code id date time difference
AiK4JJ kcy2000ok 2012-01-31 17:25:41 13
unBG1D gktoql 2012-01-31 17:25:35 3
vzqeWU gktoql 2012-01-31 17:25:32 4
vvkOSd judyssi 2012-01-31 17:25:32 8
uwhbGt kcy2000ok 2012-01-31 17:25:28 ?
unBG1D gktoql 2012-01-31 17:25:27 ?
vvkOSd judyssi 2012-01-31 17:25:24 ?
I want to calculate the time difference in seconds between recent date and previous date based on id.
If you look at kcy2000ok, time difference is 13 seconds for last row.
time difference for gktoql is 3 seconds for last row.
I need to make a query that calculate time difference based on id.
Can you help me to build MySql query?
SELECT id, UNIX_TIMESTAMP() - UNIX_TIMESTAMP(time) as difference FROM <your-table-name>
Addendum:
Your question was a little bit hard to understand until you editied it. So to make this clear: If you want to calculate the minimum difference grouped by id, you can do:
SELECT
id,
MIN(UNIX_TIMESTAMP() - UNIX_TIMESTAMP(time)) as difference
FROM your_table_name
GROUP BY id
If you mean find the number of seconds since the most recent record for each user:
SELECT id, min(UNIX_TIMESTAMP() - UNIX_TIMESTAMP(time))
GROUP BY id
Or to get the most recent record for each user:
SELECT * FROM (
SELECT *
FROM mytable
ORDER BY `date` desc) x
GROUP BY id
Related
I've got database in MySQL with Output like that.
DATE_ADD | ID_PRODUCT | NOTE
That is TimeLine status for id_product. It could be more than 100 duplicate record by every Id_product in 1 week. What I need to find : only this RECORD without New NOTES in last 21 days. (>20 days)
Means: nobody is changing status of produckt for long time.
How to write the query to find only this record without new note in last 21 days.
And show the note order by date_add desc.
Thanks in advance for help me in that issue.
Right now I wrote smg like that:
Select
N.id_product,
N.date_add,
S.transaction,
N.note
from Sale S
left join note N on N.id_product=S.id_product
Where
(...)
and (N.date_add > DATE_SUB(CURDATE(), INTERVAL 20 DAY)) is null
Group By N.id_product
order by N.date_add desc
I have this table below which contains two column
hive> select * from hivetable;
a 2016-09-16T03:01:12.367782Z
b 2016-09-16T03:01:12.300514Z
c 2016-09-16T03:01:12.241532Z
a 2016-09-16T03:01:12.138016Z
c 2016-09-16T03:01:12.136986Z
b 2016-09-16T03:01:10.512201Z
c 2016-09-16T03:01:12.235671Z
Time taken: 0.457 seconds, Fetched: 7 row(s)
and now I want to find the unique value from first column and the timestamp difference or I should say average timestamp difference in case there are more than 2 records as in case of c. so in my case the output should be like
a 1 day 5 hr 30 min 20 sec
b 5 sec
c 30 minutes
Note: it is just a sample output and not the actual output
Is it possible to get this output or any similar one in hive?
You just need to use a window function to select the previous row in the grouping. I don't believe it can be compressed into just one query.
select
id,
avg(DATEDIFF(time, prev_time)) as avg_time_diff_days
from (
select id,
time,
LAG(time, 1, 0) OVER (PARTITION BY id, time ORDER BY time ASC)) as prev_time
from table
) intervals
group by id;
Table name: activity
Field name: ProcessYM
I have mysql data like below.
ProcessYM
==========
201312
201311
201310
201309
201308
201307
201306
201305
201304
201303
201302
201301
201212
201211
201210
201209
201208
201207
201206
I want to fetch the result like below. I mean, the mysql query to fetch the every quarter of the year like 201312, 201309, 201306, 201303, 201212, 201209.. and so on.
Actual Output I expect
=======================
ProcessYM
201312
201309
201306
201303
201212
201209
201206
I have tried the below query, but it does not produce the expected result.
SELECT distinct `ActProcessYM` from `activity` where `ActProcessYM`%3=0 order by ActProcessYM desc
Output of above query
=====================
201312
201309
201306
201303
201210
201207
It is much appreciated for your smart reply.
You need to modulo of the month part only. Your query is implicitly casting your ProcessYM as an INT.
For example:
SELECT DISTINCT ProcessYM
FROM activity
WHERE RIGHT(ProcessYM,2)%3=0
ORDER BY ProcessYM DESC
fiddle
you should retrieve the last two digits from field value and do the logic as you are doing.
SELECT distinct `ActProcessYM` from `activity` where substring(ActProcessYM,5,2)%3=0 order by ActProcessYM desc
Here's a not-so-quick-and-dirty way of handing this date processing. I believe you're looking for a MySQL formula like this:
yyyymm = TRUNC_QUARTER(yyyymm)
That is, you are looking for a function that converts any yyyymm month notation into a notation that shows the month that ends the quarter in question.
Let's start with an expression that converts any particular DATETIME expression to the DATE of the beginning of the quarter.
DATE(CONCAT(YEAR(value),'-', 1 + 3*(QUARTER(value)-1),'-01'))
This takes a timestamp (e.g. '2011-04-20 11:15:01') and turns it into the date of the starting of the quarter. (e.g. '2011-04-01')
Having things in this date form is helpful because you can use them for date arithmetic. For example, you can get the last day of that quarter like this.
DATE(CONCAT(YEAR(value),'-', 1 + 3*(QUARTER(value)-1),'-01'))
+ INTERVAL 1 QUARTER - INTERVAL 1 DAY
Here's a writeup on all this: http://www.plumislandmedia.net/mysql/sql-reporting-time-intervals/
I've found it helpful to try to stick to the date datatype when processing time series data.
You need to separate out the month value before doing the modulo 3 (% 3). Doing a modulo 100 first will do it:
(ProcessYM % 100) % 3) = 0
or
mod(mod(ProcessYM,100),3) = 0
Try this,
SELECT distinct `ProcessYM` from `activity` where SUBSTRING(`ProcessYM`,5,2)%3=0 order by ProcessYM desc
I have a table in my database, my program will insert data to that table in every 10 mins.
The table has a field recording the insert date and time.
Now I want to retrieve those data, but I don't want hundreds of data comes out.
I want to get 1 records from every half hour based on insert time stamp (so less than 50 in total of a day).
For that 1 record, it can be either random pick or average from each interval.
Sorry for the ambiguit, cuz I just wanna figure out the way to select from intervals
Let say,
Table name: network_speed
----------------------------------
ID. ....... Speed ......... Insert_time
1 ....... 10 ......... 10:02am......
2 ....... 12 ......... 10:12am......
...
...
...
123 ....... 17 ........ 9:23am........
To get them all but out put must be average of each half hour record
How can I write a query to achieve this?
Here is a query that calculates half hour intervals on a specific day ( 2013-09-04).
SELECT ID, Speed, Insert_time,
ROUND(TIMESTAMPDIFF(MINUTE, '2013-09-04', Insert_time)/48) AS 'interval'
FROM network_speed
WHERE DATE(Insert_time) = '2013-09-04';
Use that in a nested query to get stats on the records in the intervals.
SELECT IT.interval, COUNT(ID), MIN(Insert_time), MAX(Insert_time), AVG(Speed)
FROM
(SELECT ID, Speed, Insert_time,
ROUND(TIMESTAMPDIFF(MINUTE, '2013-09-04', Insert_time)/48) AS 'interval'
FROM network_speed
WHERE DATE(Insert_time) = '2013-09-04') AS IT
GROUP BY IT.interval;
Here it is used to get the first record in each interval.
SELECT NS.*
FROM
(SELECT IT.interval, MIN(ID) AS 'first_id'
FROM
(SELECT ID, Speed, Insert_time,
ROUND(TIMESTAMPDIFF(MINUTE, '2013-09-04', Insert_time)/48) AS 'interval'
FROM network_speed
WHERE DATE(Insert_time) = '2013-09-04') AS IT
GROUP BY IT.interval) AS MI,
network_speed AS NS
WHERE MI.first_id = NS.ID;
Hope that helps.
Is this what you need?
SELECT HOUR(ts) as hr, fld1, fld2 from tbl group by hr
This query selects only hour from the timestamp and then groups the result based on the hour field so you get 1 row for each hour
I am looking to calculate moving averages over variable dates.
My database is structured:
id int
date date
price decimal
For example, I'd like to find out if the average price going back 19 days ever gets greater than the average price going back 40 days within the past 5 days. Each of those time periods is variable.
What I am getting stuck on is selecting a specific number of rows for subquery.
Select * from table
order by date
LIMIT 0 , 19
Knowing that there will only be 1 input per day, can I use the above as a subquery? After that the problem seems trivial....
if you only have one input per day you don't need id, date can be your primary id? Am i missing something? Then use select sum
SELECT SUM(price) AS totalPrice FROM table Order by date desc Limit (most recent date),(furthest back date)
totalPrice/(total days)
I may not understand your question
Yes you can use that as a sub-query like this:
SELECT
AVG(price)
FROM
(SELECT * FROM t ORDER BY date DESC LIMIT 10) AS t1;
This calculates the average price for the latest 10 rows.
see fiddle.