_interval
UNION ALL
SELECT start_interval AS end_interval,
GREATEST(DATE(#start_date), DATE_SUB(start_interval, INTERVAL #interval_days DAY)) AS start_interval
FROM cte
WHERE start_interval > #start_date
)
SELECT end_interval, start_interval, SUM(_value) AS total
FROM cte
LEFT JOIN tab
ON tab.created_at BETWEEN start_interval AND end_interval
GROUP BY end_interval, start_interval
Check the demo here.
I got student_id=14 through form post and I need to fetch attendance report for the student_id as below
CLASS STUDENT_ID YEAR MONTH TOTAL_CLASSES TOTAL_PRESENT
11 14 2016 April 21 20
11 14 2016 May 25 25
11 14 2016 June 30 29
11 14 2016 July 18 18
11 14 2017 January 28 28
Here TOTAL_CLASSES represents total number days school is open and TOTAL_PRESENT represents total number of says a student is present out of TOTAL_CLASSES.
From HTML Form I GOT only student_id=14 and I need to fetch and show record as above.
Please see sqlfiddle here to support my answer http://sqlfiddle.com/#!9/63b6a/3
In my table remarks represents 1,2,3 for present and 0 for absent.
You're counting attendance numbers for each year, month, class and student. The key step in this query is to use GROUP BY to indicate the columns which you're grouping, then use the COUNT and SUM aggregation functions to compute the attendance columns you're looking for:
SELECT
class_id,
student_id,
YEAR(att_date) as year,
MONTH(att_date) as month,
COUNT(remarks) AS total_classes,
SUM(remarks > 0) AS total_present
FROM attendance
WHERE student_id = 15
GROUP BY YEAR(att_date), MONTH(att_date), class_id, student_id;
http://sqlfiddle.com/#!9/63b6a/11
You can remove the WHERE clause to show attendance for all students.
So, I have a mysql table with user id(id) and date of transaction(dot) that looks like:
id dot
-------------------------------
101 2015-06-12 12:18:42 UTC
102 2015-06-12 12:18:40 UTC
103 2015-06-12 12:18:42 UTC
101 2015-07-12 12:18:42 UTC
and so on.
(Output for this data should be:
Year Month Num of users
-----------------------------
2015 06 0
2015 07 2
)
It logs all the transactions that are made. For each month m, I want to find out the count of users by month and year who transacted in m-1 month but not in m month. The results need to be grouped by year and month. Ideally, table should look like (http://sqlfiddle.com/#!9/b80f49/1)
Year Month Num of users
-----------------------------
2015 05 0
2015 06 2
2015 07 1
2015 08 4
Now for a single month(E.g. 05/2015), I can hardcode:
SELECT "2015" AS Year,"05" AS Month, "COUNT(DISTINCT id) FROM table WHERE
MONTH(dot)=4 AND YEAR(dot)=2015
AND id NOT IN
(SELECT id FROM table WHERE MONTH(dot)=5 AND YEAR(dot)=2015)
To group the count of users using GROUP BY, the query would look like:
SELECT YEAR(dot) as Year,MONTH(dot),COUNT(DISTINCT id) as Month FROM table
WHERE id NOT IN(SELECT id FROM table
WHERE DATEDIFF(dot_parent,dot_this_table)<30 AND DATEDIFF(dot_parent,dot_this_table)>=0)
Here dot_parent is the dot of the parent query and dot_this_table is the dot of the subquery. Now the problem here is that I can't pass the dot_parent inside the subquery. Is there a way to do that or frame the query in another way such that its logical structure remains similar, since I would have to make similar queries for multiple date ranges.
You must query the same table thrice: once for the months to show, once to find the users in the previous months, once for user matches in the months in question. You'd select distinct users per month, as you are not interested in whether a user had more than one transaction in a month or not.
Here is the complete query:
select
this_month.year,
this_month.month,
count(prev_month_users.user) - count(this_month_users.user) as users
from
(
select distinct year(timing) as year, month(timing) as month
from transactions
) this_month
left join
(
select distinct
year(timing) as year, month(timing) as month, id as user,
year(date_add(timing, interval 1 month)) as next_month_year,
month(date_add(timing, interval 1 month)) as next_month_month
from transactions
) prev_month_users
on prev_month_users.next_month_year = this_month.year
and prev_month_users.next_month_month = this_month.month
left join
(
select distinct year(timing) as year, month(timing) as month, id as user
from transactions
) this_month_users
on this_month_users.user = prev_month_users.user
and this_month_users.year = prev_month_users.next_month_year
and this_month_users.month = prev_month_users.next_month_month
group by this_month.year, this_month.month;
Result:
year month users
2015 5 0
2015 6 2
2015 7 1
2015 8 3
Note that I show three users for August (users 101, 102, 104). User 101 had two transactions in July, but it is still three users who had transactions in July but not in August.
Here is your SQL fiddle back: http://sqlfiddle.com/#!9/b80f49/13
I'm trying to find the number of orders that were open for each week. An order that is open for multiple weeks should be included in each week's count that it was open. The data looks something like below
id open_dt close_dt
1 2014-01-01 07:00:00 2014-01-01 07:00:00
2 2014-01-01 07:00:00 2014-01-02 07:00:00
3 2014-01-02 07:00:00 2014-01-09 07:00:00
4 2014-01-08 07:00:00 NULL
NULL close_dt counts as still open and should appear in each week since it was opened
My query looks like below however it isn't returning the numbers I'm expecting:
SELECT YEAR(open_dt) AS year, WEEK(open_dt) AS week, count(*) 'open'
FROM table
WHERE open_dt >= week(open_dt)
OR
(
close_dt > week(open_dt)
OR close_dt IS NULL
)
GROUP BY YEAR(open_dt), WEEK(open_dt)
I'm trying to get results like below:
year week open
2014 1 3
2014 2 2
2014 3 1
...
Appreciate any tips or guidance.
This is a case where it helps to have a calendar table or list of weeks. Let me assume that you have at least one open in each week:
select yw.y, yw.w, count(t.open_dt) as "Open"
from (select distinct year(open_dt) as y, week(open_dt) as w,
year(open_dt) * 100 + week(open_dt) as yw
from table t
) yw left outer join
table t
on yw.yw >= year(open_dt)*100 + week(open_dt) and
(yw.yw <= year(close_dt)*100 + week(close_dt) or close_dt is null)
group by yw.y, yw.w
order by yw.y, yw.w;
I have a database table with following columns
Id, Name, Date (FORMAT: Y-m-d H:i:s)
Now I want to retrieve data of following form
Count Year
3 2013
5 2014
It is showing total no of records generated in different years
For example If I have following data:
1 Manish 2013-10-01 23:12:12
2 Tarun 2013-10-02 23:12:12
3 Pankaj 2014-10-02 23:12:12
4 Pankaj 2015-10-02 23:12:12,
Then it will return me following data:
Count Year
2 2013
1 2014
1 2015
Is it possible?
select count(*) as cnt,
year(date) year_of_date
from your_table
group by year_of_date
select year(date) as Year,count(*) as Total
from my_table
group by year(date)