I have a very strange behavior when I got mutations in a node in xml when I try to parse it with an XSLT.
So we now assume that CustomerName has the Value 'MÖP'.
In this case, the resulting HTML 'a' tag would have a href to 'M%C3%B6P'
<a href="{CustomerName}">
<xsl:value-of disable-output-escaping="yes" select="CustomerName"/>
</a>
In this case, the resulting HTML 'div' tag would have an id 'MÖP'
<div style="display:none">
<xsl:attribute name="id"><xsl:value-of select="CustomerName"/></xsl:attribute>
</div>
It seems like the attribute href in the a tag has something to do with it.
My question is, why is it like that ?
An what can i do that in both cases i got the same output ?
Greetz
The XSLT processor is doing you a favour by escaping the URL value in the href attribute of the HTML link element. This is by design, see http://www.w3.org/TR/xslt-xquery-serialization/#HTML_ESCAPE-URI-ATTRIBUTES. If you really don't want that and you use an XSLT 2.0 processor then you can use <xsl:ouput method="html" escape-uri-attributes="no"/> in your stylesheet.
Related
I want a client-side XSL-transformed document with elements targettable (jumpable to) by #foo (URL fragments). Problem is, as soon as I attach the simplest XSL stylesheet, Firefox stops scrolling to the elements. Here's simple code:
test.xml:
<?xml version='1.0' encoding='UTF-8'?>
<?xml-stylesheet type='text/xsl' href='test.xsl'?>
<!DOCTYPE foo [<!ATTLIST bar id ID #REQUIRED>]>
<foo xmlns:html='http://www.w3.org/1999/xhtml' xml:lang='en-GB'>
<html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/>
<bar id='baz'>Baf.</bar>
</foo>
test.xsl:
<xsl:stylesheet version='1.0' xmlns:html='http://www.w3.org/1999/xhtml' xmlns:xsl='http://www.w3.org/1999/XSL/Transform'>
<xsl:template match='/'>
<xsl:copy-of select='.'/>
</xsl:template>
</xsl:stylesheet>
As soon as I uncomment the stylesheet line, /test.xml#baz does nothing. As though the transformation somehow loses some data about elements' identification.
Any ideas? Thanks.
Well the XSLT/XPath data model does not include any DTD and thus your result tree that XSLT creates is a copy of the input without the DTD, thus there is no definition of any ID attributes in the result tree and Firefox has no way of establishing to which element with which attribute #some-id refers.
Usually if you use client-side XSLT in the browser the target format is (X)HTML or SVG or a mix of both where id attributes are known by the browser implementation without needing a DTD. If you want to transform to a result format unknown to the browser then I don't think there is a way to use DTDs for the result tree in Firefox/Mozilla. And I am not sure whether they ever implemented xml:id support so that you could use that instead of defining your own ID attributes.
Martin Honnen's mention of XHTML resulted in experimentation during which I found out that setting the target element's namespace to XHTML's, xmlns='http://www.w3.org/1999/xhtml', does the trick. It doesn't seem very clean, but it doesn't seem as grave as, for instance, setting the whole doctype to XHTML's. So text.xml is now:
<?xml version='1.0' encoding='UTF-8'?>
<?xml-stylesheet type='text/xsl' href='test.xsl'?>
<foo xmlns:html='http://www.w3.org/1999/xhtml' xml:lang='en-GB'>
<html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/><html:br/>
<html:bar id='baz'>Baf.</html:bar>
</foo>
Also relevant might be http://xmlplease.com/xhtmlxhtml I found.
Thanks, all.
This is a similar question to Style inline text along with nested tags with XSLT, but I can't comment to get clarification, so I will elaborate my specific scenario here. I basically have an XML document with the following structure:
<book>
<chapter>
<para>This is some text about <place>New York</place></para>
</chapter>
</book>
I am using XSLT to output XHTML from my XML file, and I want to be able to put span tags or something around the content in the place tag in the example above. The purpose is so that I can style these segments of text with CSS. Following the example I referenced above, I added this:
<xsl:template match="book/chapter/para/place">
<span class="place">
<xsl:apply-templates/>
</span>
</xsl:template>
When I load the XML document in the browser I get the error: "Error loading stylesheet: Parsing an XSLT stylesheet failed." (the stylesheet was loading properly before I added this part)
I'm assuming I lack some basic understanding of how xsl:apply-templates should be used. I would appreciate it if someone could point me in the direction of figuring this out.
Thanks!
The match:
<xsl:template match="book/chapter/para/">
applies templates to all children of the place element, rather than place itself.
Use select within apply-templates instead:
<xsl:template match="/">
<xsl:apply-templates select="book/chapter/para/place"/>
</xsl:template>
In the absence of a select attribute, the xsl:apply-templates instruction processes all of the children of the current node, including text nodes.
A select attribute can be used to process nodes selected by an expression instead of processing all children. The value of the select attribute is an expression. The expression must evaluate to a node-set.
References
XSLT 1.0 Specification
My xsl file has this
<img>
<xsl:attribute name="src">
<xsl:value-of select="//movie[#num='1']/thumb_img1" width="100" height="111"/>
</xsl:attribute>
</img>
my xml file has
<questions>
<question>
<movie num="0">
<num>0</num>
<quote>Xslt</quote>
<title>movie</title>
<thumb_img1>pic.jpeg</thumb_img1>
<big_img>bigpic.jpeg</big_img>
</movie>
when I run this I just get an x in a picture box when I use value-of it gives me the filename pic.jpeg which is what I want to use as the source for the picture
First of all, what you wrote is not correct XSLT code. Using this code, you could never have transformed anything. The attributes width and height are not allowed on an xsl:value-of element.
Use an attribute value template instead of xsl:attribute.
<img src="{//movie[#num='1']/thumb_img1}" width="100" height="111"/>
Depending on the context of the img element in your code (the template match) you might not need to start the expression with //.
I've an XML file generated as an output of a Java program. This contains some text in the form of html in which the tags are written with < and > instead of < and > respectively. I want to convert this xml to html where in the inner html is also processed. For example:
My xml snippet:
<company>
<companyEnhancement>
Rank: -1</br> Other Links</br>http://www.gehealthcare.com/</br>
</companyEnhancement>
</company>
And, my xslt stylesheet has this part to parse it:
<td>
<xsl:value-of select="companyEnhancement"/>
</td>
But the html output on the browser, has this data as it is within a table cell:
Rank: -1 </br> Other Links</br>http://www.gehealthcare.com/</br>
I read through the links here, but I am not able to understand what exactly I should do in the stylesheet.
Please help me out. I am very new to xslt, so please excuse if it is a silly question.
Thanks
You say you have HTML in there but </br> is not HTML syntax, that would be <br> or perhaps for XHTML <br />.
If you really have escaped HTML and want to output that then you can try
<xsl:value-of select="companyEnhancement" disable-output-escaping="yes"/>
but that is only going to help if your XSLT processor serializes the result tree. Firefox for instance does not do that and does not support disable-output-escaping.
Im working with XSLT and I'm outputting an HTML5 document. In my document I need a custom attribute.
I want to achieve this:
<div class="row" data-template>...</div>
So far I have managed to do it using CDATA, like so:
<xsl:text disable-output-escaping="yes"><![CDATA[<div class="row" data-template></div>]]></xsl:text>
Whilst this produces valid markup, the problem arises here when you need to work with the actual node, such as setting the ID dynamically. One of my cohorts suggested the following output:
<div class="row" data-template=""></div>
using:
<xsl:attribute name="data-template" />
Again this is valid, but looks somewhat ugly. Is there another method that allows me to output valid custom data attributes for HTML5?
You might want to live with the fact that <xsl:attribute> produces a name-value pair attribute but make it semantically sensible as a boolean value.
<xsl:attribute name="data-template">true</xsl:attribute>
should produce
<div class="row" data-template="true"></div>
which looks a little less ugly.
Did you already tried:
<xsl:attribute name="data-template">data-template</xsl:attribute>
However I think is not possible to get rid of key-value pairs