How do I rewrite this query to show the correct value for the sub query claims if there isn't any record in listings for this account_id, but there is 1 record in claimed_listings. Thanks!
SELECT status, (SELECT count(id)
FROM claimed_listings
WHERE account_id = 1) AS claims
FROM listings
WHERE account_id = 1
I'm expecting to see a result like
status | claims
A | 1
F | 1
E | 1
in this case there are three listings and 1 claim listing.
Problem is if there is no listing(s) and 1 claim listing i get no results at all?
try this:
SELECT a.Account_ID, Count(b.Account_ID) TotalAcount
FROM claimed_Listings a LEFT JOIN listings b
on a.account_ID = b.Account_ID
WHERE a.Account_ID = 1
GROUP BY a.Account_ID
Try the following (hope I got you right..)
select count(cl.id), count(cl.account_id)
from claimed_listings cl
where cl.account_id=1 and cl.account_id not in (select account_id from listings)
group by cl.id
having count(cl.account_id) > 0;
Related
I have a strange result when performing a lateral join on a query
I have the following table structure
task->id
comment -> id , taskId, comment
tasklink -> taskId, type, userid
with a single task record (id 10), 1 comment record ("row1", "a test comment") and 5 tasklink records (all with taskid 10)
I expected this query
select task.id,
json_agg(json_build_object('id',c.id, 'user',c.comment)) as comments,
json_agg(json_build_object('type',b.type, 'user',b.userid)) as users
FROM task
left join lateral (select c.* from comment c where task.id = c.taskid) c on true
left join lateral (select b.* from taskuserlink b where task.id = b.taskid) b on true
where task.id = 10
GROUP BY task.id ;
to return
id | comments | users
---------------------------------------------------------------------
10 "[{"id":"row1","user":"a test comment"}]" "[{"type":"updatedBy","user":1},"type":"closedBy","user":5},"type":"updatedBy","user":5},"type":"createdBy","user":5},{"type":"ownedBy","user":5}]"
instead, I got this
id | comments | users
10 "[{"id":"row1","user":"a test comment"},{"id":"row1","user":"a test comment"},{"id":"row1","user":"a test comment"},{"id":"row1","user":"a test comment"},{"id":"row1","user":"a test comment"}]" "[{"type":"updatedBy","user":1},{"type":"closedBy","user":5},{"type":"updatedBy","user":5},{"type":"createdBy","user":5},{"type":"ownedBy","user":5}]"
ie , for every link row, the comment row is duplicated
I am thinking that I am missing something really obvious, but as I have only just started using Postgres (and sql ) I'm a little stumped
I would appreciate some guidance on where I'm going wrong
Move the aggregates into subqueries:
select id, comments, users
from task t
left join lateral (
select json_agg(json_build_object('id',c.id, 'user',c.comment)) as comments
from comment c
where t.id = c.taskid
) c on true
left join lateral (
select json_agg(json_build_object('type',b.type, 'user',b.userid)) as users
from taskuserlink b
where t.id = b.taskid
) b on true
DbFiddle.
So guys, trying to write a query to get the count of statuses where project_id = ? and statuses in 'New' from a couple of tables so let me break it down.
I have these three tables
Case_Status
id case_status
1 New
2 Failed
3. Accepted
Referral
id case_status_id project_id application_id
1 1 1 20
2 2 1 21
Project
id name
1 project1
2 project2
So this is my query
SELECT COUNT(referrals.id) AS count_all, case_statuses.case_status AS counted
FROM "case_statuses" LEFT OUTER JOIN "referrals" ON "referrals"."case_status_id" = "case_statuses"."id"
WHERE "case_statuses"."deleted_at" IS NULL AND (case_statuses.case_status IN ('New') AND referrals.project_id = 1)
GROUP BY case_statuses.case_status;
This is my result
count_all counted
1 New
1 Failed
But I am expecting this result instead
count_all counted
1 New
1 Failed
0 Accepted
Does anyone know what's wrong with my query that isnt showing count for all the case_statuses?
Thanks
Conditions on the second table (in a left join) should be in the on clause:
SELECT COUNT(r.id) AS count_all, cs.case_status AS counted
FROM case_statuses cs LEFT OUTER JOIN
referrals r
ON r.case_status_id = cs.id AND r.project_id = 1
WHERE cs.deleted_at IS NULL AND cs.case_status NOT IN ('New')
GROUP BY cs.case_status;
Otherwise, the WHERE clause turns the outer join into an inner join.
change your query like this
SELECT COUNT(referrals.id) AS count_all, case_statuses.case_status AS counted
FROM "case_statuses" LEFT JOIN "referrals" ON "referrals"."case_status_id" = "case_statuses"."id" AND referrals.project_id = 1
WHERE "case_statuses"."deleted_at" IS NULL AND case_statuses.case_status NOT IN ('New')
GROUP BY case_statuses.case_status;
Given your data and the expected result you just need to loose the WHERE clause.
SELECT COUNT(referrals.id) AS count_all, case_statuses.case_status AS counted
FROM case_statuses
LEFT OUTER JOIN referrals ON referrals.case_status_id = case_statuses.id
GROUP BY case_statuses.case_status;
See this fiddle for details.
I have a two tables one is Userregistration and second is user_verificationcode from which i have to get only those record whose email and mobile status are 1.Below are my table structure
Userregistration table
........................................
id fullname mobile_no email
.........................................
5 varun 12344567 abc#gmail
6 nitin 12345678 def#gmail
user_verificationcode
.............................................
id user_id codetype status
............................................
1 5 email 0
2 5 mobile 1
3 6 email 1
4 6 mobile 1
I want this kind of output
........................................
id fullname mobile_no email
.........................................
6 nitin 12345678 def#gmail
For this i have used below query but its not working i am not getting how to achieve this.
SELECT * FROM Userregistration
INNER JOIN user_verificationcode ON Userregistration.`id`=user_verificationcode.`user_id`
where user_verificationcode.`codetype`='email'
and user_verificationcode.`status`='1'
and user_verificationcode.`codetype`='mobile'
and user_verificationcode.`status`='1'
SELECT r.*
FROM Userregistration r
INNER JOIN user_verificationcode ve ON r.id = ve.user_id
and ve.codetype = 'email'
and ve.status = 1
INNER JOIN user_verificationcode vm ON r.id = vm.user_id
and vm.codetype = 'mobile'
and vm.status = 1
or
SELECT *
FROM Userregistration
where id in
(
select user_id
from user_verificationcode
group by user_id
having sum(codetype = 'email' and status = 1) > 0
and sum(codetype = 'mobile' and status = 1) > 0
)
You probably want to return only Userregistration fields, since you already know the info contained in user_verificationcode table. In this case you can use the following query:
SELECT t1.*
FROM Userregistration AS t1
JOIN (
SELECT user_id
FROM user_verificationcode
WHERE codetype IN ('mobile', 'email')
GROUP BY user_id
HAVING COUNT(DISTINCT codetype) = 2 AND SUM(status <> 1) = 0
) AS t2 ON t1.id = t2.user_id
You may would like to do something like this
SELECT Userregistration.id, Userregistration.fullName, Userregistration.mobile_no,
Userregistration.email FROM Userregistration
INNER JOIN user_verificationcode
ON Userregistration.id=user_verificationcode.user_id
WHERE user_verificationcode.codetype='email' AND user_verificationcode.status = 1
SELECT Userregistration.id,
Userregistration.fullName,
Userregistration.mobile_no,
Userregistration.email
FROM Userregistration
INNER JOIN user_verificationcode ON
Userregistration.id=user_verificationcode.user_id AND
user_verificationcode.status=1
WHERE user_verificationcode.codetype='email' AND
user_verificationcode.codetype='mobile'
I have a MySQL table
"ratings", with
an ID column
a column called like_dislike (holds either null, 0, or 1),
and a column called lesson_id (a foreign key from lessons).
the MySQL table, "lessons", with
an ID column
a teacher_id column
I need to select this information:
"SELECT r.like_dislike FROM ratings r INNER JOIN lessons l on l.lesson_id = r.lesson_id";
However, this actually part of a much larger SQL statement, and what I would like to do is:
Foreach lesson_id, if like_dislike == 0, SELECT count(like_dislike) as like
AND
Foreach lesson_id, if like_dislike == 1, SELECT count(like_dislike) as dislike
I do not know how to turn this pseudo code into SQL. I also need to do this in SQL, rather than in something like PHP, because it is part of a larger SQL statement whose conversion into properly formatted arrays is deeply troubling.
You should be able to accomplish this with grouping. For example:
SELECT r.lesson_id, COUNT(*) AS like
FROM ratings r
INNER JOIN lessons l ON l.lesson_id = r.lesson_id
WHERE r.like_dislike = 0
GROUP BY r.lesson_id;
The same for dislike, just change the WHERE clause to
WHERE r.like_dislike = 1
EDIT:
This can be combined into one query as requested, by adding another level of grouping:
SELECT r.lesson_id, r.like_dislike, COUNT(*) AS count
FROM ratings r
INNER JOIN lessons l ON l.lesson_id = r.lesson_id
GROUP BY r.lesson_id, r.like_dislike;
This will give you output, for example:
+-----------+--------------+-------+
| lesson_id | like_dislike | count |
+-----------+--------------+-------+
| 1 | 0 | 12 |
| 1 | 1 | 7 |
| 2 | 0 | 1 |
| 2 | 1 | 4 |
+-----------+--------------+-------+
so for lesson_id of 1, there are 12 likes, and 7 dislikes, etc...
EDIT 2:
To get one row for each lesson_id, you can modify the statement a little:
SELECT r.lesson_id,
CASE WHEN r.like_dislike = 0 THEN COUNT(*) END AS like,
CASE WHEN r.like_dislike = 1 THEN COUNT(*) END AS dislike
FROM ratings r
INNER JOIN lessons l ON l.lesson_id = r.lesson_id
GROUP BY r.lesson_id, r.like_dislike;
For that matter, you don't even need to join on the lessons table at all, unless you are somehow getting ratings that do not link to a lesson. If you want to include lessons that have no ratings, then you will have to change to an OUTER join:
SELECT l.lesson_id,
CASE WHEN r.like_dislike = 0 THEN COUNT(*) END AS like,
CASE WHEN r.like_dislike = 1 THEN COUNT(*) END AS dislike
FROM lessons l
LEFT JOIN ratings r ON r.lesson_id = l.lesson_id
GROUP BY l.lesson_id, r.like_dislike;
Maybe you can use a case statement, something like this:
SELECT r.lesson_id,
case when r.like_dislike == 0 then (count(*)) end as like,
case when r.like_dislike == 1 then (count(*)) end as dislike
FROM ratings r INNER JOIN lessons l ON l.lesson_id = r.lesson_id
GROUP BY r.lesson_id, r.like_dislike
I haven't tested it, but you can see the idea. Further, you must set a case to count 1's and another to count 0's because like_dislike can be null.
try this
SELECT if(r.like_dislike =0 ,count(like_dislike) as like , if( r.like_dislike =1 , count(like_dislike) as dislike, 'its null'))
FROM ratings r
INNER JOIN lessons l on l.lesson_id = r.lesson_id
if you are adding condition on yr datatable then code it like below:
Declare #Counter int
Set #Counter=(SELECT Count(Student_ID) as 'StudentCount' FROM tbCourseSemOne
where Student_ID=1 Having Count(Student_ID) < 6 and Count(Student_ID) > 0)
if(#Counter <6)
print'Sorry! You cannot add more than five subject data for a single stduent'
else
print'Insert Code'
hope it helps
The MYSQL query below gives me the output I need when there are records found in the main query e.g.
RETURN:
username | total_favs
this_user | 4
But I get nothing return if no records found in main query. I want to get something like this:
RETURN:
username | total_favs
null | 4
SELECT
c.username,
(SELECT COUNT(*) AS total_records FROM favourites f WHERE f.pic_id = 177) AS `total_favs`
FROM
comments c
WHERE
c.pic_id = 177
Switch it around so favourites is the main query:
SELECT c.username, COUNT(*) AS total_favs
FROM favourites f
LEFT OUTER JOIN comments c on f.pic_id = c.pic_id
WHERE f.pic_id = 177
GROUP BY c.username