I have a table in mysql which is not normalized and I need to query so that it groups by a certain field and gives the most recent row.
For example the table looks like
callername | callerdate | incoming | status
And I am trying to get all of the records which have their most recent status as NotAnswered and I can't figure out how you would do this, I can GROUP BY callername however I can't figure out how to get the most recent values.
Thanks.
SELECT A.* FROM
YOURTABLE A,
(
SELECT callername,callerdate,MAX(ID) AS ID
FROM YOURTABLE
WHERE status='NotAnswered'
GROUP BY callername,callerdate
) B
WHERE A.ID=B.ID;
SELECT
yourTable.*
FROM
yourTable
INNER JOIN
(
SELECT
callername,
MAX(callerdate) AS callerdate
FROM
yourTable
GROUP BY
calledname
)
AS mostRecent
ON mostRecent.callername = yourTable.callername
AND mostRecent.callerdate = yourTable.callerdate
WHERE
yourTable.status='NotAnswered'
Related
Table: MyTable
[
Here is the result I desire:
For every ID in the table, count how many times that ID appears in the column Parent_ID.
Create a custom column AS Instances to place the result.
My desired Result
I imagine to get the above result with something not more complicated than a working version of the following query:
SELECT ID, Parent_ID, COUNT( Parent_ID = ID ) AS Instances FROM MyTable
You can use a scalar subquery to compute the extra column. For example:
select
id,
parent_id,
(
select count(*) from my_table b where b.parent_id = a.id
) as instances
from my_table a
A correlated subquery is the simplest solution:
select t.*,
(select count(*) from mytable t2 where t2.parent_id = t.id) as instances
from mytable t;
I have the following data:
I want to retrieve the ids that match the highest date (represented by max(folga)), grouping by funcionario_id.
Here's the output table I want, but it's missing the id:
How can I achieve this?
Thanks for the attention.
One way to do it is with NOT EXISTS:
select
t.funcionario_id, t.folga, t.id
from tablename t
where not exists (
select 1 from tablename
where funcionario_id = t.funcionario_id and folga > t.folga
)
or you can group by funcionario_id first to get the max date (I guess this is the query that returned the result you posted) and then join to the table:
select t.*
from tablename t inner join (
select funcionario_id, max(folga) folga
from tablename
group by funcionario_id
) g on g.funcionario_id = t.funcionario_id and g.folga = t.folga
I have table like this one:
I would like to all rows, but if there is user_id 5 if this case, override other rows which have no user_id.
I tried both with MAX(user_id) and GROUP BY country_name, but it still returns, wrong results.
Final result I'm expecting:
Try this;)
select t1.*
from yourtable t1
inner join (
select max(user_id) as user_id, country_name from yourtable group by country_name
) t2 on t1.country_name = t2.country_name and t1.user_id = t2.user_id
This is just a solution based on your sample data. If you have a variety of user_id, it should be more different.
As of SQL Select only rows with Max Value on a Column you can easily get rows with max value on a column by using both MAX(column) and GROUP BY other_column in one statement.
But if you want to select other columns too, you have to this in a subquery like in the following example:
SELECT a.*
FROM YourTable a
INNER JOIN (
SELECT country_name, MAX(user_id) user_id
FROM YourTable
GROUP BY country_name
) b ON a.country_name = b.country_name AND a.user_id = b.user_id
I have a table as follows:
ident_nr|proj_nr|start_time|
----------------------------
05.26.73|0000001|1116936920|
09.56.df|0000002|1213431234|
11.ac.12|0000003|1236485758|
98.er.df|0000001|1287789755|
70.12.5n|0000001|1011245554|
33.dt.vp|0000003|1239125544|
And I want a result like this:
ident_nr|proj_nr|start_time|
----------------------------
98.er.df|0000001|1287789755|
09.56.df|0000002|1213431234|
33.dt.vp|0000003|1239125544|
where proj_nr is in asc order and start time with the max value.
Note: ident_nr is unique and proj_nr could have multiple ident_nr.
Database: MySQL.
Is there an SQL query that could achieve this result?
Thanks
SELECT t.ident_nr, t.proj_nr, t.start_time
FROM YourTable t
INNER JOIN (SELECT proj_nr, MAX(start_time) AS MaxTime
FROM YourTable
GROUP BY proj_nr) q
ON t.proj_nr = q.proj_nr
AND t.start_time = q.MaxTime
ORDER BY t.proj_nr;
SELECT t1.*
FROM table AS t1
INNER JOIN (
SELECT proj_nr, MAX(start_time) AS MaxTime
FROM table
GROUP BY proj_nr) AS t2
ON (t1.proj_nr = t2.proj_nr AND t1.start_time = t2.MaxTime)
Your criteria seems to be MAX(start_time) in your sample data. If not, please be more detailed in your question about what you want.
I need help returning a relevant result for this query. I have one table that I am hitting with three columns. trans_date, trans_amount and user_id
what I am trying to determine is this. For a given user_id when was the last trans_date and what was the trans_amount.
I'm having trouble returning the correct transaction_amount. Here is my code so far. It's returning the correct date but the amount is not right
select user_id, trans_date, trans_credit
from table
WHERE trans_credit =
(select max(trans_date) from inclick_account_act as f
where f.user_id = table.user_id);
Thanks in advance
If I understand you correctly you just want to get the most recent transaction for all users.
SELECT user_id, trans_date, trans_credit
FROM `table`
GROUP BY user_id
ORDER BY trans_date DESC;
How about something like
SELECT t.*
FROM table t INNER JOIN
(
SELECT user_id,
MAX(trans_date) max_trans_date
FROM table
GROUP BY user_id
) MaxDates ON t.user_id = MaxDates.max_trans_date