I'm trying to get deeper into "advanced"-SQL'ing but have a slight problem with some pretty basic stuff.
I have one table, where one row refers to another row. There are of course unique id's as well but I'll skip those here:
+----------+----------------------------+
| field | name | value |
+----------+----------------------------+
| 1 | aa | 0 |
| 1 | ab | 0 |
| 2 | ba | 1 |
| 2 | bb | 1 |
| 3 | ca | 2 |
| 3 | cb | 2 |
+----------+----------------------------+
What I want to accomplish is to get field when I know field=3 and name= 'ca'.
I've tried something like this:
SELECT table.value AS parent_id FROM table WHERE table.field=3 AND table.name='ca'
That works at some point, it lists everything at 2:field, I need then to find value 1 from the field. BUT if the 2:field does not have any references (as above illustrated, 1:field) then I need the last value which will be 2:field.
How would that be possible in MySQL?
What you need is a self-join by using the same table TWICE in the same query, but different ALIAS...
select
t1.field,
t1.name,
t1.value as ThisIsYourParentKey,
t2.name as ParentName,
t2.value as GrandParentKey
from
YourTable t1
left join YourTable t2
on t1.value = t2.field
where
t1.name = 'a2'
Related
I need an SQL code to compare data that doesn't exist in one table with respect to another table that holds the set of unique expected data.
I have tried using EXIST and NOT EXIST operators.
The EXIST operator will display all data in the second table. The NOT EXIST operator will not display any results.
The code looks something like
SELECT *
FROM st
WHERE EXISTS
(SELECT data FROM udt WHERE st.data <> udt.data)
This is my unique data table (udt) example:
+------+
| data |
+------+
| 1 |
| 2 |
| 3 |
| 4 |
+------+
This is my second table (st) example:
+------+------+
| name | data |
+------+------+
| AZ | 1 |
| AZ | 3 |
| BY | 2 |
| BY | 4 |
| CX | 1 |
| CX | 4 |
| DW | 2 |
| DW | 3 |
+------+------+
I would like to have a code that will display the name and the code that don't exist in the second table. That is:
+------+------+
| name | data |
+------+------+
| AZ | 2 |
| AZ | 4 |
+------+------+
and so on
For one, will this be possible? If it is possible, what code syntax can I apply?
I get why EXIST and NOT EXIST will not display the data, but is there any way I can get the required results?
Not sure if this is the best way of doing this, it's still early and not much coffee yet :o)
I've changed your field names, but kept them as close as possible to yours.
select q1.[name_],q1.data1
from
(select distinct [name_],data1 from
st,udt) as q1
left join
st as d1
on q1.[name_]=d1.[name_] and
q1.data1=d1.[data_]
where d1.[name_] is null
Gives you the results
name data1
az 2
az 4
by 1
by 3
cx 2
cx 3
dw 1
dw 4
Generate all the combinations of name and data and then remove the ones that are in the second table.
In almost any database, you can do this as:
select n.name, t1.data
from (select distinct name from table2) n cross join
table1 t1 left join
table2 t2
on t2.name = n.name and t2.data = t1.data
where t2.data is null;
MS Access does not support this syntax, so you can do:
select n.name, t1.data
from (select distinct name from table2) n,
table1 t1
where not exists (select 1
from table2 t2
where t2.name = n.name and t2.data = t1.data
);
I have two tables which have the same structure but another names (in first table I store default values, in second table I store saved values by user).
I select these values using union all:
SELECT * FROM `table_default` UNION ALL SELECT * FROM `table_saved`
Structure of table_default:
| ID | SOME_VAL |
| 1 | def_val |
| 2 | def_val |
| 3 | def_val |
Structure of table_saved:
| ID | SOME_VAL |
| 1 | test |
| 3 | text |
And now, when I using this query:
SELECT * FROM `table_default` UNION ALL SELECT * FROM `table_saved`
I got:
| ID | SOME_VAL |
| 1 | def_val |
| 2 | def_val |
| 3 | def_val |
| 1 | test |
| 3 | text |
But I want to get unique values by ID. Table_saved is more important so when select return duplicates I want to remove always record from table_default.
So finally I want to get:
| ID | SOME_VAL |
| 2 | def_val | --> from TABLE_DEFAULT because this record (by ID) is not exist in table_saved
| 1 | test | --> from TABLE_SAVED
| 3 | text | --> from TABLE_SAVED
I can't use GROUP BY id because I don't know which record will be remove (sometime GROUP BY remove duplicate from table_default but sometimes GROUP BY also remove duplicates from table_saved) so I can't manage this.
Is it possible to remove duplicates (something like GROUP BY) using table name and row name ? Or maybe somebody has another idea. Please help.
Thanks.
If I understand correctly, you want to always retain all records from table_saved, plus records from table_default having IDs not appearing in table_saved. One approach is to use a left join to find the unique records from table_default. Then union that with all records from table_saved.
SELECT t1.ID, t1.SOME_VAL
FROM table_default t1
LEFT JOIN table_saved t2
ON t1.ID = t2.ID
WHERE t2.ID IS NULL
UNION ALL
SELECT ID, SOME_VAL
FROM table_saved;
If a default value is always present you could use a LEFT JOIN and COALESCE:
SELECT d.ID, COALESCE(s.SOME_VAL, d.SOME_VAL) AS SOME_VAL
FROM table_default d
LEFT JOIN table_saved s USING(ID)
I want to select rows without duplicate values in columns. What I mean is that if there is a row with | 2 | 1 | and another one with | 1 | 2 | in the current selection, I want to show only one of them.
+------+------+
| id1 | id2 |
+------+------+
| 2 | 1 |
| 4 | 3 |
| 3 | 4 |
| 1 | 4 |
+------+------+
so in the example above it will select only first, last and either second OR third row.
and also to substitute these values with the string 'TITLE' from another table.
table values:
+----+----------+
| id | title |
+----+----------+
| 1 | title1 |
| 2 | title2 |
| 3 | title3 |
| 4 | title4 |
+----+----------+
so that the final select would have only titles in rows.
You can use least and greatest to do this. least gets the lower value of id1,id2 and greatest gets the greater of id1,id2.
select distinct least(id1,id2),greatest(id1,id2)
from t
Actually the above generates rows which aren't in the table. To avoid it, you need a left join with a derived table.
select t1.id1,t1.id2
from t t1
left join (select least(id1,id2) as id1,greatest(id1,id2) as id2
from t
group by least(id1,id2),greatest(id1,id2)
having count(*) > 1
) t2 on t2.id1=t1.id1 and t2.id2=t1.id2
where t2.id1 is null and t2.id2 is null
Edit: To get the title strings from a different table based on id's
select t1.id1,t1.id2,tt1.title,tt2.title
from t t1
left join (select least(id1,id2) as id1,greatest(id1,id2) as id2
from t
group by least(id1,id2),greatest(id1,id2)
having count(*) > 1
) t2 on t2.id1=t1.id1 and t2.id2=t1.id2
join titles tt1 on tt1.id=t1.id1 --use a left join if the titles table won't have all the id's
join titles tt2 on tt2.id=t1.id2 --use a left join if the titles table won't have all the id's
where t2.id1 is null and t2.id2 is null
I am sure this would be easy to google if I knew the right words to use, but I've tried and not come up with anything: apologies if this is a common question on SO.
I have one table which lists a set of records which can be one of 4 types.
table_1:
+-------+------------+------+
| id | value | type |
+-------+------------+------+
| 1 | x | 1 |
| 2 | y | 1 |
| 3 | z | 2 |
| 4 | a | 3 |
+-------+------------+------+
I have another table which references the id of this table and stores data
table_2:
+-------+------------+------+
| id | table_1_id |value |
+-------+------------+------+
| 1 | 4 | A |
| 2 | 2 | B |
| 3 | 3 | C |
| 4 | 2 | D |
+-------+------------+------+
I want to write a query that effects:
"Find all the records from table 1 which are of type 1, take the id's of those records, and find all the records in table 2 where 'table_1_id' which match one of that set of ids."
In the above very oversimplified table example that would result in the query returning records with ids 2 and 4 in table 2
Sounds like your looking for IN:
select *
from table2
where table_1_id in (select id from table1 where type = 1)
Or perhaps you could JOIN the tables:
select t2.*
from table2 t2
join table1 t1 on t2.table_1_id = t1.id
where t1.type = 1
Joining the tables could result in duplicate records. Depends on your needs.
SELECT t1.value,t1.type,t2.value FROM table1 t1,table2 t2 WHERE t1.id = t2.table_1_id AND t1.type = 1;
I want to use a JOIN to return a boolean result. Here's an example of the data...
t1
id | data
-----------
1 | abcd
2 | 2425
3 | xyz
t2
id | data | t1_id |
-------------------------
1 | 75 | 2 |
2 | 79 | 2 |
3 | 45 | 3 |
So with these two tables I want to select all the data from t1, and also whether a given variable appears in t2.data for each id.
So say the variable is 79, the results should be
id | data | t2_boolean
--------------------------
1 | abcd | 0
2 | abcd | 1
3 | xyz | 0
So I'm thinking some sort of join is needed, but without a WHERE clause.
I've been banging my head about this one. Is it possible? I really need it inside the same statement as I want to sort results by the boolean field.
As the boolean needs to be a field, can I put a join inside of a field?
Thanks...
You might have to do a bit of work to knock this into a format suitable for MySQL but does this help?
SELECT t1.id, t1.data, t2.id IS NOT NULL AS t2_boolean
FROM t1
LEFT OUTER JOIN t2 on t1.id = t2.id AND t2.data = 79