I should note that id is not unique in the tdemog_pfp table - there is a unique field there that auto-increments - could this be an issue?
Ok, I have the following SQL query:
SELECT id, name, total_staff AS StaffCount, COUNT( q60a ) AS TotalResp, (COUNT( q60a ) / total_staff * 100) AS Perc
FROM tdemog_pfp
LEFT JOIN tresults_pfp ON tdemog_pfp.id = tresults_pfp.q60a
GROUP BY name
ORDER BY name
Now, the demog table has multiple rows where entries can have q59, q60a, q60b and so on for the colomn qnum
I want to bring back the results WHERE qnum = q60a but I have a problem, when I add it to the above to make the following - it brings back zero results (an empty result set), which is incorrect:
SELECT id, name, total_staff AS StaffCount, COUNT( q60a ) AS TotalResp, (COUNT( q60a ) / total_staff * 100) AS Perc
FROM tdemog_pfp
LEFT JOIN tresults_pfp ON tdemog_pfp.id = tresults_pfp.q60a
WHERE qnum = q60a
GROUP BY name
ORDER BY name
Where am I going wrong?
Thanks,
H.
Make your test part of the JOIN condition instead of testing in the WHERE clause.
SELECT id, name, total_staff AS StaffCount, COUNT( q60a ) AS TotalResp, (COUNT( q60a ) / total_staff * 100) AS Perc
FROM tdemog_pfp
LEFT JOIN tresults_pfp ON tdemog_pfp.id = tresults_pfp.q60a
AND qnum = q60a
GROUP BY name
ORDER BY name
Doing this: WHERE qnum = q60a is transforming your query into an inner join; hence, no results in this case.
Related
I have the following sql query:
SELECT v.venue_id, s.zip, COUNT( * )
FROM bcs_scans s
JOIN bcs_scanners sc ON s.uuid = sc.uuid
JOIN bcs_venues v ON sc.venue_id = v.venue_id
WHERE v.banlist_id = '625'
AND s.del =0
GROUP BY s.zip
ORDER BY COUNT( * ) DESC
Which returns the count of individual zip codes, their count, and associated venue.
How do I go about selecting the top 5 zip codes for each unique venue id?
I believe I can run a subquery that groups results by venue id with the top 5 zip counts, but I am unsure of where to start
Could be you select the result in this way ... a bit complex ..
using the having for extract the value that match the max count group by venue_id from your original query ..
SELECT v.venue_id as venue_id, s.zip as , COUNT( * ) as num
FROM bcs_scans s
JOIN bcs_scanners sc ON s.uuid = sc.uuid
JOIN bcs_venues v ON sc.venue_id = v.venue_id
WHERE v.banlist_id = '625'
AND s.del =0
GROUP BY s.zip
HAVING ( v.venue_id, COUNT( * )) in
(select venue_id, max(num)
from
(SELECT v.venue_id as venue_id, s.zip as , COUNT( * ) as num
FROM bcs_scans s
JOIN bcs_scanners sc ON s.uuid = sc.uuid
JOIN bcs_venues v ON sc.venue_id = v.venue_id
WHERE v.banlist_id = '625'
AND s.del =0
GROUP BY s.zip
ORDER BY COUNT( * ) DESC ) a t
group by venue_id)
ORDER BY COUNT( * ) limit 5
I have the following table structure:
Customers - Cust_Orders - Cust_Items - Cust_Payments - Drivers
id id id id id
company cid oid oid name
driver price amount
date qty date
vat
What I want to do is showing last unpaid order marked by a specific driver id + the sum of all unpaid orders for that particular customer except the order that is already selected.
Since there might be more than one cust_items & more than one cust_payments I had to use select from select as otherwise I would have wrong sums & things got messy till I reached a point I forgot what I was doing.
Any Help would be greatly appreciated.
My current SQL which lacks the final part only (sum of other unpaid orders amounts):
SELECT `customers`.`company`,
T1.*,
ROUND( IFNULL( SUM(`cust_payments`.`amount`), 0 ), 2) AS `paid`
FROM (
SELECT `cust_orders`.*,
ROUND( IFNULL( SUM(`cust_items`.`qty` * `cust_items`.`price`), 0 ), 2) AS `total`,
SUM( ( `cust_items`.`price` * `cust_items`.`qty` * `vat` ) / 100) AS `vat`
FROM `cust_orders`
LEFT JOIN `cust_items` ON `cust_orders`.`id` = `cust_items`.`oid`
GROUP BY `cust_orders`.`id`
) `T1`
LEFT JOIN `customers` ON `T1`.`cid` = `customers`.`id`
LEFT JOIN `cust_payments` ON `T1`.`id` = `cust_payments`.`oid`
WHERE `T1`.`driver` = ? GROUP BY `T1`.`id` HAVING (`T1`.`total` - `paid`) > ?
ORDER BY `T1`.`id` DESC LIMIT 1
Can you try
SELECT
x.id,
x.company,
y.id,
y.cid,
y.driver,
y.date,
#ut:=ROUND(SUM(z.qty*z.price),2) AS unpaid_total,
#uv:=SUM((#ut*z.vat)/100) AS unpaid_vat,
#st:=ROUND(SUM(b.qty*b.price),2)-#ut AS sum_total,
SUM((#st*b.vat)/100)-#uv AS sum_vat
FROM Customers x
INNER JOIN Cust_Orders y ON x.id=y.cid
INNER JOIN Cust_Items z ON y.id=z.oid
LEFT JOIN Cust_Orders a ON x.id=a.cid
LEFT JOIN Cust_Items b ON a.id=b.oid
WHERE
y.driver=? AND
NOT EXISTS (SELECT * FROM Cust_Payments WHERE oid=y.id) AND
NOT EXISTS (SELECT * FROM Cust_Payments WHERE oid=a.id)
GROUP BY x.id,x.company, y.id, y.cid, y.driver, y.date
I'm selecting total count of villages, total count of population from my tables to build statistics. However, there is something wrong. It returns me everything (530 pop (there are 530 pop in total), (106 villages (there are 106 users in total)) in first row, next rows are NULLs
SELECT s1_users.id userid, (
SELECT count( s1_vdata.wref )
FROM s1_vdata, s1_users
WHERE s1_vdata.owner = userid
)totalvillages, (
SELECT SUM( s1_vdata.pop )
FROM s1_users, s1_vdata
WHERE s1_vdata.owner = userid
)pop
FROM s1_users
WHERE s1_users.dp >=0
ORDER BY s1_users.dp DESC
Try removing s1_users from inner SELECTS
You're already using INNER JOINs. Whan you list tables separated with comma, it is a shortcut for INNER JOIN.
Now, the most obvious answer is that your subqueries using aggregating functions (COUNT and SUM) are missing a GROUP BY clauses.
SELECT s1_users.id userid, (
SELECT count( s1_vdata.wref )
FROM s1_vdata, s1_users
WHERE s1_vdata.owner = userid
GROUP BY s1_vdata.owner
)totalvillages, (
SELECT SUM( s1_vdata.pop )
FROM s1_users, s1_vdata
WHERE s1_vdata.owner = userid
GROUP BY s1_vdata.owner
)pop
FROM s1_users
WHERE s1_users.dp >=0
ORDER BY s1_users.dp DESC
However, using subqeries in column list is really inefficient. It casues subqueries to be run once for each row in outer query.
Try like this instead
SELECT
s1_users.id AS userid,
COUNT(s1_vdata.wref) AS totalvillages,
SUM(s1.vdata.pop) AS pop
FROM
s1_users, s1_vdata --I'm cheating here! There's hidden INNER JOIN in this line ;P
WHERE
s1_users.dp >= 0
AND s1_users.id = s1_vdata.owner
GROUP BY
s1_users.id
ORDER BY
s1_users.dp DESC
SELECT s1_users.id AS userid,
(
SELECT COUNT(*)
FROM s1_vdata
WHERE s1_vdata.owner = userid
) AS totalvillages,
(
SELECT SUM(pop)
FROM s1_vdata
WHERE s1_vdata.owner = userid
) AS pop
FROM s1_users
WHERE dp >= 0
ORDER BY
dp DESC
Note that this is less efficient than this query:
SELECT s1_users.id AS user_id, COUNT(s1_vdata.owner), SUM(s1_vdata.pop)
FROM s1_users
LEFT JOIN
s1_vdata
ON s1_vdata.owner = s1_users.id
GROUP BY
s1_users.id
ORDER BY
dp DESC
since the aggregation needs to be done twice in the former.
SELECT userid,totalvillages,pop from
(
SELECT s1_users.id as userid, count( s1_vdata.wref ) as totalvillages
FROM s1_vdata, s1_users
WHERE s1_vdata.owner = userid
GROUP BY s1_users.id) tabl1 INNER JOIN
(
SELECT s1_users.id as userid, SUM( s1_vdata.pop ) as pop
FROM s1_users, s1_vdata
WHERE s1_vdata.owner = userid
GROUP BY s1_users.id) tabl2 on tabl1.userid = tabl2.userid
I have 2 tables of concern - 'videoComments', 'storyComments'.
I need to find the 'posterID' that has the most entries in videoComments and storyComments. Here's the code I have so far, but it only calls videoComments:
$sql = "SELECT (SELECT posterID
FROM videoComments
GROUP BY posterID
ORDER BY COUNT(posterID) DESC LIMIT 1) ) AS mostSocialUser ";
How do I pull it and compare the COUNT of posterID from both tables?
Use:
SELECT x.posterid,
COUNT(y.posterid) + COUNT(z.posterid) AS numComments
FROM (SELECT vc.posterid
FROM VIDEOCOMMENTS vc
UNION
SELECT sc.posterid
FROM STORYCOMMENTS sc) x
LEFT JOIN VIDEOCOMMENTS y ON y.posterid = x.posterid
LEFT JOIN STORYCOMMENTS z ON z.posterid = x.posterid
GROUP BY x.posterid
ORDER BY numComments DESC
LIMIT 1
Try this:
SELECT (
SELECT posterID FROM (
SELECT posterID FROM videoComments
UNION
SELECT posterID FROM storyComments
) GROUP BY posterID
ORDER BY COUNT(posterID) DESC LIMIT 1
) AS mostSocialUser
I'm trying to run this query:
UPDATE anothertable
INNER JOIN (SELECT *,
LEAST(table1.from_price, table2.from_price, table3.from_price) AS cheapestPrice
FROM (SELECT * FROM table1 v WHERE hotelid >= 1
UNION
SELECT * FROM table2 c WHERE hotelid >= 1
UNION
SELECT * FROM table3 k WHERE hotelid >= 1) AS temp
GROUP BY temp.hotelid, temp.country) AS i ON anothertable.id = i.hotelid
AND anothertable.country = i.country
SET price = i.cheapestPrice,
op = i.to
However I cannot get the LEAST function to get access to a field called "from_price".
Ideas?
You should use Min instead of Least:
Update anothertable
Join (
Select hotelid, country, to
, Min(from_price) AS cheapestPrice
From (
Select hotelid, country, from_price, to
From table1 v
Where hotelid >= 1
Union
Select hotelid, country, from_price, to
From table2 c
Where hotelid >= 1
Union
Select hotelid, country, from_price, to
From table3 k
Where hotelid >= 1
) AS temp
Group By temp.hotelid, temp.country, temp.to
) As i
On anothertable.id = i.hotelid
And anothertable.country = i.country
Set price = i.cheapestPrice
, op = i.to
Edit
As pointed out in comments, I omitted the to column from the inner temp query. However, it occurs to me that it isn't clear how to should be included because you are using an awful feature of MySQL with respect to declaring the Group By columns. I'm assuming that you need to include to in the Group By however if that is not the case, you should be explicit about what aggregate function it should use on the to column.
Here's an alternate where I use Min on the to column:
Update anothertable
Join (
Select temp.hotelid, temp.country
, Min(temp.to) As to
, Min(temp.from_price) AS cheapestPrice
From (
Select v.hotelid, v.country, v.from_price, v.to
From table1 v
Where hotelid >= 1
Union
Select c.hotelid, c.country, c.from_price, c.to
From table2 c
Where hotelid >= 1
Union
Select k.hotelid, k.country, k.from_price, k.to
From table3 k
Where hotelid >= 1
) AS temp
Group By temp.hotelid, temp.country
) As i
On anothertable.id = i.hotelid
And anothertable.country = i.country
Set price = i.cheapestPrice
, op = i.to