MySQL syntax: bigger than value, but NOT IN (...) - mysql

Question

Tables:
bookings: id, user_id, object_id, date1, ...
booking_status: id, book_id, status
status is int, range from 1 to 9 (request, confirmed, paid, cancelled by user and that sort of stuff), so I need all bookings, where status is at least 4 (which means paid) but no value bigger than 4 (which would mean cancelled etc).
Till now the SELECT looks about like this (I left out some fields (...) to shorten it):
SELECT b.date1, ..., u.name FROM bookings b
LEFT JOIN user u ON (b.user_id = u.id)
LEFT JOIN booking_status bs ON (b.id=bs.book_id)
WHERE ((b.object_id=$object_id) AND (bs.status NOT IN (5,6,7,8,9)));"
...but it still selects those bookings that have booking status bigger than 4 as well. Any ideas how I need to change the query??
Thank you very much in advance!
UPDATE: thank you all again, I am amazed with how many great ideas you have come up with! There is really many ways to do it and I learned a lot from you, so thank you again! I will try all your suggestions and see for the performance, for now I mixed your solutions to this query, which works for now but I need to test it further:
SELECT b.date, ..., u.name FROM bookings b
LEFT JOIN user u ON (b.user_id = u.id)
LEFT JOIN booking_status bs ON (b.id=bs.book_id AND bs.status<=4)
WHERE (b.object_id=$object_id) HAVING MAX(bs.status)=4
it does not return multiple rows, but returns the rows with 4, excludes the rows with more than 4 and has no subqueries...
EDIT 2: I edited the query again... with HAVING MAX(bs.status)=4 it then works...
EDIT 3: sorry, after testing different cases I have to admit I was much too fast by saying it works...

Answer 1

If I'm understanding correctly, what you need is this:
SELECT b.date1, ..., u.name
FROM bookings b
LEFT JOIN user u ON b.user_id = u.id
WHERE b.object_id = ...
AND EXISTS
( SELECT 1
FROM booking_status bs
WHERE bs.book_id = b.id
AND bs.status = 4
)
AND NOT EXISTS
( SELECT 1
FROM booking_status bs
WHERE bs.book_id = b.id
AND bs.status > 4
)
;
The problem with your current query is that it filters out all joined rows where bs.status > 4, but it doesn't filter out joined rows that have the same bookings.id as a joined row where bs.status > 4.

Answer 2

inspired by ruakh's solution without the correlated subqueries:
select ...
from bookings b
join (select book_id from booking_status group by book_id having max(status) = 4
) bs on b.id = bs.book_id
left join user u on b.user_id = u.id

Answer 3

Another way
SELECT id,
user_id,
object_id,
date1
FROM bookings b
INNER JOIN (SELECT book_id
FROM booking_status
GROUP BY book_id
HAVING MAX(CASE
WHEN status >= 4 THEN status
END) = 4) bs
ON bs.book_id = b.id
(or version without subselect in response to comments)
SELECT b.id,
b.user_id,
b.object_id,
b.date1
FROM bookings b
INNER JOIN booking_status bs
ON bs.book_id = b.id
GROUP BY b.id /* Other RDBMSs would require all columns listed*/
HAVING MAX(CASE
WHEN bs.status >= 4 THEN bs.status
END) = 4

Answer 4

Here's a method without subqueries:
SELECT b.date1, ..., u.name
FROM bookings b
LEFT JOIN user u ON u.id = b.user_id
JOIN booking_status bs1
ON bs1.book_id = b.id AND bs1.status = 4
LEFT JOIN booking_status bs2
ON bs2.book_id = b.id AND bs2.status > 4
WHERE b.object_id = $object_id
AND b2.book_id IS NULL
This query eliminates any row where there is a status for the same id that is greater than 4.