I have an HTML form in a JSP file in my WebContent/jsps folder. I have a servlet class servlet.java in my default package in src folder. In my web.xml it is mapped as /servlet.
I have tried several URLs in action attribute of the HTML form:
<form action="/servlet">
<form action="/servlet.java">
<form action="/src/servlet.java">
<form action="../servlet.java">
But none of those work. They all keep returning a HTTP 404 error like below in Tomcat 6/7/8:
HTTP Status 404 — /servlet
Description: The requested resource (/servlet) is not available.
Or as below in Tomcat 8.5/9:
HTTP Status 404 — Not Found
Message: /servlet
Description: The origin server did not find a current representation for the target resource or is not willing to disclose that one exists
Or as below in Tomcat 10:
HTTP Status 404 — Not Found
Type: Status Report
Message: The requested resource (/servlet) is not available
Description: The origin server did not find a current representation for the target resource or is not willing to disclose that one exists
Why is it not working?
Introduction
This can have a lot of causes which are broken down in following sections:
Put servlet class in a package
Set servlet URL in url-pattern
#WebServlet works only on Servlet 3.0 or newer
javax.servlet.* doesn't work anymore in Servlet 5.0 or newer
Make sure compiled *.class file is present in built WAR
Test the servlet individually without any JSP/HTML page
Use domain-relative URL to reference servlet from HTML
Use straight quotes in HTML attributes
Put servlet class in a package
First of all, put the servlet class in a Java package. You should always put publicly reuseable Java classes in a package, otherwise they are invisible to classes which are in a package, such as the server itself. This way you eliminate potential environment-specific problems. Packageless servlets work only in specific Tomcat+JDK combinations and this should never be relied upon.
In case of a "plain" IDE project, the class needs to be placed in its package structure inside the "Java Sources" folder, not inside "Web Content" folder, which is for web files such as JSP. Below is an example of the folder structure of a default Eclipse Dynamic Web Project as seen in Navigator view (the "Java Sources" folder is in such project by default represented by src folder):
EclipseProjectName
|-- src
| `-- com
| `-- example
| `-- YourServlet.java
|-- WebContent
| |-- WEB-INF
| | `-- web.xml
| `-- jsps
| `-- page.jsp
:
In case of a Maven project, the class needs to be placed in its package structure inside main/java and thus not main/resources, this is for non-class files and absolutely also not main/webapp, this is for web files. Below is an example of the folder structure of a default Maven webapp project as seen in Eclipse's Navigator view:
MavenProjectName
|-- src
| `-- main
| |-- java
| | `-- com
| | `-- example
| | `-- YourServlet.java
| |-- resources
| `-- webapp
| |-- WEB-INF
| | `-- web.xml
| `-- jsps
| `-- page.jsp
:
Note that the /jsps subfolder is not strictly necessary. You can even do without it and put the JSP file directly in webcontent/webapp root, but I'm just taking over this from your question.
Set servlet URL in url-pattern
The servlet URL is specified as the "URL pattern" of the servlet mapping. It's absolutely not per definition the classname/filename of the servlet class. The URL pattern is to be specified as value of #WebServlet annotation.
package com.example; // Use a package!
import jakarta.servlet.annotation.WebServlet; // or javax.*
import jakarta.servlet.http.HttpServlet; // or javax.*
#WebServlet("/servlet") // This is the URL of the servlet.
public class YourServlet extends HttpServlet { // Must be public and extend HttpServlet.
// ...
}
In case you want to support path parameters like /servlet/foo/bar, then use an URL pattern of /servlet/* instead. See also Servlet and path parameters like /xyz/{value}/test, how to map in web.xml?
Do note that it's considered a bad practice to use a Servlet URL pattern of /* or / in an attempt to have a "front controller". So do not abuse these URL patterns in an attempt to try to catch all URLs. For an in depth explanation see also Difference between / and /* in servlet mapping url pattern.
#WebServlet works only on Servlet 3.0 or newer
In order to use #WebServlet, you only need to make sure that your web.xml file, if any (it's optional since Servlet 3.0), is declared conform Servlet 3.0+ version and thus not conform e.g. 2.5 version or lower. It should absolutely also not have any <!DOCTYPE> line. Below is a Servlet 6.0 compatible one (which matches Tomcat 10.1+, WildFly 27+ (Preview), GlassFish/Payara 7+, etc) in its entirety:
<?xml version="1.0" encoding="UTF-8"?>
<web-app
xmlns="https://jakarta.ee/xml/ns/jakartaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="https://jakarta.ee/xml/ns/jakartaee https://jakarta.ee/xml/ns/jakartaee/web-app_6_0.xsd"
version="6.0"
>
<!-- Config here. -->
</web-app>
And below is a Servlet 5.0 compatible one (which matches Tomcat 10.0.x, WildFly 22+ (Preview), GlassFish/Payara 6+, etc).
<?xml version="1.0" encoding="UTF-8"?>
<web-app
xmlns="https://jakarta.ee/xml/ns/jakartaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="https://jakarta.ee/xml/ns/jakartaee https://jakarta.ee/xml/ns/jakartaee/web-app_5_0.xsd"
version="5.0"
>
<!-- Config here. -->
</web-app>
And below is a Servlet 4.0 compatible one (which matches Tomcat 9+, WildFly 11+, GlassFish/Payara 5+, etc).
<?xml version="1.0" encoding="UTF-8"?>
<web-app
xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd"
version="4.0"
>
<!-- Config here. -->
</web-app>
Or, in case you're not on Servlet 3.0+ yet (e.g. Tomcat 6 or older), then remove the #WebServlet annotation.
package com.example;
import javax.servlet.http.HttpServlet;
public class YourServlet extends HttpServlet {
// ...
}
And register the servlet instead in web.xml like this:
<servlet>
<servlet-name>yourServlet</servlet-name>
<servlet-class>com.example.YourServlet</servlet-class> <!-- Including the package thus -->
</servlet>
<servlet-mapping>
<servlet-name>yourServlet</servlet-name>
<url-pattern>/servlet</url-pattern> <!-- This is the URL of the servlet. -->
</servlet-mapping>
Note thus that you should not use both ways. Use either annotation based configuarion or XML based configuration. When you have both, then XML based configuration will override annotation based configuration.
javax.servlet.* doesn't work anymore in Servlet 5.0 or newer
Since Jakarta EE 9 / Servlet 5.0 (Tomcat 10, TomEE 9, WildFly 22 Preview, GlassFish 6, Payara 6, Liberty 22, etc), the javax.* package has been renamed to jakarta.* package.
In other words, please make absolutely sure that you don't randomly put JAR files of a different server in your WAR project such as tomcat-servlet-api-9.x.x.jar merely in order to get the javax.* package to compile. This will only cause trouble. Remove it altogether and edit the imports of your servlet class from
import javax.servlet.*;
import javax.servlet.annotation.*;
import javax.servlet.http.*;
to
import jakarta.servlet.*;
import jakarta.servlet.annotation.*;
import jakarta.servlet.http.*;
In case you're using Maven, you can find examples of proper pom.xml declarations for Tomcat 10+, Tomcat 9-, JEE 9+ and JEE 8- in this answer: How to properly configure Jakarta EE libraries in Maven pom.xml for Tomcat? The alternative is to downgrade the server to an older version, e.g. from Tomcat 10 back to Tomcat 9 or older, but this is clearly not the recommended way to go.
Make sure compiled *.class file is present in built WAR
In case you're using a build tool such as Eclipse and/or Maven, then you need to make absolutely sure that the compiled servlet class file resides in its package structure in /WEB-INF/classes folder of the produced WAR file. In case of package com.example; public class YourServlet, it must be located in /WEB-INF/classes/com/example/YourServlet.class. Otherwise you will face in case of #WebServlet also a 404 error, or in case of <servlet> a HTTP 500 error like below:
HTTP Status 500
Error instantiating servlet class com.example.YourServlet
And find in the server log a java.lang.ClassNotFoundException: com.example.YourServlet, followed by a java.lang.NoClassDefFoundError: com.example.YourServlet, in turn followed by jakarta.servlet.ServletException: Error instantiating servlet class com.example.YourServlet.
An easy way to verify if the servlet is correctly compiled and placed in classpath is to let the build tool produce a WAR file (e.g. rightclick project, Export > WAR file in Eclipse) and then inspect its contents with a ZIP tool. If the servlet class is missing in /WEB-INF/classes, or if the export causes an error, then the project is badly configured or some IDE/project configuration defaults have been mistakenly reverted (e.g. Project > Build Automatically has been disabled in Eclipse).
You also need to make sure that the project icon has no red cross indicating a build error. You can find the exact error in Problems view (Window > Show View > Other...). Usually the error message is fine Googlable. In case you have no clue, best is to restart from scratch and do not touch any IDE/project configuration defaults. In case you're using Eclipse, you can find instructions in How do I import the javax.servlet / jakarta.servlet API in my Eclipse project?
Test the servlet individually without any JSP/HTML page
Provided that the server runs on localhost:8080, and that the WAR is successfully deployed on a context path of /contextname (which defaults to the IDE project name, case sensitive!), and the servlet hasn't failed its initialization (read server logs for any deploy/servlet success/fail messages and the actual context path and servlet mapping), then a servlet with URL pattern of /servlet is available at http://localhost:8080/contextname/servlet.
You can just enter it straight in browser's address bar to test it invidivually. If its doGet() is properly overriden and implemented, then you will see its output in browser. Or if you don't have any doGet() or if it incorrectly calls super.doGet(), then a "HTTP 405: HTTP method GET is not supported by this URL" error will be shown (which is still better than a 404 as a 405 is evidence that the servlet itself is actually found).
Overriding service() is a bad practice, unless you're reinventing a MVC framework — which is very unlikely if you're just starting out with servlets and are clueless as to the problem described in the current question ;) See also Design Patterns web based applications.
Regardless, if the servlet already returns 404 when tested invidivually, then it's entirely pointless to try with a HTML form instead. Logically, it's therefore also entirely pointless to include any HTML form in questions about 404 errors from a servlet.
Use domain-relative URL to reference servlet from HTML
Once you've verified that the servlet works fine when invoked individually, then you can advance to HTML. As to your concrete problem with the HTML form, the <form action> value needs to be a valid URL. The same applies to <a href>, <img src>, <script src>, etc. You need to understand how absolute/relative URLs work. You know, an URL is a web address as you can enter/see in the webbrowser's address bar. If you're specifying a relative URL as form action, i.e. without the http:// scheme, then it becomes relative to the current URL as you see in your webbrowser's address bar. It's thus absolutely not relative to the JSP/HTML file location in server's WAR folder structure as many starters seem to think.
So, assuming that the JSP page with the HTML form is opened by http://localhost:8080/contextname/jsps/page.jsp (and thus not by file://...), and you need to submit to a servlet located in http://localhost:8080/contextname/servlet, here are several cases (note that you can here safely substitute <form action> with <a href>, <img src>, <script src>, etc):
Form action submits to an URL with a leading slash.
<form action="/servlet">
The leading slash / makes the URL relative to the domain, thus the form will submit to
http://localhost:8080/servlet
But this will likely result in a 404 as it's in the wrong context.
Form action submits to an URL without a leading slash.
<form action="servlet">
This makes the URL relative to the current folder of the current URL, thus the form will submit to
http://localhost:8080/contextname/jsps/servlet
But this will likely result in a 404 as it's in the wrong folder.
Form action submits to an URL which goes one folder up.
<form action="../servlet">
This will go one folder up (exactly like as in local disk file system paths!), thus the form will submit to
http://localhost:8080/contextname/servlet
This one must work!
The canonical approach, however, is to make the URL domain-relative so that you don't need to fix the URLs once again when you happen to move the JSP files around into another folder.
<form action="${pageContext.request.contextPath}/servlet">
This will generate
<form action="/contextname/servlet">
Which will thus always submit to the right URL.
Use straight quotes in HTML attributes
You need to make absolutely sure you're using straight quotes in HTML attributes like action="..." or action='...' and thus not curly quotes like action=”...” or action=’...’. Curly quotes are not supported in HTML and they will simply become part of the value. Watch out when copy-pasting code snippets from blogs! Some blog engines, notably Wordpress, are known to by default use so-called "smart quotes" which thus also corrupts the quotes in code snippets this way. On the other hand, instead of copy-pasting code, try simply typing over the code yourself. Additional advantage of actually getting the code through your brain and fingers is that it will make you to remember and understand the code much better in long term and also make you a better developer.
See also:
Our servlets wiki page - Contains some hello world examples
How to call servlet class from HTML form
doGet and doPost in Servlets
How do I pass current item to Java method by clicking a hyperlink or button in JSP page?
Other cases of HTTP Status 404 error:
HTTP Status 404 - Servlet [ServletName] is not available
HTTP Status 404 - The requested resource (/ProjectName/) is not available
HTTP Status 404 - The requested resource (/) is not available
JSP in /WEB-INF returns "HTTP Status 404 The requested resource is not available"
Referencing a resource placed in WEB-INF folder in JSP file returns HTTP 404 on resource
Browser can't access/find relative resources like CSS, images and links when calling a Servlet which forwards to a JSP
Scenario #1: You accidentially re-deployed from the command line while tomcat was already running.
Short Answer: Stop Tomcat, delete target folder, mvn package, then re-deploy
Scenario #2: request.getRequestDispatcher("MIS_SPELLED_FILE_NAME.jsp")
Short Answer: Check file name spelling, make sure case is correct.
Scenario #3: Class Not Found Exceptions
(Answer put here because: Question# 17982240 )
(java.lang.ClassNotFoundException for servlet in tomcat with eclipse )
(was marked as duplicate and directed me here )
Short Answer #3.1: web.xml has wrong package path in servlet-class tag.
Short Answer #3.2: java file has wrong import statement.
Below is further details for Scenario #1:
1: Stop Tomcat
Option 1: Via CTRL+C in terminal.
Option 2: (terminal closed while tomcat still running)
------------ 2.1: press:Windows+R --> type:"services.msc"
------------ 2.2: Find "Apache Tomcat #.# Tomcat#" in Name column of list.
------------ 2.3: Right Click --> "stop"
2: Delete the "target" folder.
(mvn clean will not help you here)
3: mvn package
4: YOUR_DEPLOYMENT_COMMAND_HERE
(Mine: java -jar target/dependency/webapp-runner.jar --port 5190 target/*.war )
Full Back Story:
Accidentially opened a new git-bash window and
tried to deploy a .war file for my heroku project via:
java -jar target/dependency/webapp-runner.jar --port 5190 target/*.war
After a failure to deploy, I realized I had two git-bash windows open,
and had not used CTLR+C to stop the previous deployment.
I was met with:
HTTP Status 404 – Not Found Type Status Report
Message /if-student-test.jsp
Description The origin server did not find a current representation
for the target resource or is not willing to disclose that one
exists.
Apache Tomcat/8.5.31
Below is further details for Scenario #3:
SCENARIO 3.1:
The servlet-class package path is wrong
in your web.xml file.
It should MATCH the package statement at top
of your java servlet class.
File: my_stuff/MyClass.java:
package my_stuff;
File: PRJ_ROOT/src/main/webapp/WEB-INF/web.xml
<servlet-class>
my_stuff.MyClass
</servlet-class>
SCENARIO 3.2:
You put the wrong "package" statement
at top of your myClass.java file.
For example:
File is in: "/my_stuff" folder
You mistakenly write:
package com.my_stuff
This is tricky because:
1: The maven build (mvn package) will not report any errors here.
2: servlet-class line in web.xml can have CORRECT package path. E.g:
<servlet-class>
my_stuff.MyClass
</servlet-class>
Stack Used:
Notepad++ + GitBash + Maven + Heroku Web App Runner + Tomcat9 + Windows10:
Check if you have entered the correct URL Mapping as specified in the Web.xml
For example:
In the web.xml, your servlet declaration maybe:
<servlet>
<servlet-name>ControllerA</servlet-name>
<servlet-class>PackageName.ControllerA</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>ControllerA</servlet-name>
<url-pattern>/theController</url-pattern>
</servlet-mapping>
What this snippet does is <url-pattern>/theController</url-pattern>will set the name that will be used to call the servlet from the front end (eg: form) through the URL. Therefore when you reference the servlet in the front end, in order to ensure that the request goes to the servlet "ControllerA", it should refer the specified URL Pattern "theController" from the form.
eg:
<form action="theController" method="POST">
</form>
If you're using IntelliJ, this is what fixed it for me:
Go to the Tomcat configuration:
Configuration > Deployment Tab
Scroll down and add / to the Application Context dropdown
Solution for HTTP Status 404 in NetBeans IDE:
Right click on your project and go to your project properties, then click on run, then input your project relative URL like index.jsp.
Project->Properties
Click on Run
Relative URL:/index.jsp (Select your project root URL)
My issue was that my method was missing the #RequestBody annotation. After adding the annotation I no longer received the 404 exception.
Do the following two steps. I hope, it will solve the "404 not found" issue in tomcat server during the development of java servlet application.
Step 1: Right click on the server(in the server explorer tab)->Properties->Switch Location from workspace metadata to tomcat server
Step 2: Double Click on the server(in the server explorer tab)->Select Use tomcat installation option inside server location menu
I removed the old web library such that are spring framework libraries. And build a new path of the libraries. Then it works.
An old thread, but since I didn't find it elsewhere, here is one more possibility:
If you're using servlet-api 3.0+, then your web.xml must NOT include metadata-complete="true" attribute
This tells tomcat to map the servlets using data given in web.xml instead of using the #WebServlet annotation.
First of all, run your IDE as Admin. After that, right click the project folder -> Project Facets and make sure that the Java Version is set correct. On my PC. (For Example 1.8) Now it should work.
Don't just start your server, for example Wildfly, using the cmd. It has to be launched within the IDE and now visit your localhost URL. Example: http://localhost:8080/HelloWorldServlet/HelloWorld
The fix that worked for me is(if you are using Maven): Rightclick your project, Maven -> Update project. This might give you some other error with the JDK and other Libraries(in my case, MySQL connector), but once you fix them, your original problem should be fixed!
If you would like to open a servlet with javascript without using 'form' and 'submit' button, here is the following code:
var button = document.getElementById("<<button-id>>");
button.addEventListener("click", function() {
window.location.href= "<<full-servlet-path>>" (eg. http://localhost:8086/xyz/servlet)
});
Key:
1) button-id : The 'id' tag you give to your button in your html/jsp file.
2) full-servlet-path: The path that shows in the browser when you run the servlet alone
Mapping in web.xml is what i have done :-
If there's another package made for new program then we must mention :-
packagename.filename between opening and closing of servlet-class tag in xml file.
If you are mapping your files in xml and they are not working or showing errors , then comment on the annotation line of code in the respective files.
Both methods dont work with one another , so either i use annotation method of files mentioned when we create servlet or the way of mapping , then i delete or comment the annotation line. Eg:
<servlet>
<servlet-name>s1</servlet-name>
<servlet-class>performance.FirstServ</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>s1</servlet-name>
<url-pattern>/FirstServ</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>s2</servlet-name>
<servlet-class>performance.SecondServ</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>s2</servlet-name>
<url-pattern>/SecondServ</url-pattern>
</servlet-mapping>
Commenting the annotation line of code in the respective file,if mapping in xml is done.
//#WebServlet("/FirstServ")
//#WebServlet("/SecondServ")
If someone is here who is using MySQL and felt that the code was working the previous day and now it doesn't, then I guess you must open MySQL CLI or MySQL Workbench and just make the connection to the database once. Once it gets connected, then the database also gets connected to the Java Application. I used to get the Hibernate Dialect error stating something wrong with com.mysql.jdbc.Driver. I think MySQL in some computers has a startup problem. This solved for me.
If you are a student and new to Java there might be some issue going on with your web.xml file.
Try removing the web.xml file.
Secondly check that your path variables are properly set or not.
Restart tomcat server Or your PC.
Your problem will be surely solved.
I was facing this issue too, I was receiving a 404 when accessing a URL pattern that I knew was linked to a Servlet. The reason is because I had 2 Servlets with their #WebServlet name parameter set as the same string.
#WebServlet(name = "ServletName", urlPatterns = {"/path"})
public class ServletName extends HttpServlet {}
#WebServlet(name = "ServletName", urlPatterns = {"/other-path"})
public class OtherServletName extends HttpServlet {}
Both of the name parameters are the same. If you're using the name parameter, make sure they are unique compared to all other Servlets on your application.
I had the same issue. Tried all of this but didn't help. I managed to solve this issue by adding element tags to beginning and end of the xml file. ill leave my xml file below for reference.
<?xml version="1.0" encoding="UTF-8"?>
<element>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee
http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
version="3.1">
<servlet>
<servlet-name>InsertServlet</servlet-name>
<servlet-class>com.worklog.InsertServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>InsertServlet</servlet-name>
<url-pattern>/insert</url-pattern>
</servlet-mapping>
</web-app>
</element>
I was having the same issue. I was developing a mvc based REST API where there was no explicit html configuration or files. The API was using Swagger to generate a user interface. The problem started when I introduced Swagger version "3.0.0". I reverted back to Swagger "2.9.2" This solved my problem.
<!-- Swagger -->
<dependency>
<groupId>io.springfox</groupId>
<artifactId>springfox-swagger-ui</artifactId>
<version>2.9.2</version>
</dependency>
<dependency>
<groupId>io.springfox</groupId>
<artifactId>springfox-swagger2</artifactId>
<version>2.9.2</version>
</dependency>
Please check context root cannot be empty.
If you're using eclipse:
right click, select properties, then web project settings. Check the context root cannot be empty
I am migrating a console app (REST client app) from .NET framework to .NET Core.
In my current (framework) version, I use the app.config file to set the System.Net configuration:
<system.net>
<connectionManagement>
<add address="*" maxconnection="65535"/>
</connectionManagement>
</system.net>
In .NET Core, I have to use a JSON file for configuration. There is no documentation for implementing these settings using the new configuration schema. Does anyone know how this might look inside the new JSON config, or the correct way to implement this in Core? Do I need to build a designated "System.Net.json" config file (separate from an AppSettings.json) specifically to do this?
Thanks.
I assume you're trying to avoid the limit of 2 connections per endpoint, which is default on .NET Framework. Such limit does not exist on .NET Core. So you don't need the above setting at all.
Note that to achieve better perf, we recommend to use HttpClient/HttpClientHandler over HttpWebRequest/ServicePoint on .NET Core. HttpWebRequest/ServicePoint APIs are compat-only.
If you want to limit HttpClient connections, then use HttpClientHandler.MaxConnectionsPerServer
Assuming you are using Kestrel as your web server (and not doing it through IIS implementation), you should be able to set this in your UseKestrel in your BuildWebHost.
It would go something like this:
.UseKestrel(options =>
{
options.Limits.MaxConcurrentConnections = 100;
})
You can also add this in your HttpClientHandler, It's called MaxConnectionsPerServer. It can be seen here.
Some addition to Karel Zikmund answer. (As i don’t have permissions to comment).
According to this doc connections are limited since .net core 2.0:
https://learn.microsoft.com/en-us/dotnet/api/system.net.servicepointmanager.defaultconnectionlimit?view=netcore-3.1
What is missed in doc is if ServicePointManager used for .net core HttpClient implementation. According to this info it is used in .net core, but for HttpWebRequest, not HttpClient: https://github.com/dotnet/runtime/issues/26048
I am using a JSON parser to extract the value and I am using the following jar
json-path-2.1.0, and I am getting the following error when I invoke the use case deployed as webservice on weblogic server
I wrote a small main program to extract the value from the json string and it works fine, but the server version of the use case is giving the issue. I am not sure if there are any other jars part of my ear can negatively impact this
SEVERE: defaultReader
java.lang.NoSuchFieldError: defaultReader
at com.jayway.jsonpath.spi.json.JsonSmartJsonProvider.<init>(JsonSmartJsonProvider.java:39)
at com.jayway.jsonpath.internal.DefaultsImpl.jsonProvider(DefaultsImpl.java:21)
at com.jayway.jsonpath.Configuration.defaultConfiguration(Configuration.java:174)
at com.jayway.jsonpath.internal.JsonContext.<init>(JsonContext.java:52)
at com.jayway.jsonpath.JsonPath.parse(JsonPath.java:596)
Stumbled about the same problem.
The reason why it does not work is not the JDK 8.
The reason why you encounter this issue, is the fact that weblogic 12.2.1.X is bundling some old version of json-smart.
On my machine this would be found here:
jar:file:/C:/dev/WLS_12_2_1_2_0/oracle_common/modules/net.minidev.json-smart.jar!/net/minidev/json/JSONValue.class
Now if you are using a library like json-path that depends on json-smart, then by default the container will load the required class using one of its built-in modules.
The blowup you have, seems to be that the JSONValue class that your json-path depends on seemed to have this defaultReder field.
Here is a snipet of the clode that is blowing up.
public JsonSmartJsonProvider() {
this(JSONParser.MODE_PERMISSIVE, JSONValue.defaultReader.DEFAULT_ORDERED);
}
That
JSONValue.defaultReader
Seems not to be valid on weblogs older system class loader class.
You can tell the container to use what you are packing by putting into your weblogic.xml deployment descriptor something like this:
<wls:prefer-application-packages>
<wls:package-name>net.minidev.json.*</wls:package-name>
</wls:prefer-application-packages>
I am having quite a bit of trouble getting weblogic to swallow the fine-grained instruction above.
I found myself to force weblogic to swallog all that goes into the web-inf folder instead doing:
<wls:container-descriptor>
<wls:prefer-web-inf-classes>true</wls:prefer-web-inf-classes>
</wls:container-descriptor>
I would have rather not be using a hammer like the web-inf-classes, but I am dancing with the weblogic system classloader when I do not go coarse grained...
Regards.
I too was facing this issue, It turned out some other library was using json-smart's older version, and it was getting precedence over json-path's json-smart dependency. Removing the other jar solved the issue. Or you can also downgrade your json-path's version to appropriate version such that it support json-smart's older version.
Looks like JsonParser jar is present in JVM 1.8 version and it seems to have more precedence over the JsonParser class available in Json-path.jar. Apparently the us case doesn't work in 12.2.1 version of the weblogic server but it works fine in 12.1.3
I had the same problem but I use Gradle so I had to add:
compile group: 'net.minidev', name: 'json-smart', version: '2.3' to my dependencies.
So I've OSGI-ified a war file. It still works in Tomcat. I have all the requisite fields in the manifest and the libraries are all embedded for now. I'll externalize them later. There are two which are not OSGI enabled. The war file has log4j2 embedded BTW. It will be removed later.
The war file in question is 3 simple Jersey based REST/JSON services.
It starts and goes to Active state but I can't hit it with SoapUI where I expect to find it. The logs show it starting but that is all they show.
How can I squeeze more info out of Karaf so that I can properly figure out what is going on?
Is there something special I have to do in the Activator to get it to fire up?
Note: This is a simple REST / JSON service that wraps WURFL. By license, it's Open Source but it hasn't been released yet.
karaf#root()> bundle:headers MobileWURFL
MobileWURFL Maven Webapp (104)
-------------------------------
Manifest-Version = 1.0
Bnd-LastModified = 1395276484402
Archiver-Version = Plexus Archiver
Tool = Bnd-2.1.0.20130426-122213
Embed-Directory = WEB-INF/lib
Embedded-Artifacts = WEB-INF/lib/org.osgi.core-4.3.0.jar;g="org.osgi";a="org.osgi.core";v="4.3.0",WEB-INF/lib/org.osgi.compendium-1.4.0.jar;g="org.apache.felix";a="org.osgi.compend
ium";v="1.4.0",WEB-INF/lib/org.osgi.core-1.4.0.jar;g="org.apache.felix";a="org.osgi.core";v="1.4.0",WEB-INF/lib/javax.servlet-1.0.0.jar;g="org.apache.felix";a="javax.servlet";v="1.
0.0",WEB-INF/lib/org.osgi.foundation-1.2.0.jar;g="org.apache.felix";a="org.osgi.foundation";v="1.2.0",WEB-INF/lib/servlet-api-2.5.jar;g="javax.servlet";a="servlet-api";v="2.5",WEB-
INF/lib/log4j-api-2.0-rc1.jar;g="org.apache.logging.log4j";a="log4j-api";v="2.0-rc1",WEB-INF/lib/log4j-core-2.0-rc1.jar;g="org.apache.logging.log4j";a="log4j-core";v="2.0-rc1",WEB-
INF/lib/disruptor-3.0.1.jar;g="com.lmax";a="disruptor";v="3.0.1",WEB-INF/lib/commons-lang-2.6.jar;g="commons-lang";a="commons-lang";v="2.6",WEB-INF/lib/log4j-slf4j-impl-2.0-rc1.jar
;g="org.apache.logging.log4j";a="log4j-slf4j-impl";v="2.0-rc1",WEB-INF/lib/slf4j-api-1.7.5.jar;g="org.slf4j";a="slf4j-api";v="1.7.5",WEB-INF/lib/commons-collections-3.2.1.jar;g="co
mmons-collections";a="commons-collections";v="3.2.1",WEB-INF/lib/wurfl-1.5.1.jar;g="net.sourceforge.wurfl";a="wurfl";v="1.5.1",WEB-INF/lib/json-20140107.jar;g="org.json";a="json";v
="20140107",WEB-INF/lib/jersey-server-1.8.jar;g="com.sun.jersey";a="jersey-server";v="1.8",WEB-INF/lib/asm-3.1.jar;g="asm";a="asm";v="3.1",WEB-INF/lib/jersey-core-1.8.jar;g="com.su
n.jersey";a="jersey-core";v="1.8"
Built-By = Coder_Guy
Embed-Dependency = *;scope=compile|runtime
Embed-Transitive = true
Webapp-Context = MobileWURFL
Web-ContextPath = MobileWURFL
Build-Jdk = 1.7.0_51
Created-By = Apache Maven Bundle Plugin
Bundle-Name = MobileWURFL Maven Webapp
Bundle-SymbolicName = MobileWURFL
Bundle-Version = 0.0.1.SNAPSHOT
Bundle-ManifestVersion = 2
Bundle-ClassPath = .,WEB-INF/classes,WEB-INF/lib/org.osgi.core-4.3.0.jar,WEB-INF/lib/org.osgi.compendium-1.4.0.jar,WEB-INF/lib/org.osgi.core-1.4.0.jar,WEB-INF/lib/javax.servlet-1.0
.0.jar,WEB-INF/lib/org.osgi.foundation-1.2.0.jar,WEB-INF/lib/servlet-api-2.5.jar,WEB-INF/lib/log4j-api-2.0-rc1.jar,WEB-INF/lib/log4j-core-2.0-rc1.jar,WEB-INF/lib/disruptor-3.0.1.ja
r,WEB-INF/lib/commons-lang-2.6.jar,WEB-INF/lib/log4j-slf4j-impl-2.0-rc1.jar,WEB-INF/lib/slf4j-api-1.7.5.jar,WEB-INF/lib/commons-collections-3.2.1.jar,WEB-INF/lib/wurfl-1.5.1.jar,WE
B-INF/lib/json-20140107.jar,WEB-INF/lib/jersey-server-1.8.jar,WEB-INF/lib/asm-3.1.jar,WEB-INF/lib/jersey-core-1.8.jar
As you are using a OSGi-fied war the war-extender of Pax Web will kick in. Therefore no activator needed. For debugging just start the karaf container with karaf debug, attach your debuger to port 8787.
Depending on your embedded jars there might be an issue with those, for example a servlet.jar or similar will result in errors with deployment. Also possible the log4j2.jar could cause an issue.
What's the result of bundle:header for this war?
With the command
web:list
you also receive the info of the state of the web bundle.
UPDATE:
It is right there in your Bundle-ClassPath. The servlet jar is not allowed to be in a WAR, per spec by the way. In OSGi it collides with the packages provided by Pax-Web. In a Tomcat, the servlet.jar is already loaded by the container therefore it does work, as First-Come-First-Serve is used by a classloader. With OSGi the first Servlet class is found inside the War and therefore the resolver doesn't use the one provided by Pax Web. It is essential that you remove that jar.
And I think adding those osgi jars doesn't help any either, this will most likely collide with the bundles provided by the container.
I strongly suggest using the maven-bundle-plugin to generate this war, so the imports are properly created. Or just neglect all OSGi meta information and deploy a standard WAR. If you use the following type URL:
webbundle:mvn:groupID/artifactID/version/war?Web-ContextPath=Mobile-WURFL
It will generate a proper OSGi Manifest for your war.
I am going to implement something similar to Facebook notification and this website (StackOverflow's notification which is notifying us if anyone write a comment/answer etc for our question). Please note users are going to use my application as a website not mobile application.
I came across following answer which fetch the results, but I need to push the results not fetch.
Based on suggestions I have created a simple method in my entity class and added the #PostPersist to it but it has not worked so based on this answer I added the persistence.xml file to define the listeners but after session.save(user) the aftersave method does not get triggered.
User.java
#Entity
public class User{
.....
#PostPersist
public void aftersave(){
System.err.println("*****this is post persist method****");
}
}
persistence.xml
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">
<!--
To change this template, choose Tools | Templates
and open the template in the editor.
-->
<property name="hibernate.ejb.event.pre-insert" value="my.hibernate.events.listeners.Listener" />
<property name="hibernate.ejb.event.pre-update" value="my.hibernate.events.listeners.Listener" />
<property name="hibernate.ejb.event.pre-delete" value="my.hibernate.events.listeners.Listener" />
<property name="hibernate.ejb.event.post-insert" value="my.hibernate.events.listeners.Listener" />
<property name="hibernate.ejb.event.post-update" value="my.hibernate.events.listeners.Listener" />
<property name="hibernate.ejb.event.post-delete" value="my.hibernate.events.listeners.Listener" />
pom.xml
<dependency>
<groupId>org.hibernate</groupId>
<artifactId>hibernate-core</artifactId>
<version>4.2.1.Final</version>
<type>jar</type>
</dependency>
Sounds like a task for WebSockets. It is part of Java EE 7 so the Glassfish should be one of the first AS that will support it.
For intercepting the DB access you can use #PostUpdate and #PostPersist. Here is related question.
There are many ways to do the so called Server Push for notifying the connected clients:
polling (the link you've provided in the question ("Are we there yet? Are we there yet? ..."))
long polling (smarter way of polling - long-lived HTTP technique using keepalive messages)
WebSockets (JSR 356)
piggy-backing
SPDY(wiki)
Server-Sent Events (related answer, wiki)
EDIT: In the Java world, there are couple of frameworks where server push (reverse ajax) is implemented out-of-the box. If you are familiar with GWT, I would suggest Errai. Other alternative is the Atmospere. The downside of the Atmospere is the fact that it requires standalone running process next to your regular application server with your web app. I was playing with it a year ago so this may have been changed since then.
In general, it is hard to provide you with a concrete piece of code, because it depends on the framework you will choose. I am familiar with Errai so here is an example in it:
Server Side:
#ApplicationScoped
public class TickerService {
#Inject
private Event<Tick> tickEvent;
private void sendTick() {
tickEvent.fire(new Tick());
}
}
Client Side:
#EntryPoint
public class TickerClient {
public void tickHappened(#Observes Tick tick) {
// update the UI with the new data
}
}
Other benefits of using the Errai is having the CDI on the server and on the client out-of-the-box, another thing that is nice is using the web-sockets under the covers if it is supported and falling back to other solutions otherwise.
Whatever you choose, it should fit to your existing infrastructure and to your client side UI framework.
mqtt can be used for server pushing and message broadcasting.
There are more detail information in http://mqtt.org/.
======================================
Updated: Jul 11, 2013
Mqtt is a publish/subscribe, extremely simple and lightweight messaging protocol. If server is a publisher and client browser subscribe the topic which server publish to, then server can push message to client directly.
Some useful resource:
Mosquitto is an open sourced mqtt server. Easy to install and configure.
mqtt-client is a proven powerful java mqtt client.
Use Node JS and socket.io
This technology chooses the best transportation method based on the browser that the client is using.
For latest browsers it uses Web Sockets and for others it degrades gracefully to Flash Socket or Long Pooling. See more here
What you need to do is set up a server using these technologies. The server would run at a particular port. All clients would listen to that port and server would be able to push data to the client through that port.
Comet also known as Reverse Ajax, is a web application model in which a long-held HTTP request allows a web server to push data to a browser, without the browser explicitly requesting it.
Comet (AKA long lived http, server push) allows the server to start answering the browser's request for information very slowly, and to continue answering on a schedule dictated by the server. For more information about Comet, see the following:
Alex Russell's original post coining the term
The Wikipedia article on Comet
Comet Daily, a blog with regular posts on the subject
DWR is a Java library that enables Java on the server and JavaScript in a browser to interact and call each other as simply as possible.
With Reverse Ajax, DWR allows Java code running on a server to use client side APIs to publish updates to arbitrary groups of browsers. This allows interaction 2 ways - browser calling server and server calling browser. DWR supports Comet, Polling and Piggyback (sending data in with normal requests) as ways to publish to browsers.
DWR provides integration with Spring, Struts, Guice, Hibernate and others.
You can read more from here.
Other Comet and Reverse AJAX frameworks:
Grizzly Comet API
Atmosphere
AJAX push with ICEfaces
Asynchronous Servlet using Servlet 3.0
but after session.save(user) the aftersave method does not get triggered.
#PostPersist is a JPA callback.
session.save() is a non-JPA, hibernate proprietary method. JPA uses entityManager.persist().
you're using incompatible features
Check for update from server on every 30 Seconds or as per requirement.
window.setInterval(function(){
/// call your function here
//Make AJAX call
//Update Respective HTML Contact i,e, DIV
}, 30000);