SELECT * FROM `user`
WHERE name !='' AND `date_created` BETWEEN DATE_SUB( CURDATE( ) ,INTERVAL 3 Day )
AND DATE_SUB( CURDATE( ) ,INTERVAL 0 Day )
ORDER BY `date` ASC
The above query brings record 3day before from todays date.
but i need 3day records from today,which means tomorrow , day after tomorrow etc.
date_created is mysql date format.
SELECT * FROM `user`
WHERE name !=''
AND `date_created` BETWEEN curdate() and curdate() + interval 3 day
ORDER BY `date`
I have created this will return previous 3 days record
select * from events where DATEOFEVENT IN (select date(curdate()-3 ))
Related
I am trying to select records that are older than 1 day or 24 hours from a MYSQL DB. I can't figure it out why this statement doesn't work with NOW() and it only works if I explicitly add the date manually, here is the code for your review:
date_posted is setup as "datetime" in the DB table.
Works this way (Not desirable, for testing only)
SELECT count( DISTINCT my_id ) AS 'a'
FROM my_table
WHERE date_posted >= DATE_SUB( '2015-10-03 09:10:19', INTERVAL 24 HOUR )
It should work this way, but it brings a "0" count result:
SELECT count( DISTINCT my_id ) AS 'a'
FROM my_table
WHERE date_posted >= DATE_SUB( NOW(), INTERVAL 24 HOUR )
SELECT count( DISTINCT my_id ) AS 'a'
FROM my_table
WHERE date_posted >= subdate(current_date, 1)
here subdate(current_date, 1) will return your the yesterday date
if your want to select only the yesterday post then use the following
WHERE date_posted = subdate(current_date, 1)
Table Client contains last_name and email column while table Product contain email and expiry_date column with 13 row of records. This syntax correctly select only 2 rows from Product table.
SELECT * FROM `Product` WHERE expiry_date > DATE_ADD( CURRENT_DATE, INTERVAL 24 DAY )
AND expiry_date < DATE_ADD( CURRENT_DATE, INTERVAL 24 + 1 DAY )
Now I want to join it with Client table to select last_name with matching email. Unfortunately my JOIN syntax below select all 13 records from Product table.
SELECT * FROM `Product` JOIN `Client`
ON product.email=client.email
AND (expiry_date > DATE_ADD( CURRENT_DATE, INTERVAL 24 DAY )
AND expiry_date < DATE_ADD( CURRENT_DATE, INTERVAL 24 + 1 DAY ))
This syntax also does not work. All 13 rows from Product table was selected:
SELECT * FROM
(
SELECT * FROM `Product` WHERE expiry_date > DATE_ADD( CURRENT_DATE, INTERVAL 24 DAY )
AND expiry_date < DATE_ADD( CURRENT_DATE, INTERVAL 24 +1 DAY )
) A
LEFT JOIN Client ON A.email=client.email
WHERE A.expiry_date > DATE_ADD( CURRENT_DATE, INTERVAL 24 DAY )
AND A.expiry_date < DATE_ADD( CURRENT_DATE, INTERVAL 24 +1 DAY )
How do I select only 2 last_name and not all 13. I hope I explained it clearly. Thanks in advance.
The way you are specifying your JOIN conditions, everything matches. You should specify a WHERE clause instead
SELECT * FROM `Product` JOIN `Client`
ON product.email=client.email
WHERE expiry_date > DATE_ADD( CURRENT_DATE, INTERVAL 24 DAY )
AND expiry_date < DATE_ADD( CURRENT_DATE, INTERVAL 24 + 1 DAY )
You need to use GROUP BY to get only 2 rows instead of all rows in Product table. For example:
SELECT * FROM `Product` JOIN `Client`
ON product.email=client.email
AND (expiry_date > DATE_ADD( CURRENT_DATE, INTERVAL 24 DAY )
AND expiry_date < DATE_ADD( CURRENT_DATE, INTERVAL 24 + 1 DAY ))
GROUP BY expiry_date
Basically, I've got a query which looks like the following
SELECT
*
FROM
`transactions`
WHERE
`date` > DATE_SUB(NOW(), INTERVAL 1 DAY)
AND
`status` = '1'
How can I do it so I can get it from just today, not the past 24 rolling hours; the same for a week & month etc..?
Use DATE() to get the date of your date column and compare it to today's date using CURDATE()
WHERE
DATE(`date`) = CURDATE()
Use
SELECT *
FROM `transactions`
WHERE `date` >= curdate() AND `date` < curdate() + interval 1 day
AND `status` = '1'
which can make use of indexes to speed up the query
I have table like
CREATE TABLE `survey` (
`id` int(11) NOT NULL auto_increment,
`submitdate` datetime default NULL,
`answer` varchar(5) collate utf8_unicode_ci default NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=499 ;
now to get values like
c t Clicks
2012-10-29 2012-10-22 10
2012-11-04 2012-10-30 20
2012-11-11 2012-11-05 30
2012-11-19 2012-11-12 34
I am using this query
SELECT uq.timespan, COALESCE(tsq.TotalClicks, 0) as Clicks FROM (
SELECT DATE( DATE_ADD( NOW( ) , INTERVAL -21
DAY ) ) c, DATE( DATE_ADD( NOW( ) , INTERVAL -28
DAY ) ) l
union SELECT DATE( DATE_ADD( NOW( ) , INTERVAL -15
DAY ) ) c, DATE( DATE_ADD( NOW( ) , INTERVAL -20
DAY ) ) l
union SELECT DATE( DATE_ADD( NOW( ) , INTERVAL -8
DAY ) ) c, DATE( DATE_ADD( NOW( ) , INTERVAL -14
DAY ) ) l
union SELECT curdate() c,DATE( DATE_ADD( NOW( ) , INTERVAL -7
DAY ) ) l
)uq LEFT JOIN (
SELECT CASE
WHEN submitdate >= NOW() - INTERVAL 4 WEEK
AND submitdate < NOW() - INTERVAL 3 WEEK THEN c 'to' l
DAY ) )
WHEN submitdate >= NOW() - INTERVAL 3 WEEK
AND submitdate < NOW() - INTERVAL 2 WEEK THEN c 'to' l
WHEN submitdate >= NOW() - INTERVAL 2 WEEK
AND submitdate < NOW() - INTERVAL 1 WEEK THEN c 'to' l
DAY ) )
WHEN submitdate >= NOW() - INTERVAL 1 WEEK THEN c 'to' l
END Weeksubmitdate,
count(id) TotalClicks
FROM survey
WHERE submitdate >= NOW() - INTERVAL 4 WEEK
GROUP BY Weeksubmitdate
)tsq ON uq.timespan = tsq.Weeksubmitdate";
problem is with 16th line c to l.
I am getting the following error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''to' l
DAY ) )
WHEN submitdate >= NOW() - INTERVAL 3 WEEK
' at line 16
CASE is supposed to evaluate to a scalar expression. That means its THEN clauses must evaluate to scalar expressions too. Now, what does this c 'to' l thing stand for? Is it a scalar expression? It doesn't seem one to me, however I may be unaware of some things in MySQL, so it's more important whether MySQL itself recognises that as a scalar expression. And apparently it doesn't.
There is another issue. You are trying to reference a derived table's columns inside another derived table. More specifically, you seem to be trying to reference the columns c and l of uq inside the tsq subselect, and that is illegal. If uq was a normal table, it would be fine, but since it is a virtual table, the query doesn't know about its existence at that point, i.e. at the time of parsing the tsq subquery.
Anyway, what you seem to be doing with your query could probably be rewritten more simply, like this, for instance:
SELECT
MIN(submitdate) AS startdate,
MAX(submitdate) AS enddate,
COUNT(*) AS clicks
FROM (
SELECT
CASE
WHEN submitdate >= NOW() - INTERVAL 1 WEEK THEN 1
WHEN submitdate >= NOW() - INTERVAL 2 WEEK THEN 2
WHEN submitdate >= NOW() - INTERVAL 3 WEEK THEN 3
WHEN submitdate >= NOW() - INTERVAL 4 WEEK THEN 4
END AS weekid,
*
FROM survey
) s
GROUP BY
weekid
ORDER BY
startdate
;
The subquery assigns surrogate week IDs to every row of survey. The main query groups the results by those IDs and produces the counts as well as starting & ending dates for every group.
I have a table with: userid and timestamp each time a user opens a page a new field is inserted.
I am trying to get the total amount of hours / minutes / days / weeks that appear in a 1 month interval for multiple users.
I have tried a bunch of different queries but each have ended up terribly inefficient.
Ideally I'd like to end up with something like:
userid | minutes | hours | days | weeks
1 10080 168 7 1
2 1440 24 1 0
Hopefully someone can shed some light on how to do this.
Below is a query that I tried:
SELECT
w.time AS `week`,
d.time AS `day`,
h.time AS `hour`,
m.time AS `minutes`
FROM (
SELECT
SUM( t.time ) AS `time`
FROM (
SELECT
COUNT( DISTINCT WEEK( `timestamp` ) ) AS `time`
FROM table
WHERE
userid = "1"
AND
`timestamp` > DATE_SUB( NOW( ) , INTERVAL 1 MONTH )
GROUP BY MONTH( `timestamp` )
) t
) w,
(
SELECT
SUM( t.time ) AS `time`
FROM (
SELECT
COUNT( DISTINCT DAY( `timestamp` ) ) AS `time`
FROM table
WHERE
userid = "52"
AND
`timestamp` > DATE_SUB( NOW( ) , INTERVAL 1 MONTH )
GROUP BY MONTH( `timestamp` )
) t
) d,
(
SELECT
SUM( t.timestamp ) AS `time`
FROM (
SELECT
COUNT( DISTINCT HOUR( `timestamp` ) ) AS `time`
FROM table
WHERE
userid = "1"
AND
`timestamp` > DATE_SUB( NOW( ) , INTERVAL 1 MONTH )
GROUP BY DAY( `timestamp` )
) t
) h,
(
SELECT
SUM( t.timestamp ) AS `time`
FROM (
SELECT
COUNT( DISTINCT MINUTE( `timestamp` ) ) AS `time`
FROM table
WHERE
userid = "1"
AND
`timestamp` > DATE_SUB( NOW( ) , INTERVAL 1 MONTH )
GROUP BY HOUR( `timestamp` )
) t
) m
It seems awfully excessive for this task, maybe someone has something better?
It's not clear to me what you want to "total".
If you want to determine whether a user had a "hit" (or whatever transaction it is you are storing in the table) at any given minute within the month), and then you want to count the number of "minute periods" within a month that a user had a hit:
SELECT t.userid
, COUNT(DISTINCT DATE_FORMAT(t.timestamp,'%Y-%m-%d %H:%i')) AS minutes
, COUNT(DISTINCT DATE_FORMAT(t.timestamp,'%Y-%m-%d %H' )) AS hours
, COUNT(DISTINCT DATE_FORMAT(t.timestamp,'%Y-%m-%d' )) AS days
, COUNT(DISTINCT DATE_FORMAT(t.timestamp,'%X-%V' )) AS weeks
FROM mytable t
WHERE t.timestamp >= '2012-06-01'
AND t.timestamp < '2012=07-01'
GROUP BY t.userid
What this is doing is taking each timestamp, and putting it into a "bucket", by chopping off the seconds, chopping off the minutes, chopping off the time, etc.
Basically, we're taking a timestamp (e.g. '2012-07-25 23:15:30') and assigning it to
minute '2012-07-25 23:15'
hour '2012-07-25 23'
day '2012-07-25'
A timestamp of '2012-07-25 23:25:00' would get assigned to
minute '2012-07-25 23:25'
hour '2012-07-25 23'
day '2012-07-25'
Then we go through and count the number of distinct buckets we assigned a timestamp to. If that's all the hits for this user in the month, the query would return a 2 for minutes, and a 1 for all other period counts.
For a user with a single hit within the month, all the counts for that user will be a 1.
For a user that has all their "hits" within exactly the same minute, the query will again return a 1 for all the counts.
(For a user with no "hits" within a month, no row will be returned. (You'd need to join another row source to get a list of users, if you wanted to return zero counts.)
For a user with a "hit" every second within a single day, this query will return counts like that shown for userid 2 in your example.
This result set gives you a kind of an indication of a user's activity for a month... how many "minute periods" within a month the user was active.
The largest value that could be returned for "days" would be the number of days in the month. The largest possible value to be returned for "hours" would be 24 times the number of days in the month times. The largest possible value returned for "minutes" would be 1440 times the number of days in the month.
But again, it's not entirely clear to me what result set you want to return. But this seems like a much more reasonable result set than the one from the previously "selected" answer.
SELECT userid, SUM(MINUTE(timestamp)) AS minutes, SUM(MINUTE(timestamp))/60 AS hours, SUM(MINUTE(timestamp))/(60*24) AS days, SUM(MINUTE(timestamp))/(60*24*7) AS weeks
FROM Table
GROUP BY userid
If neccesary, use ROUND(SUM(MINUTE(timestamp)), 0) if you want integer numbers.