Mysql query always returns empty value - mysql

Question

This is my code:
$pass = mysql_query("SELECT `password` FROM acc WHERE account_id = '122' LIMIT 1;");
$p = mysql_fetch_object($pass);
$passwd = ( ( $p->password != "" ) ? $p->password : "empty" );
Then I'm doing echo $passwd; and it's always is retuning the "empty" string.
Of course the row with account_id 122 exists.
What is wrong with that?

Answer 1

Try this code:
$query = mysql_query("SELECT * FROM `acc` WHERE `account_id`='122'") or die(mysql_error());
while($data=mysql_fetch_object($query)){
$pass = $data->password;
}
echo $pass
You should now be able to acces all fields from that row including the password field.

Answer 2

what if you change
$passwd = ( ( $p->password != "" ) ? $p->password : "empty" );
to
$passwd = (empty($p->password)) ? $p->password : "empty" );

Answer 3

You don't need the semi-colon at the end of your query. Why do you have a limit 1? acc should be unique on account_id as having multiple passwords for the same account should be impossible.
$pass = mysql_query("SELECT `password` FROM acc WHERE account_id = '122'");
As #shawn pointed out if your account_id is indeed a number it's better not to rely on the implicit character to number conversion. Though it doesn't actually matter it's not good practice.