Using an IF Statement in a MySQL SELECT query - mysql

Question

I am trying to use an IF statement in a MySQL select query.
I am getting an error after the AND statement where the first IF.
SELECT J.JOB_ID,E.COMPANY_NAME,J.JOB_DESC,JT.JOBTYPE_NAME,J.COMPENSATION,ST.STATE_NAME,MC.METRO_CITY_NAME,I.INDUSTRY_NAME,
J.JOB_CONTACT_PERSON,J.DT_INSRT,J.JOB_TITLE,J.JOB_EXP_DATE,J.SKILLS
FROM JOBS J
JOIN EMPLOYER E ON J.COMPANY_ID=E.COMPANY_ID
JOIN LOOKUP_JOBTYPE JT ON J.JOB_TYPE=JT.JOBTYPE_ID
JOIN LOOKUP_STATE ST ON J.STATE_ID=ST.STATE_ID
JOIN JOBS_LOCATION JL ON J.JOB_ID=JL.JOB_ID
JOIN LOOKUP_METRO_CITY MC ON JL.METRO_CITY_ID=MC.METRO_CITY_ID
JOIN LOOKUP_INDUSTRY I ON J.INDUSTRY_ID=I.INDUSTRY_ID
JOIN JOBS_QUALIFICATION JQ ON J.JOB_ID=JQ.JOB_ID
JOIN LOOKUP_DEGREE_QUALIFICATION LDQ ON LDQ.QUALIFICATION_ID = JQ.QUALIFICATION_ID
WHERE J.ACTIVE='Y' AND J.DT_INSRT > COALESCE(pEmailSntDt,DATE_SUB(SYSDATE(),INTERVAL 4 DAY))
AND
IF(JQ.COURSE_ID=0)
THEN
IF(JQ.DEGREE_ID=0)
THEN J.SKILLS LIKE CONCAT('%', pSkills,'%')
ELSE
JQ.DEGREE_ID=pDegreeId OR J.SKILLS LIKE CONCAT('%', pSkills,'%')
END IF
ELSE
JQ.COURSE_ID=pCourseId OR IF(JQ.DEGREE_ID=0)
THEN
J.SKILLS LIKE CONCAT('%', pSkills,'%')
ELSE
JQ.DEGREE_ID=pDegreeId OR J.SKILLS LIKE CONCAT('%', pSkills,'%')
END IF
END IF
GROUP BY J.JOB_ID ORDER BY J.DT_INSRT DESC;
Why doesn't this work and what is the proper way to do an IF statement in a MySQL query?

Answer 1

The IF/THEN/ELSE construct you are using is only valid in stored procedures and functions. Your query will need to be restructured because you can't use the IF() function to control the flow of the WHERE clause like this.
The IF() function that can be used in queries is primarily meant to be used in the SELECT portion of the query for selecting different data based on certain conditions, not so much to be used in the WHERE portion of the query:
SELECT IF(JQ.COURSE_ID=0, 'Some Result If True', 'Some Result If False'), OTHER_COLUMNS
FROM ...
WHERE ...

Answer 2

How to use an IF statement in the MySQL "select list":
select if (1>2, 2, 3); //returns 3
select if(1<2,'yes','no'); //returns yes
SELECT IF(STRCMP('test','test1'),'no','yes'); //returns no
How to use an IF statement in the MySQL where clause search condition list:
create table penguins (id int primary key auto_increment, name varchar(100))
insert into penguins (name) values ('rico')
insert into penguins (name) values ('kowalski')
insert into penguins (name) values ('skipper')
select * from penguins where 3 = id
-->3 skipper
select * from penguins where (if (true, 2, 3)) = id
-->2 kowalski
How to use an IF statement in the MySQL "having clause search conditions":
select * from penguins
where 1=1
having (if (true, 2, 3)) = id
-->1 rico
Use an IF statement with a column used in the select list to make a decision:
select (if (id = 2, -1, 1)) item
from penguins
where 1=1
--> 1
--> -1
--> 1
If statements embedded in SQL queries is a bad "code smell". Bad code has high "WTF's per minute" during code review. This is one of those things. If I see this in production with your name on it, I'm going to automatically not like you.

Answer 3

try this code worked for me
SELECT user_display_image AS user_image,
user_display_name AS user_name,
invitee_phone,
(CASE WHEN invitee_status = 1 THEN "attending"
WHEN invitee_status = 2 THEN "unsure"
WHEN invitee_status = 3 THEN "declined"
WHEN invitee_status = 0 THEN "notreviwed"
END) AS invitee_status
FROM your_table