Exact word match (non-English characters) - mysql

I have a table in my Mysql db (utf-8). I want to get exact word matches from this table.
My query is:
SELECT matched_rows FROM MY_TABLE WHERE string = 'MY_STRING'
Problem is when I search for 'ağaç' (tree in English) I got all rows with ağaç, agac, ağac, agaç.
what I want to get is only 'ağaç' not the rest. I also don't want results with something agac.
How do I get this effect?

i followed #gintas answer and made some modifications. in the end this one worked for me:
SELECT ROWS FROM MY_TABLE WHERE CONVERT(string_field_name USING latin5) = CONVERT('MY_STRING' USING latin5)

You should try defining collation in the query
SELECT matched_rows FROM MY_TABLE WHERE string = 'MY_STRING' COLLATE utf8_general_ci

SELECT * FROM users WHERE email REGEXP '[[:<:]]abhi[[:>:]]'
try this link on SO i think you didnt try this?
LINK: url

Related

MySQL return no results from select * where varchar="" query

I'm having issue with my study project for creating database in MySQL.
I've imported data using LOAD to my created table from a CSV file. Now when I'm executing select * from mytable everything show up perfectly, but when I execute select * from bi_jogging.routes as r where r.Creator_Email="jhenderson7c#bbb.org"
I get nothing.
The email is there, I've tried different syntax options but it seems to be something else, I suspect something with the varchar format, I really have nothing in mind.
For other tables it works fine and others not.
You can try using the query:
select * from bi_jogging.routes as r where r.Creator_Email like "%jhenderson7c#bbb.org%"
If like operator shows the result then there may be white spaces in the email, please double check..
For join try this:
select * from bi_jogging.routes as r join bi_jogging.buddies as b
on b.Email like '%r.Creator_Email%'
I think it should work. Again check with same code.
select * from bi_jogging.routes as r where r.Creator_Email='jhenderson7c#bbb.org'
if [select * from mytable] this works ,then try to copy the email from result and paste it in where clause.
There may be conflicts between quotes.
your table entry contains quotes???
check properly. i think you have quotes in your table entry,so when you try this,
select * from bi_jogging.routes as r where r.Creator_Email like "%jhenderson7c#bbb.org%"
'%' sign matches with any character and you will get the result.
Inside the tablejhenderson7c#bbb.org and "jhenderson7c#bbb.org" are completely different.
I found spaces in the mysql tables after few emails, so I guess that was it. burned 8 hours on this one, thank you all. I could not find the spaces at the end of the mail by looking at it, I had to hit backspace to see that only after two hits the last char is deleted
this helped me : UPDATE bi_jogging.results set Mail_Found = TRIM(Replace(Replace(Replace(Mail_Found,'\t',''),'\n',''),'\r',''));

FullText search with additional where

I'm having trouble working with the match against functionality of MySQL.
I converted my table and a simple query like:
SELECT * FROM 'objectclient_objecten' WHERE MATCH('dh_omschrijving) AGAINST ('these search words');
works! But.. i want to add other "where" elements. Something like:
SELECT * FROM 'objectclient_objecten' WHERE MATCH('dh_omschrijving) AGAINST ('these search words') AND `dh_status` = 1;
But then.. No results. It seems impossible to add something after using match. Is this right? Or is there a workaround?
try that
SELECT * FROM 'objectclient_objecten' WHERE MATCH(dh_omschrijving) AGAINST ('these search words') AND `dh_status` = 1;
^^^^^^^^^^^^^^^^^---without quotes here
MATCH(here columns without quotes) , you are using column between quote.

Concatenate a string with curdate in mysql

I have the following query:
INSERT INTO insertlog (Inforamtion) VALUES (
concat("Row Was Inserted",curdate());
MySQL is returning an error, but I cannot figure out why. My google searches do not show examples on how to perform something like this.
use it simpler like that
INSERT INTO insertlog (Inforamtion)
SELECT concat("Row Was Inserted ",curdate()) ;
be sure if your column is Information or Inforamtion
your query also works but you missed ) in the end . here demo with both solutions :
Demo to try here
I think you are missing one closing )
Moreover as Bill pointed, you may have spelled your column name incorrectly - information

UPDATE mysql database replace strings

I have in my db strings like www.domain.com and http://www.domain.com. I want to prepend to all entries the http:// but not affect other urls and as a result have this: http://http://www.domain.com
Can this be done with mysql only? I have used REPLACE(field,'www','http://www'), but this replaces also the http://www with http://http://www
Thanks in advance
EDIT
I forgot to mention that in the field there might be entries which don't contain www or http://www and therefore I don't want to alter or maybe there are entries like <p>domain</p> in which CONCAT() prepends the http:// before <p>
Try adding a WHERE clause to your update to only update fields that do not already have 'http://'. Test it out like this
SELECT CONCAT('http://', field) FROM foo WHERE LOCATE('http://', field)=0
and your UPDATE syntax would be:
UPDATE foo SET field=CONCAT('http://',field) WHERE LOCATE('http://', field)=0
I won't worry about performance as this seems like a one-off kind of script. That said, you can couple LEFT and CONCAT to achieve this:
UPDATE mytable
SET mycolumn = CONCAT('http://',mycolumn)
WHERE LEFT(mycolumn,7) <> 'http://'
Do note that I'm not taking CapItaliZation in to account. You may also want to consider sanitizing the information either before adding it to the database, or maybe make a trigger to do it for you.
Search and Replace Query - mysql replace
Here is the SQL query to replace string in your MySQL database table:
UPDATE table_name SET column_name = REPLACE(column_name,'original_string','replace_string')
Here is what I did to change the path URLs in all my previous posts.
UPDATE `wp_posts` SET `post_content` = REPLACE(`post_content`,'http://localhost/','https://sureshkamal1.wordpress.com/')

Escaping % sign in subquery

I have a query in mySQL that's meant to return search terms that are used on our site. Yes, this is for a tag cloud, and yes, I know it's a mullet :)
We've got an admin page where administrators can view search terms and choose to exclude them from showing up in the cloud. These words go into the "badWords" table. We've gotten some terms like "foo%2525252525252520bar", and we're having trouble getting those excluded.
In pseudocode, the query to get the search terms for the cloud is:
SELECT * FROM `searchTerms` WHERE `word` NOT IN ( SELECT `word` FROM `badWords` )
This works fine, unless one of the terms returned from the subquery has a % in it. Is there a way to escape the entire subquery? I've tried doing a
replace( SELECT `word` FROM `badWords`, '%', '\%' )
... but that's apparently not syntactically correct.
I can do two queries if need be, but wondered if there's a way to get it done as is.
Thanks!
==============================
UPDATE: closing this for now, as I think the error lies elsewhere. Will report back once I know for sure, but don't want folks wasting time answering the question here if it's not the correct question...
Upvoted both of the replies received so far. Thanks, guys.
==============================
UPDATE 2: sigh Nevermind... can't close it :\
==============================
FINAL UPDATE: Well, looks like escaping the value isn't the problem. The admin page passes the value in the URL before it's added to the badWords table. In passing the value via the URL, it changes. So what's added to badWords is actually "foo%25252525252520bar" (there's one less "25" sequence). If I manually update the value in badWords and add back the missing "25" it works as expected. So no need to replace or escape anything. I just need to fix those URL values properly.
==============================
I don't think the % is your problem here. I think that you're trying to use REPLACE() on the subquery itself (SELECT ...), and not on a column value (word). Try this instead:
SELECT * FROM `searchTerms`
WHERE `word` NOT IN (
SELECT REPLACE(`word`, '%', '\%') AS word FROM `badWords`
);
Good luck!
I'm not very good with MySQL syntax, but SQL Server let's you do it this way:
SELECT * FROM `searchTerms` WHERE `word` NOT IN ( SELECT REPLACE(`word`, '%', '\%') FROM `badWords` )
NOTE: Basically all I did was move your REPLACE over some =) Hope this helps.