I am reading .csv file through PHP using fgetcsv(). Now I am able to fetch I mean read data from .csv file.
Then I need to check SKU column with my fetch result & accordingly have to perform either Insertion Or Updation.
Suppose SKU is already present there, then I have to update my row in table else I need to insert new record.
I have write following code...Plz check n tell me where I am doing mistake-:
<?php
$row = 1;
if (($handle = fopen("localhost/data/htdocs/magento/var/import/Price.csv", "r")) !== FALSE)
{
while (($data = fgetcsv($handle, 8000, ",")) !== FALSE)
{
$num = count($data);
echo "<p> $num fields in line $row: <br /></p>\n";
for ($c=0; $c < $num; $c++)
{
$temp = $data;
$string = implode(";", $temp);
}
$pieces = explode(";", $string);
$col1 = $pieces[0];
$col2 = $pieces[1];
$col3 = $pieces[2];
$col4 = $pieces[3];
$db_name = "magento";
$con = mysql_connect("localhost", "magento", "password");
If (!$con)
{
die('Could not connect: ' . mysql_error());
mysql_close($con);
}
$seldb = mysql_select_db($db_name, $con);
$query_fetch = "SELECT `sku` from `imoprt_prices`";
$result_fetch = mysql_query($query_fetch);
$num_rows = mysql_num_rows($result_fetch);
for($i = 0; $i < $num_rows; $i++)
{
$value = mysql_result($result_fetch, i, 'sku');
if(strcmp('".$value."', '".$col2."') == 0)
{
$flag = 1;
break;
}
else
{
$flag = 0;
break;
}
}
if($flag == 1)
{
$query_upadte = "(UPDATE imoprt_prices SET customer_id= '".$col1."', sku ='".$col2."', price= '".$col3."', website= '".$col4."'
)";
mysql_query($query_upadte);
$row++;
}
if($flag == 0)
{
mysql_query("INSERT INTO `imoprt_prices`(`customer_id`,`sku`,`price`,`website`) VALUES('".$col1."','".$col2."','".$col3."','".$col4."')");
$row++;
}
}
}
?>
If you have an actual UNIQUE index on your imoprt_prices table, you can use the ON DUPLICATE KEY UPDATE syntax and simplify your code a bit to something similar to; (note, can't test, so see as pseudo code)
$db_name = "magento";
$con = mysql_connect("localhost", "magento", "password") or die(mysql_error());
$seldb = mysql_select_db($db_name, $con);
if (($handle = fopen("localhost/data/htdocs/magento/var/import/Price.csv", "r")) !== FALSE)
{
while (($data = fgetcsv($handle, 8000, ",")) !== FALSE)
{
$col1 = $pieces[0];
$col2 = $pieces[1];
$col3 = $pieces[2];
$col4 = $pieces[3];
$query_upadte = "INSERT INTO imoprt_prices (customer_id, sku, price, website) ".
"VALUES('".$col1."','".$col2."','".$col3."','".$col4."') ".
"ON DUPLICATE KEY UPDATE customer_id='".$col1."', price='".$col3.
"',website='".$col4."'";
mysql_query($query_upadte);
}
}
You may also want to either mysql_real_escape_string() or use parameterized queries to make sure there's no ' in your inserted values though. That is always a danger with building sql strings like this.
Simple demo here.
In the following snippet:
$query_upadte = "UPDATE imoprt_prices SET customer_id= '".$col1."', sku ='".$col2."', price= '".$col3."', website= '".$col4."'";
You're trying to update all the rows repeatedly, instead of just updating a single row. This is normally not allowed in MySQL. You need to specify a particular unique ID to be updated.
Related
I'm fairly new to WordPress and SQL. I have a contact form that I want to have the data be submitted to my WordPress database but only if the data that has been entered has not been entered before.
This is what i have so far, which sends data to my database when form is submitted.
if(isset($_POST['contact_us'])) {
$invalidContact = "<h5 class='invalidBooking'> Nope try again</h5>";
$successContact = "<h5 class='invalidBooking'> Message Sent!</h5>";
$table_name='contact_table';
global $wpdb;
$contact_name = esc_attr($_POST['contact_name']);
$contact_email = sanitize_email($_POST['contact_email']);
$subject = esc_attr($_POST['subject']);
$message = esc_attr($_POST['message']);
$error= array();
if (empty($contact_name)) {
$error['name_invalid']= "Name required";
}
if (empty($contact_email)){
$error['email_invaild']= "Email required";
}
// Im guessing some code here to check if row exists in database
if (count($error) >= 1) {
echo $invalid;
}
if (count($error) == 0) {
$data_array=array(
'Contact_Name'=>$contact_name,
'Contact_Email'=> $contact_email,
'Contact_Subject'=> $subject,
'Contact_Message'=> $message,
);
$rowResult=$wpdb->insert($table_name, $data_array,$format=NULL);
echo $successContact;
}
}
You may try this code
if (count($error) == 0) {
$data_array=array(
'Contact_Name'=>$contact_name,
'Contact_Email'=> $contact_email,
'Contact_Subject'=> $subject,
'Contact_Message'=> $message,
);
$query = "SELECT * FROM $table_name WHERE 'Contact_Name'= '$contact_name' AND 'Contact_Email' = '$contact_email' AND 'Contact_Subject' = '$subject' AND 'Contact_Message' = '$message'";
$query_results = $wpdb->get_results($query);
if(count($query_results) == 0) {
$rowResult=$wpdb->insert($table_name, $data_array,$format=NULL);
}
}
Hope this works for you.
fetch data using this code
$query = "SELECT * FROM {$wpdb->prefix}table WHERE column = 1";
echo $query;
$results = $wpdb->get_results($query);
and then you know what to do...
Trying to overwrite existing data based on returned values, just want to get 'location' to update to the new info coming from a CSV import. Have a duplicated table with Oldlocation (all set to DW for testing, so any changes can be seen) Seems like it should be simple....:
$file = "allinv.CSV";
if(($handle = fopen($file, "r")) !== FALSE)
{ fgetcsv($handle);
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){
$num = count($data);
for ($c=0; $c < $num; $c++) {
$col[$c] = $data[$c];}
$col1 = $col[1];
$sql = "SELECT Oldlocation FROM invbkup WHERE VIN = '$col1'"; ///works fine, gets old location for each record
$result = mysqli_query($con, $sql);
$row = mysqli_fetch_array($result);
$whl= $row['Oldlocation'];
$col8 = $col[73];
$query = "UPDATE allinv SET location = '$col8' WHERE $whl = 'DW' ";
echo $col1, $col8, $whl, "</br>";////can see all the info but get no changes in database.
$a= mysqli_query($con, $query);
}
fclose($handle);
}
Nevermind, it was a simple problem I fix by putting it in an if statement:
if($whl = 'DW'){
$query = "UPDATE allinv SET location = '$col8' WHERE VIN ='$col1'";
$a= mysqli_query($con, $query);}
sometimes you over complicate the problem yourself, take a break, drink some coffee and try not thinking so hard.
currenly i use a simple code to update gender in my mysql
my code:
<?php
ini_set('max_execution_time', 30000);
$row = 0;
if (($handle = fopen("list.csv", "r")) !== FALSE) {
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
$num = count($data);
for ($c=0; $c < $num; $c++) {
$name = $data[0];
$gender = $data[1];
}
// connect to db
mysql_connect("***", "***", "***") or die("Connection Failed");
mysql_select_db("info")or die("Connection Failed");
$query = "UPDATE data SET gender = '$gender' WHERE fname = '$name'";
if(mysql_query($query)){
$row++;
echo "$row: ";
echo '<font color="RED">' . $name . '</font> <br>';
}
}
fclose($handle);
}
?>
code works but very slow,
can process up to 10k records per 1 hour and its too slow for me
can someone give me an idea what to do with it to increase speed
You are re-connecting to the DB in every single while iteration. Take the mysql_connect and mysql_select_db calls out of the while loop...
i can't get more than one return in this json. when the original query returns 90k results.
i can't figure out what's hapening.
also the return i get isn't organized as it should. it return the following
{"material":["R8190300000","0"],"grid":["R8190300000","0"]}
sorry to ask this i have been looking for an answer but couln't get it in the internet.
<?php
$link = mysqli_connect("localhost","blablabla","blablabla","blablabla");
if (mysqli_connect_error()) {
die("Could not connect to database");
}
$query =" SELECT material,grid FROM ZATPN";
if( $result = mysqli_query( $link, $query)){
while ($row = mysqli_fetch_row($result)) {
$resultado['material']=$row;
$resultado['grid']=$row;
}
} else {
echo"doesnt work";
}
file_put_contents("data.json", json_encode($resultado));
?>
The problem is that you are overriding the value for the array keys:
$resultado['material']=$row;
$resultado['grid']=$row;
At the end you will have only the last 2 rows; I suggest you to use something like:
$resultado['material'][] = $row;
$resultado['grid'][] = $row;
This will save you pair rows in $resultado['grid'] and unpaired rows in $resultado['material'];
After the information in comments you can use this code:
$allResults = array();
while ($object = mysqli_fetch_object($result)) {
$resultado['id'] = $object->id;
$resultado['name'] = $object->name;
$resultado['item'] = $object->item;
$resultado['price'] = $object->price;
$allResults[] = $resultado;
}
file_put_contents("data.json", json_encode($allResults));
I'm working on a site and created this experimental script which populates a category menu dynamically based on the database entry.
It worked for a day and then suddenly stopped. I changed my includes for requires and it gave me this error message
Fatal error: Maximum execution time of 30 seconds exceeded in /home1/advertbo/public_html/dev_area/origocloud/include/views/blog/dbget.php on line 34
function getBlogMenu(){
$dbhost = 'localhost';
$dbuser = ' ';
$dbpass = ' ';
$con = mysql_connect($dbhost, $dbuser, $dbpass);
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("ado_ocblog", $con);
$htmlString = "";
$result = mysql_query(
"SELECT *
FROM subCat
JOIN headCat ON subCat.headid = headCat.id
ORDER BY headid ASC;");
$array = mysql_fetch_array($result);
mysql_close($con);
$pre = NULL;
$hc = 0;
$sc = 1;
while ($array) {
if($pre == NULL){
$pre = $row["headc"];
$test[0][0]=$row["headc"];
$test[0][1]=$row["subc"];
}
else
{
if($pre ==$row["headc"]){
$sc++;
$test[$hc][$sc] = $row["subc"];
}
else
{
$hc++;
$sc = 1;
$test[$hc][0]=$row["headc"];
$test[$hc][$sc]=$row["subc"];
$pre = $row["headc"];
}
}
}
foreach( $test as $arrays=>$cat)
{
$first = TRUE;
foreach($cat as $element)
{
if($first == TRUE)
{
$htmlString.= '<h3>'.$element.'</h3>
<div>
<ul>
';
$first = FALSE;
}
else
{
$htmlString.= '<li><a class="sub_menu" href="#">'.$element.'</a></li>';
}
}
$htmlString.= '</ul> </div>';
}
return $htmlString;
}
I'm really stuck, the page just keeps timing out the point where i call the function
Try this:
while ($array = mysql_fetch_array($result)) {}
Take a look on PHP docs http://php.net/mysql_fetch_array
If does not work, your SQL Query returns too much values and craches the php execution
=]
I think it's time to take a step back and look at what you're doing :) This function should do what you want (even if you fixed the infinite loop problem in the function you gave, I don't think it would act how you want it to.):
function getBlogMenu(){
$dbhost = 'localhost';
$dbuser = ' ';
$dbpass = ' ';
$con = mysql_connect($dbhost, $dbuser, $dbpass);
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("ado_ocblog", $con);
$htmlString = "";
$result = mysql_query(
"SELECT *
FROM subCat
JOIN headCat ON subCat.headid = headCat.id
ORDER BY headid ASC;");
// arrays can have strings as keys as well as numbers,
// and setting $some_array[] = 'value'; (note the empty brackets [])
// automatically appends 'value' to the end of $some_array,
// so you don't have to keep track of or increment indexes
while ($row = mysql_fetch_assoc($result))
{
$test[$row["headc"]][] = $row["subc"];
}
// don't close the connection until after we're done reading the rows
mysql_close($con);
// $test looks like: array('headc1' => array('subc1', 'subc2', 'sub3'), 'headc2' => array('subc4', 'subc5'), ...)
// so we step through each headc, and within that loop, step through each headc's array of subc's.
foreach($test as $headc => $subc_array)
{
$htmlString.= '<h3>'.$headc.'</h3><div><ul>';
foreach($subc_array as $subc)
{
$htmlString.= '<li><a class="sub_menu" href="#">'.$subc.'</a></li>';
}
$htmlString.= '</ul></div>';
}
return $htmlString;
}