How to fetch single row/data from Mysql_fetch_array? - mysql

I am reading .csv file through PHP using fgetcsv(). Now I am able to fetch I mean read data from .csv file.
Then I need to check SKU column with my fetch result & accordingly have to perform either Insertion Or Updation.
Suppose SKU is already present there, then I have to update my row in table else I need to insert new record.
I have write following code...Plz check n tell me where I am doing mistake-:
<?php
$row = 1;
if (($handle = fopen("localhost/data/htdocs/magento/var/import/Price.csv", "r")) !== FALSE)
{
while (($data = fgetcsv($handle, 8000, ",")) !== FALSE)
{
$num = count($data);
echo "<p> $num fields in line $row: <br /></p>\n";
for ($c=0; $c < $num; $c++)
{
$temp = $data;
$string = implode(";", $temp);
}
$pieces = explode(";", $string);
$col1 = $pieces[0];
$col2 = $pieces[1];
$col3 = $pieces[2];
$col4 = $pieces[3];
$db_name = "magento";
$con = mysql_connect("localhost", "magento", "password");
If (!$con)
{
die('Could not connect: ' . mysql_error());
mysql_close($con);
}
$seldb = mysql_select_db($db_name, $con);
$query_fetch = "SELECT `sku` from `imoprt_prices`";
$result_fetch = mysql_query($query_fetch);
$num_rows = mysql_num_rows($result_fetch);
for($i = 0; $i < $num_rows; $i++)
{
$value = mysql_result($result_fetch, i, 'sku');
if(strcmp('".$value."', '".$col2."') == 0)
{
$flag = 1;
break;
}
else
{
$flag = 0;
break;
}
}
if($flag == 1)
{
$query_upadte = "(UPDATE imoprt_prices SET customer_id= '".$col1."', sku ='".$col2."', price= '".$col3."', website= '".$col4."'
)";
mysql_query($query_upadte);
$row++;
}
if($flag == 0)
{
mysql_query("INSERT INTO `imoprt_prices`(`customer_id`,`sku`,`price`,`website`) VALUES('".$col1."','".$col2."','".$col3."','".$col4."')");
$row++;
}
}
}
?>

If you have an actual UNIQUE index on your imoprt_prices table, you can use the ON DUPLICATE KEY UPDATE syntax and simplify your code a bit to something similar to; (note, can't test, so see as pseudo code)
$db_name = "magento";
$con = mysql_connect("localhost", "magento", "password") or die(mysql_error());
$seldb = mysql_select_db($db_name, $con);
if (($handle = fopen("localhost/data/htdocs/magento/var/import/Price.csv", "r")) !== FALSE)
{
while (($data = fgetcsv($handle, 8000, ",")) !== FALSE)
{
$col1 = $pieces[0];
$col2 = $pieces[1];
$col3 = $pieces[2];
$col4 = $pieces[3];
$query_upadte = "INSERT INTO imoprt_prices (customer_id, sku, price, website) ".
"VALUES('".$col1."','".$col2."','".$col3."','".$col4."') ".
"ON DUPLICATE KEY UPDATE customer_id='".$col1."', price='".$col3.
"',website='".$col4."'";
mysql_query($query_upadte);
}
}
You may also want to either mysql_real_escape_string() or use parameterized queries to make sure there's no ' in your inserted values though. That is always a danger with building sql strings like this.
Simple demo here.

In the following snippet:
$query_upadte = "UPDATE imoprt_prices SET customer_id= '".$col1."', sku ='".$col2."', price= '".$col3."', website= '".$col4."'";
You're trying to update all the rows repeatedly, instead of just updating a single row. This is normally not allowed in MySQL. You need to specify a particular unique ID to be updated.

Related

WordPress and PHP | Check if row exists in database if yes don't insert data

I'm fairly new to WordPress and SQL. I have a contact form that I want to have the data be submitted to my WordPress database but only if the data that has been entered has not been entered before.
This is what i have so far, which sends data to my database when form is submitted.
if(isset($_POST['contact_us'])) {
$invalidContact = "<h5 class='invalidBooking'> Nope try again</h5>";
$successContact = "<h5 class='invalidBooking'> Message Sent!</h5>";
$table_name='contact_table';
global $wpdb;
$contact_name = esc_attr($_POST['contact_name']);
$contact_email = sanitize_email($_POST['contact_email']);
$subject = esc_attr($_POST['subject']);
$message = esc_attr($_POST['message']);
$error= array();
if (empty($contact_name)) {
$error['name_invalid']= "Name required";
}
if (empty($contact_email)){
$error['email_invaild']= "Email required";
}
// Im guessing some code here to check if row exists in database
if (count($error) >= 1) {
echo $invalid;
}
if (count($error) == 0) {
$data_array=array(
'Contact_Name'=>$contact_name,
'Contact_Email'=> $contact_email,
'Contact_Subject'=> $subject,
'Contact_Message'=> $message,
);
$rowResult=$wpdb->insert($table_name, $data_array,$format=NULL);
echo $successContact;
}
}
You may try this code
if (count($error) == 0) {
$data_array=array(
'Contact_Name'=>$contact_name,
'Contact_Email'=> $contact_email,
'Contact_Subject'=> $subject,
'Contact_Message'=> $message,
);
$query = "SELECT * FROM $table_name WHERE 'Contact_Name'= '$contact_name' AND 'Contact_Email' = '$contact_email' AND 'Contact_Subject' = '$subject' AND 'Contact_Message' = '$message'";
$query_results = $wpdb->get_results($query);
if(count($query_results) == 0) {
$rowResult=$wpdb->insert($table_name, $data_array,$format=NULL);
}
}
Hope this works for you.
fetch data using this code
$query = "SELECT * FROM {$wpdb->prefix}table WHERE column = 1";
echo $query;
$results = $wpdb->get_results($query);
and then you know what to do...

overwrite existing data based on returned values

Trying to overwrite existing data based on returned values, just want to get 'location' to update to the new info coming from a CSV import. Have a duplicated table with Oldlocation (all set to DW for testing, so any changes can be seen) Seems like it should be simple....:
$file = "allinv.CSV";
if(($handle = fopen($file, "r")) !== FALSE)
{ fgetcsv($handle);
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE){
$num = count($data);
for ($c=0; $c < $num; $c++) {
$col[$c] = $data[$c];}
$col1 = $col[1];
$sql = "SELECT Oldlocation FROM invbkup WHERE VIN = '$col1'"; ///works fine, gets old location for each record
$result = mysqli_query($con, $sql);
$row = mysqli_fetch_array($result);
$whl= $row['Oldlocation'];
$col8 = $col[73];
$query = "UPDATE allinv SET location = '$col8' WHERE $whl = 'DW' ";
echo $col1, $col8, $whl, "</br>";////can see all the info but get no changes in database.
$a= mysqli_query($con, $query);
}
fclose($handle);
}
Nevermind, it was a simple problem I fix by putting it in an if statement:
if($whl = 'DW'){
$query = "UPDATE allinv SET location = '$col8' WHERE VIN ='$col1'";
$a= mysqli_query($con, $query);}
sometimes you over complicate the problem yourself, take a break, drink some coffee and try not thinking so hard.

Bulk update to mySQL work too slow

currenly i use a simple code to update gender in my mysql
my code:
<?php
ini_set('max_execution_time', 30000);
$row = 0;
if (($handle = fopen("list.csv", "r")) !== FALSE) {
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
$num = count($data);
for ($c=0; $c < $num; $c++) {
$name = $data[0];
$gender = $data[1];
}
// connect to db
mysql_connect("***", "***", "***") or die("Connection Failed");
mysql_select_db("info")or die("Connection Failed");
$query = "UPDATE data SET gender = '$gender' WHERE fname = '$name'";
if(mysql_query($query)){
$row++;
echo "$row: ";
echo '<font color="RED">' . $name . '</font> <br>';
}
}
fclose($handle);
}
?>
code works but very slow,
can process up to 10k records per 1 hour and its too slow for me
can someone give me an idea what to do with it to increase speed
You are re-connecting to the DB in every single while iteration. Take the mysql_connect and mysql_select_db calls out of the while loop...

Creating Json file from mysql

i can't get more than one return in this json. when the original query returns 90k results.
i can't figure out what's hapening.
also the return i get isn't organized as it should. it return the following
{"material":["R8190300000","0"],"grid":["R8190300000","0"]}
sorry to ask this i have been looking for an answer but couln't get it in the internet.
<?php
$link = mysqli_connect("localhost","blablabla","blablabla","blablabla");
if (mysqli_connect_error()) {
die("Could not connect to database");
}
$query =" SELECT material,grid FROM ZATPN";
if( $result = mysqli_query( $link, $query)){
while ($row = mysqli_fetch_row($result)) {
$resultado['material']=$row;
$resultado['grid']=$row;
}
} else {
echo"doesnt work";
}
file_put_contents("data.json", json_encode($resultado));
?>
The problem is that you are overriding the value for the array keys:
$resultado['material']=$row;
$resultado['grid']=$row;
At the end you will have only the last 2 rows; I suggest you to use something like:
$resultado['material'][] = $row;
$resultado['grid'][] = $row;
This will save you pair rows in $resultado['grid'] and unpaired rows in $resultado['material'];
After the information in comments you can use this code:
$allResults = array();
while ($object = mysqli_fetch_object($result)) {
$resultado['id'] = $object->id;
$resultado['name'] = $object->name;
$resultado['item'] = $object->item;
$resultado['price'] = $object->price;
$allResults[] = $resultado;
}
file_put_contents("data.json", json_encode($allResults));

PHP MySQL script gone wrong

I'm working on a site and created this experimental script which populates a category menu dynamically based on the database entry.
It worked for a day and then suddenly stopped. I changed my includes for requires and it gave me this error message
Fatal error: Maximum execution time of 30 seconds exceeded in /home1/advertbo/public_html/dev_area/origocloud/include/views/blog/dbget.php on line 34
function getBlogMenu(){
$dbhost = 'localhost';
$dbuser = ' ';
$dbpass = ' ';
$con = mysql_connect($dbhost, $dbuser, $dbpass);
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("ado_ocblog", $con);
$htmlString = "";
$result = mysql_query(
"SELECT *
FROM subCat
JOIN headCat ON subCat.headid = headCat.id
ORDER BY headid ASC;");
$array = mysql_fetch_array($result);
mysql_close($con);
$pre = NULL;
$hc = 0;
$sc = 1;
while ($array) {
if($pre == NULL){
$pre = $row["headc"];
$test[0][0]=$row["headc"];
$test[0][1]=$row["subc"];
}
else
{
if($pre ==$row["headc"]){
$sc++;
$test[$hc][$sc] = $row["subc"];
}
else
{
$hc++;
$sc = 1;
$test[$hc][0]=$row["headc"];
$test[$hc][$sc]=$row["subc"];
$pre = $row["headc"];
}
}
}
foreach( $test as $arrays=>$cat)
{
$first = TRUE;
foreach($cat as $element)
{
if($first == TRUE)
{
$htmlString.= '<h3>'.$element.'</h3>
<div>
<ul>
';
$first = FALSE;
}
else
{
$htmlString.= '<li><a class="sub_menu" href="#">'.$element.'</a></li>';
}
}
$htmlString.= '</ul> </div>';
}
return $htmlString;
}
I'm really stuck, the page just keeps timing out the point where i call the function
Try this:
while ($array = mysql_fetch_array($result)) {}
Take a look on PHP docs http://php.net/mysql_fetch_array
If does not work, your SQL Query returns too much values and craches the php execution
=]
I think it's time to take a step back and look at what you're doing :) This function should do what you want (even if you fixed the infinite loop problem in the function you gave, I don't think it would act how you want it to.):
function getBlogMenu(){
$dbhost = 'localhost';
$dbuser = ' ';
$dbpass = ' ';
$con = mysql_connect($dbhost, $dbuser, $dbpass);
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("ado_ocblog", $con);
$htmlString = "";
$result = mysql_query(
"SELECT *
FROM subCat
JOIN headCat ON subCat.headid = headCat.id
ORDER BY headid ASC;");
// arrays can have strings as keys as well as numbers,
// and setting $some_array[] = 'value'; (note the empty brackets [])
// automatically appends 'value' to the end of $some_array,
// so you don't have to keep track of or increment indexes
while ($row = mysql_fetch_assoc($result))
{
$test[$row["headc"]][] = $row["subc"];
}
// don't close the connection until after we're done reading the rows
mysql_close($con);
// $test looks like: array('headc1' => array('subc1', 'subc2', 'sub3'), 'headc2' => array('subc4', 'subc5'), ...)
// so we step through each headc, and within that loop, step through each headc's array of subc's.
foreach($test as $headc => $subc_array)
{
$htmlString.= '<h3>'.$headc.'</h3><div><ul>';
foreach($subc_array as $subc)
{
$htmlString.= '<li><a class="sub_menu" href="#">'.$subc.'</a></li>';
}
$htmlString.= '</ul></div>';
}
return $htmlString;
}