I have a table named tblMatches containing match results of a sporting event. The score for the winning player is always stored in the P1_Score field, the P2_Score tracks the losing player score.
There are 4 fields within the table that I need to reference.
(P1_ID), (P1_Score), (P2_ID), (P2_Score)
I am passing through an ID_value. I have managed to calculated the total match wins vs total match losses using a mysql_num_rows function.
I am now trying to calculate the total number of games won vs the total number of games lost. I need to somehow determine the sum of the scores.
What about
SELECT (SELECT SUM(P1_Score) FROM tbl WHERE P1_ID = $id) won,
(SELECT SUM(P2_Score) FROM tbl WHERE P2_ID = $id) lost
replace $id with particular player's id and you'll get how much games he won and lost accordingly
Related
I have a table in my database which contains data for recording games between people. I wanted to have a query that would return the game which was closest between two players, ie, the smallest difference between the two scores recorded, regardless of who won. I have started with something like this as a query, but I can't quite get what I want.
SELECT recorder_score, opponent_score
from games
where recorder_id = $recorder_id
order by (recorder_score - opponent_score)
limit 1
The above obviously would only return the closest game that the person submitting the game has won, but as I mentioned, I want the closest game regardless of who wins. What will be the best way of doing this?
Use ABS in Order by to get the closest game between two players
SELECT recorder_score, opponent_score
from games
where recorder_id = $recorder_id
order by ABS(recorder_score - opponent_score)
limit 1
I'm fairly new to php / mysql programming and I'm having a hard time figuring out the logic for a relational database that I'm trying to build. Here's the problem:
I have different leaders who will be in charge of a store anytime between 9am and 9pm.
A customer who has visited the store can rate their experience on a scale of 1 to 5.
I'm building a site that will allow me to store the shifts that a leader worked as seen below.
When I hit submit, the site would take the data leaderName:"George", shiftTimeArray: 11am, 1pm, 6pm (from the example in the picture) and the shiftDate and send them to an SQL database.
Later, I want to be able to get the average score for a person by sending a query to mysql, retrieving all of the scores that that leader received and averaging them together. I know the code to build the forms and to perform the search. However, I'm having a hard time coming up with the logic for the tables that will relate the data. Currently, I have a mysql table called responses that contains the following fields,
leader_id
shift_date // contains the date that the leader worked
shift_time // contains the time that the leader worked
visit_date // contains the date that the survey/score was given
visit_time // contains the time that the survey/score was given
score // contains the actual score of the survey (1-5)
I enter the shifts that the leader works at the beginning of the week and then enter the survey scores in as they come in during the week.
So Here's the Question: What mysql tables and fields should I create to relate this data so that I can query a leader's name and get the average score from all of their surveys?
You want tables like:
Leader (leader_id, name, etc)
Shift (leader_id, shift_date, shift_time)
SurveyResult (visit_date, visit_time, score)
Note: omitted the surrogate primary keys for Shift and SurveyResult that I would probably include.
To query you join shifts and surveys group on leader and taking the average then jon that back to leader for a name.
The query might be something like (but I haven;t actually built it in MySQL to verify syntax)
SELECT name
,AverageScore
FROM Leader a
INNER JOIN (
SELECT leader_id
, AVG(score) AverageScore
FROM Shift
INNER JOIN
SurveyResult ON shift_date = visit_date
AND shift_time = visit_time --depends on how you are recording time what this really needs to be
GROUP BY leader ID
) b ON a.leader_id = b.leader_id
I would do the following structure:
leaders
id
name
leaders_timetabke (can be multiple per leader)
id,
leader_id
shift_datetime (I assume it stores date and hour here, minutes and seconds are always 0
survey_scores
id,
visit_datetime
score
SELECT l.id, l.name, AVG(s.score) FROM leaders l
INNER JOIN leaders_timetable lt ON lt.leader_id = l.id
INNER JOIN survey_scores s ON lt.shift_datetime=DATE_FORMAT('Y-m-d H:00:00', s.visit_datetime)
GROUP BY l.id
DATE_FORMAT here helps to cut hours and minutes from visit_datetime so that it could be matched against shift_datetime. This is MYSQL function, so if you use something else you'll need to use different function
Say you have a 'leader' who has 5 survey rows with scores 1, 2, 3, 4 and 5.
if you select all surveys from this leader, sum the survey scores and divide them by 5 (the total amount of surveys that this leader has). You will have the average, in this case 3.
(1 + 2 + 3 + 4 + 5) / 5 = 3
You wouldn't need to create any more tables or fields, you have what you need.
I've got a MySQL database with lots of entris of highscores for a game. I would like to get the "personal best" entry with the max value of score.
I found a solution that I thought worked, until I got more names in my database, then it returnes completely different results.
My code so far:
SELECT name, score, date, version, mode, custom
FROM highscore
WHERE score =
(SELECT MAX(score)
FROM highscore
WHERE name = 'jonte' && gamename = 'game1')
For a lot of values, this actually returns the correct value as such:
JONTE 240 2014-04-28 02:52:33 1 0 2053
It worked fine with a few hundred entries, some with different names. But when I added new entries and swapped name to 'gabbes', for the new names I instead get a list of multiple entries. I don't see the logic here as the entries in the database seem quite identical with some differences in data.
JONTE 176 2014-04-28 11:03:46 1 0 63
GABBES 176 2014-04-28 11:09:12 1 0 3087
The above has two entires, but sometimes it may also return 10-20 entries in a row too.
Any help?
If you want the high score for each person (i.e. personal best) you can do this...
SELECT name, max(score)
FROM highscore
WHERE gamename = 'game1'
GROUP BY name
Alternatively, you can do this...
SELECT name, score, date, version, mode, custom
FROM highscore h1
WHERE score =
(SELECT MAX(score)
FROM highscore h2
WHERE name = h1.name && gamename = 'game1')
NOTE: In your SQL, your subclause is missing the name = h1.name predicate.
Note however, that this second option will give multiple rows for the same person if they recorded the same high score multiple times.
The multiple entries are returned because multiple entries have the same high score. You can add LIMIT 1 to get only a single entry. You can choose which entry to return with the ORDER BY clause.
I'm currently working on a league systeme for my sport team. A ladder, as seen as in some video games.
It's a mobile web site, allowing coaches to create games, and monitor players performances.
I have games automatically balanced, taking into accounts player's experiences and points, then, i give bonus points to the all the players of the winner team, and remove points from the losers.
I have a relatively simple database. 3 tables.
User : id - name
Games : id - ETA - cration_date
game_joueur: id- id_game - id_joueur - team - result - bonus
game_joueur beeing an assoc table, in wich i register for each new game players id, the team he has been seeded on, and afterwards, update the bonus field with the points earned and the result field with an integer (1 = lose, 2= win)
That way i can sum the bonus on my players stat and get the total points.
You can have a better look at the table here :
http://sqlfiddle.com/#!2/d3e06/2
What i'm tryng to acomplish is for each player's stat page, retrieve from the database the name of his most succesfull partner( the guy wich whom he won the most games), and also his worst ally , the men he lost the most match with.
This is what i do on my user stat page :
SELECT
(SELECT COUNT(lad_game_joueur.result) FROM lad_game_joueur WHERE result = 1 AND lad_game_joueur.id_joueur = lad_user.id) as lose,
(SELECT SUM(lad_game_joueur.bonus) FROM lad_game_joueur WHERE lad_game_joueur.id_joueur = lad_user.id) as points,
lad_user.id as id ,
(SELECT COUNT(lad_game_joueur.result) FROM lad_game_joueur WHERE lad_game_joueur.id_joueur = lad_user.id AND result =2) as win,
lad_user.name
FROM lad_user,lad_game_joueur
WHERE lad_game_joueur.id_joueur = lad_user.id AND lad_user.id
='.$id_joueur.'
GROUP BY lad_user.id
ORDER BY puntos DESC
I'm sure this is not the best way to do it, but it works :) ( i'm no sql specialist)
How can i tune this query to also retrive the informations i'm looking for?
I wont mind doing another query.
Thanks a lot in advance!
Ben
Ok i finealy found a way.
Here's what i did :
SELECT
SUM(result)as result_sum, sum(Bonus) as bonus_sum, id_joueur
from lad_game_joueur
where result= 2
and id_game in
(SELECT lad_game_joueur.id_game from lad_game_joueur,lad_game where id_joueur=2
AND result= 2 and lad_game_joueur.id_game=lad_game.id)
group by id_joueur
order by result_sum DESC, bonus_sum desc
As you see, the sum of result would give me 4 if i won two games with the person, but i just divide by 2 on php and voilà :)
I own an online game in which you become the coach of a rugby team and I recently started to optimize my database. The website uses CodeIgniter framework.
I have the following tables (the tables have more fields but I posted only those which are important now):
LEAGUES: id
STANDINGS: league_id, team_id, points
TEAMS: id, active
Previously, I was having in the LEAGUES table a field named teams. This was representing the number of active teams in that league (of which users logged in recently).
So, I was doing the following select to get a random league that has between 0 and 4 active teams (leagues with less teams first).
SELECT id FROM LEAGUES WHERE teams>0 AND teams<4 ORDER BY teams ASC, RAND( ) LIMIT 1
Is there any way I can do the same command now without having to add the teams field?
Is it efficient? Or It's better to keep the teams field in the database?
LATER EDIT
This is what I did until now:
function test()
{
$this->db->select('league_id, team_id');
$this->db->join('teams', 'teams.id = standings.team_id');
$this->db->where('active', 0);
$query = $this->db->get('standings');
return $query->result_array();
}
The function returns all inactive teams alongside with their league_id.
Now how do I count the number of inactive teams in each league and how to I sort them after this number?
Try this:
select league_id
from standings s
join teams t on t.id = s.team_id and t.active
group by 1
having count(*) < 5