IN Clause selects all variables - mysql

Question

When I run this procedure:
SELECT * FROM photo
LEFT JOIN photo_selectedTags
ON photo.COUNTER = photo_selectedTags.PHOTO_COUNTER
WHERE photo_selectedTags.TAGS_COUNTER IN (6,192)
It retrieves rows where TAGS_COUNTER = 6 OR 192
How do I retrieve the rows from 'photo' where TAGS_COUNTER = 6 AND 192?
Corrected: the IN for ALL

Answer 1

The basic idea is this:
SELECT PHOTO_COUNTER
FROM photo_selectedTags
WHERE TAGS_COUNTER in (6, 192)
group by PHOTO_COUNTER
having count(distinct TAGS_COUNTER) = 2 --2 matches # of items in IN clause
You can then do this to get the rest of the columns:
SELECT *
from PHOTO_COUNTER
LEFT JOIN photo_selectedTags
ON photo.COUNTER = photo_selectedTags.PHOTO_COUNTER
where photo.COUNTER in (
SELECT PHOTO_COUNTER
FROM photo_selectedTags
WHERE TAGS_COUNTER in (6,192)
group by PHOTO_COUNTER
having count(distinct TAGS_COUNTER) = 2 --2 matches # of items in IN clause
) a

Answer 2

Edit
Now that i understand what you want and DB structure, try with this:
SELECT * FROM photo
LEFT JOIN photo_selectedTags
ON photo.COUNTER = photo_selectedTags.PHOTO_COUNTER
WHERE photo_selectedTags.TAGS_COUNTER = 6 AND photo_id IN
(SELECT photo_id FROM photoSELECT * FROM photo
LEFT JOIN photo_selectedTags
ON photo.COUNTER = photo_selectedTags.PHOTO_COUNTER
WHERE photo_selectedTags.TAGS_COUNTER = 192)
I don't know if photo_id is an actual field of your table, but try to adapt it to your structure
Obviously in the first SELECT don't insert PHOTO_COUNTER because i'll be always the same value and it haven't much sense.

Answer 3

I would propose to use 2 joins
SELECT *
FROM photo
JOIN photo_selectedTags as photo_selectedTags6 -- this join restricts to 'photo.COUNTER' whic have TAGS_COUNTER = 6
ON photo.COUNTER = photo_selectedTags6.PHOTO_COUNTER
AND photo_selectedTags6.TAGS_COUNTER = 6
JOIN photo_selectedTags as photo_selectedTags192 -- this join restricts to 'photo.COUNTER' whic have TAGS_COUNTER = 192
ON photo.COUNTER = photo_selectedTags192.PHOTO_COUNTER
AND photo_selectedTags192.TAGS_COUNTER = 192
Also would be possible to achive it with analytical functions (if supported by your DB)
-- This one works on teradata. Something similar should work on oracle. Don't know about others
SELECT *
FROM photo
LEFT JOIN photo_selectedTags
ON photo.COUNTER = photo_selectedTags.PHOTO_COUNTER
QUALIFY max(case when photo_selectedTags.TAGS_COUNTER = 6 then 1 end) over (partition by photo.COUNTER) = 1
AND max(case when photo_selectedTags.TAGS_COUNTER = 192 then 1 end) over (partition by photo.COUNTER) = 1
If you have many values in the list (in addition to 192,6), then this might be possible solution
SELECT *
FROM photo
JOIN
(
SELECT PHOTO_COUNTER, count(distinct TAGS_COUNTER) cnt
FROM photo_selectedTags
WHERE TAGS_COUNTER in (192,6)
HAVING cnt = 2 -- adjust this according to the number of different values
) as pht
ON photo.COUNTER = pht.PHOTO_COUNTER
In subquery only PHOTO_COUNTERs are left which have both (192 and 6), then this is joined