Getting nested unread messages from within a message thread - mysql

I have two tables, message_threads and messages. When returning a results set of message_threads, I'm performing a JOIN on the two tables to see whether any message from the sender (to the receiver) within that thread is unread.
Below is my SQL...
SELECT mt.id AS thread_id, m.id AS message_id,
m.is_read, m.from_type, mt.company_id
FROM message_threads AS mt
LEFT JOIN messages AS m
ON m.thread_id = mt.id;
...the full results set from a given query...
+-----------+------------+---------+-----------+------------+
| thread_id | message_id | is_read | from_type | company_id |
+-----------+------------+---------+-----------+------------+
| 1 | 1 | N | company | 1 |
| 1 | 9 | N | company | 1 |
| 1 | 19 | N | company | 1 |
| 2 | 2 | Y | coder | 1 |
| 2 | 3 | N | company | 1 |
| 2 | 6 | N | company | 1 |
| 2 | 8 | N | company | 1 |
| 3 | 4 | N | company | 1 |
| 6 | 13 | N | company | 1 |
| 6 | 14 | N | coder | 1 |
| 6 | 15 | N | company | 1 |
| 8 | 20 | N | company | 1 |
| 8 | 21 | N | coder | 1 |
| 4 | 5 | N | company | 2 |
| 4 | 7 | N | company | 2 |
| 4 | 22 | N | coder | 2 |
| 5 | 10 | N | company | 8 |
| 5 | 11 | N | coder | 8 |
| 5 | 12 | N | company | 8 |
| 7 | 16 | N | company | 18 |
| 7 | 17 | N | coder | 18 |
| 7 | 18 | N | company | 18 |
+-----------+------------+---------+-----------+------------+
...and the desired result set:
+-----------+------------+---------+-----------+------------+
| thread_id | message_id | is_read | from_type | company_id |
+-----------+------------+---------+-----------+------------+
| 1 | 19 | N | company | 1 |
| 2 | 2 | Y | coder | 1 |
| 3 | 4 | N | company | 1 |
| 6 | 14 | N | coder | 1 |
| 8 | 21 | N | coder | 1 |
| 4 | 22 | N | coder | 2 |
| 5 | 11 | N | coder | 8 |
| 7 | 17 | N | coder | 18 |
+-----------+------------+---------+-----------+------------+
How can I perform this query? I've tried GROUP BY and DISTINCT, and neither quite do what I want. I also can't do this using a WHERE clause to filter my data, because I need all the threads regardless of the is_read flag.
Thanks!

There are a lot of ways of doing this. If your looking to see the number of unread messages from a thread you may want to join an inner query.
Example:
SELECT
mt.id AS thread_id,
mt.company_id,
CASE WHEN m_c.m_unread IS NOT NULL THEN m_c.m_unread ELSE 0 END AS unread
FROM message_threads AS mt
LEFT JOIN
(
SELECT
thread_id,
COUNT(*) AS m_unread
FROM messages
WHERE
is_read ='N'
GROUP BY 1
)m_c
ON mt.thread_id = m_c.thread_id

Related

Mysql Row To Column Select Specific Data

I have column user and rating.
SELECT rating.idUser, user.nmUser, rating.idBengkel, rating.nilai FROM `rating`
JOIN user on rating.idUser = user.idUser
WHERE rating.idBengkel=1 or rating.idBengkel=2
Result :
+--------+---------------------------+-----------+-------+
| idUser | nmUser | idBengkel | nilai |
+--------+---------------------------+-----------+-------+
| 10 | Hudson mas77 | 1 | 5 |
| 11 | Vina Nurfadzilah | 1 | 5 |
| 12 | Angelica Amartya | 1 | 5 |
| 15 | Syahrul K | 1 | 4 |
| 27 | Ashar Murdihastomo | 1 | 5 |
| 28 | Eril Obeit Choiri | 1 | 2 |
| 29 | Ariyadi | 1 | 3 |
| 30 | Robertus Dwian Augusta | 1 | 4 |
| 31 | Irfan Setiaji | 1 | 4 |
| 33 | Baby Ayuna | 1 | 5 |
| 9 | Nur k hamid | 2 | 5 |
| 10 | Hudson mas77 | 2 | 5 |
| 13 | Yuana Putra | 2 | 4 |
| 14 | Nanda Aulia Irza Ramadhan | 2 | 4 |
| 26 | taufiq rahman | 2 | 5 |
| 27 | Ashar Murdihastomo | 2 | 5 |
| 28 | Eril Obeit Choiri | 2 | 5 |
| 30 | Robertus Dwian Augusta | 2 | 4 |
| 44 | halim budiono | 2 | 1 |
+--------+---------------------------+-----------+-------+
When i try to get similar records using this query
SELECT rating.idUser, user.nmUser FROM rating
JOIN user
ON rating.idUser = user.idUser
WHERE rating.idBengkel = 1 and rating.idUser
IN (SELECT rating.idUser from rating WHERE rating.idBengkel = 2)
ORDER by idUser
Result :
+-----------+------------------------+
| idUser | nmUser |
+-----------+------------------------+
| 10 | Hudson mas77 |
| 27 | Ashar Murdihastomo |
| 28 | Eril Obeit Choiri |
| 30 | Robertus Dwian Augusta |
+-----------+------------------------+
The result work fine, but I want show column 'nilai' as ItemX and ItemY. Those are user similar data. In this case I have 4 similar user who rate on idBengkel=1 and idBengkel=2 as the results above. I want it like the table below.
+--------+------------------------+-------+-------+
| idUser | nmUser | ItemX | ItemY |
+--------+------------------------+-------+-------+
| 10 | Hudson mas77 | 5 | 5 |
| 27 | Ashar Murdihastomo | 5 | 5 |
| 28 | Eril Obeit Choiri | 2 | 5 |
| 30 | Robertus Dwian Augusta | 4 | 4 |
+--------+------------------------+-------+-------+
I need solution for this and i was trying with this solution in https://stackoverflow.com/a/7976379/12396302 but it resulting more than one row. Please help me, I cant implement that query's solution. Regards!
I think you need below query -
SELECT rating.idUser,
user.nmUser,
MAX(CASE WHEN rating.idBengkel = 1 THEN rating.nilai END) ItemX,
MAX(CASE WHEN rating.idBengkel = 2 THEN rating.nilai END) ItemY,
FROM `rating`
JOIN user on rating.idUser = user.idUser
WHERE rating.idBengkel IN (1, 2)
GROUP BY rating.idUser,
user.nmUser

MySQL SELECT 8 unique users, then SELECT all records within those 8 users, then SELECT 4 most recent and available records of each 8 users?

I have a database (dates are just examples for order sake)...
---------------------
| user | item | date |
---------------------
| 1 | a | 123 |
| 3 | b | 124 |
| 1 | c | 125 |
| 2 | d | 126 |
| 5 | i | 127 |
| 4 | e | 128 |
| 6 | f | 129 |
| 9 | g | 130 |
| 3 | h | 131 |
| 9 | s | 132 |
| 1 | j | 133 |
| 2 | k | 134 |
| 1 | l | 135 |
| 1 | m | 136 |
| 1 | n | 137 |
| 8 | o | 138 |
| 5 | p | 139 |
| 9 | q | 140 |
| 7 | r | 141 |
---------------------
I would like to get all records up to the first 8 unique users, which would make the results...
---------------------
| user | item | date |
---------------------
| 1 | a | 123 |
| 3 | b | 124 |
| 1 | c | 125 |
| 2 | d | 126 |
| 5 | i | 127 |
| 4 | e | 128 |
| 6 | f | 129 |
| 9 | g | 130 |
| 3 | h | 131 |
| 9 | s | 132 |
| 1 | j | 133 |
| 2 | k | 134 |
| 1 | l | 135 |
| 1 | m | 136 |
| 1 | n | 137 |
| 8 | o | 138 |
---------------------
Then from those records, I'd like to get the most recent 4 records per unique user, making the results look like...
---------------------
| user | item | date |
---------------------
| 3 | b | 124 |
| 2 | d | 126 |
| 5 | i | 127 |
| 4 | e | 128 |
| 6 | f | 129 |
| 9 | g | 130 |
| 3 | h | 131 |
| 9 | s | 132 |
| 1 | j | 133 |
| 2 | k | 134 |
| 1 | l | 135 |
| 1 | m | 136 |
| 1 | n | 137 |
| 8 | o | 138 |
---------------------
Ideally I would be able to do this with one query. The closest I've been able to come is with this query:
SELECT users,
GROUP_CONCAT(items)
FROM db
GROUP BY users
ORDER BY date
LIMIT 8
But GROUP_CONCAT gives back all results for that user, not just the amount in the selection.
I've also tried...
SELECT users
FROM db AS u1
JOIN (SELECT DISTINCT users FROM db) AS u2 ON u1.users = u2.users
from another suggestion I found but this also didn't work.
I've tried a ton of other things that I didn't really save because they didn't work and I was pretty confident I'd figure it out, but it's been two weeks and I haven't got close. If any SQL gurus are out there that can point me in the right direction, that would be really great. Thanks.
Hoping this can help you.
--get all records up to the first 8 unique users,depending on there first order date
select distinct a.user,a.date as first_order_date from yourtable as a where
a.date = (select MIN(date) from yourtable as b where a.user=b.user) order by a.date LIMIT 8
Then using above result to get the most recent 4 records per unique user like below:
select * from yourtable as t where t.date in
(select date from yourtable as t2 where t.user=t2.user order by t2.date desc LIMIT 4 ) and
t.user in (select distinct a.user,a.date as first_order_date from yourtable as a
where a.date = (select MIN(date) from yourtable as b where a.user=b.user) order by a.date LIMIT 8)
References:
correlated subqueries
Example

Mysql Best way to query notifications like on stackoverflow

I have 4 tables:
comments
+----+-----------+--------------+-------+
| id | content | user_id | article_id |
+----+-----------+--------------+-------+
| 1 | Comment 1 | 2 | 5 |
| 2 | Comment 2 | 5 | 3 |
| 3 | Comment 3 | 1 | 6 |
| 4 | Comment 4 | 6 | 8 |
| 5 | Comment 5 | 1 | 6 |
| ...| ... | ... | ... |
+----------------+---------+------------+
votes
+----+----------+--------------+---+
| id | type | user_id | article_id |
+----+----------+--------------+---+
| 1 | 1 | 2 | 5 |
| 2 | 1 | 3 | 3 |
| 3 | 0 | 1 | 6 |
| 4 | 1 | 7 | 4 |
| 5 | 0 | 9 | 4 |
| 6 | 0 | 1 | 6 |
| ...| ... | ... | ... |
+------------+----------+----------+
notifications (object_id is the id of the vote|comment)
+----+----------+--------------+-------------+-------------+--------------+
| id | object_url| object_id |activitytype_id| sender_id | recipient_id |
+----+----------+------------+---------------+-------------+--------------+
| 1 | /../../.. | 1 | 2 | 2 | 6 |
| 2 | /../../.. | 2 | 2 | 3 | 2 |
| 3 | /../../.. | 1 | 1 | 2 | 7 |
| 3 | /../../.. | 2 | 1 | 5 | 2 |
| 3 | /../../.. | 3 | 1 | 1 | 3 |
| 3 | /../../.. | 3 | 3 | 1 | 2 |
| 3 | /../../.. | 4 | 2 | 7 | 8 |
| 3 | /../../.. | 5 | 3 | 9 | 1 |
| 3 | /../../.. | 6 | 3 | 1 | 5 |
| ...| ... | ... | ... | | |
+----+-----------+-----------+---------------+-------------+--------------+
activitytypes
+----+------------+
| id | label |
+----+------------+
| 1 | comment |
| 2 | vote up |
| 3 | vote down |
| ...| ... |
+-----------------+
I would like to get notifications like on stackoverflow.
I want to query the last notification (with comment content if the activity type is a comment or null if not) for every activitytype and object_url combinaison for a specific user.
For example I have 3 artiles A,B and C which all have 3 comments, 4 voteup and 2 votedown. How to get the last comment, voteup and votedown for every article ?
I have tried this query:
SELECT n.id, n.object_url , n.object_id, n.activitytype_id, IF(n.activitytypeId = 1,
(SELECT content FROM comments WHERE id=n.object_id), null) AS activitycontent
FROM notifications n WHERE n.recipient_id =1
GROUP BY n.activitytype_id,n.object_url
ORDER BY n.id DESC
But it doesn't work. Can anyone help ?
EDIT:
This following query in farhadamjady's answer gives me the first comment:
SELECT
n.id,
n.object_url,
n.object_id,
n.activitytype_id,
cm.content AS activitycontent
FROM
notifications n
LEFT OUTER JOIN `COMMENT` AS cm ON cm.id = n.object_id and n.activitytypeId = 1
WHERE
n.recipient_id = 1
GROUP BY
n.activitytype_id,
n.object_url
HAVING MAX(cm.id)
ORDER BY
n.id DESC
How can I change it to get the last ?
you should use left outer join like this :
SELECT
n.id,
n.object_url,
n.object_id,
n.activitytype_id,
cm.content AS activitycontent
FROM
notifications n
LEFT OUTER JOIN `COMMENT` AS cm ON cm.id = n.object_id and n.activitytypeId = 1
WHERE
n.recipient_id = 1
GROUP BY
n.activitytype_id,
n.object_url
HAVING MAX(cm.id)
ORDER BY
n.id DESC

MySQL how to find averages / day for different clients with different creation days

I've tried the following queries but unfortunately they don't work :(.
Worth mentioning that each customer has more than one CustomerUsers
select (a.TotalJobs / b.DaysActive) from
(select count(jr.id) as TotalJobs
from jobrequests jr, customers c, customerusers cu
where jr.customeruserid=cu.id
and cu.customerid=c.id
group by c.name) as a,
(select datediff(curdate(), from_unixtime(c.CreationTime)) as DaysActive
from customers c
group by c.name) as b
Please see below the tables
Jobs:
+----+--------------+
| ID | JobRequestID |
+----+--------------+
| 1 | 1 |
| 2 | 1 |
| 3 | 1 |
| 4 | 1 |
| 5 | 1 |
| 6 | 2 |
| 7 | 2 |
| 8 | 3 |
| 9 | 3 |
| 10 | 3 |
| 11 | 4 |
| 12 | 4 |
| 13 | 5 |
| 14 | 5 |
| 15 | 6 |
| 16 | 7 |
| 17 | 8 |
| 18 | 8 |
| 19 | 9 |
| 20 | 10 |
+----+--------------+
JobRequests:
+----+---------------+
| ID | CustomeUserID |
+----+---------------+
| 1 | 1 |
| 2 | 1 |
| 3 | 2 |
| 4 | 2 |
| 5 | 2 |
| 6 | 3 |
| 7 | 4 |
| 8 | 4 |
| 9 | 4 |
| 10 | 5 |
| 11 | 5 |
| 12 | 5 |
| 13 | 6 |
| 14 | 6 |
| 15 | 7 |
+----+---------------+
CustomerUsers:
+----+------------+
| ID | CustomerID |
+----+------------+
| 1 | 1 |
| 2 | 1 |
| 3 | 1 |
| 4 | 2 |
| 5 | 2 |
| 6 | 2 |
| 7 | 2 |
| 8 | 3 |
| 9 | 3 |
| 10 | 4 |
+----+------------+
Customers:
+----+------+--------------+
| ID | Name | CreationTime |
+----+------+--------------+
| 1 | a | 1415814194 |
| 2 | b | 1415814194 |
| 3 | c | 1415986994 |
| 4 | d | 1415986994 |
+----+------+--------------+
For the moment it returns 16 results (4X4), dividing each result from 1st sub-query to each result from the 2nd one (each of these sub-queries return 4 results). Can anyone please help me to get this to divide only 1 result from sub-query 1 to it's corespondent from sub-query 2?
Thank you in advance.
I suspect that you can do what you want this a query like this:
select c.name, count(*) / (datediff(curdate(), from_unixtime(c.CreationTime))
from customerusers cu join
jobrequests jr
on jr.customeruserid = cu.id join
customers c
on cu.customerid = c.id
group by c.name;
I don't see why you need two subqueries for this.
I'm guessing you need to join your results together -- as currently written, you're producing a cartesian product.
Try something like this adding c.id to each subquery (it's better to group by it presumably rather than the name):
select (a.TotalJobs / b.DaysActive)
from (
select c.id,
count(jr.id) as TotalJobs
from jobrequests jr
join customers c on jr.customeruserid=cu.id
join customerusers cu on cu.customerid=c.id
group by c.id) a join (
select c.id,
datediff(curdate(), from_unixtime(c.CreationTime)) as DaysActive
from customers c
group by c.id) b on a.id = b.id
Please note, I've updated your syntax to use the more standard join syntax.

Creating a formulaic query with multiple columns and joined columns

I'm trying to produce a formula which pits our students' reward points against their negative behaviour flags.
Students are given LEAP points (in the transactions table) for their positive behaviour. They get more points depending on the category of their reward, i.e. Model Citizen gives the student 10 points.
On the other hand, students are given single Flags for negative behaviour. The category of the Flag is then weighted in a database table, i.e. the Aggressive Defiance category will have a high weighting of 4 whereas Low Level Disruption will only be worth 1.
The difficulty therefore is trying to factor in the Flag categories' weightings. They're stored in the categories table under the Weight column.
Here's the SQL fiddle: http://sqlfiddle.com/#!2/2e5756
In my head, the pseudo-SQL code would look something like this...
SELECT
CONCAT( stu.Surname, ", ", stu.Firstname ) AS `Student`,
SUM(t.Points) AS `LEAP Points`,
SUM(<<formula>>) AS `Flags`
( `LEAP Points` - `Flags` ) AS `Worked Out Points Thing`
FROM student stu
LEFT JOIN transactions t ON t.Recipient_ID = stu.id
LEFT JOIN flags f ON f.Student_ID = stu.id
LEFT JOIN categories c ON f.Category_ID = c.ID
GROUP BY stu.id
However, it's the <<formula>> that I have no idea how to implement in MySQL. It needs to be something like this:
SUM OF[ Each of Student's Flags * that Flag's Category Weighting ]
So, if a student has these flags...
#1 f.Reason "Being naughty", f.Category_ID "1", c.Title "Low Level Disruption", c.Weight "1"
#1 Reason "Aggressively naughty!", Category "Aggressive Defiance", Category Weighting "4"
#1 Reason "Missed detention", Category "Missed Detention", Category Weighting "3"
They would have a total of 1+4+3 = 9 points to use in the Worked Out Points Thing equation.
The desired output therefore is essentially...
Student LEAP Points Flags Equation Points LEAP Points minus Flag Points
D Wraight 1000 800 200
D Wraight2 500 800 -300
D Wraight3 1200 300 900
From the SQL fiddle above, here is the required output.. I've missed out some students because I had to work these out manually:
STUDENT FLAGS LEAP EQUATION
137608 4 (2+2) 12 (2+5+5) 8 (12-4)
139027 2 (2) 7 (2+5) 5 (7-2)
139041 4 (2+1+1+NULL) 8 (2+2+2+2) 4 (8-4)
139892 4 (4) 0 -4 (0-4)
138832 4 (4) 0 -4 (0-4)
34533 4 (4) 0 -4 (0-4)
137434 0 10 (2*5) 10 (10-0)
Which will help us to work out the choices we make available to each student when looking at end of year reward trips.
Hope that makes sense.. it's kinda boggled my head trying to explain it..
Thanks in advance,
figure out your 'formula' bit first because it's the deepest part. work outwards.
build a table of flags * weight per student
select sum(weight), student_id from flags f
join categories c
on f.category_id = c.id
group by student_id
so now you've got a table of flag values to minus from sum of transactions per student
select sum(points), recipient_id from transactions
group by recipient_id
so now we have two tables with positive and negative values by student id (assuming obviously that student id is recipient id)
you want those with transactions but without flags to appear in the result, so outer join.
and number minus null is null so ifnull function on the flags to get 0
select a.student, points - ifnull(penalties, 0) as netPoints
from
(select sum(points) as points, recipient_id as student from transactions
group by student) as a
left outer join
(select sum(weight) as penalties, student_id as student from flags f
join categories c
on f.category_id = c.id
group by student) as b
on
a.student = b.student
so with the name in there it's just
select
concat(firstname, ', ', surname) as name,
ifnull(points,0) as totalPoints,
ifnull(penalties,0) as totalPenalties,
ifnull(points,0) - ifnull(penalties, 0) as netPoints,
ifnull(countFlags, 0)
from
student
left join
(select sum(points) as points, recipient_id as student from transactions
group by student) as a
on student.id = a.student
left join
(select sum(weight) as penalties, count(f.id) as countFlags, student_id as student from flags f
join categories c
on f.category_id = c.id
group by student) as b
on
student.id = b.student
join condition is always from student's id column, which is never null.
there are probably more efficient ways, but who cares?
Returning to the question (and at the risk of repeating myself!), given the following data set, what would the desired result set look like...
SELECT * FROM flags;
+------+------------+----------+---------------------+-----------+-------------+--------------------------+---------------------+
| ID | Student_ID | Staff_ID | Datetime | Period_ID | Category_ID | Action_Taken_Category_ID | Action_Taken_Status |
+------+------------+----------+---------------------+-----------+-------------+--------------------------+---------------------+
| 8843 | 137608 | 35003 | 2014-03-11 08:31:00 | 8 | 16 | 7 | P |
| 8844 | 137608 | 35003 | 2014-03-11 08:31:00 | 8 | 16 | 7 | P |
| 8845 | 139027 | 35003 | 2014-03-11 08:31:00 | 8 | 16 | 7 | P |
| 8846 | 139041 | 35003 | 2014-03-11 08:31:00 | 8 | 16 | 7 | P |
| 8847 | 139041 | 34961 | 2014-03-11 09:01:02 | 2 | 12 | 26 | P |
| 8848 | 139041 | 34996 | 2014-03-11 09:23:21 | 3 | 12 | 27 | C |
| 8849 | 139041 | 35022 | 2014-03-11 11:07:46 | 4 | 34 | 28 | P |
| 8850 | 139892 | 138439 | 2014-03-11 11:12:47 | 4 | 21 | 7 | C |
| 8851 | 138832 | 138439 | 2014-03-11 11:12:48 | 4 | 21 | 7 | C |
| 8852 | 34533 | 138439 | 2014-03-11 11:12:48 | 4 | 21 | 7 | C |
+------+------------+----------+---------------------+-----------+-------------+--------------------------+---------------------+
SELECT * FROM categories;
+----+------+--------------------------------------+--------+----------+
| ID | Type | Title | Weight | Added_By |
+----+------+--------------------------------------+--------+----------+
| 10 | F | Low level disruption | 1 | NULL |
| 11 | F | Swearing directly at another student | 2 | NULL |
| 12 | F | Late | 1 | NULL |
| 13 | F | Absconded | 3 | NULL |
| 14 | F | Refusal to follow instruction | 3 | NULL |
| 15 | F | Smoking | 2 | NULL |
| 16 | F | No homework | 2 | NULL |
| 17 | F | Disruptive outside classroom | 2 | NULL |
| 18 | F | Eating/drinking in lesson | 1 | NULL |
| 19 | F | Incorrect uniform/equipment | 1 | NULL |
| 20 | F | Phone out in lesson | 3 | NULL |
| 21 | F | Aggressive defiance | 4 | NULL |
| 22 | F | Missed detention | 3 | NULL |
| 23 | F | Inappropriate behaviour/comments | 3 | NULL |
| 32 | F | IT Misuse | NULL | NULL |
| 34 | F | Inappropriate attitude towards staff | NULL | NULL |
| 35 | F | Care & Guidance | NULL | NULL |
+----+------+--------------------------------------+--------+----------+
SELECT * FROM transactions;
+----------------+------------+----------+--------------+--------+-------------+
| Transaction_ID | Datetime | Giver_ID | Recipient_ID | Points | Category_ID |
+----------------+------------+----------+--------------+--------+-------------+
| 34 | 2011-09-07 | 35019 | 137608 | 2 | 1 |
| 35 | 2011-09-07 | 35019 | 139027 | 2 | 1 |
| 36 | 2011-09-07 | 35019 | 139041 | 2 | 1 |
| 37 | 2011-09-07 | 35019 | 139041 | 2 | 1 |
| 38 | 2011-09-07 | 35019 | 139041 | 2 | 1 |
| 39 | 2011-09-07 | 35019 | 139041 | 2 | 1 |
| 40 | 2011-09-07 | 35019 | 137434 | 2 | 1 |
| 41 | 2011-09-07 | 35019 | 137434 | 2 | 1 |
| 42 | 2011-09-07 | 35019 | 137434 | 2 | 1 |
| 43 | 2011-09-07 | 35019 | 137434 | 2 | 1 |
| 44 | 2011-09-07 | 35006 | 137434 | 2 | 1 |
| 45 | 2011-09-07 | 35006 | 90306 | 2 | 1 |
| 46 | 2011-09-07 | 35006 | 90306 | 2 | 1 |
| 47 | 2011-09-07 | 35006 | 90306 | 2 | 1 |
| 48 | 2011-09-07 | 35023 | 137608 | 5 | 2 |
| 49 | 2011-09-07 | 35023 | 139027 | 5 | 2 |
| 50 | 2011-09-07 | 35023 | 139564 | 5 | 2 |
| 51 | 2011-09-07 | 35023 | 139564 | 5 | 2 |
| 52 | 2011-09-07 | 35023 | 139564 | 5 | 2 |
| 53 | 2011-09-07 | 35023 | 137608 | 5 | 3 |
+----------------+------------+----------+--------------+--------+-------------+
SELECT id,UPN,Year_Group,Tutor_Group,SEN_Status,Flags FROM student;
+--------+---------------+------------+-------------+------------+--------+
| id | UPN | Year_Group | Tutor_Group | SEN_Status | Flags |
+--------+---------------+------------+-------------+------------+--------+
| 137608 | A929238400044 | 11 | 11VID | A | |
| 139027 | A929238401045 | 10 | 10KS | | |
| 139041 | A929238402017 | 10 | 10RJ | A | FSM |
| 139892 | A929238403018 | 9 | 9BW | | |
| 139938 | A929238403020 | 9 | 9RH | | |
| 137434 | A929238500027 | 11 | 11VID | | |
| 138832 | A929238502002 | 10 | 10RY | A | FSM,PA |
| 34533 | A929238599028 | 0 | | | PA |
| 139564 | A929241500025 | 12 | | | PA |
| 90306 | A929253100006 | 12 | SLH | A | PA |
+--------+---------------+------------+-------------+------------+--------+