How to manipulate each line in a file in TCL - tcl

I'm trying to write some data from iperf to a file using tcl script.The file has more than 100 lines. Now i need to parse the first 10 lines, neglect it and consider the next set of 10 lines and print it, again i need to neglect the next set of 10 lines and print the next 10 lines and keep continuing until i reach the end of file. How could i do it programmatic ally?
exec c:\\iperf_new\\iperf -c $REF_WLAN_IPAddr -f m -w 2M -i 1 -t $run_time > xx.txt
set fp [open "xx.txt" r ]
set file_data [read $fp]
set data [split $file_data "\n"]
foreach line $data {
if {[regexp {(MBytes) +([0-9\.]*)} $line match pre tput]==1 } {
puts "Throughput: $tput Mbps"
}

Well, as your example shows, you have found out how to split a (slurped) file into lines and process them one-by-one.
Now what's the problem with implementing "skip ten lines, process ten lines, skip another ten lines etc"? It's just about using a variable which counts lines seen so far plus selecting a branch of code based on its value. This approach has nothing special when it comes to Tcl: there are commands available to count, conditionally select branches of code and control looping.
If branching based on the current value of a line counter looks too lame, you could implement a state machine around that counter variable. But for this simple case it looks like over-engeneering.
Another approach would be to pick the necessary series of lines out of the list returned by split using lrange. This approach might use a nice property of lrange which can be told to return a sublist "since this index and until the end of the list", so the solution really boils down to:
set lines [split [read $fd] \n]
parse_header [lrange $lines 0 9]
puts [join [lrange $lines 10 19] \n]
parse_something_else [lrange 20 29]
puts [join [lrange $lines 30 end] \n]
For a small file this solution looks pretty compact and clean.

If I understood you correctly, you want to print lines 11-20, 31-40, 51-60,... The following will do what you want:
package require Tclx
set counter 0
for_file line xxx.txt {
if {$counter % 20 >= 10} { puts $line }
incr counter
}
The Tclx package provides a simple way to read lines from a file: the for_file command.

Related

FPGA - Using TCL to increment a constant

I'm having a problem that involves an increment of a constant in a VHDL library .vhd file.
I need to create a tcl script that will look for a specific line from the library file:
constant a : integer :=0;
and will increment the 0 to a 1 and the 1 to a 2 with every run of the tcl script.
If the file isn't very large (no more than, oh, 100MB) then the easiest way is to read it all in, find the line, do the update "in place" in memory, and then write it all back out again.
# read the file
set f [open theFile.vhd]
set lines [split [read $f] "\n"]
close $f
# find the line with a regular expression (remember, brace your REs!)
set RE {^\s*constant\s+a\s*:\s*integer\s*:=\s*(\d+)\s*;\s*$}
set idx [lsearch -regexp $lines $RE]
# extract the current value and update it
regexp $RE [lindex $lines $idx] -> value
incr value
# write back into the list of lines
lset lines $idx "constant a:integer := $value;"
# write the lines back to the file
set f [open the file.vhd w]
puts -nonewline $f [join $lines "\n"]
close $f
In this case we are using the regular expression twice, and I made the RE by taking the line and putting in whitespace matchers (\s+/\s*) and number matchers (\d+) in the sensible places.

Search in file for number, increment and replace

I have a VHDL file which has a line like this:
constant version_nr :integer := 47;
I want to increment the number in this line in the file. Is there a way to accomplish this with TCL?
This is principally a string operation. The tricky bit is finding the line to operate on and picking the number out of it. This can be occasionally awkward, but it is mainly a matter of choosing a suitable regular expression (as this is the kind of parsing task that they excel at). A raw RE to do the matching would be this:
^\s*constant\s+version_nr\s*:integer\s*:=\s*\d+\s*;\s*$
This is essentially converting all possible places for a whitespace sequence into \s* (except where whitespace is mandatory, which becomes \s+) and matching the number with \d+, i.e., a digit sequence. We then add in parentheses to capture the interesting substrings, which are the prefix, the number, and the suffix:
^(\s*constant\s+version_nr\s*:integer\s*:=\s*)(\d+)(\s*;\s*)$
Now we have enough to make the line transform (which we'll do as a procedure so we can give it a nice name):
proc lineTransform {line} {
set RE {^(\s*constant\s+version_nr\s*:integer\s*:=\s*)(\d+)(\s*;\s*)$}
if {[regexp $RE $line -> prefix number suffix]} {
# If we match, we increment the number...
incr number
# And reconcatenate it with the prefix and suffix to make the new line
set line $prefix$number$suffix
}
return $line
}
In Tcl 8.7 (which you won't be using yet) you can write this as this more succinct form:
proc lineTransform {line} {
# Yes, this version can be a single (long) line if you want
set RE {^(\s*constant\s+version_nr\s*:integer\s*:=\s*)(\d+)(\s*;\s*)$}
regsub -command $RE $line {apply {{- prefix number suffix} {
# Apply the increment when the RE matches and build the resulting line
string cat $prefix [incr number] $suffix
}}}
}
Now that we have a line transform, we've just got to apply that to all the lines of the file. This is easily done with a file that fits in memory (up to a few hundred MB) but requires additional measures for larger files as you need to stream from one file to another:
proc transformSmallFile {filename} {
# Read data into memory first
set f [open $filename]
set data [read $f]
close $f
# Then write it back out, applying the transform as we go
set f [open $filename w]
foreach line [split $data "\n"] {
puts $f [transformLine $line]
}
close $f
}
proc transformLargeFile {filename} {
set fin [open $filename]
# The [file tempfile] command makes working with temporary files easier
set fout [file tempfile tmp [file normalize $filename]]
# A streaming transform; requires that input and output files be different
while {[gets $fin line] >= 0} {
puts $fout [transformLine $line]
}
# Close both channels; flushes everything to disk too
close $fin
close $fout
# Rename our temporary over the original input file, replacing it
file rename $tmp $filename
}

Regarding got to command in tcl

I want to print character from the next line:
say :
when this variable dum=183 exists in file , then print the very next charater from next line.
Note : I am using tcl
Thanks,
This should help you get started.
The typical idioms for working with a file one line at a time are:
1) linewise reading:
set f [open thefile.txt]
while {[gets $f line] >= 0} {
# work with the line of text in "line"
}
close $f
2) block reading with line splitting:
set f [open thefile.txt]
set text [read $f]
close $f
set lines [split [string trim $text] \n]
foreach line $lines {
# work with the line of text in "line"
}
This can be simplified by using a package:
package require fileutil
::fileutil::foreachLine line thefile.txt {
# work with the line of text in "line"
}
Another way is to search and extract using a regular expression. This is the worst method as it is inflexible and very likely to be buggy in use.
set f [open thefile.txt]
set text [read $f]
close $f
# this regular expression is an example
if {[regexp {\ydum\y[^\n]*.(.)} $text -> thecharacter]} {
# the character you wanted should be in "thecharacter"
}
Documentation:
>= (operator),
close,
fileutil (package),
foreach,
gets,
if,
open,
package,
read,
regexp,
set,
split,
string,
while,
Syntax of Tcl regular expressions

Manipulating file in tcl language

First time poster and new to TCL so please pardon my knowledge.
I've found a few examples on stackoverflow and with that help created a script.
I need to modify few lines of a file, I've tried the following (see code). I can seem to add the line of interest but it does not write it in the correct location e.g. if I want to replace line 3 it adds line after line 3
and moreover deletes subsequent lines if there is more than one line operation.
Lastly could some one kindly suggest the best way to identify the line of interest with name rather than line number. Name is always in the form Filter.HpOrd_n =
where n is 0...k
Data in info.dat
AA
BB
Filter.HpOrd_1 = 2
Filter.HpOrd_2 = 2
Filter.HpOrd_3 = 0.1
Filter.HpOrd_4 = 0.2
CC
DD
EE
FF
Code:
set fd [open "info.dat" r+]
set i 0
while { [gets $fd line] != -1 } {
set line [split $line "\n"]
incr i
if {$i == 3} {
set nLine [lreplace $line 0 0 Filter.LoPass]
puts $fd [join $nLine "\n"]
}
if {$i == 6} {
set nLine [lreplace $line 0 0 Filter.Butterworth]
puts $fd [join $nLine "\n"]
}
}
close $fd
With plain Tcl:
# the input and output file handles
set fin [open info.dat r]
set fout [file tempfile fname]
# process the file
while {[gets $fin line] != -1} {
puts $fout [string map {
"Filter.HpOrd_1" "Filter.LoPass"
"Filter.HpOrd_4" "Filter.Butterworth"
} $line]
}
close $fin
close $fout
# backup the original and overwrite it
file link -hard info.dat.bak info.dat
file rename -force -- $fname info.dat
TCL is just a meta language and set fd [open "info.dat" r+] is related to general file descriptor handling. If you open a file descriptor "r+" you can read and write to that file descriptor, but one file descriptor always points to one point in a file.
With "r+" your file descriptor initially points to the start of the file. Then you gets $fd line a line from the file, so $fd points to the start of the second line afterwards. Now you puts $fs [join $nline "\n"] blindly overwriting from the start of the second line and so on.
Generally you cannot replace lines in one file, but you will write a second file and move that after you closed both files. You can overwrite with seek, but you overwrite from a point in the file. So what you put should always have the same size, of you have read before.
Plain files (in basically all programming languages) are byte/character oriented rather than line oriented. This means 1) that you need to use a seek operation to get back to the beginning of the line you want to overwrite, and 2) unless the new line is exactly the same length as the old one, you will experience stub lines around it.
You have other problems as well. set line [split $line "\n"] doesn't do anything: you've just read line from gets, so it's guaranteed not to have any newlines in it. [join $nLine "\n"] doesn't do what you probably think it does: it will replace any sequences of whitespace in $line with single newlines, but it will not place any newline at the end of the string.
Unless your files are insanely large, I recommend something like this:
Replace by line number
proc lineReplace args {
set lines [split [lindex $args end] \n]
foreach {n line} [lrange $args 0 end-1] {
set index [incr n -1]
if {$index > 0} {
lset lines $index $line
}
}
join $lines \n
}
package require fileutil
fileutil::updateInPlace info.dat {
lineReplace
3 Filter.LoPass
6 Filter.Butterworth
}
In the "front end" you only specify the command to use and thereafter pairs of line number / new line text.
In the "back end" (the lineReplace command) the parameter args will contain those number / line pairs and at the end, as a single item, the complete contents of the file. The file contents are then split into a list of lines, and for every number / line pair you replace one of the items in that list. Finally, the list of lines are joined back into a string with newlines between each line. This string is returned by lineReplace to fileutil::updateInPlace, which replaces the old contents in the file with the returned string.
Replace by name
proc lineReplaceByName args {
set lines [split [lindex $args end] \n]
foreach {name line} [lrange $args 0 end-1] {
set index [lsearch $lines $name*]
if {$index > 0} {
lset lines $index $line
}
}
join $lines \n
}
fileutil::updateInPlace info.dat {
lineReplaceByName
Filter.HpOrd_1 Filter.LoPass
Filter.HpOrd_4 Filter.Butterworth
}
In this case the "back end" calculates the line number by searching for the given name at the beginning of each line. If the name isn't found, the replacement operation is skipped. Otherwise it's the same as before.
Replacing just the name
If you don't want to replace the complete line, but just the name part of it, some changes are necessary. If you are 100% sure that 1) the name never has any whitespace in it, and 2) there is always whitespace between the name and the =, you can just replace lset lines $index $line with lset lines $index 0 $line. If you want to play it safer, you can replace the line with
lset lines $index [regsub {.+(?=\s*=\s*)} [lindex $lines $index] $line]
which uses a regular expression to find the character region that precedes the = character (optionally with whitespace around it) and then replaces that with the text you provided.
The fileutil package is a part of the Tcllib companion library to Tcl.
Documentation: fileutil package, foreach, if, incr, join, lindex, lrange, lsearch, lset, package, proc, regsub, seek, set, split

Looking for a search string in a file and using those lines for processing in TCL

To be more precise:
I need to be looking into a file abc.txt which has contents something like this:
files/f1/atmp.c 98 100
files/f1/atmp1.c 89 100
files/f1/atmp2.c !! 75 100
files/f2/btmp.c 92 100
files/f2/btmp2.c !! 85 100
files/f3/xtmp.c 92 100
The script needs to find "!!" and use those lines to print out the following as output:
atmp2.c 75
btmp2.c 85
Any help?
this should do the trick.
set data {files/f1/atmp.c 98 100
files/f1/atmp1.c 89 100
files/f1/atmp2.c !! 75 100
files/f2/btmp.c 92 100
files/f2/btmp2.c !! 85 100
files/f3/xtmp.c 92 100}
set lines [split $data \n]
foreach line $lines {
set match [regexp {(\S+)\s+!!\s+(\d+)} $line -> file num]
if {$match} {puts "$file $num"}
}
Although regexp has a -all switch I don't think we can use it here as we only get the last match vars with -all
If your file isn't huge, you can slurp the whole thing into memory, split the lines into a TCL list, and then iterate through the list looking for a match. For example:
set fh [open foo]
set lines [read $fh]
close $fh
set lines [split $lines "\n"]
foreach line $lines {
if { [regexp {.*/(\S+\.c)\s*!!\s*(\d+)} $line match file data] } {
puts "$file $data"
}
}
This will successfully return just the lines with "!!" in them. With your posted corpus, the results are:
atmp2.c 75
btmp2.c 85
I might be tempted in this case to exec to awk:
set output [exec awk {$2 == "!!" {print $1, $3}} abc.txt]
puts $output
The trick is to combine the code that reads lines from the file with a regular expression that detects matching lines and extracts the relevant parts (a one-step process with regexp). The only tricky part is working out what exactly to use as the regular expression, so that you get exactly what you want. I'm going to guess that you're after the parts of the filenames after the /, that those filenames won't contain spaces, and that the number you're after is the entirety of the first digit sequence after the double exclamation. (Other formats are possible, some of which are easier to extract with other tools such as scan.) That would give us something like this:
set f [open abc.txt]
while {[gets $f line] >= 0} {
if {[regexp {([^\s/]+)\s+!!\s+(\d+)} $line -> name value]} {
# Or do whatever you want with these
puts "$name $value"
}
}
close $f
(The gets command with two arguments returns the length of line read, or -1 on failure. For normal files the only failure mode is EOF, so we can just terminate the loop when we get a negative value. Other kinds of channels can be more complex…)