I have a table with values as shown
Player || Match || Score
A 1 72
B 1 55
A 2 100
C 1 90
B 2 175
I wish to obtain the player name who has scored maximum runs(sum of his scores in all the matches) in this table.
How can this be done in efficient way in mysql
Thanks
Unverified:
select Player
from myTable
group by Player
order by sum(score) desc
limit 1
$query = "SELECT player,MAX(SUM(Score)) FROM table_name GROUP BY player";
Related
I have a Mysql table with users playing as double partners in a tennis tournament and also a table with rankings in which every player has a ranking score in doubles matches.
Tournaments_registrations_doubles
id
player1_id
player2_id
1
32
25
2
25
28
3
143
83
Rankings_doubles
id
player_id
points
1
25
127
2
19
83
3
32
97
4
83
41
I am trying to build an SQL query that will get the ids of the Tournaments_registrations_doubles table in descending order based on the sum of the ranking points of each player group. So player_1 and player_2 who's sum of point in rankings table is highest should come first, and so on. Not all players are registered in the ranking table.
Any ideas on how to implement this?
Join the tournament table to the doubles table twice, once for each of the two player columns. Then order the result set descending by the sum of points.
SELECT t.id, t.player1_id, t.player2_id,
COALESCE(r1.points, 0) + COALESCE(r2.points, 0) AS total
FROM Tournaments_registrations_doubles t
LEFT JOIN Rankings_doubles r1 ON r1.player_id = t.player1_id
LEFT JOIN Rankings_doubles r2 ON r2.player_id = t.player2_id
ORDER BY COALESCE(r1.points, 0) + COALESCE(r2.points, 0) DESC;
Notice that we use left joins here, so that we may treat missing points as zero when computing the totals.
I'm creating a simple database which will allow me to track snooker results, producing head to head results between players. Currently I have 3 tables: (Player, Fixture, Result)
PlayerID PlayerName
1 Michael Abraham
2 Ben Mullen
3 Mark Crozier
FixtureID Date TableNo Group
1 07/12/2015 19:00:00 12 0
2 08/12/2015 12:00:00 9 0
ResultID FixtureID PlayerID FramesWon
1 1 1 3
2 1 3 1
3 2 1 5
4 2 2 1
I would like a query which returns all rows in the result table for fixtures which took place between players 1 and 3. Currently my query is:
SELECT *
FROM Result
WHERE PlayerID IN (1,3);
This returns the first 3 rows of the result table - when I'm only looking for the top 2 rows because they share the same FixtureID. Is there an easy way to remove the third row from this query result, or should I reconsider my database design? Any help would be appreciated.
One solution is to use a GROUP BY query, grouping by FixtureID and counting the rows for each FixtureID. This query will select all FixtureIDs with both players 1 and 3:
select
FixtureID
from
Results
where
PlayerID IN (1,3)
group by
FixtureID
having
count(*)=2
then to get the record from the Results table you can use this query:
select *
from Results
where FixtureID IN (
select FixtureID
from Results
where PlayerID IN (1,3)
group by FixtureID
having count(*)=2
)
You could join your fixtures table twice, like this:
select
*
from
Result as R1
join Result as R2 on R1.FixtureID = R2.FixtureID
where
R1.PlayerID in (1,3)
AND R2.PlayerID in (1,3)
AND R1.PlayerID != R2.PlayerID
group by
R1.FixtureID
;
Or, since it's a bit messy now, show it like a snooker score display often is shown:
select
R1.FixtureID, R1.PlayerID as player1, R1.FramesWon as player1_frames, R1.FramesWon+R2.FramesWon as total_frames, R2.FramesWon as player2_frames, R2.PlayerID as player2
from
Result as R1
join Result as R2 on R1.FixtureID = R2.FixtureID
where
R1.PlayerID in (1,3)
AND R2.PlayerID in (1,3)
AND R1.PlayerID != R2.PlayerID
group by
R1.FixtureID
;
I'm creating a simple database which will allow me to track snooker results, producing head to head results between players. Currently I have 3 tables: (Player, Fixture, Result)
PlayerID PlayerName
1 Michael Abraham
2 Ben Mullen
3 Mark Crozier
FixtureID Date TableNo Group
1 07/12/2015 19:00:00 12 0
2 08/12/2015 12:00:00 9 0
ResultID FixtureID PlayerID FramesWon
1 1 1 3
2 1 3 1
3 2 1 2
4 2 3 5
As you can see in the Result table, Player1 has played Player3 two times, with Player1 winning the first match 3-1, and Player3 winning the second match 5-2. I would like a query which returns the total number of matches won between the two players. In this case the expected output should be:
PlayerID MatchesWon
1 1
3 1
Any help would be appreciated - I'm not even sure if this can be achieved via a query
I agree using windowing function would be best way to go if available (SQL Server for example)
Might be possible with a straight SQL method this way (given that the one having most wins in a "fixture" is the match winner)
SELECT PlayerId, FixtureID, Count(*) As MatchesWon
FROM Result r
WHERE r.Frameswon = (SELECT MAX(frameswon) FROM Result r2
WHERE
r.FixtureId = r2.FixtureId)
GROUP BY PlayerID,FixtureId
OR if can leave out the fixtureId, and filter for just the 2 players something like this one as well. with data given above should bring the sample results.
SELECT PlayerId, MatchesWon
FROM
(
SELECT FixtureID,PlayerId, Count(*) As MatchesWon
FROM Result r
WHERE r.Frameswon = (SELECT max(frameswon) FROM Result r2
WHERE
r.FixtureId = r2.FixtureId)
GROUP BY FixtureId,PlayerID
) s
WHERE
PlayerID IN (1,3)
Perhaps this would work for you:
select playerid, count(*) as matcheswon
from result as r1
where frameswon =
(
select max(frameswon)
from result as r2
where r2.fixtureid = r1.fixtureid
)
group by playerid
In a fiddle here: http://sqlfiddle.com/#!9/60821/2
This is the alternative you can try.
SELECT r.PlayerID, COUNT(r.PlayerID)
FROM (
SELECT FixtureID, MAX(FramesWon) AS FramesWon
FROM `result`
GROUP BY FixtureID
) win
INNER JOIN result r ON win.FixtureID = r.FixtureID AND win.FramesWon = r.FramesWon
GROUP By r.PlayerID
I have a table, it similar with this table
ID Name Age Status
1 John 32 Life
2 Andre 99 Life
3 Anton 89 Dead
4 Maria 99 Life
5 Mario 13 Life
6 Santi 89 Dead
7 Anggy 56 Dead
8 Amir 99 Life
I want to do something like this
1. Group rows by status (Life)
2. Get the max Age from that group (99) (only the max number need)
4. Make new group by age and sort it by ID.
The result will be
8 Amir 99 Life
4 Maria 99 Life
2 Andre 99 Life
Any way to use only 1 line query for that job? with some (php) data procesing its not to hard to get the result i want, but i want to make code as clean as posible, so maybe i can do that 3 step in just a single query?
I think the right logic is:
select t.id, t.name, t.age, t.status
from table t join
(select max(t2.age) from table t2 where t2.status = 'life') m
on t.age = m.age
where t.status = 'life'
order by id desc;
select id, name, age, status
from thetable
where age =
(select max(age)
from thetable
where status="Life"
)
where status="Life"
order by id desc
Use the below mentioned query :
SELECT
*
FROM
t4
CROSS JOIN
(SELECT
MAX(`age`) AS 'age'
FROM
t4
WHERE
`status` = 'Life') AS t5
WHERE
`status` = 'Life' AND t4.`age` = t5.age
ORDER BY `id` DESC;
Check SQLFiddle
I have a table:
quiz userid attempt grade
1 3 1 33
1 3 2 67
1 3 3 90
1 3 4 20
Now, I want the last two attempts i.e., 4 and 3 and I want average grade of these 2 grades i.e, 90 and 20
Could anyone help me?
Use ORDER and LIMIT to get the 2 last attempts and the AVG aggregation function :
SELECT AVG(grade) AS average FROM (
SELECT grade FROM table
WHERE userid = 3
ORDER BY attempt DESC LIMIT 2) AS t
If you want to list both test results separately, with the average in each row, then something like this maybe (otherwise you just need the subquery for the average of the two tests):
SELECT userid, attempt, grade,
( SELECT AVG(grade)
FROM table
ORDER BY attempt DESC LIMIT 0, 2 ) AS avg_grade
FROM table
ORDER BY attempt DESC LIMIT 0, 2;